Chandigarh TGT Science - Non Medical Mock Test - 1 - SSA Chandigarh MCQ

Documents obtained through an RTI application by Tamil Nadu’s BJP chief K. Annamalai reveal India’s inconsistent approach to the Katchatheevu island dispute with Sri Lanka. Katchatheevu, a small island in the Palk Strait, lacks a permanent settlement and freshwater source. Administered by both India and Sri Lanka historically, a 1974 agreement marked its boundary. Indian fishermen, particularly from Tamil Nadu, face challenges due to conflicting claims over the island.

"Readiness for learning" refers to the cognitive level of students in the learning continuum. Readiness for learning means how a person seeks out knowledge on their own. This trait in students stimulates maximum achievement. Motivation, inspiration, or the dreams to accomplish a goal helps a lot to achieve this readiness for learning in life.
Hence, the correct answer is, 'Present cognitive level of students in the learning continuum.'

The process of socialization includes communicating with another person or a group of people. It involves actively listening to the other person and also effectively reverting the other person.

Playgrounds are essential safe spaces where children can be themselves and express their fun-loving nature while developing crucial cognitive, physical, social, and emotional skills.

The magnetic field from the centre of wire of radius R is given by
B = ((μ₀I)/(2R²))r (r < R) ⇒ B ∝ r
and B = μ₀I/2πr (r > R) ⇒ B ∝ 1/r
From this descriptions, we can say that the graph (b) is a correct representation.

Q = It also Q = ne [e = 1.6 × 10⁻¹⁹C]
∴ ne = It or
= 6.25 × 10¹⁸ electrons s⁻¹

The power of a lens is the reciprocal of the focal length with measurement in metres. The unit is diopter.

It is given that the focal length of a convex lens is 10 cm = 0.1 m.

⇒ The power of the lens is 1/0.1= 10 diopter.

From air to liquid:
1 ->air
2->liquid
 
n₁sinθ₁= n₂sinθ₂
1 x sin35^o=1.48sinθ₂
θ₂=arcsin((1xsin35o)/1.48)=22.8^o

Light is refracted when it crosses the interface from air into glass in which it moves more slowly. Since the light speed changes at the interface, the wavelength of the light must change, too. The wavelength decreases as the light enters the medium and the light wave changes direction

Mobility of charge carriers in a conductor is defined as the magnitude of their drift velocity per unit applied electric field.
Mobility,
μ=Drift of electric field
μ=V_dE
S.I. unit of mobility is m²Vs or ms NC.

 

Gamma rays are electromagnetic radiation (high-energy photons) with an extreme frequency and a high energy. They are created by the decay of nuclei as they travel from a high-energy state to a lower state; this process is called “gamma decay.” Most atomic responses are accompanied by gamma emission.

With a known resistance in one of the gaps, the meter bridge is used to determine the value of unknown resistance by the formula. 

When the light is incident at Brewster’s angle, the angle between the reflected ray and refracted ray is 90o, irrespective of the value of the refractive index.

∆H_{neutralisation} =  ∆H_H⁺ _{+ OH}- + ∆_rHionisation 
-5.1 = -57.3 + ∆H_ionisation
∆H_ionisation = 52.2 kJ mol^-1

Volume : 10 × 10 × 10^–2 = 1 cm³
mass of Cu = 8.94 g


= 27172 C

The sign of ΔG will change from positive to negative (or vice versa) where T = ΔH/ΔS. In cases where ΔG is: negative, the process is spontaneous and may proceed in the forward direction as written. positive, the process is non-spontaneous as written, but it may proceed spontaneously in the reverse direction.

(C_p)_mixture = (µ₁C_p1+µ₂C_p2+µ₃C_p3+.........)/µ₁+µ₂+µ₃+.........   where µ is the no of moles.
Or (C_p)_mixture = ƞ₁C_p1+ƞ₂C_p2+ƞ₃C_p3+.............  Where ƞ is the corr. mole fraction.
On putting the values, we have 
Cp_mixture= ( 7/2*0.8 +7/2*0.18 +4*0.02)R
=3.15R

Only when x = 0 and when x = 0 , y = 1. So, only at (0,1) tangent is parallel to x- axis.

Both  y² = x³ and |y| = 2x are symmetric about y – axis and on solving them we get :

ANSWER :- a

Solution :- Matrix equivalence is an equivalence relation on the space of rectangular matrices.

For two rectangular matrices of the same size, their equivalence can also be characterized by the following conditions

• The matrices can be transformed into one another by a combination of elementary row and column operations.

If a matrix B is obtained from matrix A by an elementary row or column transformation then B is said to be equivalent of A.​

y = 5 sin x - 11 cosx + 1/x²
dy/dx = 5 cosx - 11(-sinx) + (-2/x³)
= 5cosx + 11sinx - 2/x³

Since the number of terms is finite, just differentiate term by term using the power rule.
 dy/dx = 0 + 1 + 2x/2! + 3x2/3! + ... + nx^n-1/n!
dy/dx = 1 + x + x2/2! + ... + xn-1/(n -1)!
Compare dy/dx to y and note that the last term of y, which is xn/n!, is not in dy/dx, while all the other terms of y are in dy/dx.
Then dy/dx = y - xⁿ/n! 
⇒ dy/dx + xⁿ/n! = y

xy = 2
x dy/dx + y = 0
x dy/dx = -y
dy/dx = -y/x

 ∫(π/8 to π/4)1/(sin²x cos²x)
= ∫(π/8 to π/4)(sin²x + cos^2x)/(sin²x cos²x) dx
= ∫(π/8 to π/4)(1/cos²x +1/sin²x) dx
= ∫(π/8 to π/4)(sec² x dx + cosec² x dx)
= [tan x - cot x](π/8 to π/4) + c
= [tan(π/8) - tan(π/4)] - [cot((π/8) - cot(π/4)]
= ((2)^½ +1  - 1) - (1/(2)^½ +1 - 1)
= 2

As a and b are disjoint sets, they have no elements in common. Thus,
n(a∪b) = n(a) + n(b) 
→n(b) = n(a∪b) − n(a)
= 475 − 435
= 40