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MET Mock Test - 4 - JEE MCQ


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30 Questions MCQ Test - MET Mock Test - 4

MET Mock Test - 4 for JEE 2024 is part of JEE preparation. The MET Mock Test - 4 questions and answers have been prepared according to the JEE exam syllabus.The MET Mock Test - 4 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MET Mock Test - 4 below.
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MET Mock Test - 4 - Question 1

A particle falls from a height 'h' on a fixed horizontal plane and rebounds. If 'e' is the coefficient of restitution, the total distance travelled by the particle before it stops is

Detailed Solution for MET Mock Test - 4 - Question 1

Total distance travelled si

Hence the correct choice is (a)

MET Mock Test - 4 - Question 2

A disc of radius r is connected to a string of length L. The string is tied to a point on the circumference of the disc. This system is made to oscillate in vertical plane of the disc with a small angular amplitude θ0. Find the speed of the lowest point of the disc at the moment the string become vertical.

Detailed Solution for MET Mock Test - 4 - Question 2

This is a compound pendulum with angular frequency is: 

Angular displacement can be expressed as a function of time θ = θ0 sin (ωt)
∴ dθ/dt = θ0 cos (ωt)
When the string is vertical θ = 0 ∴ sin (ωt) = 0 and cos (ωt) = 1
∴ dθ/dt = θ0ω
∴ speed of lowest point is: 

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MET Mock Test - 4 - Question 3

A long cylindrical volume contains a uniformly distributed charge of density ρ. The radius of cylindrical volume is R. A charge particle (q) revolves around the cylinder in a circular path. The kinetic energy of the particle is:

Detailed Solution for MET Mock Test - 4 - Question 3

MET Mock Test - 4 - Question 4

If  and  are two vectors satisfying the relation  . Then the value of  will be:

Detailed Solution for MET Mock Test - 4 - Question 4


AB cosθ = AB sinθ ⇒ θ = 45°

*Answer can only contain numeric values
MET Mock Test - 4 - Question 5

A small block of mass M moves on a frictionless surface of an inclined plane, as shown in figure. The angle of the incline suddenly changes from 60° to 30° at point B. The block is initially at least at A. Assume that collisions between the block and the incline are totally inelastic. (g = 10 m/s2)

If collision between the block and the incline is completely elastic, then the vertical (upward) component of the velocity of the block at point B, immediately after it strikes the second incline, is


Detailed Solution for MET Mock Test - 4 - Question 5

In case of elastic collision, component of v1 parallel to BC will remain unchanged, while component perpendicular to BC will remain unchanged in magnitude but reverse in its direction.

Now, the vertical component of velocity of the block is given by:

Now the vertical component of velocity of the block is,

v' = vT cos 30° - v2 cos 60°

= 0

*Answer can only contain numeric values
MET Mock Test - 4 - Question 6

A wire of length 2.5 m and area of cross section 1×10–6 m2 has a mass of 15 kg hanging on it. What is the extension produced? How much is the energy stored in the standard wire if Young’s modulus of wire is 2×1011 Nm–2.


Detailed Solution for MET Mock Test - 4 - Question 6

Here,

Length of wire l = 2.5m

Area of cross-section, A = 1×10–6 m2

Hanging mass, m = 15 kg

Elongation, e = ?

Energy stored in the wire, E = ?

Young’s modulus of steel, Y = 2×1011 Nm–2.

We have,

Young’s modulus of elasticity,

e = 1.875 ×10-3 m

Again, 

Energy stored in the stretched wire,

      E = 1/2​ .F .e

Or, E = 1/2​ × mg × e 

Or, E = 1/2​ × 15×10 ×1.875 ×10-3

∴∴ E = 0.141 J

*Answer can only contain numeric values
MET Mock Test - 4 - Question 7

Two soap bubbles A and B are kept in a closed chamber where the air is maintained at pressure 8 N/m2. The radii of bubbles A and B are 2 cm and 4 cm, respectively. Surface tension of the soap-water used to make bubbles is 0.04 N/m. Find the ratio nA/nB, where nA and nB are the number of moles of air in bubbles A and B, respectively. [Neglect the effect of gravity.]

(Round off upto 2 decimal places)


Detailed Solution for MET Mock Test - 4 - Question 7

Excess pressure above atmospheric pressure, due to surface tension in a bubble = 4T/r

Surrounding pressure, P0 = 8 N/m2

MET Mock Test - 4 - Question 8

In presence of alkali, C₂H₅OH reacts with Cl₂ to give

MET Mock Test - 4 - Question 9

At room temperature formaldehyde is

MET Mock Test - 4 - Question 10

How many monochlorobutanes will be obtained on chlorination of n-butane?

Detailed Solution for MET Mock Test - 4 - Question 10

MET Mock Test - 4 - Question 11

The ratio of the molar amounts of H₂S needed to precipitate the metal ions from 20 mL each of 1M Cd(NO₃)₂ and 0.5 M CuSO₄ is

Detailed Solution for MET Mock Test - 4 - Question 11

As Cd2+ and Cu2+, both are dipositive ions but Cu2+ has one half of the concentration compared to that of the Cd2+. Thus, the molar amount of the H2S used to precipitate the metals ions Cd2+ and Cu2+ is 2 : 1.

*Answer can only contain numeric values
MET Mock Test - 4 - Question 12

At 345 K, the half life for the decomposition of a sample of a gaseous compound initially at 55.5 kPa was 340 s. When the pressure was 27.8 kPa, the half life was found to be 170 s. The order of the reaction is ________. [integer answer]


Detailed Solution for MET Mock Test - 4 - Question 12


2 = (2)1 - n
1 - n = 1
n = 0

*Answer can only contain numeric values
MET Mock Test - 4 - Question 13

The difference in oxidation state of chromium in chromate and dichromate salts is ______. (in integer)


Detailed Solution for MET Mock Test - 4 - Question 13

Chromate ion →  , oxidation state of Cr = +6
Dichromate ion → , oxidation state of Cr = +6
Difference in oxidation state = zero

*Answer can only contain numeric values
MET Mock Test - 4 - Question 14

The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg, respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x × 10-1. The value of x is _________. (Nearest integer)


Detailed Solution for MET Mock Test - 4 - Question 14

xA = 0.6
PT = xAPAo + xBPBo
= 0.6 × 90 + 0.4 × 15
= 54 + 6 = 60
xAPAo = yAPT
0.6 × 90 = yA(60)
yA = 0.9
yB = 0.1 = 1 × 10-1
∴ x = 1

MET Mock Test - 4 - Question 15

If the slope of the normal to the curve x3 = 8a2y, a > 0, at a point in the first quadrant is - 2/3, then the point is

MET Mock Test - 4 - Question 16

Area bounded by parabola y2 = x and st.line 2 y = x is

MET Mock Test - 4 - Question 17

If | z1 − 1 | < 1 , | z2 − 2 | < 2 , | z3 − 3 | < 3 then | z1 + z2 + z3 |

MET Mock Test - 4 - Question 18

The order of the differential equation y(dy/dx)=x/(dy/dx)+(dy/dx)3 is

MET Mock Test - 4 - Question 19

The solution of the equation xdy-ydx=0 is

MET Mock Test - 4 - Question 20

The order of differential equation (d2y/dx2)= (1+dy/dx)1/2 is

*Answer can only contain numeric values
MET Mock Test - 4 - Question 21

The number of solutions of the equation log(x + 1) (2x2 + 7x + 5) + log(2x + 5) (x + 1)2 - 4 = 0, x > 0, is ________.


Detailed Solution for MET Mock Test - 4 - Question 21

log(x + 1) (2x2 + 7x + 5) + log(2x + 5) (x + 1)2 - 4 = 0
log(x + 1) (2x + 5) (x + 1) + 2log(2x + 5) (x + 1) = 4
log(x + 1) (2x + 5) + 1 + 2 log(2x + 5) (x + 1) = 4
Put log(x + 1) (2x + 5) = t

t = 1, 2
log(x + 1) (2x + 5) = 1 and log(x + 1) (2x + 5) = 2
x + 1 = 2x + 3 and 2x + 5 = (x + 1)2
x = -4 (rejected) x2 = 4 ⇒ x = 2, -2 (rejected)
So, x = 2
No. of solutions = 1

*Answer can only contain numeric values
MET Mock Test - 4 - Question 22

Let A =  and B =   Then the number of elements in the set {(n, m) : n, m ∈ {1, 2 ..., 10} and nAn + mBm = l} is ___________.


Detailed Solution for MET Mock Test - 4 - Question 22


⇒ AK = A, K ∈ l
nAn + mBm = nA + mB

So, 2n - m = 1,
-n + m = 0,
2m - n = 1
Hence, (m, n) = (1, 1)

*Answer can only contain numeric values
MET Mock Test - 4 - Question 23

Let f(θ) = . Then the value of  is _______. (in integer)


Detailed Solution for MET Mock Test - 4 - Question 23


Clearly, f(θ) = asinsθ + bcosθ
Where a = 1 + dt
⇒ a = 1 + 2b ... (1)
and b = (at sint + bt cos t) dt  
⇒ b = 2a ... (2)
From (1) and (2), we get

So, f(θ) = 

*Answer can only contain numeric values
MET Mock Test - 4 - Question 24

If  and , then tan is equal to ________.


Detailed Solution for MET Mock Test - 4 - Question 24


Now,


MET Mock Test - 4 - Question 25

Find the synonym of RUPTURE

MET Mock Test - 4 - Question 26

Improve the sentence by choosing best alternative for capitalised part of the sentence.

Despite his old age, his movements were as spirited as A YOUNG MAN

MET Mock Test - 4 - Question 27

Find the antonym of CORPULENT

MET Mock Test - 4 - Question 28

Find the Synonym of LANGUISHING

MET Mock Test - 4 - Question 29

Choose the alternative which best expresses the meaning of the idiom/phrase.

To be under a cloud

MET Mock Test - 4 - Question 30

Improve the sentence by choosing best alternative for capitalised part of the sentence.

He has very good command ON English.

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