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Bihar PGT Chemistry Mock Test - 10 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar PGT Chemistry Mock Test - 10

Bihar PGT Chemistry Mock Test - 10 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT/TGT/PRT preparation. The Bihar PGT Chemistry Mock Test - 10 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar PGT Chemistry Mock Test - 10 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar PGT Chemistry Mock Test - 10 below.
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Bihar PGT Chemistry Mock Test - 10 - Question 1

The following sentence has been broken into four parts with an error in one part. Identify that part and mark it as your answer. If there are no errors in any of the given parts, mark option 4 or ‘No error’ as your answer.

Q. He informed me (1)/ earlier that he (2)/ will not come.(3)/ No error (4).

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 1

The sentence starts in past tense hence the ending cannot be in the future tense so as to maintain uniformity.
Correct Sentence- He informed me earlier that he would not come.  

Bihar PGT Chemistry Mock Test - 10 - Question 2

Directions: In the following question, out of the four alternatives, select the word similar in meaning to the word given.

Dissuade

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 2

The correct option is Option 4, i.e., ‘discourage’.
The word ‘dissuade’ means ‘to advise against something’. The word closest in meaning, from the given options is ‘discourage’, which has a similar meaning. Hence, the correct option is Option 4.

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Bihar PGT Chemistry Mock Test - 10 - Question 3

“कहते हुए यों उत्तरा के नेत्र जल से भर गए। 
हिम के कणों से पूर्ण मानो हो गए पंकज नए।। 

इन पंक्तियों में प्रयुक्त छंद का नाम बताइये?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 3

उक्त पँक्तियों में गीतिका छन्द का प्रयोग किया गया है।

प्रत्येक चरण में 14 और12 की यति से 26 मात्राएँ होती हैं 

प्रत्येक चरण के अंत में लघु और गुरु होता है।  

Bihar PGT Chemistry Mock Test - 10 - Question 4
Devaluation is majorly done to ________.
Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 4

The correct answer is Encourage export.

Key Points
  • Devaluation of a currency occurs when the currency's value in foreign exchange is low.
  • For example, devaluation of Indian currency means one rupee has less worth compared to other foreign currencies.
  • It makes the exports (nation’s goods) more affordable in the global market.
  • It helps in the country's economic growth.
  • Devaluation makes imports more expensive and creates demand for exports.
Bihar PGT Chemistry Mock Test - 10 - Question 5
The headquarters of South Asian Association for Regional Co-operation (SAARC) is
Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 5

The correct answer is Kathmandu (Nepal)

Key Points

  • SAARC is South Asian Association for Regional Cooperation, which is a regional intergovernmental organisation.
  • It was founded on 8 December 1985 in Dhaka.
  • It aims to promote the development of economic and regional integration.
  • It is headquartered in Kathmandu, Nepal.
  • The South Asian Free Trade Area was launched on 1st January 2006 to create a free trade zone between its members.
  • As of March 2020 Esala Ruwan Weerakoon is the Secretary-General. He assumed office on 1st March 2020.

Additional Information

  • Given below is the list of all members of SAARC:
    • Afghanistan
    • Bangladesh
    • Bhutan
    • India
    • Maldives
    • Nepal
    • Pakistan
    • Sri Lanka
Bihar PGT Chemistry Mock Test - 10 - Question 6

Ravi goes 40 km to North, then turns right and walks 50 km then again turns right and walks 30 km, then again turns right and walks 50 km. Now how many km away is he from his original position ? 

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 6

According to the information given in the question, we can draw the following diagram.

AC = 40 km
BC = 30 km
AB = AC - BC
AB = 40 - 30
AB = 10 km
Ravi is 10 km away from his starting point.
Hence, the correct answer is "10 km".

Bihar PGT Chemistry Mock Test - 10 - Question 7

What is the local time difference between Dwarka in Gujarat to Dibrughar in Assam?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 7

The correct answer is 1 hour 45 minutes

There is a time lag of two hours from Gujarat to Assam because of the longitudinal extent of India. Gujarat is situated in the extreme west of India while Assam located in the north-eastern part. The Sun rises almost two hours earlier in Assam than in Gujarat.

Key-Points

  • India lying entirely in the Northern hemisphere the mainland extends between latitudes 8°4'N and 37°6'N and longitudes 68°7'E and 97°25'E.
  • The Westernmost point of India is 68°7'E, known as Ghuar Mati, Gujarat
  • Location of DwarkaGujarat, India (N 22° 14' 36.0132", E 68° 58' 7.6908") on the map
  • Coordinates of Dibrugarh: 27° 28' 22.2024'' N, 94° 54' 43.0704'' E
  • The difference between the two points is almost 26°2'.
  • Difference of time, 1° longitudinal difference = 4 mins time lag
  • 30° longitudinal difference brings 26*4 = 104 mins difference in time
  • 104 mins or 1 hour 44 mins hours time-lag between Gujrat and Assam found.
  • So it is clear that 1 hour 45 minutes is the local time difference between Dwarka in Gujarat to Dibrugarh in Assam

Hence, option 1 is the correct answer.

Bihar PGT Chemistry Mock Test - 10 - Question 8

In the following question, select the related letters from the given alternatives.

NZ : MA :: TV : ?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 8

For this question, we will use the given table-

The relation of NZ : MA  is given below-

Similarly,

We will apply the same relation to TV : ? as-

Hence, Option (3) is correct.

Bihar PGT Chemistry Mock Test - 10 - Question 9

For a reaction 1/2 A→ 2B, rate of disappearance of ‘A’ related to the rate of appearance of ‘B’ by the expression -   

 [AIEEE 2008]

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 9

The correct answer is option A
For the reaction rate of disappearance of A is related to rate of appearance of B by the expression:

Bihar PGT Chemistry Mock Test - 10 - Question 10

What is wrong about enantiomers of 2-chloropropanoic acid?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 10

The correct answer is option D.
Pair of enantiomers react differently with pure enantiomers of other compounds.
 

*Multiple options can be correct
Bihar PGT Chemistry Mock Test - 10 - Question 11

In which of the following cases, entropy of I is larger than that of II?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 11

a) More molar mass, more entropy. So ∆SN2O4 > ∆SNO2
b) CO2 has more entropy than dry ice at -78°C
c) Pure alumina iss crystalline solid while ruby is amorphous. And ∆Samorphous > ∆SCrystalline. So alumina has less entropy than ruby.
d) At lower pressure, entropy be higher as gas particles are far from each other. So (∆SN2)1 bar > (∆SN2)5 bar 
 

Bihar PGT Chemistry Mock Test - 10 - Question 12

Which of the ligand can show linkage isomerism and acts as flexidentate ligand:

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 12

Bihar PGT Chemistry Mock Test - 10 - Question 13

In a first order reaction, the concentration of the reactant, decreases from 0.8 M to 0.4 M in 15 minutes. The time taken for the concentration to change from 0.1 M to 0.025 M is - 

[AIEEE-2004]

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 13

The correct answer is  Option A.
The concentration of the reactant decreases from 0.8M to 0.4M in 15 minutes, i.e. t1/2 = 15 minutes. Therefore, the concentration of the reactant will fall from 0.1M to 0.025M in two half lives. i.e.    2t1/2 = 2 × 15 = 30 minutes.

Bihar PGT Chemistry Mock Test - 10 - Question 14

Out of Cr (VI) as  , which is better oxidising agent?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 14

 + 4H2O + 3e- → Cr(OH)3 + 5OH-, E° = - 0.13 V 
+ 14H+ + 6e- → 2Cr3+ + 7H2O , E° = 1.33 V

Bihar PGT Chemistry Mock Test - 10 - Question 15

Which of the following is amphoteric?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 15

BeO is amphoteric as it can react with both acids and base
BeO+2NaOH = Na2BeO2
BeO+H2SO4 + BeSO4 + H2O
On the other hand, MgO and Cao are metallic oxides and act as a base only.

Bihar PGT Chemistry Mock Test - 10 - Question 16

When diazonium salt solution is treated with water at a temperature of 283 K it forms?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 16

Benzene diazonium chloride is hydrolysed to phenol when heated with water.
ArN2Cl + H2O ----> ArOH + N2 + HCl 

Bihar PGT Chemistry Mock Test - 10 - Question 17

2-Hexyne gives trans -2- Hexene on treatment with - 

[AIEEE 2012]

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 17

The correct answer is option A
2-hexyne with Li/NH3​ gives trans-2-hexene. This reaction is also considered as Birch reduction.

Bihar PGT Chemistry Mock Test - 10 - Question 18

What is the product formed when excess of ethanol reacts with concentrated sulphuric acid at 383 K and then the temperature of reaction mixture is increased to 443 K?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 18

Bihar PGT Chemistry Mock Test - 10 - Question 19

Electron gain enthalpy values of noble gases are positive because:

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 19

Electron gain enthalpy values of noble gases are positive because they have stable electronic configuration and thus have no tendency to take additionalelectron.

Bihar PGT Chemistry Mock Test - 10 - Question 20

Which representation for the Lewis structure of HNO3 is correct?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 20

Only structure a is able to show the valence electrons along with charge distributions. So, ith the Lewis structure of HNO3 .

Bihar PGT Chemistry Mock Test - 10 - Question 21

Elimination of bromine from 2–bromobutane results in the formation of –

[AIEEE-2005]

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 21


In elimination reaction of alkyl halide major product is obtained according to Saytzeff’s rule, which states that when two alkenes may be formed, the alkene which is most substituted one predominates.

Bihar PGT Chemistry Mock Test - 10 - Question 22

 (A)  

(B) 

Relation between given pair is

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 22

Bihar PGT Chemistry Mock Test - 10 - Question 23

C7H7Cl shows how many benzenoid aromatic isomers?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 23

4 aromatic isomers are possible.

Bihar PGT Chemistry Mock Test - 10 - Question 24

Alkaline earth metals combine with halogens to form:​

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 24

Alkaline earth metals have valency +2. So on reaction with halogen, they form compounds MX2.

Bihar PGT Chemistry Mock Test - 10 - Question 25

Ionisation energy of He+ is 19.6 x 10-18 J atom-1. The energy of the first stationary state (n = 1) of Li2+ is

[AIEEE 2010]

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 25

Bihar PGT Chemistry Mock Test - 10 - Question 26

amongst the following compounds, the optically active alkane having lowest molar mass is 

[AIEEE 2004]

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 26

Here all compounds except in option c are achiral. So automatically option c is correct.

Bihar PGT Chemistry Mock Test - 10 - Question 27

The conversion of primary aromatic amines into diazonium salts is known as:

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 27

The process of conversion of primary aromatic amines into its diazonium salt is called diazotization. Diazonium salts are important synthetic intermediates that can undergo coupling reactions to form azo dyes and electrophilic substitution reactions to introduce functional groups.

Bihar PGT Chemistry Mock Test - 10 - Question 28

A 5.2 molal aqueous solution of methyl alcohol (CH3OH) is supplied. What is the mole fraction of methyl alcohol in the solution?

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 28

Bihar PGT Chemistry Mock Test - 10 - Question 29

 Shape of XeF2 is:

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 29

XeF2 molecular geometry is linear. It acquires such shape as the lone pairs present around the central atom tend to take up equatorial positions. The bond angle is said to be 180°.

Bihar PGT Chemistry Mock Test - 10 - Question 30

In Lyman series, shortest wavelength of H-atom appears at x m, then longest wavelength in Balmer series of He+ appear at

Detailed Solution for Bihar PGT Chemistry Mock Test - 10 - Question 30

For the spectral line in H -atom and H -like species (one electron)

For Lyman series
For shortest wavelength (maximum wave number) n2 → ∞



For longest wave length (minimum wave number), n2 = (n1, + 1).
For Balmer series, n1 = 2


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