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DSSSB TGT/PGT/PRT Exam  >  DSSSB TGT/PGT/PRT Tests  >  DSSSB PGT Chemistry Mock Test - 8 - DSSSB TGT/PGT/PRT MCQ

DSSSB PGT Chemistry Mock Test - 8 - DSSSB TGT/PGT/PRT MCQ


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30 Questions MCQ Test - DSSSB PGT Chemistry Mock Test - 8

DSSSB PGT Chemistry Mock Test - 8 for DSSSB TGT/PGT/PRT 2024 is part of DSSSB TGT/PGT/PRT preparation. The DSSSB PGT Chemistry Mock Test - 8 questions and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus.The DSSSB PGT Chemistry Mock Test - 8 MCQs are made for DSSSB TGT/PGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSSSB PGT Chemistry Mock Test - 8 below.
Solutions of DSSSB PGT Chemistry Mock Test - 8 questions in English are available as part of our course for DSSSB TGT/PGT/PRT & DSSSB PGT Chemistry Mock Test - 8 solutions in Hindi for DSSSB TGT/PGT/PRT course. Download more important topics, notes, lectures and mock test series for DSSSB TGT/PGT/PRT Exam by signing up for free. Attempt DSSSB PGT Chemistry Mock Test - 8 | 300 questions in 180 minutes | Mock test for DSSSB TGT/PGT/PRT preparation | Free important questions MCQ to study for DSSSB TGT/PGT/PRT Exam | Download free PDF with solutions
DSSSB PGT Chemistry Mock Test - 8 - Question 1
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How many days will there be from 23rd January, 2011 to 31st July, 2013 (both days included)?  

Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 1

As 2012 was a leap year, so the number of days in each month from 23rd January, 2011 to 31st July, 2013 is given as follows.
Since 2011 is not a leap year = 365 - 22 = 343 days
Number of days in 2012 = 366 days (leap year)
Number of days in 2013:
January = 31 days
February = 28 days
March = 31 days
April = 30 days
May = 31 days
June = 30 days
July = 31 days
Total number of days in 2013 = 212
Therefore, total number of days from 23rd January, 2011 to 31st July, 2013 = 343 + 366 + 212 = 921

DSSSB PGT Chemistry Mock Test - 8 - Question 2
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Two clocks are set correctly at 10 a.m. on Friday. The first clock gains 2 minutes per hour, which is twice as much as gained by the second clock. What time will the second clock register when the correct time is 2 p.m. on the following Monday?  

Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 2

The time duration from 10 a.m. on Friday to 2 p.m. on the following Monday is 76 hours.
The clock gains 1 minute per hour.
∴ Time gained in 76 hours = 76 minutes = 1 hour 16 minutes
∴ Time shown by the second clock will be 3:16 p.m.

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DSSSB PGT Chemistry Mock Test - 8 - Question 3
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A clock gains 2 minutes in an hour and an other clock loses 4 minutes in an hour. If both these clocks were set at 8 a.m, what will be the time in the first clock, if the second clock shows 10 p.m?  

Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 3

In 1 hour, the first clock turns 62 minutes and the second 56 minutes. This implies that for every 56 minutes of the second clock, the first clock gains 6 minutes.
'The second clock shows 10 p.m.' means that it runs for 14 hours.
In this time, the first clock gains = 90 minutes.
So, the time will be 11:30 p.m.

DSSSB PGT Chemistry Mock Test - 8 - Question 4
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To every action there is an,
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 4

To every action, there is an equal and opposite reaction. This is the newton’s third law of motion.

DSSSB PGT Chemistry Mock Test - 8 - Question 5
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Which committee in the Indian Parliament ensures that the expenditure has not exceeded the grants made by the Parliament and the money has been spent for the intended purpose?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 5
The Committee on Public Undertakings ensures that the expenditure has not exceeded the grants and that the money has been spent for the intended purpose.
DSSSB PGT Chemistry Mock Test - 8 - Question 6
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How does the role of the legislature in budget control differ between the USA and Anglo-Saxon countries?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 6
In the USA, the legislature (Congress) has greater control over budget amendments compared to Anglo-Saxon countries due to the different systems of checks and balances in place.
DSSSB PGT Chemistry Mock Test - 8 - Question 7
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Direction: Read the following passage carefully and answer the questions. Your answer to these questions should be based on passage only.

A stout old lady was walking with her basket down the middle of a street in retrograde to the great confusion of the traffic and no small peril to herself. It was pointed out to her that the pavement was the place for foot-passengers, but she replied, 'I m going to walk where I like. We have got liberty now.' It did not occur to the dear lady that if liberty entitled the foot-passenger to walk down the middle of the the road it also entitled the taxi-drive on the pavement, and that the end of such liberty would be universal chaos. Everything would be getting in everybody else's way and nobody would get anywhere. Individual liberty would have become social anarchy

Q. The lady refused to move from the middle of the street because?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 7

She felt that she was entitled to do whatever she liked.

DSSSB PGT Chemistry Mock Test - 8 - Question 8
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Direction: In 1900, to a shipping clerk---Alexander Fleming---a career in science seemed like a distant dream. Alexander the youngest son of a Scottish farmer from Ayrshire was born on 6, August, 1881. He was able to complete High school but then his family funds ran out. At sixteen he took a job as a shipping clerk and stayed there for four years. In 1901. Alexander came across a small legacy which enabled him to continue his education, and, on the advice of one of his brothers who was a doctor, he chose to prepare for a career in medicine. Alexander did unusually well in medical school along with rifle shooting, swimming, water polo and painting. After his graduation, his teacher Prof. Wright asked him to join him in bacteriological research, which he readily agreed.

Q. What problem was faced by Alexander that nipped his completion of High School ?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 8

Alexander faced financial crisis.

DSSSB PGT Chemistry Mock Test - 8 - Question 9
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Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 1, 2, 3, 6, 9, 18, ?, 54
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 9

1st term = 1
2nd term = 1 * 2 = 2
3rd term = 2 * 3/2 = 3
4th term = 3 * 2 = 6
5th term = 6 * 3/2 = 9
6th term = 9 * 2 =18
7th term = ?
8th term = 54

⇒ For every even position term, the previous term is multiplied by 2 and for the odd positioned term, the previous term is multiplied by 3/2

So, missing term = 18 x 3/2 = 27.

DSSSB PGT Chemistry Mock Test - 8 - Question 10
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A sum of Rs. 600 amounts to Rs. 720 in 4 years at Simple Interest. What will it amount to if the rate of interest is increased by 2%?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 10

600 becomes 720 in 4 years SI —> SI per year = Rs. 30 and hence the SI rate is 5%.
At 7% rate of interest the value of 600 would become 768 in 4 years. (600 + 28% of 600)

DSSSB PGT Chemistry Mock Test - 8 - Question 11
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When a positive number n is divided by 7 leaves the remainder 2, when 3n is divided by the same number, then the remainder is
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 11

N = 7+2 =9
3n = 27
27/7 = 6

DSSSB PGT Chemistry Mock Test - 8 - Question 12
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P, Q, R enter into a partnership. P initially invests 25 lakh & adds another 10 lakhs after one year. Q initially invests 35 lakh & withdrawal 10 lakh after 2 years and R invests Rs 30 Lakhs . In what ratio should the profit be divided at the end of 3 years?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 12

P : Q : R
= (25 × 1 + 35 × 2) : (35 × 2 : 25 × 1) : (30 × 3)
= 95 : 95 : 90
= 19 : 19: 18

DSSSB PGT Chemistry Mock Test - 8 - Question 13
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A police saw a Thief at a distance of 2km. When Police started chasing him Thief also started running. If the ratio of Speeds of Police to Thief is 5:4. Then thief was caught at a certain distance then how many Kms did police run to catch the Thief?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 13

2+x/5 = x/4
X = 8
Police = 8+2 = 10

DSSSB PGT Chemistry Mock Test - 8 - Question 14
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गलत विलोम युग्म छाँटिए:
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 14
  • वैकल्पिक-ऐच्छिक का जो विलोम युग्म है, वह यहाँ गलत है। 
  • वैकल्पिक का सही विलोम- अनिवार्य (युग्म: वैकल्पिक-अनिवार्य)
  • ऐच्छिक का सही विलोम- अनैच्छिक (युग्म: ऐच्छिक-अनैच्छिक)
DSSSB PGT Chemistry Mock Test - 8 - Question 15
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इनमें से ‘मठ’ किसका पर्यायवाची शब्द है?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 15

‘मठ’ के अन्य पर्यायवाची शब्द - विहार, कुटी, स्तर, अखाड़ा, संघ

DSSSB PGT Chemistry Mock Test - 8 - Question 16
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In an experiment, 4 g of M2Ox oxide was reduced to 2.8g of the metal.Tf the atomic mass of the metal is 56 g mol-1, the number of O atoms in the oxide is
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 16

M20x → m
W1/E1 = W2/E2

⟹ 4E = 2.8E + 22.4
1.2E = 22.4
E= 22.4/1.2 = 18.6
Eq = mw/VF  = 18.6= 56/VF
M203    VF=3
The number of O atoms is 3

DSSSB PGT Chemistry Mock Test - 8 - Question 17
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Comprehension Type
This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).

Potassium crystallises in a bcc lattice as shown

Q.

Distance between the two nearest neighbours and between next nearest neighbour respectively, is
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 17

(a)

Nearest neighbours are along the diagonal at the half distance apart, Diagonal AB = √3a

∴ Distance of the nearest neighbour

Next nearest neighbours are along the cell edge = 520 pm

K-atom at the centre is surrounded by eight K-atoms as nearest neighbours.

In bcc, coordination number is six as next nearest neighbours

DSSSB PGT Chemistry Mock Test - 8 - Question 18
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Why do metallic solids conducts electricity?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 18
  • Metals conduct electricity because they have “free electrons.” 
  • Unlike most other forms of matter, metallic bonding is unique because the electrons are not bound to a particular atom.
  • This allows the delocalized electrons to flow in response to a potential difference. 

Thus, metals are good conductors of electricity.

*Multiple options can be correct
DSSSB PGT Chemistry Mock Test - 8 - Question 19
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Which of the following sets of quantum numbers is correct for an electron in 4f orbital ?          [AIEEE- 2004]
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 19

For 4f orbital electrons, n = 4

                       s p d f

l = 3 (because 0 1 2 3 )

m = +3, +2, +1, 0, –1, –2, –3

s = ±1/2.

DSSSB PGT Chemistry Mock Test - 8 - Question 20
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Which one of the following sets of ions represents the collection of isoelectronic species ? [AIEEE- 2004]
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 20

 Isoelectronic species are those which have same number of electrons.
K+ = 19 – 1 = 18 ; Ca2+ = 20 – 2 = 18
Sc3+ = 21 – 3 = 18 ; Cl– = 17 + 1 = 18
Thus all these ions have 18 electrons in them.

DSSSB PGT Chemistry Mock Test - 8 - Question 21
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lf En = total energy, Kn = kinetic energy, Vn = potential energy and rn = radius of the nth orbit, then based on Bohr’s theory, match the parameter in Column I with the values in Column II.
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 21





DSSSB PGT Chemistry Mock Test - 8 - Question 22
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Direction (Q. Nos. 11-14) This section contains  a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given options (a),(b),(c),(d)

Passage I

Solid ammonium chloride is in equilibrium with ammonia and hydrogen chloride gases

0.980 g of solid NH4CI is taken in a closed vessel of 1 L capacity and heated to 275° C.

Q. Partial pressure of NH3(g) or HCI (g) at equilibrium is
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 22

The reaction is as follow:-
NH4Cl(s)  ⇋  NH3(g) + HCl(g)
Kp = (pNH3)(pHCl)
1×10-2 = p2   (SInce reactant dissociates into same ratio, so the partial pressure will be same for both)
100×10-4 = p2
Or p = 10×10-2 = 0.10
So,  the partial pressure of NH3 and HCl are 0.10 atm.

DSSSB PGT Chemistry Mock Test - 8 - Question 23
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The equilibrium constant for the reaction

CO(g) + H2O(g)  CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.

What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 23







DSSSB PGT Chemistry Mock Test - 8 - Question 24
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pH of saturated solution of silver salt of monobasic acid HA is found to be 9.

Find the Ksp of sparingly soluble salt Ag A(s).

Given : Ka(HA) = 10-10
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 24




Ksp  = S (S–X) = 11 × 10–6 × 10–6
= 1.1 × 10–11

DSSSB PGT Chemistry Mock Test - 8 - Question 25
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The solubility of Mg(OH)2 is x mole/ltr. then its solubility product is - 

[AIEEE-2002]

Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 25

DSSSB PGT Chemistry Mock Test - 8 - Question 26
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Adsorption is a
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 26

Adsorption is entirely a bulk phenomenon while absorption is bulk phenomenon.

DSSSB PGT Chemistry Mock Test - 8 - Question 27
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Decomposition of  H2O2 was studied by titration against KMnO4 solution. It was found that 0.4 mol of H2O2 was reduced to 0.2 mol in 20 min and to 0.1 mol in 40 min and to 0.05 mol after 1 hr, the order of reaction must be
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 27

For 1st order reaction, 
Co  (t1/2)→Co/2  (t1/2)→Co/4  (t1/2)→…….Co/2n
Here, t1/2 = 20
So after 1st half life, concentration should be 0.4/2 = 0.2 
After 2nd half life, concentration should be 0.4/4 = 0.1
This is correct with given data. So the order is 1st order. 

DSSSB PGT Chemistry Mock Test - 8 - Question 28
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In the equation Kt = log C0 – log Ct, the curve between t and log Ct is -  

[AIEEE-2002]
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 28

The correct answer is option A
Compare straight line equation
(y = mx + c) with Kt = -log (Ct) + log(C0)
where,
K being constant,
"t" is equivalent to "y" in straight line equation
(-1) is slope for equation which is "m" in straight line equation
log (Ct) is x-component
& log (C0) is y-intercept.
 

DSSSB PGT Chemistry Mock Test - 8 - Question 29
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Select the correct statement if -

E°Mg2+/Mg = - 2.4V,      E°Sn4+/Sn2+ = 0.1 V,     E°MnO4-,H+/Mn2+ = 1.5 V, E° I2/I- = 0.5 V    Here,
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 29

[Hint: Reverse of (B) & (C) is spontaneous; weakest Oxidizing Agent here is Mg2+]

DSSSB PGT Chemistry Mock Test - 8 - Question 30
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 What is the value of pKb (CH3COOH-) if λm∞ = 390 & λm = 7.8 for 0.04 of a CH3COOH at 25°C          
Detailed Solution for DSSSB PGT Chemistry Mock Test - 8 - Question 30

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