Percentage- 2 - Free MCQ Practice Test with solutions, CLAT Quant Techniques

Given:

This is a percentage problem, where we need to calculate 
Step 1: Convert the mixed fraction to an improper fraction

Step 2: Convert the percentage to a decimal

To convert a percentage to a decimal, divide by 100:

Step 3: Multiply by 1600

Now, calculate:

0.875 × 1600 = 1400

None of the given options match the correct answer of 1400.

Therefore, the correct option is: D: None

Given:

This is a percentage problem where we need to calculate 
Step 1: Convert the mixed fraction to an improper fraction

Step 2: Convert the percentage to a decimal

To convert a percentage to a decimal, divide by 100:

Step 3: Multiply by 8008
Now, calculate:
0.875 × 8008 = 7007
The correct option is C: 7007.

Given:

We need to calculate 
Step 1: Convert the mixed fraction to an improper fraction

Step 2: Convert the percentage to a decimal

To convert a percentage to a decimal, divide by 100:

Step 3: Multiply by 3300

Now, calculate:

The correct option is B: 1100.

Given:
75% of 400 = ?
Step 1: Convert the percentage to a decimal

Step 2: Multiply by 400
0.75 × 400 = 300
The correct option is A: 300.

The correct option is C.
Pass marks is 650 + 50 = 700
which is 35 % of the total marks
let x be the max marks
then 35% of x = 700
x = 2000

Given:

Passing % = 35%

⇒ He gets 650 and fails by 50 marks. 

Calculation:

⇒ 35% = 650 + 50

⇒ 35% = 700

⇒ 100% = 2000 marks

So, the maximum marks of the examination are 2000 marks.

Hence, the correct answer is "2000 marks".

Given:

1. A student who gets 36% of the total marks fails by 32 marks.
2. Another student who gets 45% of the total marks passes by 40 marks.

We need to find the maximum marks (total marks).

Step 1: Let the total marks be x.

• The passing marks will be some percentage of the total marks.

Step 2: Express the conditions mathematically:

1. The first student gets 36% of total marks and fails by 32 marks:
   
2. The second student gets 45% of total marks and passes by 40 marks:
   

Step 3: Set both equations equal to each other (since both represent the passing marks):

Step 4: Solve the equation:

1. First, get rid of the fractions by multiplying the entire equation by 100:
   36x + 3200 = 45x - 4000
2. Bring all terms involving x on one side and constants on the other:
   45x - 36x = 3200 + 4000
3. Solve for x:
   x = 7200/9 = 800

The total (maximum) marks are 800.

Given:

1. A candidate secures 40% of the votes.
2. The candidate is defeated by a majority of 2020 votes.

We need to find the total number of votes polled.
Step 1: Let the total number of votes be x.

• The first candidate received 40% of the total votes, which is:
  

• The second candidate received the remaining 60% of the total votes, which is:
  

Step 2: The majority by which the second candidate won is the difference between the votes received by the two candidates:
Majority = Votes of second candidate − Votes of first candidate
2020 = 0.6x − 0.4x
2020 = 0.2x
Step 3: Solve for x:
x = 2020/0.2 ​= 10100
The total number of votes polled is 10100.
The correct option is C: 10100.

The correct option is C.
Vote secured by defeated candidate = 40%
vote secured by winner candidate= 100 - 40 = 60%
Difference of vote% = 60 - 40 = 20%
So, 20% = 300. 100% = 300 × 100/20 = 1500

Given:

• Winner's vote percentage = 65%
• Losing candidate's vote percentage = 35%
• Losing candidate lost by = 750 votes.

Calculation:

We will compare the difference between both candidates' vote percentages and their actual vote count difference.

1. Difference between the vote percentages:
   (65% − 35%) = 30%
   Now, the difference in votes (750 votes) corresponds to this 30%:
2. Total votes × 30% = 750
   This can be written as:
   
   Simplifying:
   
3. Solve for total votes:
   

The total number of votes polled is 2500.
Hence, the correct answer is Option B: 2500.

Given:

• Rajesh is 40% older than Neeraj.

We need to find out how much percentage younger Neeraj is compared to Rajesh.

Step 1: Let Neeraj's age be N.

• Since Rajesh is 40% older, Rajesh's age will be:
  Rajesh’s age = N + 40% of N = N + 0.4N = 1.4N

Step 2: Find the percentage by which Neeraj is younger than Rajesh.

• The difference in age between Rajesh and Neeraj is:
  Difference in age = 1.4N − N = 0.4N
• Now, to find how much younger Neeraj is as a percentage of Rajesh's age, we use the formula:
  

Substituting the values:

Neeraj is 28.57% younger than Rajesh, which matches the fraction 
Thus, the correct answer is Option A: 

The correct option is D.
P{(1 + R/100)ⁿ}
= 37500 {(1 + 4/100)²}
= 37500 {(1+1/25)²}
= 37500 {(26/25)²}
= 37500 {(676/625)}
= 676 * 60
= 40560

Present population is 50,000. It has been increasing by 4%.
So, after 1 year, population 
After 2 years, population

Given:

• The price of milk has increased by 75%.
• We need to find by what percentage a householder must reduce his consumption so that his expenditure does not increase.

Step 1: Understanding the situation.

If the price of milk has risen by 75%, the price is now 1.75 times what it was before. To keep the expenditure the same, the householder must reduce his consumption in such a way that the total expenditure remains constant.

Step 2: Formula to calculate the percentage reduction in consumption:

The formula to calculate the percentage reduction required is:

In this case, the increase in price is 75%, or 0.75.

Step 3: Substituting the values into the formula:

Percentage reduction = 0.4286 × 100 = 42.86%

Step 4: Simplifying:

The reduction in consumption should be approximately
The householder must reduce his consumption by
Therefore, the correct answer is Option C.

The correct option is C as
Let original price of a unit be Rs. 100
Increased price = Rs. 160
Reduction on Rs. 160 = Rs. 60
Reduction on Rs. 100 = 60/160 * 100 = 37.5 %

Given:

• Petrol prices are reduced by 20%.
• We need to find by how much percentage a vehicle owner must increase his consumption so that his expenditure does not decrease.

Step 1: Understanding the situation.

If the price of petrol has decreased by 20%, it is now 80% of what it was before. To keep the expenditure the same, the vehicle owner must increase his consumption so that the total expenditure remains constant.

Step 2: Formula to calculate the percentage increase in consumption:

The formula to calculate the percentage increase required is:

In this case, the reduction in price is 20%, or 0.20.

Step 3: Substituting the values into the formula:

The vehicle owner must increase his consumption by 25% to maintain the same expenditure on petrol.

Given:

• A reduction of 20% in the price of rice enables a man to buy 10 kg more rice for Rs. 1600.
• We need to find the reduced price of rice per kg.

Step 1: Let the original price of rice per kg be p Rs.
After a reduction of 20%, the new price per kg of rice becomes:

Step 2: Set up the equation.

• The man spends Rs. 1600 to buy rice, and the reduction in price enables him to buy 10 kg more rice.
• At the original price p, the quantity of rice he could buy with Rs. 1600 is:
  1600/p
• At the reduced price 0.8p, the quantity of rice he can buy with Rs. 1600 is:
  
• According to the problem, the difference in the quantity of rice purchased is 10 kg:
  

Step 3: Solve the equation.

1. Factor out 1600/p:
   
2. Simplify 1/0.8​:
   
   Now the equation becomes:
   
3. Solve for p:
   

Step 4: Find the reduced price.

• The original price of rice per kg is Rs. 40.
• The reduced price per kg is:
  0.8 × 40 = 32 Rs.

The reduced price of rice per kg is Rs. 32.

Reduction in Rupees = 320 x 20/100

= 64

With this Rs. 64 Sumeer can buy 16 Apples

Reduced price of 16 Apples = Rs. 64

Reduced price of 1 Apple = 64/16 = 4

Reduced price of 10 Apples = 4 x 10

= Rs 40

Given:

A reduction of 20% in the price of rice enables a person to purchase 10 kg more in Rs. 600.

Calculation:

Let the price per kg was Rs. 100x and after 20% reduction new price becomes Rs. 80x

According to question,

New quantity rice – old quantity rice = 10 kg

⇒ 600/80x – 600/100x = 10

⇒ 120/80x = 10

⇒ x = 3/20

Original price = 100x = Rs. (100 × 3/20) = Rs. 15 per kg

New price = 80x = Rs. (80 × 3/20) = Rs. 12 per kg

∴ Original price and the new price are Rs. 15/kg and Rs. 12/kg respectively.