DSSSB PGT Mathematics Mock Test - 10 - DSSSB TGT/PGT/PRT MCQ

 I – ‘The doctor away’ is an inference which follows from ‘An apple a day’.
J – This is a quote which is an opinion of someone.
J – This is a quote which is an opinion of someone.
J – This is a quote which is an opinion of someone.

Let marks required be x 
= (45 + 62 + x)/3 > 60
45+62+ x > 60*3
107 + x > 180 
x > 180 - 107
x > 73

So, 73 is the minimum score required in the third attempt to qualify.

As Ornithologist is a specialist of Birds similarly Archealogist is a specialist of Archealogy.

As cat has Paw similarly Horse has Hoof.

• As per Article (1) of Convention of 1890, it was agreed that the boundary of Sikkim and Tibet should be the crest of the mountain range separating the waters flowing into the Sikkim Teesta, and its effluents from the waters flowing into the Tibetan Mochu and northwards into other rivers of Tibet.

• The line commences at Mount Gipmochi on the Bhutan frontier and follows the parting of water to the point where it meets Nepal territory. However, Tibet refused to recognize the validity of the Convention of 1890 and further refused to affect the provisions of the said Convention.

• In 1904, a treaty known as a Convention between Great Britain and Tibet was signed at Lhasa. In 1906, a treaty was signed between Great Britain and China at Peking, which confirmed 1904 between Great Britain and Tibet.

The author is most worried about lack of qualified teachers. Because if there are no qualified teachers, students will not be able to learn.

P + 2 years interest on P = 1000 + 1 years interest on 1000 + 1000 -+ 1.21P = 2100 → P = 1736 (approx).

ओढ़ना शब्द "ना" प्रत्यय लगा कर बना है। प्रभाव ,पराजय,अपवाद क्रमशः उपसर्ग युक्त शब्द हैं।

Given:
One student who scored 20 marks more than the other, his score was 60% of the sum of their marks.
Let the students be A and B
Let the marks secured by B = x
Marks secured by A = x + 20
Sum of their marks = x + x + 20 = 2x + 20
Also, x + 20 = 60% of sum of marks

Marks secured by B = 40 + 20 = 60 marks
∴ The correct answer is 60 marks.

Given:

The identity element of b for any element

Therefore identity element is -1

Therefore e = -1

now for a inverse,

When a = -2, a^-1 = 0

9x² + 5y² - 30y = 0
9x² + 5(y−3)² = 45
We can write it as : [(x-0)²]/5 + [(y-3)²]/9 = 1
Compare it with x²/a² + y²/b² = 1
e = [(b² - a²)/b²]^½
e = [(9-5)/9]^1/2
e = (4/9)^½
e = ⅔

Given,

|A∪B∪C| = |A| + |B| + |C| - |A∩B∩C'| - |B∩C∩A'| - |A∩C∩B'| + |A∩B∩C| 

⇒ 34 = 22 + 18 + 6 - 3 - 2 - 4 + |A∩B∩C| 

⇒ |A∩B∩C| 

= 34 - 22 - 18 - 6 + 3 + 2 + 4 

= 43 - 46 

= -3

So, |A∩B∩C| = 3

The numbers between and can either be a three digit number or a four digit number. The solution is divided into these two different cases and their sum will give us the desired result. Any number between and must be of three or four digits.
Case I: When number is of three digits: The hundreds place can be filled by any one of the three digits and in ways. The remaining two places can be filled by the remaining five digits in , ways.
∴ The number of numbers formed in this case
Case II: When number is of four digits: The thousands place can be filled by any one of the two digits 1 and 2 in 2 ways and the remaining three places can be filled by the remaining five digits in ways.
∴ The number of numbers formed in this case
∴ Total numbers

Let p=q

From option (2);

We know that,
(i) Pythagoras Theorem: In a right-angled triangle,
Base ²+ Perpendicular ² = Hypotenuse² 

(i) The graph of the function y = cos x is continuous and extends on either side in symmetrical wave form.
(ii) Since the graph of y = cos x intersects the x-axis at the origin and at points where x is an odd multiple of 90°, hence cos x is zero at x = (2n + 1)/π² where n = 0, ±1, ±2, ±3, ±4, ……………... .

Given:

The general equation of a line is y = mx + c   -----(A)

Where m is the slope and c is any constant.

The slope of parallel lines is equal.

Slope of the perpendicular line have their product = -1
The given lines are,
and
Slope of the lines (i) is, i.e,
Similarly slope of the line

(ii) is, i.e,

Since the given lines are perpendicular to the same line, therefore, these lines are parallel which gives the lines have equal slope.

⇒ p(p² + 1) = -(p² +1)

⇒ (p² + 1) (p + 1) = 0

but p² + 1 ≠ 0

⇒ p + 1 = 0

⇒ p = -1

represents the unit vectors along the co ordinate axis i.e. OX ,OY and OZ respectively.