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CAT Practice Test: Month (May) - CAT MCQ


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30 Questions MCQ Test - CAT Practice Test: Month (May)

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CAT Practice Test: Month (May) - Question 1

Detailed Solution for CAT Practice Test: Month (May) - Question 1

CAT Practice Test: Month (May) - Question 2

If x = loga (bc), y = logb (ca) and z = logc (ab) when which of the following is equal to 1?

Detailed Solution for CAT Practice Test: Month (May) - Question 2

 

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CAT Practice Test: Month (May) - Question 3

If logk x.log5 k = 1 k ≠ 1.k > 0, then x is equal to

Detailed Solution for CAT Practice Test: Month (May) - Question 3

CAT Practice Test: Month (May) - Question 4

Detailed Solution for CAT Practice Test: Month (May) - Question 4

CAT Practice Test: Month (May) - Question 5

 

Detailed Solution for CAT Practice Test: Month (May) - Question 5

CAT Practice Test: Month (May) - Question 6

Direction for questions 1 to 2 : Read passage below and solve the questions based on it.
Tn a horticultural show, a participant arranged a total of 1000 fruits of four types in a long straight line He first placed one apple, then two mangoes, three oranges, four custard apples, five apples, six mangoes, seven oranges, eight custard apples and so on (with apples followed by mangoes, oranges, custard apples in that order) uplo the 1000th fruit.

What was the 1000th fruit?

Detailed Solution for CAT Practice Test: Month (May) - Question 6

Fruits are ordered like 1. Apple 2. Mangoes 3 Oranges 4. Custard apple Fruits arc being pul up first one. then two, then three, then four and so oil.

1 + 2 + 3 + ... +44 = 990
So, the 45th fruit will be the 100th fruit. Since we are having a set of four different types of fruits, 45th will be Apple.

CAT Practice Test: Month (May) - Question 7

Direction for questions 1 to 2: Read passage below and solve the questions based on it.
In a horticultural show, a participant arranged a total of 1000 fruits of four types in a long straight line He first placed one apple, then two mangoes, three oranges, four custard apples, five apples, six mangoes, seven oranges, eight custard apples and so on (with apples followed by mangoes, oranges, custard apples in that order) uplo the 1000th fruit.

Q.

What was the position of the 100th Mango?

Detailed Solution for CAT Practice Test: Month (May) - Question 7

Fruits are ordered like 1. Apple 2. Mangoes 3 Oranges 4. Custard apple Fruits arc being pul up first one. then two, then three, then four and so oil.

Mangoes will come like 2, 6, 10, 14 etc. 100th mango will come 2 + 6 + 10 + 14 + 18 + 22 + 26 + 2= 100
100th mango will come in its 8th turn.
Before that apple must have got its 8th turn, orange and custard apple must have got their 7th turn.
Total apples displayed till now = 1 + 5 + 9 + ... + 29= 120
Total oranges displayed till now = 3 + 7+11 + ... +27=105
Total custard apples displayed till now = 4 + 8+ 12 + ... +28= 112
So, total fruits displayed till now (other than mangoes) = 337
So, the position of the 100th mango = 437

CAT Practice Test: Month (May) - Question 8

Find the number of non-negative integer solutions to the system of equations a + b + c + d + e = 20 and a + b + c = 5 is

Detailed Solution for CAT Practice Test: Month (May) - Question 8

Given a + b + c + d+ e = 20 ...(1)

a + b + c = 5 ... (2)

Given, system of equations is equivalent to a + b + c = 5 ...(3)
and d+ e = 15

Number non-negative integral solutions of equation (3)

CAT Practice Test: Month (May) - Question 9

In a test of 10 multiple choice questions of one correct answer, each having 4 alternative answers, then the number of ways to put ticks at random for the answers to all the questions is

Detailed Solution for CAT Practice Test: Month (May) - Question 9

Each of the questions can be answered in 4 ways. So, 10 questions can be answered in 410 ways.

CAT Practice Test: Month (May) - Question 10

Last year, there were 3 sections in the Catalyst, a mock CAT paper. Out of them 33  students cleared the cut-off in Section 1, 34 students cleared the cut-off in Section 2 and 32 cleared the cut-off in Section 3. 10 students cleared the cut-off in Section 1 and Section 2, 9 cleared the cut-off in Section 2 and Section 3, 8 cleared the cut-off in Section 1 and Section 3. The numberof people who cleared each section alone wasequal and was 21 for each section.

How many cleared only one of the three sections ?

Detailed Solution for CAT Practice Test: Month (May) - Question 10

21 + 21 +21 = 63

Option (B) is correct

CAT Practice Test: Month (May) - Question 11

Last year, there were 3 sections in the Catalyst, a mock CAT paper. Out of them 33  students cleared the cut-off in Section 1, 34 students cleared the cut-off in Section 2 and 32 cleared the cut-off in Section 3. 10 students cleared the cut-off in Section 1 and Section 2, 9 cleared the cut-off in Section 2 and Section 3, 8 cleared the cut-off in Section 1 and Section 3. The numberof people who cleared each section alone wasequal and was 21 for each section.

The ratio of  the number of students clearing then cut-off in one or  more of  the sections to     the number of  students clearing the cutoff  in Section 1 alone is?

Detailed Solution for CAT Practice Test: Month (May) - Question 11

(21+ 21 +21 +6+4+3+2)/21 = 78/21

Option (A) is correct

 

CAT Practice Test: Month (May) - Question 12

Directions: 

In a locality having 1500  households, 1000 watch Zee TV, 300 watch NDTV and 750 watch Star Plus.
Based on this information answer the questions that follow:

The minimum number of  households watching both Zee TV and NDTV is:

 

Detailed Solution for CAT Practice Test: Month (May) - Question 12

In this case,the number of households watching ZeeTV and NDTV can be separate from each other since there is no interference required between the households     watching ZeeTV and the households watching NDTV  as their individual sum(1000 +300) is smaller than the 1500 available householdsin the locality.Hence,the answer in this question is 0.

CAT Practice Test: Month (May) - Question 13

Directions: 

In a locality having 1500  households, 1000 watch Zee TV, 300 watch NDTV and 750 watch Star Plus.
Based on this information answer the questions that follow:

The maximum number of  households who watch neither of the three channels is:

Detailed Solution for CAT Practice Test: Month (May) - Question 13

For this  to occur  the following situation would give us the required solution:

As you can clearly see from the figure, all the requirements of each category of viewers is fulfilled by the given allocation of 1000 households. In this situation,the maximum number of households who do not watch any of the three channels is visible as 1500 –1000 = 500.

CAT Practice Test: Month (May) - Question 14

From a 60 m high building, the angles of depression of two cars on the opposite ends of the building are observed to be 60° and 30°. Find the distance between the cars, if the line joining them passes through the foot of the building.

Detailed Solution for CAT Practice Test: Month (May) - Question 14

Suppose OP is the building, and A and B are the two cars. Then, OP = 60, PAO = 60° and PBO = 30°
From the right triangle OBP, tan 30° =  60/OB
OB = 60 √m ...(i)
Also, from the right triangle AOP, tan 60° = 60/OA

OA = 60/√3 ....(ii)
Thus, from (i) and (ii),

CAT Practice Test: Month (May) - Question 15

If 10 sinθ = 6, then tanθ + cotθ =

Detailed Solution for CAT Practice Test: Month (May) - Question 15

If 10 sinθ = 6,
sinθ = 6/10 = 3/5

CAT Practice Test: Month (May) - Question 16

In a right triangle ABC, right-angled at B, cot2 A = 9/16. What is the value of cos A?

Detailed Solution for CAT Practice Test: Month (May) - Question 16


In right ΔABC,
∠B = 90°, cot2 A = 9/16
Taking square root on both sides, we get
cot A = 3/4… (1)

From (1) and (2), we get
b/p = 3/4
⇒ b = 3k and p = 4k
Now, using Pythagoras theorem,
AC2 = AB2 + BC2
h2 = p2 + b2
= (4k)2 + (3k)2
= 16k2 + 9k2
= 25k2
h = 5k
cos A = b/h = 3/5

CAT Practice Test: Month (May) - Question 17

Directions: Read the given passage and answer the question that follows.
A museum allowed groups of students from ten different schools A, B, C, D, E, P, Q, R, S and T to visit it in 10 different shifts over five days, from 21st May, 2018 to 25th May, 2018. There were two shifts (morning and evening) on each day and in a particular shift, only one school could visit. Each school came with a different number of students. The schools were instructed to bring at least 30 students, but not more than 60 students. None other than these ten schools visited the museum over these five days.
Over these five days, 210 students visited in the morning shift and 250 students visited in the evening shift. School D visited on 24th May with 32 students. The total number of students who visited in the two shifts on 23rd May was 100. Three schools visited the museum between schools D and A. School R visited the museum two days after school P, but in the same shift. School E visited the museum three days after school C, but in the same shift. School C visited the museum with 13 more students than school A, but on a different day. The sum of the numbers of students from schools E and B was the same as the sum of the numbers of students from schools R and T. School Q visited immediately after school E, but with 10 more students. The school that visited last came with 60 students. One school visited the museum between school S and school T. School T visited the museum after school S with 10 more students than school A. The number of students who came from school R was a square number. The numbers of students who visited from schools C and S were multiples of 9. The number of students who visited from school C was more than that from school S.

How many students from school P visited the museum?

Detailed Solution for CAT Practice Test: Month (May) - Question 17

School D visited on 24th May with 32 students.
Three schools visited the museum between schools D and A.
School E visited the museum three days after school C, but in the same shift.
School C visited the museum with 13 more students than school A, but on a different day.
School Q visited immediately after school E, but with 10 more students.
Using the above given information, the only possibility is:

School R visited the museum two days after school P, but in the same shift.
There are two possibilities of the above given information:
Case-I

Case-II

One school visited the museum between school S and school T.
School T visited the museum after school S with 10 more students than school A.
The above given information is only possible in Case-I.
Here is the arrangement of slots of ten schools:-

The school that visited last came with 60 students - So, number of students that visited from School B is 60.
The number of students who came from school R was a square number - A square number between 30 and 60 is (36 and 49). So, number of students that came from School R will either be 36 or 49.
The total number of students who visited in the two shifts on 23rd May was 100 - So, number of students that visited from School T must be (100 - 49) = 51. As (100 - 36) = 64 (not possible)
Thus, number of students that visited the museum from School R and School T will be 49 and 51 respectively.
School T visited the museum after school S with 10 more students than school A - So, number of students that visited the museum from School A must be (51 - 10) = 41
School C visited the museum with 13 more students than school A - So, number of students from School C must be (41 + 13) = 54.
The sum of the numbers of students from schools E and B was the same as the sum of the numbers of students from schools R and T. - So, number of students from School E = ([49 + 51] - 60) = 40
School Q visited immediately after school E, but with 10 more students. - So, number of students that visited from School Q = 40 + 10 = 50
Accordingly, if 250 students visited in the evening shift- So, number of students from School S = (250 - (54 + 51 + 40 + 60 )) = 250 - 205 = 45
and If 210 students visited in the morning shift - So, number of students that visited from School P = (210 - (41 + 49 + 32 + 50)) = 210 - 172 = 38
Here is the complete arrangement:-

38 students from school P visited the museum.

CAT Practice Test: Month (May) - Question 18

Directions: Read the given passage and answer the question that follows.
A museum allowed groups of students from ten different schools A, B, C, D, E, P, Q, R, S and T to visit it in 10 different shifts over five days, from 21st May, 2018 to 25th May, 2018. There were two shifts (morning and evening) on each day and in a particular shift, only one school could visit. Each school came with a different number of students. The schools were instructed to bring at least 30 students, but not more than 60 students. None other than these ten schools visited the museum over these five days.
Over these five days, 210 students visited in the morning shift and 250 students visited in the evening shift. School D visited on 24th May with 32 students. The total number of students who visited in the two shifts on 23rd May was 100. Three schools visited the museum between schools D and A. School R visited the museum two days after school P, but in the same shift. School E visited the museum three days after school C, but in the same shift. School C visited the museum with 13 more students than school A, but on a different day. The sum of the numbers of students from schools E and B was the same as the sum of the numbers of students from schools R and T. School Q visited immediately after school E, but with 10 more students. The school that visited last came with 60 students. One school visited the museum between school S and school T. School T visited the museum after school S with 10 more students than school A. The number of students who came from school R was a square number. The numbers of students who visited from schools C and S were multiples of 9. The number of students who visited from school C was more than that from school S.

The students from which school visited the museum in the evening shift on 22nd May?

Detailed Solution for CAT Practice Test: Month (May) - Question 18

School D visited on 24th May with 32 students.
Three schools visited the museum between schools D and A.
School E visited the museum three days after school C, but in the same shift.
School C visited the museum with 13 more students than school A, but on a different day.
School Q visited immediately after school E, but with 10 more students.
Using the above given information, the only possibility is:

School R visited the museum two days after school P, but in the same shift.
There are two possibilities of the above given information:
Case-I

Case-II

One school visited the museum between school S and school T.
School T visited the museum after school S with 10 more students than school A.
The above given information is only possible in Case-I.
Here is the arrangement of slots of ten schools:-

The school that visited last came with 60 students - So, number of students that visited from School B is 60.
The number of students who came from school R was a square number - A square number between 30 and 60 is (36 and 49). So, number of students that came from School R will either be 36 or 49.
The total number of students who visited in the two shifts on 23rd May was 100 - So, number of students that visited from School T must be (100 - 49) = 51. As (100 - 36) = 64 (not possible)
Thus, number of students that visited the museum from School R and School T will be 49 and 51 respectively.
School T visited the museum after school S with 10 more students than school A - So, number of students that visited the museum from School A must be (51 - 10) = 41
School C visited the museum with 13 more students than school A - So, number of students from School C must be (41 + 13) = 54.
The sum of the numbers of students from schools E and B was the same as the sum of the numbers of students from schools R and T. - So, number of students from School E = ([49 + 51] - 60) = 40
School Q visited immediately after school E, but with 10 more students. - So, number of students that visited from School Q = 40 + 10 = 50
Accordingly, if 250 students visited in the evening shift- So, number of students from School S = (250 - (54 + 51 + 40 + 60 )) = 250 - 205 = 45
and If 210 students visited in the morning shift - So, number of students that visited from School P = (210 - (41 + 49 + 32 + 50)) = 210 - 172 = 38
Here is the complete arrangement:-

The students of school S visited the museum in the evening of 22nd May.

CAT Practice Test: Month (May) - Question 19

Directions: Read the given passage and answer the question that follows.
A museum allowed groups of students from ten different schools A, B, C, D, E, P, Q, R, S and T to visit it in 10 different shifts over five days, from 21st May, 2018 to 25th May, 2018. There were two shifts (morning and evening) on each day and in a particular shift, only one school could visit. Each school came with a different number of students. The schools were instructed to bring at least 30 students, but not more than 60 students. None other than these ten schools visited the museum over these five days.
Over these five days, 210 students visited in the morning shift and 250 students visited in the evening shift. School D visited on 24th May with 32 students. The total number of students who visited in the two shifts on 23rd May was 100. Three schools visited the museum between schools D and A. School R visited the museum two days after school P, but in the same shift. School E visited the museum three days after school C, but in the same shift. School C visited the museum with 13 more students than school A, but on a different day. The sum of the numbers of students from schools E and B was the same as the sum of the numbers of students from schools R and T. School Q visited immediately after school E, but with 10 more students. The school that visited last came with 60 students. One school visited the museum between school S and school T. School T visited the museum after school S with 10 more students than school A. The number of students who came from school R was a square number. The numbers of students who visited from schools C and S were multiples of 9. The number of students who visited from school C was more than that from school S.

How many more students were there in the group from school R than in the group from School S?

Detailed Solution for CAT Practice Test: Month (May) - Question 19

School D visited on 24th May with 32 students.
Three schools visited the museum between schools D and A.
School E visited the museum three days after school C, but in the same shift.
School C visited the museum with 13 more students than school A, but on a different day.
School Q visited immediately after school E, but with 10 more students.
Using the above given information, the only possibility is:

School R visited the museum two days after school P, but in the same shift.
There are two possibilities of the above given information:
Case-I

Case-II

One school visited the museum between school S and school T.
School T visited the museum after school S with 10 more students than school A.
The above given information is only possible in Case-I.
Here is the arrangement of slots of ten schools:-

The school that visited last came with 60 students - So, number of students that visited from School B is 60.
The number of students who came from school R was a square number - A square number between 30 and 60 is (36 and 49). So, number of students that came from School R will either be 36 or 49.
The total number of students who visited in the two shifts on 23rd May was 100 - So, number of students that visited from School T must be (100 - 49) = 51. As (100 - 36) = 64 (not possible)
Thus, number of students that visited the museum from School R and School T will be 49 and 51 respectively.
School T visited the museum after school S with 10 more students than school A - So, number of students that visited the museum from School A must be (51 - 10) = 41
School C visited the museum with 13 more students than school A - So, number of students from School C must be (41 + 13) = 54.
The sum of the numbers of students from schools E and B was the same as the sum of the numbers of students from schools R and T. - So, number of students from School E = ([49 + 51] - 60) = 40
School Q visited immediately after school E, but with 10 more students. - So, number of students that visited from School Q = 40 + 10 = 50
Accordingly, if 250 students visited in the evening shift- So, number of students from School S = (250 - (54 + 51 + 40 + 60 )) = 250 - 205 = 45
and If 210 students visited in the morning shift - So, number of students that visited from School P = (210 - (41 + 49 + 32 + 50)) = 210 - 172 = 38
Here is the complete arrangement:-

Number of students in school S' group = 45
Difference = 49 - 45 = 4

CAT Practice Test: Month (May) - Question 20

In a school with 800 students, 480 students are enrolled in Chemistry and 160 students are enrolled in both Chemistry and Physics. If the number of students who do not enrol in any of the subjects is equal to the one-seventh of the total number of students enrolled in Physics, then find how many students are not enrolled in either of them.  

Detailed Solution for CAT Practice Test: Month (May) - Question 20


Number of students in the school = 800
Number of students who are enrolled in Chemistry = 480
Number of students who are enrolled in both Chemistry and Physics = 160
∴ From the diagram,
480 + P + x = 800
[According to the question, 7x = P + 160 because x = (1/7)th of the total number of students enrolled in Physics]
Or, P = 7x - 160
⇒ 480 + 7x -160 + x = 800
⇒ 320 + 8x = 800
⇒ 8x = 480
⇒ x = 60
Hence, total number of students enrolled in neither Physics nor Chemistry = 60

CAT Practice Test: Month (May) - Question 21

In a town of 10000 families, it was found that 40% families buy newspaper A, 20% families buy newspaper B and 10% families buy newspaper C, 5% families buy A and B, 3% buy B and C and 4% buy A and C. If 2% families buy all the three newspapers, then the number of families that buy none of these newspapers is  

Detailed Solution for CAT Practice Test: Month (May) - Question 21

Number of families who buy none of A, B and C = N - n(A ∪ B ∪ C),
where N = Total number of families.
n(A): Number of Newspaper A readers.
n(B): Number of Newspaper B readers.
n(C): Number of Newspaper C readers.
Number of families who buy none of A, B and C = 10000 - {n(A) + n(B) + n(C) - n(A ∩ B) - n(B ∩ C) - n(A ∩ C) + n(A ∩ B ∩ C)}
= 10000 - 4000 - 2000 - 1000 + 500 + 300 + 400 - 200
= 4000
Number of families who buy none of A, B and C = 4000

CAT Practice Test: Month (May) - Question 22

Directions: Read the following passage and answer the question that follows.

Today, the greatest crisis the country faces is increase in population. There are many problems which are being caused by population like health, unemployment, shortage of food, malnutrition, housing problem, illiteracy, ecological imbalance, etc. The country is outstripping China in population growth, adding the population of Australia almost every year and making sure that one person in every four is an Indian. The rapid increase in population has serious implications for the overall socio-economic development of the country. Various social customs and beliefs favour large families and impede the process of change for adoption of modern methods of birth control. What happens to our poverty curve, our standard of living, our per capita gross national product? Where would these additional millions be absorbed? Where will they work? Would they not boost the crime graph?

It is said that even if the entire 66 million of the unemployed do not take to crime, quite a large number may be tempted to do so. Cannot education come to their rescue? Surely not. Firstly, there are not enough teachers to meet the demand and the necessity to earn something to fill their own bellies and of their parents, makes education usually a low priority, in spite of facilities and incentives available to bring every child to school. This leads people from their school to their work location where they do not find much opportunity. Hence, they revert to crime.

Rapid population growth has also disturbed the ecological balance of nature. Water is everywhere but not a drop to drink. Hardly 69 per cent people have access to safe drinking water. Thousands died and lakhs were affected by cholera and gastroenteritis for want of safe drinking water in trans-Yamuna areas in Delhi. If the present ecological damage continues as a result of increasing population, one shudders to think of what is to follow.

Another major problem encountered is that the prices are going up and poverty is increasing. About 40% of the population in India is below the poverty line. Food reserves are diminishing. Essential goods are scarce. Land is being divided into smaller units. As a result, the standard of living is going down. Can we check these deteriorating conditions? Can we find answers anywhere else?

China has managed to bring down their population growth to 1.2% by enactment of law. In India, enactment of law for limiting family size is not feasible. Moreover, simply enacting a law won't make much difference, unless the law enforcing machinery, health workers and the masses join hands together. For national prosperity, we must have thorough planning. Our survival hangs in the balance. Strong human power must intervene in the sad state of affairs. This need not necessarily be the power of the government as we generally assume it to be but an effort of the collective.

Q. The standard of living is going down primarily because of
(I) poor governance
(II) increase in prices
(III) division of land into smaller units

Detailed Solution for CAT Practice Test: Month (May) - Question 22

The fourth paragraph states the factors which affect the standard of living. Rising prices, increase in poverty, scarcity of essential goods, diminishing food reserves, division of land into smaller units have been mentioned as the factors deteriorating our standard of living. 'Poor governance' is not the primary cause of a decrease in the standard of living as evident from the last line of the paragraph, which states 'This need not necessarily . . . an effort of the collective.' Thus, it is not only the government which is responsible for upholding national prosperity, it is also the duty of the masses to take an active part in any initiative aimed at planning and prosperity. Thus, 'poor governance' cannot be termed as a direct and primary cause for a decrease in the standard of living.

CAT Practice Test: Month (May) - Question 23

Directions: Read the following passage and answer the question that follows.

Today, the greatest crisis the country faces is increase in population. There are many problems which are being caused by population like health, unemployment, shortage of food, malnutrition, housing problem, illiteracy, ecological imbalance, etc. The country is outstripping China in population growth, adding the population of Australia almost every year and making sure that one person in every four is an Indian. The rapid increase in population has serious implications for the overall socio-economic development of the country. Various social customs and beliefs favour large families and impede the process of change for adoption of modern methods of birth control. What happens to our poverty curve, our standard of living, our per capita gross national product? Where would these additional millions be absorbed? Where will they work? Would they not boost the crime graph?

It is said that even if the entire 66 million of the unemployed do not take to crime, quite a large number may be tempted to do so. Cannot education come to their rescue? Surely not. Firstly, there are not enough teachers to meet the demand and the necessity to earn something to fill their own bellies and of their parents, makes education usually a low priority, in spite of facilities and incentives available to bring every child to school. This leads people from their school to their work location where they do not find much opportunity. Hence, they revert to crime.

Rapid population growth has also disturbed the ecological balance of nature. Water is everywhere but not a drop to drink. Hardly 69 per cent people have access to safe drinking water. Thousands died and lakhs were affected by cholera and gastroenteritis for want of safe drinking water in trans-Yamuna areas in Delhi. If the present ecological damage continues as a result of increasing population, one shudders to think of what is to follow.

Another major problem encountered is that the prices are going up and poverty is increasing. About 40% of the population in India is below the poverty line. Food reserves are diminishing. Essential goods are scarce. Land is being divided into smaller units. As a result, the standard of living is going down. Can we check these deteriorating conditions? Can we find answers anywhere else?

China has managed to bring down their population growth to 1.2% by enactment of law. In India, enactment of law for limiting family size is not feasible. Moreover, simply enacting a law won't make much difference, unless the law enforcing machinery, health workers and the masses join hands together. For national prosperity, we must have thorough planning. Our survival hangs in the balance. Strong human power must intervene in the sad state of affairs. This need not necessarily be the power of the government as we generally assume it to be but an effort of the collective.

Q. According to the author, what is the relationship between the unemployment and the crime statistics?

Detailed Solution for CAT Practice Test: Month (May) - Question 23

The author makes two main points in 'It is said that even if the entire 66 million of the unemployed do not take to crime, quite a large number may be tempted to do so.' in the second paragraph. First, 'a large number' of unemployed people is expected to take to crime. Second, these people taking to crime is only an expectation or a prediction. This is not actually the case currently.

(1) - This statement contrasts with both the points of the author. 'Very few people' contrasts with 'a large number', and 'actually take to crime' contrasts with 'may be tempted'. Thus, it is incorrect.
(2) - The author states that majority of the unemployed are expected to take to crime. The pronoun 'all' would exaggerate the context of the statement.
(3) - Most of the unemployed are only expected to take to crime as the author believes that they may be tempted to do so. They are not actually taking to crime. The phrase 'may be' points towards this expectation.
(4) - Not 'some', but 'a large number' may take to crime.
(5) - This most accurately conforms to the ideas presented by the author.
Thus, option 5 is correct.
 

CAT Practice Test: Month (May) - Question 24

Directions: The passage below IS followed by a question based on its content. Answer the question on the basis of what is stated or implied in the passage.

The categorization by literary historians can be to some extent a precarious venture. When Asian poets are discussed independently as a set, for example, the degree to which their work reveals the advancement of poetry in broad–spectrum should not be forgotten, or a misrepresentation of literary history may be the consequence. This prudence is predominantly pertinent in an appraisal of the divergence between Asian poets at the start century (1900–1909) and those of the generation of the 1920's. These dissimilarities include the intrepid and more candid vocalizations of the later generation and its methodological ingenuity. It should not be forgotten, though, that analogous differences also existed for parallel generations of British poets.
When poets of the 1910's and 1920's are considered collectively, however, the peculiarities that literary historians might make out between "traditional" and "experimental" would be of little consequence in a debate of Asian poets, although these remain supportive classifications for British poets of these decades. Positively differences can be noted between "traditional" Asian poets such as Tagore and Seth and "experimental" ones such as Chan and Qayuum. But Asian poets were not fighting over old or fresh styles; rather, one consummate Asian poet was ready to welcome another, without caring for his or her styles, for what weighed was racial pride.
But, in the 1920's, Asian poets deliberated over the issue whether they should deal with particularly racial themes. The questions were raised like whether they should only write about Asian experience for an Asian audience or whether such demands were restraining. It may be believed, though, that nearly all these poets wrote their finest poems when they spoke out of racial sentiment, race being, as Kim Sun rightly put it,
"Necessarily the thing the Asian poet knows best".
At the start of the century, by comparison, most Asian poets generally wrote in the conformist manner of the age and articulated noble, if ambiguous, sentiments in their poetry. These poets were not extraordinarily gifted, though Rosh Jannah and J. Mitra may be segregated from the group. They decided not to write in vernacular, which as Stuart Bergmann has suggested, "Intended a refutation of stereotypes of Asian life," and they declined to write solely about racial issues. This denial had both a positive and negative results. As Bergmann observes, "Usefully persisted that Asian poets should not be cramped to issues of race, these poets made error .... They declined to introspect and write". These are vital perspicacities, but one must accentuate that this refusal to look within was also characteristic of most British poets of the time. They, too, often ignored their own familiarity and consequently fashioned some very ordinary poems about indistinct topics, such as the tranquility of nature.

Q. According to the passage, most turn-of-the century Asian poets generally did which of the following?

Detailed Solution for CAT Practice Test: Month (May) - Question 24

This is a `specific fact` question. The turn-of-the-century Asian poets are referred to in the first sentence of fourth paragraph. This sentence reads, "At the start of the century, by comparison, most Asian poets generally wrote in the conformist manner of the age and articulated noble, if ambiguous, sentiments in their poetry". The phrase among the choices, which best paraphrases the sentiments expressed above, is "They wrote in styles that did not confront accepted literary practice".

CAT Practice Test: Month (May) - Question 25

Directions: Select the word/phrase most similar in meaning to the word given in bold letters.

ARDUOUS

Detailed Solution for CAT Practice Test: Month (May) - Question 25

The word 'arduous' means requiring great effort or difficult and tiring.

CAT Practice Test: Month (May) - Question 26

Directions: Select the word that most closely defines the word given in bold letters.

ACCESS

Detailed Solution for CAT Practice Test: Month (May) - Question 26

The word 'access' means 'opportunity to approach'. The word 'admittance' means 'chance of entering somewhere'. So, the word 'access' means the same as 'admittance'.
'Summons' means 'to order (someone) to be present'.

CAT Practice Test: Month (May) - Question 27

Directions: Select the word/phrase that is antonymous to the word given in bold letters.

AMORTIZE

Detailed Solution for CAT Practice Test: Month (May) - Question 27

'Amortize' means 'to reduce or pay off.'
Whereas 'mortgage' means 'mortgage' means 'to put up as collateral or security.'
So, option C is the antonym of the given word.

CAT Practice Test: Month (May) - Question 28

Directions: Select the word/phrase that most closely defines the word given in bold letters.

BANAL

Detailed Solution for CAT Practice Test: Month (May) - Question 28

'Banal' means 'lacking in originality as to be obvious and boring.'
'Commonplace' also means 'happening often or often seen or experienced and so not considered to be special.'
So, option B is the correct answer.

CAT Practice Test: Month (May) - Question 29

Directions: Select the word/phrase that is antonymous to the word given in bold letters.

APPROBATION

Detailed Solution for CAT Practice Test: Month (May) - Question 29

The word 'approbation' means 'approval' or 'praise'.
The word 'admonition' means 'warning or reprimand'.
So, the word 'approbation' is the antonym of 'admonition'.

CAT Practice Test: Month (May) - Question 30

Directions: The sentence below has been divided into four parts. Identify the part having an error. If no part has an error, mark (5).

(1) Without hardly (2) any delay, (3) the government machinery began to provide (4) succour to quake victims. (5) No error

Detailed Solution for CAT Practice Test: Month (May) - Question 30

Use either `without` or `hardly`. Because both `without` and `hardly` have negative meaning.

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