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AWES PGT Chemistry Mock Test - 4 - AWES TGT/PGT MCQ


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30 Questions MCQ Test - AWES PGT Chemistry Mock Test - 4

AWES PGT Chemistry Mock Test - 4 for AWES TGT/PGT 2024 is part of AWES TGT/PGT preparation. The AWES PGT Chemistry Mock Test - 4 questions and answers have been prepared according to the AWES TGT/PGT exam syllabus.The AWES PGT Chemistry Mock Test - 4 MCQs are made for AWES TGT/PGT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for AWES PGT Chemistry Mock Test - 4 below.
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AWES PGT Chemistry Mock Test - 4 - Question 1

Name the majority group of the Russian Social Democratic Workers Party led by Lenin?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 1

The correct answer is i.e. Bolsheviks.

Some facts about the Russian Socialist Democratic party(RSDP):

  • The formation was the party that happened in 1898.
  • The party followed Marxist ideas, believing the industrial working class, not peasants, would bring about revolution.
  • The party ideas were based on the philosophies of Karl Marx and Friedrich Engels, namely that despite Russia's agrarian life, the real radical potential extended with the industrial working class.
  • They played an important role in the politics of Russia at that time and they also won few seats in the elections.
  • It was mainly divided into two groups - Bolsheviks and Mensheviks.
  • The following table will help you to understand them better:
AWES PGT Chemistry Mock Test - 4 - Question 2

Recently, which institute hosted the International Chess Federation (FIDE) rated chess tournament?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 2

IIT Madras hosts the 6th Shaastra Rapid FIDE Rated Chess Tournament from March 30 to 31, 2024, in Chennai. It’s the sole IIT in India to conduct an annual Open Rapid Rating Tournament. Over 35 players from IIT Madras join, alongside international players from countries like Australia, England, America, and Singapore. Notable participants include six grandmasters, sixteen International Masters, three female grandmasters, and a Woman International Master.

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AWES PGT Chemistry Mock Test - 4 - Question 3

The First Cotton Textile Mill was established in India at

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 3

Key Points

In 1854, the first cotton mill was set up in Bombay and It grew as an important port for the export of raw cotton from India to England and China.

  • This cotton crop became a huge demand and farmers started investing in it.
  • Cotton turned the market upside down.
  • A huge number of labours started working in mills.
  • In Bombay, about 84 mills were established by Parsi and Gujarati businessmen by 1900.
  • The construction and development of mills in cities started and the first mill in Ahmedabad was started in 1861.
  • The growth of cotton mills demanded manpower.
  • Poor peasants, artisans, and agricultural labourers started working in the mills.
  • The textile industry of India faced problems such as difficulty competing with the cheap textiles imported from Britain.
  • In most countries, the government-supported industrialization by applying and imposing heavy duties on imports which eliminated competition and protected infant industries.
  • The first major spurt in the development of cotton factory production in India was during the First World War when textile imports from Britain were declined and Indian factories were called upon to produce cloth for military supplies.
AWES PGT Chemistry Mock Test - 4 - Question 4
When members of the same family become rulers one after the other, the family is called 
Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 4

The correct answer is Dynasty.

Key Points

  • When members of the same family become rulers one after the other, the family is called a dynasty.
  • An example of a dynasty is the Mauryan Dynasty.
  • Wherein, there were three important rulers- Chandragupta, his son Bindusara, and Bindusara's son Ashoka.
  • Alternative terms for dynasty are 'family', 'clan' etc.

 Thus, we can say that Dynasty is when members of the same family become rulers one after the other.

Additional Information

  •  Empire is a political construct in which one state dominates over another state or a series of states.
AWES PGT Chemistry Mock Test - 4 - Question 5
The state having the highest rainfall by North-East monsoon is_______________.
Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 5

The correct answer is Option(3).i.e.Tamil Nadu.

Key Points:

  • The state has the highest rainfall by North-East monsoon in Tamil Nadu. 
  • Nort-East Monsoon: 
    • The north-east monsoon, generally known as a monsoon of winter which blows from the land towards the sea and south-west monsoon is just the opposite, known as a monsoon of summer which blows from sea to land.
    • The North-East monsoon usually occurs within October to March, although it may change every year. 

 North-east monsoons are called as retreating monsoons

AWES PGT Chemistry Mock Test - 4 - Question 6

Which of the following statements is NOT correct in the context of teaching area- measurement of plane figures?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 6

"Use of formula for area-measurement should be taught before estimation of areas" is NOT correct in the context of teaching area- measurement of plane figures.

Measurement of plane figures: A plane, or flat, surface has two dimensions—length and width. The perimeter of a plane figure is the distance around it.

In the context of teaching area- measurement of plane figures correct statements:

  • Students should be given a chance to 'discover' the various formulae.
  • Grid paper can be a useful device for introducing and implementing the formal units of measurement.
  • Tessellations with regular shapes can be useful for teaching area measurement.

AWES PGT Chemistry Mock Test - 4 - Question 7

‘Choice of challenge’ is a characteristic of which of the following?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 7

‘Choice of challenge’ is a characteristic of motivation.

Motivation is the drive to achieve something in life that satisfies one’s needs. There are two primary types of motivation namely, intrinsic motivation and extrinsic motivation. A number of behavioural characteristics are indicators of high motivation. Here are some of the important factors and some ways to help a child develop these characteristics:

  • Persistence is the ability to stay with a task for a reasonably long period of time. While very young children cannot concentrate on one activity for an hour, there are still measurable differences in the length of time that young children will engage in an activity. A highly motivated child will stay involved for a long period of time, whereas an unmotivated child will give up very easily when not instantly successful.  Children learn persistence when they are successful at a challenging task.
  • Choice of challenge is another characteristic of motivation. Children who experience success in meeting one challenge will become motivated, welcoming another. These motivated learners will choose an activity that is slightly difficult for them but provides an appropriate challenge. Unmotivated children (those who have not experienced early success) will pick something that is very easy and ensures instant success.
  • The amount of dependency on adults is another indicator of motivation. Children with strong intrinsic motivation do not need an adult constantly watching and helping with activities. Children who have a lower level of motivation or are extrinsically motivated need constant attention from adults and cannot function independently.
  • The last indicator of motivational level is emotion. Children who are clearly motivated will have a positive display of emotion. They are satisfied with their work and show more enjoyment in the activity. Children without appropriate motivation will appear quiet, sullen and bored.

AWES PGT Chemistry Mock Test - 4 - Question 8

How does NEP 2020 address the issue of gender-based discrimination in education?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 8

NEP 2020 emphasizes providing equal opportunities for all genders and addressing gender-based discrimination in education.

AWES PGT Chemistry Mock Test - 4 - Question 9

Which of the following elements belongs to the same group as the element having configuration 1s2 2s2 2p1

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 9

The electronic configuration of B is 1s2 2s2 2p6 3s2 3p1 and the number of electron in last p orbital is 1 so it belongs to the same group as element with configuration (1s2 2s2 2p1).

AWES PGT Chemistry Mock Test - 4 - Question 10

A gas absorbs 200 J of heat and expands by 500 cm3 against a constant pressure of 2 x 105 Nm-2. Change in internal energy is 

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 10

The expression for the change in internal energy is given by,
ΔU=q+w
q = heat absorbed = 200 J
w = work done = −P x V
=−2×10⁵ × 500×10−6
= −100 N - m
ΔU=200−100J= 100 J
Hence, the correct option is C.

AWES PGT Chemistry Mock Test - 4 - Question 11

What does the following reaction shows about the structure of glucose?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 11

The correct answer is Option A.
 
Glucose gets oxidized to cyanohydrin in reaction with HCN . This indicates that the carbonyl group is present as an aldehydic group.

AWES PGT Chemistry Mock Test - 4 - Question 12

Identify the correct statements with reference to the given reaction 

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 12

P4 is undergoing oxidation as well as reduction. As oxidation number of P4 is 0 in reactant and it increases to +1 in H2PO2and decreases to -3 in PH3

AWES PGT Chemistry Mock Test - 4 - Question 13

Which of the following has incomplete octet?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 13


AWES PGT Chemistry Mock Test - 4 - Question 14

Dipole moment of   is 1.5 D. Thus, dipole moment 

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 14

 If one considers following molecule, it is 


Symmetrical and thus
In the given species

AWES PGT Chemistry Mock Test - 4 - Question 15

Which is the most likely product when the following iodide is heated with water?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 15


AWES PGT Chemistry Mock Test - 4 - Question 16

The electronic configuration of palladium is

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 16

[Kr]4d105s0

AWES PGT Chemistry Mock Test - 4 - Question 17

The enthalpy change when 1 mole of it dissolves in a specified amount of solvent is known as enthalpy of

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 17

Enthalpy of solution (ΔHsoln) is the change in enthalpy that occurs when a specified amount of solute dissolves in a given quantity of solvent.

AWES PGT Chemistry Mock Test - 4 - Question 18

Passing carbon dioxide through slaked lime gives:​

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 18

If CO2 is passed through slaked lime(calcium hydroxide Ca(OH)2), it gives out calcium carbonate (CaCO3) also called marble/limestone.

CO2 + Ca(OH)2→ CaCO3+ H2O

AWES PGT Chemistry Mock Test - 4 - Question 19

t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value. If the rate constant for a first order reaction is K, t1/4  can be written as –  

[AIEEE-2005]

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 19

The correct answer is option A
Let initial concentration be ao​
After concentration decreases by

Using first order kinetic equation,

AWES PGT Chemistry Mock Test - 4 - Question 20

The EAN of Ni in [Ni(CN)4]2-- is

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 20

EAN = 28 (Z) – 2 (oxidation number) + 2*4 (CN) = 34

Hence A

AWES PGT Chemistry Mock Test - 4 - Question 21

The standard reduction potential of a silver chloride electrode is 0.2 V and that of a silver electrode is 0.79 V. The maximum amount of AgCl that can dissolve in 106 L of a 0.1 M AgNO3 solution is          

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 21

AWES PGT Chemistry Mock Test - 4 - Question 22

Hydrogen peroxide is ______________ in nature.

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 22

One of the most important chemical properties of hydrogen peroxide i.e. H2O2 is that it is acidic in nature. It is weakly acidic in nature and pure hydrogen peroxide turns blue Litmus red (an indication of acidic nature).

AWES PGT Chemistry Mock Test - 4 - Question 23

 Which of the following amine will form stable diazonium salt at 273-283 K ?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 23

The correct answer is Option A.
Aromatic Primary amine will form the most stable diazonium salt because it releases water when it reacts with nitronium ions. If aliphatic primary amine reacts with nitrosonium ion it Also releases water but in this case water reacts with alkyl diazonium salt and it forms alcohol while benzene diazonium salt does not react with water at this temperature.

AWES PGT Chemistry Mock Test - 4 - Question 24

Amino acid are connected to each other by:

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 24

Peptide bonds are formed by a biochemical reaction that extracts a water molecule as it joins the amino group of one amino acid to the carboxyl group of a neighboring amino acid.

AWES PGT Chemistry Mock Test - 4 - Question 25

+ 4 ion of which has half-filled 4f subshell

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 25

Tb (Z = 65) have [Xe] 4f95d06s2 configuration. Tb4+ have half-filled 4f subshell, i.e. 4f7.

AWES PGT Chemistry Mock Test - 4 - Question 26

Mean bond enthalpy of different bonds are given

Out of the given pairs, which compound is more stable than the other?

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 26

)bond enthalpy > )bond enthalpy hence, is stable.


Bond enthalpy of six (P— P) bond = 6 x 215 = 1290 k j mol-1

Bond enthalpy of six (N — N) bond = 6 x 160
= 960 kJ mol-1
Thus, P4 is more stable than N4.

AWES PGT Chemistry Mock Test - 4 - Question 27

RNA is different from DNA because RNA contains:

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 27

DNA differs from RNA because DNA has deoxyribose sugar while RNA has ribose sugar. DNA has thymine as pyrimidine while, in RNA thymine is replaced by uracil.So, the correct answer is 'In the nature of sugar and pyrimidines'

AWES PGT Chemistry Mock Test - 4 - Question 28

Li and Mg both form chlorides which are:

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 28

Chlorides of both Li and Mg are deliquescent (absorb moisture from surroundings) and soluble in alcohol and pyridine. Lithium chloride, like magnesium chloride (MgCl2.6H2O) separates out from hydrated crystal LiCl.2H2O.

AWES PGT Chemistry Mock Test - 4 - Question 29

Consider the following elimination reaction,

When reaction is carried out with C2H5ONain ethanol, 2-menthene is the major product while 3-menthene is the major product if reaction is substrate is heated in ethanol only. It is due to

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 29

With strong base C2H5ONa, reaction proceeds by E2 mechanism. Since, there is no H in the anti position at tertiary β-carbon, deprotonation occur from secondary β-carbon giving 2-menthene as the major product. On the other hand, with weak base, reaction proceeds by E1 mechanism and the most stable tertiary carbocation formed, gives the major product 3-menthene.

AWES PGT Chemistry Mock Test - 4 - Question 30

Given



Q. Thus, heat of formation of CH3OH(/)is

Detailed Solution for AWES PGT Chemistry Mock Test - 4 - Question 30

Let's number our eqns-
CH3OH + 3/2 O2 → CO2 + 2H2O ...(1)
ΔH1 = –726 kJ/mol
C + O2 → CO2 ...(2)
ΔH2 = –393 kJ/mol
H2 + 1/2 O2 → H2O ...(3)
ΔH3 = –286 kJ/mol
Eqn(2) + 2×eqn(3) - eqn(1) :-
C + O2 + 2H2 + O2 + CO2 + 2H20→ CO2 + 2H20 + CH3OH + 3/2 O2
C + 1/2 O2 + 2H2 → CH3OH
Thus enthalpy of formation-
∆Hf(CH3OH) = ∆H2 + 2∆H3 - ∆H1
∆Hf(CH3OH) = -393 + 2(-286) + 726
∆Hf(CH3OH) = -239 kJ/mol

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