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Test: Data Handling - 3 - CTET & State TET MCQ


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10 Questions MCQ Test - Test: Data Handling - 3

Test: Data Handling - 3 for CTET & State TET 2024 is part of CTET & State TET preparation. The Test: Data Handling - 3 questions and answers have been prepared according to the CTET & State TET exam syllabus.The Test: Data Handling - 3 MCQs are made for CTET & State TET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Data Handling - 3 below.
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Test: Data Handling - 3 - Question 1

How many votes did chocolate get?

Detailed Solution for Test: Data Handling - 3 - Question 1

Chocolate got 8 votes. 

Test: Data Handling - 3 - Question 2

Directions: Given line graph represents the number of people in a store since its opening till closing at various times of a day.

Study the line graph and answer the questions given below:

What was the busiest time of the day at the store?

Detailed Solution for Test: Data Handling - 3 - Question 2

Option (b) is correct. The maximum number of people at the store were 40 at 1 pm. Therefore, the busiest time of the day at the store was 1 pm.

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Test: Data Handling - 3 - Question 3

Find the number of toys sold during the week.

Detailed Solution for Test: Data Handling - 3 - Question 3

One symbol represents 10 toys sold. 

So total symbols = 67

Toys sold = 67*10

= 670

Test: Data Handling - 3 - Question 4

How many more children voted for Puppet Street than voted for Beneath the Sea?

 

Detailed Solution for Test: Data Handling - 3 - Question 4

Children voted for Puppet Street = 5*2 = 10

Children voted for Beneath the Sea = 4*2 = 8

Difference = 10 - 8 = 2

Test: Data Handling - 3 - Question 5

Given pie chart represents the number of books on different subjects sold by a book seller.

Of which two subjects, the books sold by the book seller were equal in number?

Detailed Solution for Test: Data Handling - 3 - Question 5

Option (b) is correct. Seeing the pie chart, we find that Maths and English subjects represent two equal parts. Therefore, books of English and Mathematics were equal in number that were sold by the book seller.

Test: Data Handling - 3 - Question 6

Directions: Given bar graph represents the number of students of different classes of a school who participated in a competition.

Study the bar graph and answer the questions below:

How many more students of class IV participated in the competition in comparison to class III?

Detailed Solution for Test: Data Handling - 3 - Question 6

Option (b) is correct. Number of students of class III who participated = 10
Number of students of class IV who participated =60 Required difference = 60−10=50
Therefore, 50 more students of class IV participated in the competition in comparison to class III.

Test: Data Handling - 3 - Question 7

Directions: Given bar graph represents the number of students of different classes of a school who participated in a competition.

Study the bar graph and answer the questions below:

How many students of class II and class V altogether participated in the competition?

Detailed Solution for Test: Data Handling - 3 - Question 7

students of class II participated = 50

students of class V participated = 30

Total = 50 + 30 = 80

Test: Data Handling - 3 - Question 8

The ages in years of 10 teachers of a school are: 32, 41, 28, 54, 35, 26, 23, 33, 38, 40. What is the age of the youngest teacher?

Detailed Solution for Test: Data Handling - 3 - Question 8

Age of oldest teacher = 54 Years. Age of youngest teacher = 23 years.

Test: Data Handling - 3 - Question 9

Which flavor got 1 vote?

Detailed Solution for Test: Data Handling - 3 - Question 9

Blueberry got one vote only

Test: Data Handling - 3 - Question 10

Given pictograph represent the different number of plants that were planted by the students of school in a particular week.

What is the difference between maximum and minimum number of plants that were planted on two days in the week?

Detailed Solution for Test: Data Handling - 3 - Question 10

Option (b) is correct. Seeing the pictograph, we find that the maximum number of plants were planted on Wednesday = 8×15=120 and the minimum number of plants were planted on Tuesday =3×15=45.

Hence, the required difference = 120−45=75

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