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HPSC PGT Chemistry Mock Test - 10 - HPSC TGT/PGT MCQ


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30 Questions MCQ Test - HPSC PGT Chemistry Mock Test - 10

HPSC PGT Chemistry Mock Test - 10 for HPSC TGT/PGT 2024 is part of HPSC TGT/PGT preparation. The HPSC PGT Chemistry Mock Test - 10 questions and answers have been prepared according to the HPSC TGT/PGT exam syllabus.The HPSC PGT Chemistry Mock Test - 10 MCQs are made for HPSC TGT/PGT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPSC PGT Chemistry Mock Test - 10 below.
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HPSC PGT Chemistry Mock Test - 10 - Question 1

Renewable source of energy is 

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 1

The correct answer is Sun.

Key Points

  • Renewable source of energy:
    • Renewable energy is useful energy that is collected from renewable resources, which are naturally replenished on a human timescale, including carbon-neutral sources like sunlight, wind, rain, tides, waves, and geothermal heat.
    • This type of energy source stands in contrast to fossil fuels, which are being used far more quickly than they are being replenished.
    • Although most renewable energy is sustainable energy, some are not, for example, some biomass is unsustainable.
    • Renewable energy often provides energy in four important areas: electricity generation, air, and water heating/cooling, transportation, and rural (off-grid) energy services.
  • Renewable energy flows involve natural phenomena such as sunlight, wind, tides, plant growth, and geothermal heat, as the International Energy Agency explains.
  • Renewable energy is derived from natural processes that are replenished constantly.
  • In its various forms, it derives directly from the sun, or from heat generated deep within the earth.
  • Included in the definition is electricity and heat generated from solar, wind, ocean, hydropower, biomass, geothermal resources, and biofuels, and hydrogen derived from renewable resources.
  • Rapid deployment of renewable energy and energy efficiency, and technological diversification of energy sources, would result in significant energy security and economic benefits.
  • It would also reduce environmental pollution such as air pollution caused by the burning of fossil fuels and improve public health, reduce premature mortalities due to pollution and save associated health costs that amount to several hundred billion dollars annually only in the United States.
  • Renewable energy sources, that derive their energy from the sun, either directly or indirectly, such as hydro and wind, are expected to be capable of supplying humanity energy for almost another 1 billion years, at which point the predicted increase in heat from the Sun is expected to make the surface of the Earth too hot for liquid water to exist.
HPSC PGT Chemistry Mock Test - 10 - Question 2

Which famous folk dance of Haryana is performed by both Men & Women?

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 2

The correct answer is Phag dance.

Key Points

  • The Phag or Phalgun dance is performed by the agricultural folks of Haryana in the months of February- March.
  • This dance celebrates the harvest of the farmers and is essentially an expression of joy and bliss.
  • The men sport the most colourful and best of their turbans during the performance, while the women wear colourful traditional costumes.
  • The dance is performed in the Dhamal style of Haryana.
  • There are different songs for the male and the female performers.

Additional Information

  •  Loor Dance 
    • Loor dance is one of the popular traditional folk dances of the northern Indian state of Haryana.
    • It is a medium for the local people to express joy and sorrow.
    • It is performed during the month of 'Phalguna' which corresponds to February of the Gregorian calendar.
    • The dance is also performed during the festival of Holi.
  • Khodia Dance
    • It is a variant of the Jhumar dance and is exclusively performed by women.
    • This dance is very popular in certain parts of central Haryana.
    • The dancers wear gleaming gold-work skirts and colourful chunries.
    • One of the dancers begins by singing a folk song and is followed by the rest of the dancers to form a circular arrangement.
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HPSC PGT Chemistry Mock Test - 10 - Question 3

In which of the following month Pinjore heritage festival is celebrated in Haryana?

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 3

The correct answer is December.

Key Points

  • Pinjore heritage festival is celebrated in Haryana in the last week of December. 
    • The festival celebrates the vibrant and rich culture of Haryana.
    • Many art forms are performed by the poet, singers, and dancers in this festival.
    • It is an annual event of Haryana that focuses on the history and heritage of Pinjore town.
    • Pinjore gardens are also known as Yadavindra Gardens.
    • The gardens resemble the Mughal garden architectural style.
    • Sikh rulers of the Patiala dynasty had renovated this garden.
    • The garden was built by Fadai Khan.
HPSC PGT Chemistry Mock Test - 10 - Question 4

In the following question, select the related letters from the given alternatives.

NZ : MA :: TV : ?

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 4

For this question, we will use the given table-

The relation of NZ : MA  is given below-

Similarly,

We will apply the same relation to TV : ? as-

Hence, Option (3) is correct.

HPSC PGT Chemistry Mock Test - 10 - Question 5

Heating limestone at a temperature of 1070 K we get:

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 5

Heating limestone at a temperature of 1070K we get quick lime i.e CaO.

CaCO3 ⇌ CaO (s) + CO2 (s)

Additional Information: Calcium oxide can be produced by the thermal decomposition of materials like limestone or seashells that contain calcium carbonate in a lime kiln.

HPSC PGT Chemistry Mock Test - 10 - Question 6

KCl.MgCl2.6H2O is a

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 6

KCl.MgCl2.6H2O is double salt

HPSC PGT Chemistry Mock Test - 10 - Question 7

 Shape of XeF2 is:

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 7

XeF2 molecular geometry is linear. It acquires such shape as the lone pairs present around the central atom tend to take up equatorial positions. The bond angle is said to be 180°.

HPSC PGT Chemistry Mock Test - 10 - Question 8

Alkaline earth metals combine with halogens to form:​

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 8

Alkaline earth metals have valency +2. So on reaction with halogen, they form compounds MX2.

HPSC PGT Chemistry Mock Test - 10 - Question 9

Direction (Q. Nos. 1-18) This section contains 18 multiple choice questions. Each question has four
choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. Oxidation can be defined as the terms

I. gain of electron and hydrogen
II. gain of oxygen and loss of electron
III. increase in oxidation number
IV. decrease in oxidation number

Select the correct terms

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 9


Oxidation number increases, oxygen gained and loss of electrons is oxidation.

HPSC PGT Chemistry Mock Test - 10 - Question 10

Hydrogen is prepared from H2O by adding

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 10

Preparation of Hydrogen from H2O with Ca (Calcium)

  • Hydrogen can be prepared from water (H2O) through a chemical reaction with calcium (Ca).
  • In this reaction, calcium acts as a reducing agent. This is because calcium has the ability to donate electrons during the reaction, which reduces the other reactant, in this case, water.
  • The overall chemical reaction that occurs is: Ca + 2H2O → Ca(OH)2 + H2
  • In this reaction, calcium (Ca) reacts with water (H2O) to form calcium hydroxide (Ca(OH)2) and hydrogen gas (H2).
  • The hydrogen gas that is produced can be collected and used for various purposes.
  • Thus, out of the given options, it is calcium that can act as a reducing agent to prepare hydrogen from water.

Why Other Options are Incorrect

  • Ag (Silver) and Au (Gold) are noble metals and do not readily participate in chemical reactions. They cannot act as reducing agents to produce hydrogen from water.
  • Al (Aluminium) can act as a reducing agent, but it does not react with water under normal conditions to produce hydrogen.

Conclusion

  • Therefore, the correct answer is option B: 'Ca, which acts as reducing agent'.
HPSC PGT Chemistry Mock Test - 10 - Question 11

Which of the following is amphoteric?

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 11

BeO is amphoteric as it can react with both acids and base
BeO+2NaOH = Na2BeO2
BeO+H2SO4 + BeSO4 + H2O
On the other hand, MgO and Cao are metallic oxides and act as a base only.

HPSC PGT Chemistry Mock Test - 10 - Question 12

For a reaction 1/2 A→ 2B, rate of disappearance of ‘A’ related to the rate of appearance of ‘B’ by the expression -   

 [AIEEE 2008]

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 12

The correct answer is option A
For the reaction rate of disappearance of A is related to rate of appearance of B by the expression:

HPSC PGT Chemistry Mock Test - 10 - Question 13

The conversion of primary aromatic amines into diazonium salts is known as:

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 13

The process of conversion of primary aromatic amines into its diazonium salt is called diazotization. Diazonium salts are important synthetic intermediates that can undergo coupling reactions to form azo dyes and electrophilic substitution reactions to introduce functional groups.

HPSC PGT Chemistry Mock Test - 10 - Question 14

Among the following compounds the maximum number of lone pair is present on the central atom of:

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 14

HPSC PGT Chemistry Mock Test - 10 - Question 15

Direction (Q. Nos. 1- 8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. For the given reaction, = - 1.3818 kcal at 300 K. Thus equilibrium constant is

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 15

Since the reaction is not reversible, equilibrium constant is zero.

HPSC PGT Chemistry Mock Test - 10 - Question 16

amongst the following compounds, the optically active alkane having lowest molar mass is 

[AIEEE 2004]

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 16

Here all compounds except in option c are achiral. So automatically option c is correct.

HPSC PGT Chemistry Mock Test - 10 - Question 17

In a first order reaction, the concentration of the reactant, decreases from 0.8 M to 0.4 M in 15 minutes. The time taken for the concentration to change from 0.1 M to 0.025 M is - 

[AIEEE-2004]

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 17

The correct answer is  Option A.
The concentration of the reactant decreases from 0.8M to 0.4M in 15 minutes, i.e. t1/2 = 15 minutes. Therefore, the concentration of the reactant will fall from 0.1M to 0.025M in two half lives. i.e.    2t1/2 = 2 × 15 = 30 minutes.

HPSC PGT Chemistry Mock Test - 10 - Question 18

Melamine is

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 18

HPSC PGT Chemistry Mock Test - 10 - Question 19

Requirement of macronutrient per acre of the land is

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 19

Requirement of macronutrient per acre of the land is 5 to 200 kg

HPSC PGT Chemistry Mock Test - 10 - Question 20

Passage

Consider the following isomers of [Co(NH3)4Br2]+. The black sphere represents Co, grey sphere represents NH3 and unshaded sphere represents Br.

Q. 

Which of the structures is identical?

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 20

Structure (a) = structure (c) and, structure (b) = structure (d)

HPSC PGT Chemistry Mock Test - 10 - Question 21

Direction (Q. Nos. 14 -15) This section contains a paragraph, wach describing  theory, experiments, data etc. three Questions related to paragraph have been  given.Each question have only one correct answer among the four given  ptions  (a),(b),(c),(d).

Based on the following thermochemical data of the given process, answer the questions.


 

Q. Bond energy of (C— C) bond is 

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 21

For C3H8 : 3C + 4H2 → C3H8 ; ∆H1
For C3H8 : 2C + 3H2 → C2H6 ; ∆H2
∆H1 = -[2(C-C)+8(C-H)]+[3Cs→g+4(H-H)]     -(I)
∆H2 = -[1(C-C)+6(C-H)]+[2Cs→g+3(H-H)]     -(2)
Let bond energy of C-C be x kcal and bond energy of C-H be y  kcal.
From eqn I and 2
 ∆H1 = -[2x+8y]+[3×172+4×104]     -(3)
∆H2 = -[x+6y]+[2×172+3×104]     -(4)
Also given, C+O2 → CO2; ∆H = -94.0 kcal     -(5)
H2 + ½ O2 → H2O ; ∆H = -68.0 kcal      -(6)
C2H6 + 7/2 O2 → 2CO2 + 3H2O ; ∆H = -372 kcal     -(7)
C3H8 + 5O2  → 3CO2 + 4H2O ; ∆H = -530 kcal-(8)
By inspection method,2 × (5) + 3 × (6) - (7) gives
2C + 3H2 → C2H6 ; ∆H2 = -20 kcal
And  3×(5) + 4×(6) -(8)
3C + 4H2 → C3H8 ; ∆H3 = -20 kcal 
By eqn. (3), (4), (9) and (10)
x+6y = 676
2x+8y = 956
x = 82 kcal and y = 99 kcal

HPSC PGT Chemistry Mock Test - 10 - Question 22

Elimination of bromine from 2–bromobutane results in the formation of –

[AIEEE-2005]

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 22


In elimination reaction of alkyl halide major product is obtained according to Saytzeff’s rule, which states that when two alkenes may be formed, the alkene which is most substituted one predominates.

HPSC PGT Chemistry Mock Test - 10 - Question 23

C7H7Cl shows how many benzenoid aromatic isomers?

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 23

4 aromatic isomers are possible.

HPSC PGT Chemistry Mock Test - 10 - Question 24

In the following set of nucleophiles, the strongest and the weakest nucleophile respectively are

I. CH3S-
II. CH3COC-
III. HO-
IV. C6H5C-

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 24

CH3S-(I) is strongest nucleophile and C6H5O-(IV) is weakest due to resonance stabilisation in it.

*Multiple options can be correct
HPSC PGT Chemistry Mock Test - 10 - Question 25

In which of the following cases, entropy of I is larger than that of II?

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 25

a) More molar mass, more entropy. So ∆SN2O4 > ∆SNO2
b) CO2 has more entropy than dry ice at -78°C
c) Pure alumina iss crystalline solid while ruby is amorphous. And ∆Samorphous > ∆SCrystalline. So alumina has less entropy than ruby.
d) At lower pressure, entropy be higher as gas particles are far from each other. So (∆SN2)1 bar > (∆SN2)5 bar 
 

HPSC PGT Chemistry Mock Test - 10 - Question 26

A red solid is insoluble in water. However, it becomes soluble if some KI is added to water. Heating the red solid in a test tube results in liberation of some violet coloured fumes and droplets of a metal appear on the cooler parts of the test tube. The red solid is  

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 26

HPSC PGT Chemistry Mock Test - 10 - Question 27

The formula of bleaching powder is:​

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 27

The chemical name of bleaching powder is calcium hypochlorite.it is manufactured by the action of chlorine on slaked lime (Ca(OH).
2Ca(OH)2+ 2Cl2→CaOCl2+ 2H2O+CaCl2

HPSC PGT Chemistry Mock Test - 10 - Question 28

What compound is produced when cyclohexene is treated with concentrated KMnO4?

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 28

Conc KMnO4 will cause oxidation and ring opening forming adipic acid.

HPSC PGT Chemistry Mock Test - 10 - Question 29

Passage lI

One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.

Initial partial pressure
CO(g) = 1.40 atm
CO2(g) = 0.80 atm

Q. Under the given partial pressure, reaction is

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 29

We know that with increase in pressure on one side, reaction shifts to that side which has less no. of moles(of gaseous species). However the no. of moles are same on both sides. So the REACTION WILL REMAIN IN EQUILIBRIUM.

HPSC PGT Chemistry Mock Test - 10 - Question 30

The conjugate acid of NH2- is

Detailed Solution for HPSC PGT Chemistry Mock Test - 10 - Question 30

Conjugate acid of a base is formed by adding H+ to it
NH2- + H+ → NH3
 

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