HPSC PGT Chemistry Mock Test - 9 - HPSC TGT/PGT MCQ

Concept:

• Food comprises constituents like proteins, carbohydrates, fats and supplementary substances such as minerals, vitamins and water that are vital for life.
• These constituents are known as nutrients. For proper functioning of our body, we need to consume bodybuilding foods (e.g. milk, meat, poultry, fish, eggs, pulses, groundnuts); energy-giving foods (e.g. cereals, sugar, roots, fats and oils); and protective foods (e.g. vegetables, fruits).

Explanation:

• Carbohydrates are the main source of energy for our body.
• Carbohydrates are of two types – simple and complex.
• Simple carbohydrates - These are quick-energy foods, e.g. sugar. Sources of simple carbohydrates are natural fruits, milk and milk products, and vegetables including potatoes and carrots.
• Complex carbohydrates - These are better sources of energy than sugar since they are released slowly. Sources of complex carbohydrates are bread, cereals (rice, wheat, bajra, corn, barley, ragi, sorghum, millets etc.),

Gram is not a source of carbohydrate, it is a source of protein.

Additional Information

Proteins:

• proteins are obtained from the animal as well as vegetable sources. Proteins of animal origin are found in milk, eggs, cheese, fish and meat.
• Proteins from these sources contain all the essential amino acids (EAA) in adequate amounts.
• Vegetable proteins are found in pulses (legumes), cereals, beans, nuts, oilseeds, etc

The correct answer is Bronze.

Key Points

• Vinesh Phogat has won the bronze medal in the ongoing World Wrestling Championships in Belgrade.
• She has become the first Indian woman wrestler to win two world championship medals.
• She won the bronze medal in the 53 kg freestyle event by defeating Sweden's Jonna Malmgren 8–0.

Additional Information

• ​Vinesh won three gold in Commonwealth Games.
• She won a gold medal in wrestling in the 48 kg category at the 2014 Commonwealth Games, and in the 50 kg category at the 2018 Commonwealth Games.
• After this, Vinesh won gold in the 53 kg weight category in the Commonwealth Games this year as well.

The correct answer is 2006

Key Points

• To promote sustainable development of forest resources in the State, Haryana Government framed its own Forest Policy in 2006.
• The policy has fixed the goal of achieving 20% Forest and Tree Cover in the state in a phased manner.
• The forests in Haryana are classified as Reserve Forests, Protected Forests, Unclassed Forests, Areas closed under section 38 of Indian Forest Act, 1927 and Areas closed under section 4 & 5 of Punjab Land Preservation Act, 1900.
• Blocks of Reserve Forest area are mainly confined to the Shivalik ranges in Panchkula and Yamunanagar districts.
• Small blocks of Reserved Forest are found at a number of places in the districts of Yamunanagar, Kaithal, Ambala, Jind and Hisar.
• The majority of forests in the state belong to the Subtropical dry deciduous category whereas subtropical thorn forests are found only in the Aravalli hills in the southern parts of the state.
• Pine forests are located at higher reaches in the Protected Forests of Morni Hills in Panchkula district, whereas Sal Forests dominate the Reserve Forests in the Shiwaliks of Yamunanagar district.

Given:

The ratio of the present age of Annu and Raj = 4 : 5

Then after 8 years ratio of their age = 5 : 6

Calculation:

Let be assume the present age of Annu and Raj is 4x and 5x respectively

⇒ (4x + 8)/(5x + 8) = 5/6

⇒ 24x + 48 = 25x + 40

⇒ x = 8

⇒ The age of Annu = 4x = 4 × 8 = 32

⇒ The age of Raj = 5x = 5 × 8 = 40

∴ The required result will be 32 years, and 40 years respectively.

One of the oldest arguments in the history of psychology is the 'nature vs nurture' debate. Each of these sides has good point that it is really hard to decide whether a person's development is predisposed in his DNA, or a majority of it is influenced by his life's experiences and his environment. 

(a) Zn is oxidised to Zn²⁺ in complex

(b) Au⁺ is reduced to Au — True
(c) Au (s) is displaced
(d) Since, it is a spontaneous reaction ΔG° < 0

n can vary from to 10 and can be +ve or –ve.

When freshly prepared solution of FeSO₄ is added in a solution containing NO₃^– ion, it leads to formation of a brown coloured complex. This is known as brown ring test of nitrate.

⇒ Exothermic low temperature
∴ Addition of reactant Δn_g < 0
⇒ Increase in pressure lower the volume.

Greater the number of hydroxy groups , greater its a bility to form H-bonds with water, hence greater solubility.

The electronic configuration of carbon in its ground state is given by 1s²2s²2p⁴. When it’s in an excited state, that is when it loses an electron, that would be from 2p-orbital. So the excited state’s electronic configuration is 1s²2s¹2p³.

Number of orbitals in a shell = n² = (5)² = 25

Also X, has CH₃—CH(OH)—, gives iodoform test and it is chiral.

Reaction involves rearrangement of carbocation

Adsorption and absorption is commonly known as sorption.

EC of Cr (24) is

∆S_X→Z = ∆S_X→Y + ∆S_Y→Z(Entropy is a state function, so it is additive)
W_X→Y→Z = WX→Y (work done in _y→z is zero as the process is isochoric)

Diazonium reacts with phenols and napthols to form dyes.

In HOCl, Cl acts as a cation and OH acts as an anion. First Cl⁺ attacks the aleke to form an electron deficient species(dueto repulsion, OH^- can’t attack). Then OH^- attacks to form compound a.

Vicinal diols which is not tertiary, prefer to form dioxane while tertiary diols prefer to undergo Pinacol-pinacolone rearrangement.

The diol is not tertiary, hence more likely to form dioxane.

The correct answer is option A
Due to solute presence in the solution, the solution's boiling point is greater than the pure solvent's boiling point. This is called as elevation in boiling point and it can be represented as:
ΔT_b​=K_b​ × molality

• John Newlands arranged the known elements in increasing order of their atomic masses.
• He started with the element having the lowest atomic mass ( hydrogen) and ended at thorium which was the 56th element.
• He found that every eighth element had properties similar to the first.

6 x 10²³ gram wheat

1 sec → 10^2O gm distributed

1 hour - 3600sec - 10²⁰ x 3600

= 3.6 x 10²³ wheat

3.6 x 10²³g  — 1 hour

Formal charge (F)

where, v = valence electrons = 6
s = shared electrons = 4
u = unshared electron = 4

Electronegativity increases as we move from left to right due to lanthanide contraction.