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Bihar PGT Mathematics Mock Test - 9 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar PGT Mathematics Mock Test - 9

Bihar PGT Mathematics Mock Test - 9 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT/TGT/PRT preparation. The Bihar PGT Mathematics Mock Test - 9 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar PGT Mathematics Mock Test - 9 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar PGT Mathematics Mock Test - 9 below.
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Bihar PGT Mathematics Mock Test - 9 - Question 1

इनमें से एकवचन-बहुवचन का कौन-सा युग्म सही नहीं है?

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 1

'ऑंसू - ऑँसुओं' युग्म गलत है। आँसू हमेशा बहुवचन में ही प्रयोग होता है।

सदैव बहुवचन में प्रयुक्त होने वाले अन्य शब्द-प्राण, दर्शन, होश, बाल, हस्ताक्षर आदि हैं।

Bihar PGT Mathematics Mock Test - 9 - Question 2

'चाँदनी' का पर्यायवाची शब्द नहीं है:

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 2

चाँदनी के पर्यायवाची शब्द है - चन्द्रिका, कौमुदी, ज्योत्स्ना, चन्द्रमरीचि, उजियारी, चन्द्रप्रभा, जुन्हाई आदि।

मयंक, चांद का पर्यायवाची है।

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Bihar PGT Mathematics Mock Test - 9 - Question 3

निम्नलिखित विकल्पों में यह शुद्ध है:

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 3

"पर + अधीन" शुद्ध सन्धि विच्छेद है। जिसके मेल होने पर पराधीन शब्द बनेगा।

इसमें 'अ + आ = आ' का सूत्र प्रयोग हुआ है। इसमें दीर्घ सन्धि है।

Bihar PGT Mathematics Mock Test - 9 - Question 4

'सामान्य' शब्द का विलोम है:

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 4

सामान्य - मामूली, साधारण

श्रेष्ठ - अति उत्तम, उत्कृष्ट

सर्वज्ञ - सबकुछ जाननेवाला

साधारण - सब जगह पाया जानेवाला, आम, साधारण दृश्य, साधारण पहनावा, सामान्य, मामूली

विशिष्ट - विशेषता युक्त, असाधारण

Bihar PGT Mathematics Mock Test - 9 - Question 5

निम्‍नलिखित कवियों को उनकी रचनाओ के साथ सुमेलित कीजिए:

नीचे दिए गए विकल्‍पों में से सही उतर चुनिए: 

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 5

Bihar PGT Mathematics Mock Test - 9 - Question 6

प्रकाशन वर्ष की दृष्टी से निम्नलिखित काव्यकृतियों का सही अनुक्रम है:

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 6

प्रकाशन वर्ष की दृष्टी से काव्यकृतियों का सही अनुक्रम-3 आँसू, पल्लव, स्वप्न, साकेत है। 

आँसू- 1925 ई. में जयशंकर प्रसाद द्वारा रचित काव्य है। पल्लव सुमित्रानंदन पन्त का तीसरा कविता संग्रह है जो 1928 में प्रकाशित हुआ था। स्वप्न 1929 में रामनरेश त्रिपाठी द्वारा रचित काव्य है। साकेत मैथिलिशरण गुप्त द्वारा रचित महाकाव्य का नाम है। इसका प्रथम प्रकाशन सन् 1931 में हुआ था। 

Bihar PGT Mathematics Mock Test - 9 - Question 7

Select the option that is related to the third word in the same way as the second word is related to the first word.

Abduct : Kidnap :: Fierce : ?

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 7

The logic followed is:

Abduct and Kidnap are synonyms.

Similarly,

Fierce and Violent are synonyms.

Hence, the correct answer is "Violent".

Bihar PGT Mathematics Mock Test - 9 - Question 8

Select the number which can be placed at the sign of the question mark (?) from the given alternatives.

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 8

The pattern followed is:

Top right number = multiplication of top left number and bottom number 

In fig 1:

729 = 81 × 9

729 = 729

In fig 2:

512 = 64 × 8

512 = 512

Similarly,

In fig 3:

? = 49 × 7

? = 343 

Hence, the correct answer is "343".

Bihar PGT Mathematics Mock Test - 9 - Question 9
If x + y + 1 = 0, then x3 + y3 - 3xy = ?
Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 9

Given:

x + y + 1 = 0

Concept Used:

(a + b )3 = a3 + b3 + 3ab (a + b)

Calculations:

x + y + 1 = 0

⇒ x + y = -1

Cubing on both sides we get

(x + y)3 = ( -1 )3

⇒ x3 + y3 + 3xy( x + y ) = -1

⇒ x3 + y3 + 3xy ( -1) = -1

∵ x + y = -1

⇒ x3 + y3 - 3xy = -1

∴ required value = -1

Bihar PGT Mathematics Mock Test - 9 - Question 10
Four word-pairs have been given, out of which three are alike in some manner and one is different. Select the odd one.
Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 10

The logic followed here is:

1) Intact and Unflawed are synonyms meaning not damaged and perfect.

2) Entire and Partial are antonyms.

3) Bright and Luminous are synonyms.

4) Pure and Perfect are synonyms.

Both the words are synonyms in all the options except option 2, where the given words are antonyms.

Hence, the correct answer is "Entire : Partial".

Bihar PGT Mathematics Mock Test - 9 - Question 11

A, B, C, D, E and F are sitting on a row facing the South direction, but not necessarily in the same order. E is sitting immediate left to the B. A is sitting fourth right to the B. F is sitting between A and D. Who is sitting immediate left to the D?

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 11

Persons: A, B, C, D, E and F

1) E is sitting immediate left to the B.

2) A is sitting fourth right to the B.

3) F is sitting between A and D.

4) Final Sitting arrangement.

Hence, “C” is sitting immediate left to the D.

Bihar PGT Mathematics Mock Test - 9 - Question 12
                        was the source of alpha particles in Rutherford scattering experiment.
Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 12

The correct answer is the Helium nucleus.

  • Helium nucleus was the source of alpha particles in the Rutherford scattering experiment.
  • Ernest Rutherford, a British scientist conducted an experiment and proposed the atomic structure of elements.

Key Points

  • Rutherford conducted an experiment by bombarding a thin sheet of gold with α-particles.
  • He then analysed the trajectory of these particles after their interaction with the gold foil.
  • Since very few α-particles were deflected back, and only a few α-particles had nearly 180o angle of deflection.
  • Hence he concluded that the volume occupied by the positively charged particles in an atom is very small as compared to the total volume of an atom.
Bihar PGT Mathematics Mock Test - 9 - Question 13
In which Schedule of the Constitution of India is the list of States and Union Territories given?
Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 13
  • First schedule contains the list of states and union territories.
  • First schedule comprises
  • Indian constitution has 12 schedules.

How to remember 12 schedules?

Trick: TEARS OF OLD PM

1st Schedule: T – Territory

2nd Schedule: E – Enrolment

3rd Schedule: A – Affirmations/Oaths

4th Schedule: R – Rajya Sabha

5th Schedule: S – Scheduled Areas

6th Schedule: O – Other Scheduled Areas

7th Schedule: F – Federal Structure

8th Schedule: O – Official Languages

9th Schedule: L – Land Reforms

10th Schedule: D – Defection

11th Schedule: P – Panchayats

12th Schedule: M – Municipality
Bihar PGT Mathematics Mock Test - 9 - Question 14
The image formed by a plane mirror is always ________.
Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 14

The correct answer is Virtual and erect.

Key Points

  • plane mirror is a mirror with a flat reflective surface.
    • For light rays striking a plane mirror, the angle of reflection equals the angle of incidence.
    • The angle of the incidence is the angle between the incident ray and the surface normal.
    • The image formed by a plane mirror is always virtual and erect.
    • The image formed by the plane mirror is virtual and erect i.e. image cannot be projected or focused on a screen.
    • The distance of the image 'behind' the mirror is the same as the distance of the object in front of the mirror.
    • The size of the image formed is the same as the size of the object.

Additional Information

  • convex mirror or diverging mirror is a curved mirror in which the reflective surface bulges towards the light source.
    • Convex mirrors reflect light outwards, therefore they are not used to focus light.
    • The image is smaller than the object but gets larger as the object approaches the mirror.
  • A concave mirror is called a converging mirror because it converges the Ray of light incident parallels to the mirror into a point called the focus.
Bihar PGT Mathematics Mock Test - 9 - Question 15

If l1, m1, n1 and l2, m2, n2 are the direction cosines of two lines; and θ is the acute angle between the two lines; then

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 15

If l1, m1, n1 and l2, m2, n2 are the direction cosines of two lines; and θ is the acute angle between the two lines; then the cosine of the angle between these two lines is given by : 

Bihar PGT Mathematics Mock Test - 9 - Question 16

If A = {x : x = 2n, n ≤ 6, n ∈ N} and B = {x : x = 4n, n ≤ 2, n ∈ N}, then A – B is

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 16

A = {x : x = 2n, n ≤ 6}
For (n = 1,2,3,4,5,6) {2,4,8,16,32,64}
B = {x : x = 4n, n ≤ 2}
For (n = 1,2) {4,8}
A - B = {2, 8, 32, 64}

Bihar PGT Mathematics Mock Test - 9 - Question 17

Find the equation of a curve passing through the point (0, –2) given that at any point (x, y) on the curve, the product of the slope of its tangent and y coordinate of the point is equal to the x coordinate of the point.

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 17


When x= 0 and y = - 2 ,we have : c = 2,

Bihar PGT Mathematics Mock Test - 9 - Question 18

Magnitude of the vector 

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 18

We have : 

Bihar PGT Mathematics Mock Test - 9 - Question 19

The point from which the tangents to the circles x2 + y2 – 8x + 40 = 0,  5x2 + 5y2 – 25 x + 80 = 0, x2 + y2 – 8x + 16y + 160 = 0 are equal in length is

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 19

The Required point is the radical centre of the three given circles. The radical axes of the three circles taken in pairs are 3x - 24 = 0,16y + 120 = 0 and - 3x + 16y + 80 = 0. On solving, the required point is (8, -15/2).

Bihar PGT Mathematics Mock Test - 9 - Question 20

The least value of P for which the two curves arg z = π/6 and |z - 2 √3i| = P have a solution is ..

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 20

  represents a circle of radius p having centre at (0, 2 √3) and arg z = π/6 is a line making an angle of 300 with OX and lying in 1st quadrant.  
Let CM be perpendicular from C on OA.  Then, 

Now, the two curves will intersect if CM ≤ P  i.e., 3 ≤ P ⇒ P ≥ 3
Hence, the least value of p is 3 

Bihar PGT Mathematics Mock Test - 9 - Question 21

The value of 1 + 1.1! + 2. 2! + 3.3! + …… + n. n! is

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 21

n. n! = [(n + 1) – 1]n! = (n + 1)! – n!
∴ 1 + 2! – 1! + … + (n + 1)! – n! = (n + 1)!

Bihar PGT Mathematics Mock Test - 9 - Question 22

In a college there are 20 professors including the principal and the vice principal. A committee of 5 is to be formed. In how many ways it can be formed so that neither the principal nor the vice principal is included?

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 22

Out of 20 professors, excluding the principal and vice-principal, 18 professors are left.
No. of ways of selecting 5 professors out of 18 = 18C5

Bihar PGT Mathematics Mock Test - 9 - Question 23

A function F(n) is defined as F(n - 1) = 1/(2 - F(n)) for all natural numbers ‘n’. If F(1) = 2, then what is the value of [F(1)] + [F(2)] +…………+ [F(50)]?
(Here, [x] is equal to the greatest integer less than or equal to ‘x’)

(2012)

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 23

Given that 


Similarly, we can find the values of F(3), F (4), F (5) as  respectively..

From this we can say that every term except [F(1)], of the series [F(1)] + [F (2)] + .... + [F (50)] is equal to 1 as for 'n' > 0, F (n) lies between 1 and 2.
Therefore, [F (1)] + [F (2)] + .... +  [F (50)] = 51.
Hence, option (a) is the correct choice.

Bihar PGT Mathematics Mock Test - 9 - Question 24

If a, b, c are in H.P., then the straight line  always passes through a fixed point. That point is 

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 24

a,b,c are in H.P
∴1/a , 1/b , 1/care in A.P
∴2/b= 1/a+1/c_______ (1)
∴ x/a+y/b+1/c=0 ________ (2)
∴ From (1)
1/a+1/c−2/b=0 ______ (3)
∴ From (2) & (3)
We infer that,
(x=1,y=−2)
∴ Point is (1,−2)

Bihar PGT Mathematics Mock Test - 9 - Question 25

If A and B are disjoint, then n (A ∪ B) is equal to:

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 25

As n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
But in case of disjoint sets, n(A ∩ B) = 0
∴ n(A ∪ B) = n(A) + n(B)

Bihar PGT Mathematics Mock Test - 9 - Question 26

If f (x)  then f (1) is equal to

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 26

Bihar PGT Mathematics Mock Test - 9 - Question 27

A circle C and the circle x2 + y2 = 1 are orthogonal and have radical axis parallel to y-axis, then C can be  

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 27

(A) The  radical axis of the circle x2 + y2 = 1 and the circle given in is x = -2, which is | | to y-axis 
(B) is y = 2, which is | | to x-axis
(C) is x = 0, which is y-axis 
The radical axis with circle in (A) | | to y-axis and the given circle intersect circle given in A orthogonally. 

Bihar PGT Mathematics Mock Test - 9 - Question 28

The coefficients of 9th, 10th and 11th terms in the expansion of (1 + x)n are in A.P. then n =

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 28

(n - 2r)2 = n + 2

Bihar PGT Mathematics Mock Test - 9 - Question 29

The value of   is

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 29



Bihar PGT Mathematics Mock Test - 9 - Question 30

A variable chord PQ of the parabola y = 4x2 substends a right angle at the vertex. Then the locus of points of intersection of the tangents at P and Q is

Detailed Solution for Bihar PGT Mathematics Mock Test - 9 - Question 30


Slope of OP x slope of OQ = -1 
⇒ 4t1.4t2 = -1
Eq of tangent at 



Eq of tangent at 

Let (x1 , y1) is the point of intersection

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