JEE Exam  >  JEE Tests  >  MHT CET Mock Test - 1 - JEE MCQ

MHT CET Mock Test - 1 - JEE MCQ


Test Description

30 Questions MCQ Test - MHT CET Mock Test - 1

MHT CET Mock Test - 1 for JEE 2024 is part of JEE preparation. The MHT CET Mock Test - 1 questions and answers have been prepared according to the JEE exam syllabus.The MHT CET Mock Test - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MHT CET Mock Test - 1 below.
Solutions of MHT CET Mock Test - 1 questions in English are available as part of our course for JEE & MHT CET Mock Test - 1 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt MHT CET Mock Test - 1 | 150 questions in 180 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
MHT CET Mock Test - 1 - Question 1

Basic materials used in the present solid state electronic devices like diode, transistor, ICs, etc are

Detailed Solution for MHT CET Mock Test - 1 - Question 1

Explanation:Semiconductors are materials that have electrical conductivity between conductors such as most metals and nonconductors or insulators like ceramics. Semiconductor material is used in the manufacturing of electrical components and used in electronic devices such as transistors and diodes.Semiconductors are the basic materials used in the present solid state electronic devices like diode, transistor, ICs etc

MHT CET Mock Test - 1 - Question 2

Different planets have different escape velocities because:

Detailed Solution for MHT CET Mock Test - 1 - Question 2

The formula for calculating the escape velocity from the surface of a celestial body (e.g. a planet) is:

where G is the universal gravitation constant, M is the planet’s mass and R is its radius. Different planets have different mass and radius - and therefore different escape velocity.

1 Crore+ students have signed up on EduRev. Have you? Download the App
MHT CET Mock Test - 1 - Question 3

Referring to the Young’s double slit experiment, Phase difference corresponding to a Path Difference of λ /3 is

Detailed Solution for MHT CET Mock Test - 1 - Question 3

We know that,
Phase difference=K× path difference. K=2π/ λ.
Therefore, phase difference=(2π/ λ) ×( λ/3)=2π/3=120 degree.

MHT CET Mock Test - 1 - Question 4

The electrostatic field due to a point charge depends on the distance r as 1/r2 . Indicate which of the following quantities shows same dependence on r.

 

Detailed Solution for MHT CET Mock Test - 1 - Question 4

MHT CET Mock Test - 1 - Question 5

Damping in galvanometers is based oUpdate Questionn

Detailed Solution for MHT CET Mock Test - 1 - Question 5

Explanation : The coil of galvanometer is wound on a light metal frame. When the coil and frame rotate in the field of the permanent magnet, the eddy current set up in the frame oppose the motion so that the coil returns to zero quickly.

MHT CET Mock Test - 1 - Question 6

An object is placed at a distance u from a concave mirror and its real image is received on a screen placed at a distance of v from the mirror. If f is the focal length of the mirror, then the graph between 1/v versus 1/u is

Detailed Solution for MHT CET Mock Test - 1 - Question 6

For real object and real Image,
(1/v)+(1/u)=(1/f)=> -(1/v)-(1/u)=-(1/f)
(1/v)+(1/u)=(1/f) => 1/v=-(1/u)+(1/f)
y=mx+c
The correct answer is option B.

MHT CET Mock Test - 1 - Question 7

Shown in figure is a Post Office box. In order to calculate the value of external resistance, it should be connected between

Detailed Solution for MHT CET Mock Test - 1 - Question 7

Total external resistance will be the total resistance of whole length of box. It should be connected between A and D.

MHT CET Mock Test - 1 - Question 8

A coil carrying electric current is placed inuniform magnetic field, then         [1993]

Detailed Solution for MHT CET Mock Test - 1 - Question 8

A current carrying coil has magnetic dipole moment. Hence, a torque  acts on it in magnetic field.

MHT CET Mock Test - 1 - Question 9

Carbon disulfide (n = 1.63) is poured into a container made of crown glass (n = 1.52). What is the critical angle for internal reflection of a ray in the liquid when it is incident on the liquid-to-glass surface?​

Detailed Solution for MHT CET Mock Test - 1 - Question 9

Refractive index of glass with respect to liquid:
n = 1.52/1.63 = 0.9325
thus, critical angle, i = sin-1(n) = 68.8 degrees

MHT CET Mock Test - 1 - Question 10

The unit of G/g is 

Detailed Solution for MHT CET Mock Test - 1 - Question 10

We know that Gravitational force = 

and,


The SI unit of the universal gravitational constant is N m2/kg2
The SI unit of the acceleration due to gravity is the same as that of acceleration.
Hence, the SI unit of the acceleration due to gravity is m/s2.
So, the SI unit of 

MHT CET Mock Test - 1 - Question 11

The heat of sun comes to us through:

Detailed Solution for MHT CET Mock Test - 1 - Question 11

The sun heats the earth through radiation. Since there is no medium (like the gas in our atmosphere) in space, radiation is the primary way that heat travels in space. When the heat reaches the earth it warms the molecules of the atmosphere, and they warm other molecules and so on.

MHT CET Mock Test - 1 - Question 12

Express which of the following set ups can be used to verify Ohm’s law?

 

Detailed Solution for MHT CET Mock Test - 1 - Question 12

In ohm's law, we check V = IR where I is the current flowing through a resistor and V is the potential difference across that resistor. Only option (a) fits the above criteria.
NOTE : Remember that ammeter is connected in series with resistance and voltmeter parallel with the net resistance.

MHT CET Mock Test - 1 - Question 13

Resolving power of a telescope depends on

Detailed Solution for MHT CET Mock Test - 1 - Question 13

The resolving power of a telescope is given by RP∝2μsinθ​/122λ
Further, sinθ ∝ tanθ ∝ diameter of the objective.
So, the resolving power of a telescope depends on the diameter of the objective lens.

MHT CET Mock Test - 1 - Question 14

Three identical blocks of masses m = 2 kg are drawn by a force F = 10.2N with an acceleration of 0.6 ms-2 on a frictionless surface, then what is the tension (in N) in the string between that blocks B and C ? 

[AIEEE 2002]

                      

Detailed Solution for MHT CET Mock Test - 1 - Question 14

Let the tension between B and C be T

M=2kg

F−T=ma

10.2−T=ma

10.2−T=2×0.6

10.2−T=1.2

10.2−1.2=T

T=9N

MHT CET Mock Test - 1 - Question 15

The molar mass of Al2O3 is

Detailed Solution for MHT CET Mock Test - 1 - Question 15

Molar mass = 2(27) +3 (16) = 102g.

MHT CET Mock Test - 1 - Question 16

An element has configuration 4d55s2. The element belongs to

Detailed Solution for MHT CET Mock Test - 1 - Question 16

Ford-block elements, group number is equal to the number of electrons in (n - 1)d subshell + number of electrons in valence shell (nth shell).

MHT CET Mock Test - 1 - Question 17

The reaction of an element A with water produces combustible gas B and an aqueous solution of C. When another substance D reacts with this solution C also produces the same gas B.D also produces the same gas even on reaction with dilute H2SO4 at room temperature. Element A imparts golden yellow colour to Bunsen flame. Then A,B,C and D may be identified as

Detailed Solution for MHT CET Mock Test - 1 - Question 17


Zn + NaOH → Na2ZnO2 + H2
Amphoteric
Nz + dil H2SO4 → ZnSO4 + H2

MHT CET Mock Test - 1 - Question 18

The orbital angular momentum for a d-orbital electron is given by

Detailed Solution for MHT CET Mock Test - 1 - Question 18


MHT CET Mock Test - 1 - Question 19

 Gibbs free energy change for a cell reaction is positive what does it indicates?

Detailed Solution for MHT CET Mock Test - 1 - Question 19

The correct answer is Option C.

Reactions with a negative ∆G release energy, which means that they can proceed without an energy input (are spontaneous). In contrast, reactions with a positive ∆G need an input of energy in order to take place (are non-spontaneous). Reactions with a positive ∆H and negative ∆S are non-spontaneous at all temperatures.

MHT CET Mock Test - 1 - Question 20

Yellow colour of NaCl crystals in sodium vapour is due to

Detailed Solution for MHT CET Mock Test - 1 - Question 20
  • This yellow colour is due to metal excess defect of anionic valency.
  • Na+ion deposited on the surface of crystal of NaCl . The Cl-ion diffused to form NaCl. This happens by loss of electron from Na to Na+.
  • The released electro diffused into the crystal and occupy anionic site called F center which imparts yellow colour to NaCl.
MHT CET Mock Test - 1 - Question 21

Penicillin is

Detailed Solution for MHT CET Mock Test - 1 - Question 21

Penicilli is bactericidal. They kill susceptible bacterial by inhibiting the synthesis of the bacterial peptidoglycan cell wall

MHT CET Mock Test - 1 - Question 22

(Yellow ppt) T  X  Y. (Yellow ppt) + Z­ (pungent smellinggas)

If X gives green flame test. Then, X is :

Detailed Solution for MHT CET Mock Test - 1 - Question 22

Green flame is given by Ba2+

BaS2O3+K2CrO4 → BaCrO4+K2S2O3   yellow ppt

MHT CET Mock Test - 1 - Question 23

Glucose solution is one molal. Glucose present in 1 kg glucose solution is

Detailed Solution for MHT CET Mock Test - 1 - Question 23

Glucose solution is one molal. Thus, 1000 g water (solvent) has glucose = one mole = 180 g

Total mass of solution = 1000 +180 = 1180 g

1180 g of solution has glucose = 180 g 

∴ 1000 g of solution has glucose =
180 x 1000/1180 = 152.5 ≈ 153g  

MHT CET Mock Test - 1 - Question 24

Give IUPAC names of the following compound:

Detailed Solution for MHT CET Mock Test - 1 - Question 24

This is 1-phenyl propan-1-one.

MHT CET Mock Test - 1 - Question 25

Lewis structure of HCI, H2O and NH3 are

Detailed Solution for MHT CET Mock Test - 1 - Question 25

MHT CET Mock Test - 1 - Question 26

A biochemical catalyst is:

Detailed Solution for MHT CET Mock Test - 1 - Question 26

Enzymes are biological catalyst, they catalize different chemical reactions in body.

MHT CET Mock Test - 1 - Question 27

The area bounded by the curve y = 2x - x2 and the line x + y = 0 is

Detailed Solution for MHT CET Mock Test - 1 - Question 27

The equation y = 2x − x2 i.e. y – 1 = - (x - 1)2 represents a downward parabola with vertex at (1, 1) which meets x – axis where y = 0 .i .e . where x = 0 , 2. Also , the line y = - x meets this parabola where – x = 2x − x2 i.e. where x = 0 , 3. 
Therefore , required area is :

MHT CET Mock Test - 1 - Question 28

The diagram given below shows that 

Detailed Solution for MHT CET Mock Test - 1 - Question 28

Because, the element b in the domain A has no image in the co-domain B.

MHT CET Mock Test - 1 - Question 29

The number of arbitrary constants in the particular solution of a differential equation of third order are:

Detailed Solution for MHT CET Mock Test - 1 - Question 29

0 , because the particular solution is free from arbitrary constants.

MHT CET Mock Test - 1 - Question 30

The binary relation S = Φ (empty set) on set A = {1, 2, 3} is

Detailed Solution for MHT CET Mock Test - 1 - Question 30

Reflexive : A relation is reflexive if every element of set is paired with itself. Here none of the element of A is paired with themselves, so S is not reflexive.
Symmetric : This property says that if there is a pair (a, b) in S, then there must be a pair (b, a) in S. Since there is no pair here in S, this is trivially true, so S is symmetric.
Transitive : This says that if there are pairs (a, b) and (b, c) in S, then there must be pair (a,c) in S. Again, this condition is trivially true, so S is transitive.

View more questions
Information about MHT CET Mock Test - 1 Page
In this test you can find the Exam questions for MHT CET Mock Test - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for MHT CET Mock Test - 1, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE