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MHT CET Mock Test - 4 - JEE MCQ


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30 Questions MCQ Test - MHT CET Mock Test - 4

MHT CET Mock Test - 4 for JEE 2024 is part of JEE preparation. The MHT CET Mock Test - 4 questions and answers have been prepared according to the JEE exam syllabus.The MHT CET Mock Test - 4 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MHT CET Mock Test - 4 below.
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MHT CET Mock Test - 4 - Question 1

A slide projector gives a magnification of 10. If a slide of dimensions 3 cm x 2 cm is projected on the screen, the area of the image on the screen is:​

Detailed Solution for MHT CET Mock Test - 4 - Question 1

Area of magnification, 
A1​A22
A1/6​​=100
A1​=600 cm2

MHT CET Mock Test - 4 - Question 2

In an N-P-N transistor, P-type crystal is

Detailed Solution for MHT CET Mock Test - 4 - Question 2

Explanation:When the p-type crystal is grown between relatively wide sections of n-type crystals then the transistor is called NPN transistor.

 

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MHT CET Mock Test - 4 - Question 3

In the given circuit, with steady current, the potential drop across the capacitor must be

Detailed Solution for MHT CET Mock Test - 4 - Question 3

There will be no current flowing in branch BE in steady condition.
Let I be the current flowing in the loop ABCDEFA.
Applying Kirchoff's law in the loop moving in anticlockwise direction starting from C. + 2V – I (2R) – I (R) – V = 0
∴V = 3IR
⇒ I = V/3R ... (1)

Applying Kirchoff's law in the circuit ABEFA we get on moving  in anticlockwise direction starting from B

+ V + Vcap – IR – V = 0 (where Vcap is the p.d. across capacitor).

MHT CET Mock Test - 4 - Question 4

In the case of metals the valence and conduction bands have

Detailed Solution for MHT CET Mock Test - 4 - Question 4

Explanation:The materials can be classified by the energy gap between their valence band and the conduction band. The valence band is the band consisting of the valence electron, and the conduction band remains empty. Conduction takes place when an electron jumps from valence band to conduction band and the gap between these two bands is forbidden energy gap. Wider the gap between the valence and conduction bands, higher the energy it requires for shifting an electron from valence band to the conduction band.In the case of conductors, this energy gap is absent or in other words conduction band, and valence band overlaps each other. Thus, electron requires minimum energy to jump from valence band. The typical examples of conductors are Silver, Copper, and Aluminium.In insulators, this gap is vast. Therefore, it requires a significant amount of energy to shift an electron from valence to conduction band. Thus, insulators are poor conductors of electricity. Mica and Ceramic are the well-known examples of insulation material.Semiconductors, on the other hand, have an energy gap which is in between that of conductors and insulators. This gap is typically more or less 1 eV, and thus, one electron requires energy more than conductors but less than insulators for shifting valence band to conduction band.

MHT CET Mock Test - 4 - Question 5

Magnifying power of a compound microscope is high if

Detailed Solution for MHT CET Mock Test - 4 - Question 5

Magnifying power of a compound- microscope is given by m=− (l​D​/f0​fe​)
where, l is length of tube
D is least distance of clear vision
f0​ is focal length of objective
fe​ is focal length of eyepiece
So, clearly, it can be seen that focal length of objective and eyepiece needs to be decreased so that magnifying power increases.
 

MHT CET Mock Test - 4 - Question 6

In electromagnetic induction, line integral of induced field E around a close path is __________, induced electric field is ___________.​

Detailed Solution for MHT CET Mock Test - 4 - Question 6

In electromagnetic induction, line integral of induced field E around a close path is non zero, and induced electric field is non conservative.

MHT CET Mock Test - 4 - Question 7

At the minimum deviation Dm, the refracted ray inside the prism

Detailed Solution for MHT CET Mock Test - 4 - Question 7

When the deviation is minimum, then the incidence angle and emergence angle are equal and this is possible only when the refracted ray inside the prism is parallel to the base of the prism. 
Minimum deviation is given by δ=2i−A, where A is prism angle.

MHT CET Mock Test - 4 - Question 8

Optical rotations of some compounds along with their structures are given below which of them have D configuration.

Detailed Solution for MHT CET Mock Test - 4 - Question 8

The correct answer is Option A.
 
I, II and III structures have D configuration with -OH group on the lowest asymmetric carbon is on the right side which is comparable to (+) glyceraldehyde.

MHT CET Mock Test - 4 - Question 9

Consider the following reaction,

 

Q. 

The correct statement concerning I and II is

Detailed Solution for MHT CET Mock Test - 4 - Question 9

This is an example of E1 reaction and more substituted alkene (I) is formed as the major product.

MHT CET Mock Test - 4 - Question 10

How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of Pbo and 3.2 g of HCl?

Detailed Solution for MHT CET Mock Test - 4 - Question 10

PbO + 2HCl 
6.5\223
= 2.9 x 10-2
= 2.9x10-2 - x 
nx = 9a
PbCl2 + H2O
3.2/36.5
= 8.76 x 10-2 
8.76 x 10-2 - x
x = 2.9 x 10-2

MHT CET Mock Test - 4 - Question 11

Comprehension Type

Direction (Q. Nos. 16 and 17) This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

Oxides are generally formed by the reaction of metals with oxygen at high temperatures. All the metals except scandium form MO oxides which are ionic. The highest oxidation number in the oxides, coincides with the group number and is attained in Sc2O3 to Mn2O7. Beyond 7th group, higher oxides coinciding with the group number do not form. As the oxidation number of metal increases covalent character and acidity increases. Mn2O7, CrO3 are acidic and their lower oxides are basic and amphoteric. Stability of higher oxides increases down the group.

Q. 

Which of the following reacts with both acids and bases?

Detailed Solution for MHT CET Mock Test - 4 - Question 11

ZnO and V2O5 are am photeric oxides.

MHT CET Mock Test - 4 - Question 12

The wavelengths of two photons are 2000 Å and 4000 Å respectively. What is the ratio of their energies?

Detailed Solution for MHT CET Mock Test - 4 - Question 12



= 4000/2000
= 2

MHT CET Mock Test - 4 - Question 13

Which one of the following is a water soluble vitamin?

Detailed Solution for MHT CET Mock Test - 4 - Question 13

The correct answer is Option C
Fat soluble vitamin - A, D, E, K
Water soluble vitamin - Vitamin B complex and C
So, vitamin B is water soluble.
Vitamins which can dissolve in water are called water-soluble vitamins. Water-soluble vitamins include vitamin-C and vitamin-B because they remove the toxins from our body through urine. Therefore, they are not stored in our body and should be taken on a daily basis through the food we eat.

MHT CET Mock Test - 4 - Question 14

The amino acid which are synthesized in the body are known as:

Detailed Solution for MHT CET Mock Test - 4 - Question 14

Nonessential amino acids can be synthesized in the body, whereas essential amino acids must be obtained in the diet. Cells in the body can provide the carbon skeleton of the nonessential amino acids.

MHT CET Mock Test - 4 - Question 15

Which of the following is a tertiary amine?

Detailed Solution for MHT CET Mock Test - 4 - Question 15

Diphenhydramine​ is an antihistamine mainly used to treat allergies. It can also be used for insomnia, symptoms of the common cold, tremor in parkinsonism, and nausea. It is used by mouth, injection into a vein, injection into a muscle, or applied to the skin.

MHT CET Mock Test - 4 - Question 16

Pyrolusite in MnO2 is used to prepare KMnO4. Steps are

Here, I and II are

Detailed Solution for MHT CET Mock Test - 4 - Question 16


MHT CET Mock Test - 4 - Question 17

For k = 1, 2, 3, the box Bk contains k red balls and (k + 1) white balls. Let P(B1) = 1/2, P(B2) = 1/3, P(B3) = 1/6. A box is selected at random and a ball is drawn from it. If a red ball is drawn, then probability that it has come from box B2 is

Detailed Solution for MHT CET Mock Test - 4 - Question 17

Use Baye’s Theorem formula


A : Red ball is drawn






= 14/39

MHT CET Mock Test - 4 - Question 18

The value of 

Detailed Solution for MHT CET Mock Test - 4 - Question 18

To find the determinant we have to cross mutliply the elements and then subtract it.
cos2θ - (-sin2θ) = 1

MHT CET Mock Test - 4 - Question 19

Let the vectors  be such that  is a unit vector if the angle between vectors  is 

Detailed Solution for MHT CET Mock Test - 4 - Question 19


MHT CET Mock Test - 4 - Question 20

If the straight lines x = 1 + s, y = - 3 - λs, z = 1 + λs and x = t/2, y = 1 + t, z = -t + 2 with parameters s and t respectively are coplanar, then λ equals

Detailed Solution for MHT CET Mock Test - 4 - Question 20

Given line can be rewritten as

and 

since two line are coplanar, then

λ = -2

MHT CET Mock Test - 4 - Question 21

The function f (x) = x + cos x

Detailed Solution for MHT CET Mock Test - 4 - Question 21

f(x) = x
g(x) = cosx 
D(f) = R
D(g) = R
D(f+g) = D(f) ⋂ D(g)
So , D(f+g) = R
Therefore, given function is defined for real numbers.

MHT CET Mock Test - 4 - Question 22

The number of ways in which 6 “ + “ and 4 “ – “ signs can be arranged in a line such that no two “ – “ signs occur together is

Detailed Solution for MHT CET Mock Test - 4 - Question 22

′+′ signs can be put in a row in one way creating seven gaps shown as arrows:
Now 4′−′ signs must be kept in these gaps. So, no tow ′−′ signs should be together.
Out of these 7 gaps 4 can be chosen in 7C4 ways.

MHT CET Mock Test - 4 - Question 23

The mean deviation about the mean for the following data: 6, 7, 10, 12, 13, 4, 8, 12.

Detailed Solution for MHT CET Mock Test - 4 - Question 23

MHT CET Mock Test - 4 - Question 24

If A+B+C = π, then the value of   

Detailed Solution for MHT CET Mock Test - 4 - Question 24



MHT CET Mock Test - 4 - Question 25

Detailed Solution for MHT CET Mock Test - 4 - Question 25




MHT CET Mock Test - 4 - Question 26

Let x be any real, then [x + y] = [x] + [y] holds for

Detailed Solution for MHT CET Mock Test - 4 - Question 26

Let y has some fractional part
x = 6.5
y = 0.9
[x] = 6, [y] = 0, [x]+[y] = 6
[x + y] = [7.4] = 7
[x + y] ≠ [x]+[y]
Let x, y be integers
x = 6.5
y = 1
[x] = 6, [y] = 1, [x]+[y] = 7
[x + y] = [7.5] = 7
[x + y] = [x]+[y]
So, [x + y] = [x]+[y] holds for y ϵ I

MHT CET Mock Test - 4 - Question 27

The unit vector in the direction of a given vector  

Detailed Solution for MHT CET Mock Test - 4 - Question 27

 is called the unit vector of a given vector 

MHT CET Mock Test - 4 - Question 28

The value of x, if  = 0 , is​

Detailed Solution for MHT CET Mock Test - 4 - Question 28

MHT CET Mock Test - 4 - Question 29

Detailed Solution for MHT CET Mock Test - 4 - Question 29

MHT CET Mock Test - 4 - Question 30

Tangents to the curve y = x3 at the points (1, 1) and (– 1, – 1) are

Detailed Solution for MHT CET Mock Test - 4 - Question 30

therefore , slopes of the tangents at (1,1) and (- 1 , -1)are equal. Hence, the two tangents in reference are parallel.

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