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Alligation & Mixture- 3 - Free MCQ Practice Test with solutions, CAT Quant


MCQ Practice Test & Solutions: Test: Alligation & Mixture- 3 (15 Questions)

You can prepare effectively for CAT Quantitative Aptitude (Quant) with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Alligation & Mixture- 3". These 15 questions have been designed by the experts with the latest curriculum of CAT 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 25 minutes
  • - Number of Questions: 15

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Test: Alligation & Mixture- 3 - Question 1

Ram bought 3 types of wheat flour which are type A, type B and type C. The cost of type A flour is Rs 38/kg. The cost of type B is flour is Rs 45/kg and the cost of type C flour is Rs 50/kg. He mixes flour of each type in such a way that he gets a profit of 14 2/7 % when he sells it for  Rs 48/kg. If a sample of the mixture is taken such that amount of type B is 12 kgs and the amount of the other two types of flour are also positive integers, then which of the following can not be the weight of the sample?

Detailed Solution: Question 1

Profit of 14 2/7 ​% is received when the mixture is sold at Rs 48/ kg. Let the cost price of the mixture be CP

Then, (1+14 2/7 ​%) CP =48

(8/7) CP = 48

CP = Rs 42/kg

Since Rs 38 < Rs 42 < Rs 45.

We have to take 2 mixtures, 1 of type A+ type B and another one of type A + type C as per the allegations.

Mixture 1: type A and type B

Let the ratio be a:b, then

38a + 45b = 42 (a+b)

3b = 4a or a:b = 3:4....(I)

Mixture 2: type A and type C

Let the ratio be a1​ : c, then

38a1​ + 50c = 42(a+c)

8c = 4a1​ or a1​ : c = 2:1 ....(II)

If mixture 1 and mixture 2 are mixed in ratio x:y then

a:b:c = 3x + 2y : 4x: y

4x=12 thus x=3

Weight of overall mixture = 3x+2y+4x+y = 21+ + 3y

When y = 1, the weight of mixture = 24 kg

when y = 2, the weight of mixure = 27kgs

when y = 3, the weight of mixture = 30 kgs

When y = 4, the wight of mixture = 33kgs

Option A is not possible.

*Answer can only contain numeric values
Test: Alligation & Mixture- 3 - Question 2

Nimbooz, a beverage manufacturing company made a 500 ml of packaged drink that had 80% water, 15% sugar and 5% lemon juice in it. To target special consumers, it also began manufacturing Lemonkiss, a 200 ml packaged drink that had 70% water, 15% sugar, 5% salt and 10% lemon juice in it. Raghu observed that when he mixed one bottle of Nimbooz and Lemonkiss each, the drink was extremely delicious. Raghu was now considering packaging this hybrid drink to sell in the market. If 15 ml lemon juice can be extracted from a lemon, what is the minimum number of lemons needed to make 10 litres of this hybrid drink?


Detailed Solution: Question 2

For Nimbooz, containing 500 ml drink, amount of lemon juice= 5% of 500 ml= 25 ml.
For Lemonkiss- a 200 ml drink, amount of lemon juice= 10%of 200= 20 ml.
So, total lemon juice= 45 ml in 500+200 ml of the drink= 45 ml in 700 ml of the drink.
Raghu wants to produce 10L of this drink, which will have ml of lemon juice.
'.' 1 lemon is used to extract 15 ml of lemon juice.
.'. Lemons required for ml of lemon juice=
Lemons to be used= 42.85 or 43 lemons.

Test: Alligation & Mixture- 3 - Question 3

There are three solutions, A, B and C containing alcohol and water. The strength of the three solutions are 80%, 90% and 70% respectively. When 1 litre each of A and B is mixed with C, the strength of C increases to 75%. What would be the strength of C if two litres of A and 0.5 litres of B were mixed with C?

Detailed Solution: Question 3

Let the volume of C be x litres.
As the strengths of A and B are 80% and 90%, by mixing 1 litre each of A and B with C, we are adding 800 ml and 900 ml respectively of alcohol to C.
The strength of C is 70% which increases to 75%.
So, the new strength = 75%

On solving, we get x = 4 litres
So, alcohol present in C = 70% of 4 litres = 2.8 litres
In the second case, total alcohol added = (1.6 + 0.45) litres = 2.05 litres

Hence, option A is the correct answer.

Test: Alligation & Mixture- 3 - Question 4

There are 2 containers of 1 L each which are exactly half filled. The first container named container A contains pure alcohol and the second container named container B contains pure water. A cup of volume 70 ml is used to transfer the contents among the containers. Initially, 2 cups of A is poured in B and was mixed thoroughly. After this 3 cups were taken from B and were put in A and mixed. After which 1 cup was taken and put in B. If the concentration of alcohol in A is P and the concentration of water in B is Q. Which of the following is true?

Detailed Solution: Question 4

A has 500ml of alcohol and B has 500ml of water.
We see that after all the transfer, both the container will have 500ml each.
Let A has x ml of alcohol in it. Thus it will have 500 - x ml of water.  
Since overall A+B has 500 ml each of water and alcohol. If A has x ml alcohol then B will have 500 − x ml of alcohol.
Therefore B will have x ml of water.
Concentration of alcohol in 

Concentration of water in

Thus P = Q

Test: Alligation & Mixture- 3 - Question 5

Glucose solution containing 6% glucose and rest water, is mixed with water. One third ofthe quantity of the solution obtained is drained out and replaced by juice which has 10% fruit concentrate and rest water. If water now accounts for 94% of the total solution, what isthe ratio of glucose and fruit concentrate?

Detailed Solution: Question 5

We start at the stage when one third of the solution is removed and replaced with fruit concentrate solution. Assume that the fruit concentrate solution is 100 ml in quantity, which is one third of the total solution so total solution must be 300 ml in volume. Also 10% i.e. 10 ml of this fruit concentrate solution added should be fruit concentrate. So the final solution has 10 ml of fruit concentrate. Also since final solution contains 94% water, which is 94 X 3 = 282 ml. Out of 300 ml, 282 ml is water and 10 ml is fruit concentrate, so glucose should be 300 - 282 - 10 = 8 ml. Required ratio therefore is 8 : 10 or 4 : 5.

*Answer can only contain numeric values
Test: Alligation & Mixture- 3 - Question 6

Two types of lemonade (lemon syrup and water) X and Y were mixed in the proportion 1 : 4 by volume. Later on, volume of the mixture was tripled by adding lemonade X such that resulting mixture had 60% water. If lemonade X has 50% water, then the percentage of water in lemonade Y is __________ (Key in the percent value up to two decimal places).


Detailed Solution: Question 6

Suppose the quantity of lemonade X is 1 litre.
Suppose the quantity of lemonade Y is 4 litres.
Total mixture of lemonades X and Y = 5 litres
To triple this mixture, i.e. to make 15 litres, 10 liters of lemonade X needs to be added.
Now, 15 liters of mixture = 11 litres of X + 4 litres of Y
Given: 60% of the resultant mixture is water; this means, 60% of 15 litres = 9 liters is water and the remaining 6 litres is lemon syrup.
Also, it is given that lemonade X has 50% water; this means, 5.5 litres is water and 5.5 litres is lemon syrup.
This means that out of 9 litres of water in the mixture, 5.5 litres is of lemonade X.
Thus, 9 - 5.5 = 3.5 litres of water in the mixture belongs to lemonade Y.
The percentage of this water in lemonade Y is thus (3.5/4) × 100 = 87.50%.
Answer = 87.50 (up to two places of decimal)

Test: Alligation & Mixture- 3 - Question 7

A mixture contains lemon juice and sugar syrup in equal proportion. If a new mixture is created by adding this mixture and sugar syrup in the ratio 1 : 3, then the ratio of lemon juice and sugar syrup in the new mixture is

Detailed Solution: Question 7

Lemon juice : sugar syrup in the mixture is 1:1, i.e. 50% Lemon juice and 50% sugar syrup.

In sugar syrup, 100% is sugar syrup.

These two are mixed in the ratio 1:3.

Test: Alligation & Mixture- 3 - Question 8

A glass contains 500 cc of milk and a cup contains 500 cc of water. From the glass, 150 cc of milk is transferred to the cup and mixed thoroughly. Next, 150 cc of this mixture is transferred from the cup to the glass. Now, the amount of water in the glass and the amount of milk in the cup are in the ratio

*Answer can only contain numeric values
Test: Alligation & Mixture- 3 - Question 9

From a container filled with milk, 9 litres of milk are drawn and replaced with water. Next, from the same container, 9 litres are drawn and again replaced with water. If the volumes of milk and water in the container are now in the ratio of 16 : 9, then the capacity of the container, in litres, is


Detailed Solution: Question 9

Let initial volume be V, final be F for milk.
The formula is given by :  is the number of times the milk is drawn and replaced.

V =5, but this is not possible because 9 liters is drawn every time.

Test: Alligation & Mixture- 3 - Question 10

If a certain weight of an alloy of silver and copper is mixed with 3 kg of pure silver, the resulting alloy will have 90% silver by weight. If the same weight of the initial alloy is mixed with 2 kg of another alloy which has 90% silver by weight, the resulting alloy will have 84% silver by weight. Then, the weight of the initial alloy, in kg, is

Detailed Solution: Question 10

Let the alloy contain x Kg silver and y kg copper
Now when mixed with 3Kg Pure silver

we get 10x+30 =9x+9y+27
9y-x=3 (1)
Now as per condition 2 silver in 2nd alloy = 2(0.9) =1.8

we get 21y-4x =3 (2)
solving (1) and (2) we get y= 0.6 and x =2.4
so x+y = 3

Test: Alligation & Mixture- 3 - Question 11

A glass is filled with milk. Two-thirds of its content is poured out and replaced with water. If this process of pouring out two-thirds the content and replacing with water is repeated three more times, then the  final ratio of milk to water in the glass, is

Detailed Solution: Question 11

Let the initial quantity of milk in the glass be like 81 liters.

Test: Alligation & Mixture- 3 - Question 12

A vessel contained a certain amount of a solution of acid and water. When 2 litres of water was added to it, the new solution had 50% acid concentration. When 15 litres of acid was further added to this new solution, the final solution had 80% acid concentration. The ratio of water and acid in the original solution was

Detailed Solution: Question 12

At the time when, concentration was 50%
Let x is acid and x is water.
When 15 litres of acid is added then, the acid concentration becomes 80%

On solving, we get x = 5
So, there were 5 litres of acid and 5 litres of water after mixing 2 litres of water:
So, there would be 5 litres of acid and 3 litres of water before adding the water.
So, the required ratio of acid to water would be 3 : 5
Hence, option D is the required answer.

Test: Alligation & Mixture- 3 - Question 13

A container holds 200 litres of a solution of acid and water, having 30% acid by volume. Atul replaces 20% of this solution with water, then replaces 10% of the resulting solution with acid, and finally replaces 15% of the solution thus obtained, with water. The percentage of acid by volume in the final solution obtained after these three replacements, is nearest to

Detailed Solution: Question 13

200 L with (30%) acid ⇒ acid = 0.30 × 200 = 60L 
Replace 20% with water: remaining acid =60 × (1 − 0.20) = 60 × 0.8 = 48L.
Replace 10% with pure acid: After removing 10% of the mixture, the acid becomes 48 × 0.9 = 43.2 L, then adding back 20 L pure acid ⇒ acid = 43.2 + 20 = 63.2L.
Replace 15 with water: acid left = 63.2 × (1 − 0.15) = 63.2 × 0.85 = 53.72L.
Final concentration 
The answer is 27%

Test: Alligation & Mixture- 3 - Question 14

A mixture of coffee and cocoa, 16% of which is coffee, costs Rs 240 per kg. Another mixture of coffee and cocoa, of which 36% is coffee, costs Rs 320 per kg. If a new mixture of coffee and cocoa costs Rs 376 per kg, then the quantity, in kg, of coffee in 10 kg of this new mixture is

Detailed Solution: Question 14

Let coffee price = C Rs/kg and cocoa price = K Rs/kg.

From the two given mixtures:

Multiply both equations by 100 to remove decimals:

Subtract the first from the second:


For the new mixture priced at Rs 376/kg, let the coffee fraction be p. Then

Thus, coffee is (50%) of the new mixture. In 10 kg of this mixture, coffee = 10 × 0.5 = 5kg

Test: Alligation & Mixture- 3 - Question 15

A thief steals four gallons of liquid soap kept in a train compartment’s bathroom from a container that is full of liquid soap. He then fills it with water to avoid detection. Unable to resist the temptation he steals 4 gallons of the mixture again, and fills it with water. When the liquid soap is checked at a station it is found that the ratio of the liquid soap now left in the container to that of the water in it is 36 : 13. What was the initial amount of the liquid soap in the container if it is known that the liquid soap is neither used nor augmented by anybody else during the entire period?

Detailed Solution: Question 15

It can be seen from the ratio 36:13 that the proportion of liquid soap to water is 36/49 after two mixings. This means that 6/7th of the liquid soap must have been allowed to remain in the container and hence l/7th of the conatiner’s original liquid soap would have been drawn out by the thief. Since he takes out 4 gallons every time, there must have been 28 gallons in the container. ( as 4 should be l/7th of 28)

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