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Test: Molecular Orbital Theory (May 26) - JEE MCQ


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10 Questions MCQ Test - Test: Molecular Orbital Theory (May 26)

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Test: Molecular Orbital Theory (May 26) - Question 1

In which of the following pairs of molecules/ions both the species are not likely to exist?

Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 1

Species with (zero) bond order will not exist.
Electrons in orbital

 

Test: Molecular Orbital Theory (May 26) - Question 2

Assuming (2s-2p) mixing is not operative, the paramagnetic species among the following is

[JEE Advanced 2014]

Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 2

If (2s-2p) mixing is not operative, then

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Test: Molecular Orbital Theory (May 26) - Question 3

According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order?

Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 3

Test: Molecular Orbital Theory (May 26) - Question 4


Probability (electron charge density) of bonding and anti-bonding molecular orbitals are given.

Select the correct probability,

Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 4

Electron-charge density in a bonding molecular orbital is high in the internuclear region as shown in II.
In an anti-bonding molecular orbital, it is high in parts of the molecule away from the internuclear region.

Test: Molecular Orbital Theory (May 26) - Question 5

The bond energy of H2 is 436 kJ mol -1. Thus, bond energy of   is

Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 5

Test: Molecular Orbital Theory (May 26) - Question 6

Direction (Q. Nos. 15) This sectionis based on statement I and Statement II. Select the correct answer from the code given below.

Q. 

Statement I : N2 has a greater dissociation energy than  , where as O2 has lower dissociation energy than .

Statement II : N2 has 14 electrons while O2 has 16 electrons .

Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 6


Electron from bonding molecular orbital of higher stability is lost (requires higher energy).

Electron from antibonding molecular orbital of lower stability is lost (requires lower energy).
N2 has 14 electrons and O2 has 16 electrons.
Thus, both Statements I and II are correct but Statement II is not the correct explanation of Statement I

*Multiple options can be correct
Test: Molecular Orbital Theory (May 26) - Question 7

In which of the following processes, does the value of magnetic moment change ?

Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 7

(a) CO (14e), no unpaired electron, magnetic moment = 0
CO+ (13e), One electron is lost from bonding melecular orbital unpaired electron = 1, magnetic moment =
(b)  (15e) Unpaired electron = 1, magnetic moment =
(13e) Unpaired electron = 1, magnetic moment =
(c) Zn, Zn2+, unpaired electron = 0
(d) O2 (16e), unpaired electron = 2, magnetic moment =
, unpaired electron = 1, magnetic moment =

Test: Molecular Orbital Theory (May 26) - Question 8

Valence shell MO electronic configuration of a diatomic species is shown

* is for anti-bonding molecular orbital (MO).

 

Q. Divalent cation of this species

Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 8

Total number of electrons = 16

Number of bonding electrons = 10, Number of anti-bonding electrons = 6,

*Answer can only contain numeric values
Test: Molecular Orbital Theory (May 26) - Question 9

Direction (Q. Nos. 22 and 23) This section contains 3 questions. when worked out will result in an integer from 0 to 9 (both inclusive).

Q. Total number of electrons in anti-bonding MO in (superoxide ion) is .......


Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 9

 (17 electrons) has molecular orbital electronic configuration 

Underlined are anti-bonding molecular orbital Thus, seven electrons are in anti-bonding molecular orbitals.

*Answer can only contain numeric values
Test: Molecular Orbital Theory (May 26) - Question 10

How many bonding MO are used in the formation of NO?


Detailed Solution for Test: Molecular Orbital Theory (May 26) - Question 10

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