Chandigarh TGT Science - Non Medical Mock Test - 8 - SSA Chandigarh MCQ

Hence, Option B is correct.

Hence, Option A is correct.

• Dragging: This is the correct term used when you press and hold the left mouse key and move the mouse around the slide. It refers to the action of moving an object or selecting multiple objects by holding down the mouse button and moving the cursor.


• Highlighting: This term is not applicable in this context. Highlighting usually refers to the action of selecting text or a portion of text by changing its background color.


• Selecting: This term is also not specifically used to describe the action of pressing and holding the left mouse key and moving the mouse around the slide. Selecting typically refers to choosing or picking something from a list or group of items.


• Both (b) and (c): This option is incorrect because the correct term for pressing and holding the left mouse key and moving the mouse around the slide is only dragging. The term "selecting" is not accurate in this context.

Diversion: The act of turning aside or redirecting from a course or path, often to something more enjoyable or entertaining.
Deviation: The act of departing or straying from a standard or expected course; a divergence or deviation from the norm.

Answer: A
Explanation:

The analogy can be understood as follows:
- Hong Kong is a Special Administrative Region (SAR) of China.
- Vatican City, also known as the Holy See, is an independent city-state enclaved within Rome, Italy.

Therefore, the correct option to complete the analogy is:

Hong Kong : China :: Vatican : Rome

The Correct Answer is "C.V. Raman"

C.V. Raman was awarded the Bharat Ratna in 1954, the same year the award was established. He was one of the most prominent scientists in India, noted for his work in the field of light scattering. This work led to his discovery of the phenomenon, now called "Raman scattering," which earned him the Nobel Prize in Physics in 1930. He was the first Asian and first non-white person to receive any Nobel Prize in the sciences.

Alongside C.V. Raman, the first recipients of the Bharat Ratna in 1954 were politician C. Rajagopalachari and philosopher Sarvepalli Radhakrishnan.

Child development focuses on human beings. Mainly, psychologists wanted to know how humans grow and change every year by emotion, social growth, how they learn, how their minds work, etc.
Hence, the correct answer is "Humans".

The Ministry of Women and Child Development makes laws and regulations to take care of the women and child development in India.

• In child development, sequencing refers to the consistent order in which certain developmental milestones or abilities are typically acquired. While the sequencing of development tends to follow a predictable pattern, the speed at which children reach these milestones can vary between individuals.
• Individual action refers to the actions and behaviors of an individual child. Each child develops at their own pace, influenced by factors such as genetics, environment, and individual characteristics. Some children may reach developmental milestones earlier or later than average, and the rate of development can vary across different areas, such as cognitive, motor, social, or emotional development.

The correct option among the given choices is Individual action.

• The RTE Act was enacted in 2009 and came into effect in 2010.
• It guarantees the right of every child in the age group of 6 to 14 years to free and compulsory education in a neighborhood school.
• The Act also provides for a number of other safeguards, such as the prohibition of corporal punishment and the right to education for children with disabilities.

Hence, it can be concluded that Option (1) is the correct answer.

Potentiometer measures the potential difference using null deflection method, where no current is drawn from the cell; whereas voltmeter needs a small current to show deflection. So, accurate measurement of p.d is done using a potentiometer.

Tan(90-i)=14/11.2
Cot i=14/11.2
I=cot-1(14/11.2)
I=39.4^o

for concave mirror u=−7.5 ; f=−5
(1/v)+1/u=1/f
1/v-2/15=-1/5
i.e, image formed at pole of convex mirror for convex mirror, u=0;f=+5
(1/v)+1/u=1/f
(1/v)+1/0=1/5
V=0
So the final image is formed on a pole of a convex mirror.

Image formed is complete but has decreased intensity.

In a convex lens,  (1/v)−(1/u)=(1/f)​
Or (1/v)​−(1/f)​=(1/u)​ where u is always negative and f is always positive.
(1/v)​=(1/f)​−(1/u)​
So, as u is increased 1/u will decrease and  (1/f)​−(1/u)​  will increase, so, 1/v​ increases or v decreases.
So, its graph will be a hyperbola

The bright colors seen in an oil slick floating on water or in a sunlit soap bubble are caused by interference. The brightest colors are those that interfere constructively. This interference is between light reflected from different surfaces of a thin film; thus, the effect is known as thin film interference.

To convert temperature to voltage we can do a precise measurement of the temperature in a room. A NTC resistor or a thermistor
It is used as a sensor that has a strong temperature dependence.

When light moves from 1 medium to another, refraction takes place. And when light enters a denser medium, the ray bends away from normal and meets at a point above the actual point where they would have met, if the medium was absent. So, apparent depth decreases.

Cross -multiply by change in oxidation number and balance H by H⁺ ions.

Thus, x = 2, y = 5 and z = 6 

Mol. wt. of methane =16gm
Heat liberated during the combustion of 4gm methane = 2.5kcal
Heat liberated during the combustion of 16gm methane = 2.5/4×16=10kcal
Hence the heat of combustion of methane is 10 kcal.

Given :
P = 1 kW
P = 1 × 10³ watt
E = 10³ J/S in one sec
v = 880 Hz
∴ E = nhv
⇒  10³ x  ×  6.626 × 10^–34 × 880
⇒  x = 1.71 × 10³³ in one sec

For g orbital, value of l is 4.
(0 = s, 1 = p , 2 = d, 3 = f, 4 = g)
Since l = n - 1, n should be 5.

The correct answer is D. Both b and c.
One of the common disaccharides is sucrose which on hydrolysis gives an equimolar mixture of D−(+)− glucose and D−(−) fructose. These two monosaccharides are held together by a glycosidic linkage between Cl of α- glucose and C2 of β- fructose. Since the reducing groups of glucose and fructose are involved in glycosidic bond formation, sucrose is a non-reducing sugar.

Reduction potential of fe is more than that of cr, so fe will reduce and act as cathode and cr will act as anode. now emf of cell is reduction potential of cathode - reduction potential of anode. so EMF= -0.45-(-0.75) = 0.3 V

cos(sin^-1x)/(1-x²)^½……………….(1)
t = sin^-1 x
dt = dx/(1-x²)^½
Put the value of dt in eq(1)
= ∫cost dt
= sint + c
= sin(sin^-1 x) + c
⇒ x + c

Focus of parabola y² = 8x is (2,0). Equation of circle with centre (2,0) is (x−2)² + y² = r²
Let AB is common chord and Q is mid point i.e. (1,0)
AQ² = y² = 8x
= 8×1 = 8
∴ r² = AQ² + QS²
= 8 + 1 = 9
So required circle is (x−2)² + y² = 9

The scalar and vector components of the vector with initial point (2, 1) and terminal point (– 5, 7) is given by : (- 5 – 2) i.e. – 7 and (7 – 1) i.e. 6. Therefore, the scalar components are – 7 and 6 .,and vector components are 

Total students who took any of the subjects = 40 - x
Let x be the no. of students who took neither of the subjects
Then, 40 - x = 14 + 29 - 5
⇒ x = 2