AWES PGT Physics Mock Test - 4 - AWES TGT/PGT MCQ

The Indian Institute of Technology (IIT Kanpur) Kanpur signed an MoU with Conlis Global for licensing an innovative bone healing technology based on Nano Hydroxyapatite-based Porous Composite Scaffolds. This collaboration aims to promote bone healing and regeneration in orthopaedic and dental applications, among others.

The correct answer is Sun.

Key Points

• Renewable source of energy:
  • Renewable energy is useful energy that is collected from renewable resources, which are naturally replenished on a human timescale, including carbon-neutral sources like sunlight, wind, rain, tides, waves, and geothermal heat.
  • This type of energy source stands in contrast to fossil fuels, which are being used far more quickly than they are being replenished.
  • Although most renewable energy is sustainable energy, some are not, for example, some biomass is unsustainable.
  • Renewable energy often provides energy in four important areas: electricity generation, air, and water heating/cooling, transportation, and rural (off-grid) energy services.
• Renewable energy flows involve natural phenomena such as sunlight, wind, tides, plant growth, and geothermal heat, as the International Energy Agency explains.
• Renewable energy is derived from natural processes that are replenished constantly.
• In its various forms, it derives directly from the sun, or from heat generated deep within the earth.
• Included in the definition is electricity and heat generated from solar, wind, ocean, hydropower, biomass, geothermal resources, and biofuels, and hydrogen derived from renewable resources.
• Rapid deployment of renewable energy and energy efficiency, and technological diversification of energy sources, would result in significant energy security and economic benefits.
• It would also reduce environmental pollution such as air pollution caused by the burning of fossil fuels and improve public health, reduce premature mortalities due to pollution and save associated health costs that amount to several hundred billion dollars annually only in the United States.
• Renewable energy sources, that derive their energy from the sun, either directly or indirectly, such as hydro and wind, are expected to be capable of supplying humanity energy for almost another 1 billion years, at which point the predicted increase in heat from the Sun is expected to make the surface of the Earth too hot for liquid water to exist.

The correct answer is 2 i.e. Bolsheviks.

Some facts about the Russian Socialist Democratic party(RSDP):

• The formation was the party that happened in 1898.
• The party followed Marxist ideas, believing the industrial working class, not peasants, would bring about revolution.
• The party ideas were based on the philosophies of Karl Marx and Friedrich Engels, namely that despite Russia's agrarian life, the real radical potential extended with the industrial working class.
• They played an important role in the politics of Russia at that time and they also won few seats in the elections.
• It was mainly divided into two groups - Bolsheviks and Mensheviks.
• The following table will help you to understand them better:

Fluency, elaboration, originality and flexibility are associated with divergent thinking. Divergent thinking is creating multiple ideas, unique possible solutions, or ideas of a problem in a short period. Fluency, elaboration, originality, and flexibility are the dimensions of Divergent thinking and are associated with giftedness. Divergent thinking is important in the creative thinking process. Guilford (1986) considered creative thinking as involving divergent thinking, consisting of four elements: fluency, flexibility, originality, and elaboration. 
Thus, this is the correct answer. 

Inclusive Education:

• It refers to an education system that accommodates all children regardless of their physical, intellectual, social, emotional, linguistic, or other conditions.
• It provides a provision to include disabled children along with normal children in a regular classroom environment.

An inclusive classroom refers to an education system that includes children regardless of physical, intellectual, social, linguistic, or other differently-abled conditions.

• In an inclusive classroom with diverse learners, cooperative learning, and peer-tutoring is actively promoted to facilitate peer-acceptance.
  • Cooperative learning: It refers to a heterogeneous group where students work collaboratively to achieve learning outcomes. It develops critical thinking, brainstorming, communication, and life long learning skills.
  • Peer tutoring: It refers to the learning process where fellow students teach each other. In this strategy, a higher-performing student is paired with a lower performing student to teach specific skills.
• An inclusive classroom is not limited to children with a disability but also gifted children, economically disadvantaged children, children from remote populations, children belonging to ethnic, linguistic, or cultural minorities, or children from other marginalized groups.

Therefore, Social skills development can become a positive strength for normal children in inclusive classrooms.

‘Choice of challenge’ is a characteristic of motivation.

Motivation is the drive to achieve something in life that satisfies one’s needs. There are two primary types of motivation namely, intrinsic motivation and extrinsic motivation. A number of behavioural characteristics are indicators of high motivation. Here are some of the important factors and some ways to help a child develop these characteristics:

• Persistence is the ability to stay with a task for a reasonably long period of time. While very young children cannot concentrate on one activity for an hour, there are still measurable differences in the length of time that young children will engage in an activity. A highly motivated child will stay involved for a long period of time, whereas an unmotivated child will give up very easily when not instantly successful.  Children learn persistence when they are successful at a challenging task.
• Choice of challenge is another characteristic of motivation. Children who experience success in meeting one challenge will become motivated, welcoming another. These motivated learners will choose an activity that is slightly difficult for them but provides an appropriate challenge. Unmotivated children (those who have not experienced early success) will pick something that is very easy and ensures instant success.
• The amount of dependency on adults is another indicator of motivation. Children with strong intrinsic motivation do not need an adult constantly watching and helping with activities. Children who have a lower level of motivation or are extrinsically motivated need constant attention from adults and cannot function independently.
• The last indicator of motivational level is emotion. Children who are clearly motivated will have a positive display of emotion. They are satisfied with their work and show more enjoyment in the activity. Children without appropriate motivation will appear quiet, sullen and bored.

The central fringe will be white because all the component color bands will superimpose there. The option (a) is true.
Since the fringes of different wavelengths of light have different fringe-widths, there will not be a completely dark fringe. Option (b) is true.
Since the wavelength of the violet light is nearly half of the red light, the fringe-width of the violet light is half of the red light. Since the central bright violet fringe combines with other fringes to form the white fringe, the next to it will be a minima for violet light. So violet will not be next to the central white fringe. Next will be a very thin band of white light minus violet light which will give a shade of off white. In this way, the components of indigo, blue, green, yellow and orange colors will be withdrawn respectively in the very thin consecutive bands. These will effect in different off white shades which cannot be clearly differentiated from the white band. The first color away from the center will be recognized as red when in these very thin bands yellow + orange + red, orange + red or red remains. Hence the option (d) is true.

Young's Double Slit Experiment with White light

The principle of homogeneity of dimensions states that “For an equation to be dimensionally correct, the dimensions of each term on LHS must be equal to the dimensions of each term on RHS.”

In fibre optics ,an optical phenomenon known as total internal reflection is used to transmit light rays. In case of the simplest form of optical fiber, light entering one end of the fiber strikes the boundary of the fiber and is reflected inward.

Explanation:In the first half of the cycle, power is supplied to the inductive circuit. In the next half the inductor dissipates the energy supplied by circuit.Thus overall no power is supplied to the circuit

In stationary position, spring balance reading  => mg = 49

Concept:

Central force:

• The central force in classical mechanics is defined as the force that is acting on an object which is directed along the line joining the object and the origin.
• The magnitude of the central force depends only on the distance of the object and the centre.
• Due to the central force, the body moves or tends to move in a circular or an elliptical orbit around an axis.
• Since there is no torque due to the central force. So, the angular momentum will remain constant.
• Some example of central forces is gravitational force and electrostatic force.

Explanation:

Let, r represents the distance of the particle from origin and r̂ is radial direction, than central force

F(r) = F(r)r̂ 

So the torque acting on it

τ = r × F(r)r̂

⇒ τ = r × F = F(r) (r × r)

⇒ τ = 0    ......(1)

Let p = mv = linear momentum,

Now we know that momentum is also conserved in this case, therefore

Angular momentum L = r × P

r.L = r.(r × p)  = 0     ......(2)

Also, to know angle b/w velocity and angular momentum

v.L = v.(r × p) = 0    .....(3)

Hence, from equation (2) and (3), we can see that both the position vector r  and the velocity vector v  thus lie in the plane perpendicular to  L.

Therefore, we can say that, if a particle moving under a central force, its motion will be in phase.

Energy is supplied to the damped oscillatory system at the same rate at which it is dissipating energy, and then the amplitude of such oscillations would become constant. Such oscillations are called maintained oscillations. By the definition of maintained oscillations.

Properties of Electric Field Lines. At every point on an electric field line, the tangent represents the direction of electric field. If two field lines cross each other at the point, then there would be two possible directions for electric field which is physically impossible.

There are 20 divisions in 4 cm of main scale
⇒ 1 cm of main scale will have 20/4 = 5 divisions

Thus,  1 MSD  = 1/5 = 0.2 cm Vernier scale has 10 divisions 
Thus, L.C. = 0.2/10 = 0.02 cm 

As the power of 10 is irrelevant in the determination of significant figures hence, the numbers of significant figures are 5 i.e. 9,4,6,0,5

ϕ=6t²−5t+1
e= dϕ​/dt =12t−5
at t=0.25sec
∣e∣=(12/4−5)=∣3−5∣=2
i=e/R=2/10=0.2A

Mass, m = 14.5 kg
Length of the steel wire, l = 1.0 m
Angular velocity, ω = 2 rev/s = 2 × 2π rad/s = 12.56 rad/s
Cross-sectional area of the wire, a = 0.065 cm² = 0.065 × 10^-4 m²
Let Δl be the elongation of the wire when the mass is at the lowest point of its path.
When the mass is placed at the position of the vertical circle, the total force on the mass is:
F = mg + mlω²
= 14.5 × 9.8 + 14.5 × 1 × (12.56)²
= 2429.53 N
Young’s modulus = Strss / Strain
Y = (F/A) / (∆l/l)
∴ ∆l = Fl / AY
Young’s modulus for steel = 2 × 10¹¹ Pa
∆l = 2429.53 × 1 / (0.065 × 10^-4 × 2 × 10¹¹)   =   1.87 × 10^-3 m
Hence, the elongation of the wire is 1.87 × 10^–3 m
Hence 1.87 × 10^–3 m

As we know time interval will have dimensions of time so check in option for dimension of time.
Dimensions of v is "per second" or [T^-1]

Velocity of efflux 

Find ‘h’ to have range of ejected water ≥ x x 

Both the objects with different masses will attain the same v when striking the ground because acceleration and height is the same. 
As, K.E=(1​/2)mv²P.E=−GMm​p/r=mv
Thus K.E, P.E, and p will be different.
 

Ultrasound waves are a type of a sound wave which is longitudinal in nature while others are electromagnetic waves because they are transverse in nature.

In liquids the current is carried by ions. Ions are charged particles (atoms or groups of atoms). Ions can either be positive or negative, the positive ions being attracted to the negative plate and the negative ions to the positive plate. A positive ion is a particle with some negative charge taken away and a negative ion is a particle with some extra negative charge added.

In the direction of electric field the electric potential decreases. This is because electric potential is the work done against the direction of the electric field.

Tension is uniformly transmitted if the springs are massless.

Field intensity is proportional to the inverse of the square of the distance separating the point charges:

F = k*q1*q2/d^2

Since k, q1, and q2 are assumed to be constant, their product can be combined to form a single constant:

K = k*q1*q2, so

F = K/d^2 (and by algebraic manipulation we have K=F*d^2).

Therefore we know that

F(at d=4) = K/4^2, and

F(at d=2) = K/2^2.

Since K is a constant, we can equate K=F*d^2 for each case:

K=F(at d=4)*4^2 = F(at d=2)*2^2

so

F(at d=2) = (F(at d=4)*4^2)/2^2

F(at d=2) = 200N/C * (4^2)/(2^2) = 200N/C *16/4 = 800N/C.

Work required to turn the dipole is given by
W=MB[cosθ_i- cosθ_f]
Here θi is the initial angle made by a dipole with a magnetic field and   is the final angle made by a dipole with a magnetic field.
magnetic moment is normal to the field direction.
so, θ_i=0 and θ_f=90
W = 1.5 × 0.22 [ cos0° - cos90° ]
W = 0.33J
 
magnetic moment is opposite to the field direction.
so, θ_i=0 and θ_f=180
now, W = 1.5 × 0.22 [ cos0° - cos180°]
= 0.33 [ 1 - (-1) ]
= 0.66 J

From the first law of thermodynamics,
we know, dU = dQ - dW ; (work done BY the system is considered +ve)
For an adiabatic process, dQ = 0, and hence, dU = -dW
For an ideal gas expansion, we see that work done
BY the system is +ve (recall the sign convention for work done), i.e., dW > 0.
Therefore, dU is less than 0, and thus, the internal energy decreases.

There is no current inside the pipe. Therefore