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30 Questions MCQ Test - COMEDK Mock Test - 1

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COMEDK Mock Test - 1 - Question 1

When the current in the portion of the circuit, shown in the figure, is 2 A and is increasing at the rate of 1 A/s, then the measured potential difference Vab is 8 V. However, when the current is 2 A and is decreasing at the rate of 1 A/s, the measured potential difference Vab is 4V. The values of R and L are

Detailed Solution for COMEDK Mock Test - 1 - Question 1

For the first case, when the current is increasing di/dt = 1A / s

8 = 2R + L …..(1)

For the first case, when the current is increasing di/dt = -1A / s

4 = 2R - L …..(2)

From 1 and 2, R = 3Ω, L = 2H

COMEDK Mock Test - 1 - Question 2

Two beams of red and violet colors are made to pass separately through a prism (angle of the prism is 60°). In the position of minimum deviation, the angle of refraction will be:

Detailed Solution for COMEDK Mock Test - 1 - Question 2

Two beams of red and violet colors are made to pass separately through a prism (angle of the prism is 60°).
We have to find the angle of refraction at the position of minimum deviation.
In the position of minimum deviation, light passes symmetrically through the prism irrespective of the light wavelength used.

In the position of minimum deviation, r + r = 2r = A[ as deviation δ = 0]
  for both the colour.

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COMEDK Mock Test - 1 - Question 3

A parallel plate air-filled capacitor has a capacitance of 2 μF . When it is half-filled with a dielectric of dielectric constant k = 3, its capacitance becomes

Detailed Solution for COMEDK Mock Test - 1 - Question 3

COMEDK Mock Test - 1 - Question 4

To raise the temperature of a certain mass of gas by 50°C at a constant pressure, 160 calories of heat is required. When the same mass of gas is cooled by 100°C at constant volume, 240 calories of heat is released. How many degrees of freedom does each molecule of this gas have (assume gas to be ideal)?

Detailed Solution for COMEDK Mock Test - 1 - Question 4

COMEDK Mock Test - 1 - Question 5

The magnetic field associated with a light wave is given, at the origin, by B = B0 [sin(3.14 × 107)ct + sin(6.28 × 107)ct]. If this light falls on a silver plate having a work function of 4.7 eV, what will be the maximum kinetic energy of the photo electrons ?
(c = 3 × 10ms-1, h = 6.6 × 10-34 J-s)

Detailed Solution for COMEDK Mock Test - 1 - Question 5

B = B0sin(π × 107C)t + B0sin (2π × 107C)t
Since there are two EM waves with different frequency, to get maximum kinetic energy, we take the photon with higher frequency.
B1 = B0sin(π × 107C)t  v1 = 107/2 x c 
B2 = B0sin(2π × 107C)t v2 = 107C
where C is speed of light C = 3 × 108 m/s
v2 > v1
so KE of photoelectron will be maximum for photon of higher energy.
v= 107C Hz
hv = φ + KEmax
energy of photon
Eph = hv = 6.6 × 10-34 × 107 × 3 × 109
Eph = 6.6 × 3 × 10-19J

KEmax = Eph - φ
= 12.375 - 4.7 = 7.675 eV  7.72 eV

COMEDK Mock Test - 1 - Question 6

Value of gas constant, R for one mole of a gas is independent of the

Detailed Solution for COMEDK Mock Test - 1 - Question 6

We know that PV=nRT also PM=dRT
So in the equation The value of R depends on P , V , n , T , d , M
except atomicity 
 so the ans is A

COMEDK Mock Test - 1 - Question 7

A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of magnetic field will be equal to

Detailed Solution for COMEDK Mock Test - 1 - Question 7

B = μ0ni
Now i → 2i
And n  → n/2

COMEDK Mock Test - 1 - Question 8

When a conductor is placed in an electric field; its free charge carriers adjust itself in order to oppose the electric field. This happen until

Detailed Solution for COMEDK Mock Test - 1 - Question 8
  • When an external electric field is applied to the conductor, the free electrons in the conductor move in an opposite direction to that of the applied electric field.
  • This movement of electrons induces another electric field inside the conductor which opposes the original external electric field.
  • This continues until the induced electric field cancels out the external field. 
COMEDK Mock Test - 1 - Question 9

The above graph for Freundlich adsorption isotherm will be true when:

Detailed Solution for COMEDK Mock Test - 1 - Question 9

Freundlich gave an empirical relationship between quantity of gas adsorbed by unit mass of solid adsorbent and pressure at a particular temperature.

(x is mass of gas adsorbed on a mass mm of the adsorbent at a pressure p, k and n are constant, which depends on nature of adsorbent and gas at a particular temperature)
From above equation of Freundlich adsorption isotherm

Taking log both sides 

Now if 1/n = 0, so the above equation will be independent of p and, we will get a straight line parallel to x-axis as required. 

COMEDK Mock Test - 1 - Question 10

The following equilibria are given:
a. N2 + 3H2  2NH3; K1
b. N2 + O2  2NO; K2
c. H2 + O H2O; K3
The equilibrium constant for the reaction,
2NHO2  2NO + 3H2O in terms of K1, K2 and K3 will be

Detailed Solution for COMEDK Mock Test - 1 - Question 10

From the given equations, we have
K1 = 
K2 = 
K3 = 
For the given reaction,
K = 

K = 

COMEDK Mock Test - 1 - Question 11

In the Newman projection for 2, 2-dimethylbutane, X and Y, respectively, will be

A. H and H
B. H and C2H5
C. C2H5 and H
D. CH3 and CH3

Detailed Solution for COMEDK Mock Test - 1 - Question 11


The Newman projection formula using C2 and C3 is:

Hence, option (d) is correct.

COMEDK Mock Test - 1 - Question 12

Considering H2O as a weak field ligand, the number of unpaired electrons in [Mn(H2O)6]2+ will be
(Atomic number of Mn = 25)

Detailed Solution for COMEDK Mock Test - 1 - Question 12

Mn in [Mn(H2O)6]2+ is present as Mn2+(3d5).

sp3d2 hybridisation occurs in [Mn(H2O)6]2+
Due to the presence of a weak field ligand, pairing of electrons do not take place. Hence, the number of unpaired electrons is five.

COMEDK Mock Test - 1 - Question 13

Metallic lustre is explained by

Detailed Solution for COMEDK Mock Test - 1 - Question 13

Metallic lustre is the property of metals which describes the amount of light that reflects by metals.

The reflection of light happens due to oscillation of free electron. Because loosely held electrons oscillate in all directions so, when light hits the metals, it gets reflected.

COMEDK Mock Test - 1 - Question 14

Any redox reaction would occur spontaneously, if –

Detailed Solution for COMEDK Mock Test - 1 - Question 14

Any redox reaction would occur spontaneously, if the cell emf is positive.

COMEDK Mock Test - 1 - Question 15

Which of the following relations is correct?

Detailed Solution for COMEDK Mock Test - 1 - Question 15

The Gibbs free energy change at a constant temperature and pressure is given as:

where, ΔH is the change in the enthalpy of the process and ΔS is the change in the entropy of the process.

For the process to be spontaneous, ΔG must be negative.

COMEDK Mock Test - 1 - Question 16

There is no S - S bond in

Detailed Solution for COMEDK Mock Test - 1 - Question 16

In the lewis structure of disulfate  ion, sulfur atoms are located as center atoms and oxygen atoms are located around sulfur atoms. There are two double bonds around a sulfur atom in the lewis structure. Oxidation number of sulfur is six in  ion.

has no s−s linkage :

COMEDK Mock Test - 1 - Question 17

Acid hydrolysis of which of the following compounds yields two different organic compounds?

Detailed Solution for COMEDK Mock Test - 1 - Question 17

Acid hydrolysis of an ester gives two different organic compounds.

COMEDK Mock Test - 1 - Question 18

Which of the following is aromatic?

Detailed Solution for COMEDK Mock Test - 1 - Question 18

According to Huckle, an aromatic compound must be cyclic planar having (4n + 2)π electrons.

COMEDK Mock Test - 1 - Question 19

One mole of an ideal gas for which Cv = 3/2 R is heated reversibly at a constant pressure of 1 atm from 25°C to 100°C. Here, H (the value in Calories to be provided correct upto two decimal places) is

Detailed Solution for COMEDK Mock Test - 1 - Question 19

At constant pressure, heat given by one mole gas (qp) = nCpΔT

COMEDK Mock Test - 1 - Question 20

Isopropylbenzene, on air oxidation in the presence of dilute acid, gives

Detailed Solution for COMEDK Mock Test - 1 - Question 20

Isopropylbenzene is cumene. Its air oxidation and then, acidic hydrolysis gives phenol.

COMEDK Mock Test - 1 - Question 21

The standard enthalpy of neutralisation of HCl by NaOH is -57.62 kJ mol-1, which is the enthalpy of formation of water.

The standard enthalpy of neutralisation of HCN by NaOH is

Detailed Solution for COMEDK Mock Test - 1 - Question 21

Enthalpy of neutralisation is defined as the amount of heat evolved when 1 equivalent of H+ ions from an acid is completely neutralised by 1 equivalent of HO- ions from a base.
For a strong base and a strong acid, which are strong electrolytes, this value is fixed under standard conditions at -57.62 kJ mol-1.
But for a weak acid like HCN or a weak base, the value is less as some of the heat liberated is utilised to ionise the weak acid or the weak base.

COMEDK Mock Test - 1 - Question 22

Let f : N → R be a function such that f(x + y) = 2f(x) f(y) for natural numbers x and y. If f(1) = 2, then the value of α for which  holds, is

Detailed Solution for COMEDK Mock Test - 1 - Question 22

f : N → R, f(x + y) = 2 f(x) f(y) ...(1)
f (1) = 2,

= 2f(α)(f(1) + f(2) + ... + f(10)) ...(2)
From (1),
f(2) = 2f2(1) = 23
f(3) = 2f(2) f(1) = 25
---------------------------------
f(10) = 29 f10(1) = 219
f (α) = 22α-1; α  N
From (2),


Hence, α = 4

COMEDK Mock Test - 1 - Question 23

Let A and B be two independent events such that P(A) = 1/3 and P(B) = 1/6. Then which of the following is TRUE?

Detailed Solution for COMEDK Mock Test - 1 - Question 23


∵ Option (3) is correct.

COMEDK Mock Test - 1 - Question 24

Consider the following two propositions:
P1 : ~(p → ~q)
P2 : (p ∧ ~q) ∧ ((~p) ∨ q)
If the proposition p →  ((~p) ∨ q) is evaluated as FALSE, then:

Detailed Solution for COMEDK Mock Test - 1 - Question 24

P1 : ~(p → ~q)
P2 : (p ∧ ~q) ∧ ((~p) ∨ q)
if p →  ((~p) ∨ q) is false
Then p is ture and ~p v q is false
∴ q  is false
⇒ P1 is false and P2 is also false

COMEDK Mock Test - 1 - Question 25

Let P be the plane passing through the intersection of the planes  and the point (2, 1, -2). Let the position vectors of the points X and Y be  and , respectively. Then the points

Detailed Solution for COMEDK Mock Test - 1 - Question 25

Let the equation of the required plane be:

∵ (2, 1, -2) lies on it, 2 + λ (-2) = 0
 ⇒ λ = 1
Hence, π : 3x + 2y - 8 = 0

Clearly, X and Y are on the opposite sides of plane .

COMEDK Mock Test - 1 - Question 26

Let the points on the plane P be equidistant from the points (-4, 2, 1) and (2, -2, 3). Then the acute angle between the plane P and the plane 2x + y + 3z = 1 is:

Detailed Solution for COMEDK Mock Test - 1 - Question 26

Let P1(x, y, z) be any point on plane P.
Then (x + 4)2 + (y - 2)2 + (z - 1)2 = (x - 2)2 + (y + 2)2 + (z - 3)2
⇒ 12x − 8y + 4z + 4 = 0
⇒ 3x - 2y + z + 1 = 0
And P2 : 2x + y + 3z = 1
∴ Angle between P1 and P2 

COMEDK Mock Test - 1 - Question 27

The value of 2sin(12°) - sin(72°) is:

Detailed Solution for COMEDK Mock Test - 1 - Question 27

sin 12° + sin12° - sin 72°
= sin 12° - 2cos 42° sin30°
= sin 12° - sin48°
= -2cos30° sin 18°

COMEDK Mock Test - 1 - Question 28

If the real part of the complex number (1 - cosθ + 2i sinθ)-1 is 1/5 for θ ∈ (0, π), then the value of the integral  dx is equal to:

Detailed Solution for COMEDK Mock Test - 1 - Question 28


COMEDK Mock Test - 1 - Question 29

Let x, y > 0. If x3y2 = 215, then the least value of 3x + 2y is

Detailed Solution for COMEDK Mock Test - 1 - Question 29

x, y > 0 and x3y2 = 215
Now, 3x + 2y = (x + x + x) + (y + y)
So, by A.M ≥ G.M inequality

∴ Least value of 3x + 2y = 40

COMEDK Mock Test - 1 - Question 30

Let λ * be the largest value of λ for which the function fλ(x) = 4λx3 - 36λx2 + 36x + 48 =  is increasing for all x ∈ R. Then, fλ * (1) + fλ* (-1)  is equal to:

Detailed Solution for COMEDK Mock Test - 1 - Question 30


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