Test:Fractions - 2 - CTET & State TET MCQ

Equivalent fraction of a given fraction is obtained by multiplying its numerator and denominator by the same number.

On cross-multiplication, we get 9 × 8 ×__ 15 × 16
72 < 240
∴ 9 / 16 < 15 / 8.

The required number

The numerator of a proper fraction is less than its denominator.

Five - eighteenth = 5 / 18.

Part of the cake Ravi had = 5 / 6
Part of the Ravi's cake eaten = 2 / 3
∴ Part of the cake eaten = 2 / 3 × 5 / 6 = 5 / 9

The required difference

Convert all fractions to those with the same denominators and compare their numerators.
∴ The fraction greater than 7 / 8 is 11 / 12.

Amount Manish had = Rs.45
Fraction of the amount spent = 35
∴ Amount left = 

Reciprocals of 9 and 2 / 9 are 1 / 9 and 9 / 2 respectively.
Their sum =

1 / 8 < 1 / 4. So, it should lie between 0 and 1.

On cancelling the factors common to numerator and denominator on both the sides,
          


Hence the missing number is 5.

The product of a fraction and its reciprocal is 1.

NO part os shaded hance correct answer will be- 0/8=0

Hence, there are 2 tenths in 
look only at Question part for number of tens

Score of Pavan = 76 = 4 / 5 of score of Prateek 4 / 5 → 76,
5 / 5 → 76 × 5 / 4
= 19 × 5 = 95
∴ Their total marks = 76 + 95 = 171.

Numerator + Denominator = 67
After adding 31 to the denominator, the numerator is 3 units and denominator is 11 units.
3 + 11 = 14 units = 67 + 31 = 98
∴ 1 unit = 98 ÷ 14 = 7
3 units = 3 × 7 = 21 and 11 units = 11 × 7 = 77
New fraction = 21 / 77
Hence, the original fraction