EMRS Exam  >  EMRS Test  >   PGT Mock Test Series 2026  >  EMRS PGT Physics Mock Test - 10 - EMRS MCQ

EMRS PGT Physics Mock Test - 10 Free Online Test 2026


Test Description

30 Questions MCQ Test EMRS PGT Mock Test Series 2026 - EMRS PGT Physics Mock Test - 10

EMRS PGT Physics Mock Test - 10 for EMRS 2026 is part of EMRS PGT Mock Test Series 2026 preparation. The EMRS PGT Physics Mock Test - 10 questions and answers have been prepared according to the EMRS exam syllabus.The EMRS PGT Physics Mock Test - 10 MCQs are made for EMRS 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for EMRS PGT Physics Mock Test - 10 below.
Solutions of EMRS PGT Physics Mock Test - 10 questions in English are available as part of our EMRS PGT Mock Test Series 2026 for EMRS & EMRS PGT Physics Mock Test - 10 solutions in Hindi for EMRS PGT Mock Test Series 2026 course. Download more important topics, notes, lectures and mock test series for EMRS Exam by signing up for free. Attempt EMRS PGT Physics Mock Test - 10 | 150 questions in 180 minutes | Mock test for EMRS preparation | Free important questions MCQ to study EMRS PGT Mock Test Series 2026 for EMRS Exam | Download free PDF with solutions
EMRS PGT Physics Mock Test - 10 - Question 1

On which date is National Sports Day observed in India? 

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 1

The Correct Answer is Option 1 i.e 29th August.

  • National Sports Day is celebrated every year on 29th August.
  • It is celebrated to commemorate the birth anniversary of hockey legend Major Dhyan Chand.
  • On this day, President of India honors eminent sports personalities with major awards including Khel Ratna, Arjuna Awards, Dronacharya Awards, and Dhyan Chand Award.
  • Dhyan Chand: Born on August 29, 1905, Dhyan Chand is considered the greatest hockey player of all time.
    • Born in Uttar Pradesh, Chand earned three Olympic gold medals in 1928, 1932 and 1936 in field hockey.
    • He was conferred the Padma Bhushan award.
EMRS PGT Physics Mock Test - 10 - Question 2

Ravi goes 40 km to North, then turns right and walks 50 km then again turns right and walks 30 km, then again turns right and walks 50 km. Now how many km away is he from his original position ? 

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 2

According to the information given in the question, we can draw the following diagram.

AC = 40 km
BC = 30 km
AB = AC - BC
AB = 40 - 30
AB = 10 km
Ravi is 10 km away from his starting point.
Hence, the correct answer is "10 km".

EMRS PGT Physics Mock Test - 10 - Question 3

Rohit walked 30m towards South, took a left turn and walked 50m, again he took a left turn and walked 30m. How far is he from the starting point?

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 3

i) Rohit walked 30m towards South.
ii) Took a left turn and walked 50m
iii) Again he took a left turn and walked 30m.
Drawing the Diagram as per the given information:

AB = CD = 50m
Thus we can see he is 50m far from the starting point.
Hence, the correct answer is "50m".

EMRS PGT Physics Mock Test - 10 - Question 4

Which answer figure will complete the pattern in the question figure?

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 4

EMRS PGT Physics Mock Test - 10 - Question 5

An Excel workbook is a collection of:

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 5

A workbook is a collection of one or more spreadsheets and charts in a single file.

EMRS PGT Physics Mock Test - 10 - Question 6

Which toolbar allows you to enter values and formulas?

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 6
The Formula Bar
The toolbar that allows you to enter values and formulas in various software applications, such as Microsoft Excel, is called the Formula Bar. It is a crucial component of spreadsheet programs that enables users to input and edit data in cells.
Key features of the Formula Bar:
- Input Box: The Formula Bar consists of an input box where you can enter values, numbers, and formulas.
- Cell Selection: It displays the reference of the currently selected cell, making it easy to identify and locate specific cells.
- Formula Editing: You can directly edit formulas in the Formula Bar by selecting the desired cell and making changes in the input box.
- AutoComplete: The Formula Bar often provides autocomplete suggestions, which can enhance efficiency and accuracy when entering complex formulas.
- Error Display: If there is an error in a formula, the Formula Bar may display an error message, allowing you to identify and correct the issue.
Advantages of using the Formula Bar:
- Accuracy: The Formula Bar ensures precise data entry by allowing users to enter formulas and calculations directly.
- Efficiency: It provides a centralized location for entering and editing data, saving time and effort.
- Visibility: The Formula Bar makes it easy to view and modify formulas, improving overall spreadsheet comprehension and management.
Therefore, the Formula Bar is an essential toolbar that facilitates the input and manipulation of data, formulas, and calculations in spreadsheet applications like Microsoft Excel.
EMRS PGT Physics Mock Test - 10 - Question 7

What is the small triangle which draws lines on the logo screen called?

EMRS PGT Physics Mock Test - 10 - Question 8

Which of the following sentences is true about learning?

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 8

Learning is effective in an environment that is emotionally positive and satisfying to learners. Any learner who is emotionally unstable may not be able to learn anything. The teacher must make the environment conducive for students to study and learn efficiently.
Errors made by the students do not indicate that no learning has taken place. Instead, they are the windows through which a teacher can understand the thought process of the students.
Learning is affected by emotional factors at any stage. Emotions change over time as the child matures, and in response to changing environmental interactions. The kind of learning that takes place at different emotional levels also differs.
Learning involves physical, social and emotional activity also.

EMRS PGT Physics Mock Test - 10 - Question 9

Naresh loves to work without supervision and set goals that are challenging, but not impossible. He learns best in solitude.
Which of the following sentences is true about Naresh?

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 9

Naresh loves to work without supervision and set goals that are challenging, but not impossible. He learns best in solitude; thus he is a intrapersonal learner. The intrapersonal learners, as opposed to interpersonal, are the ones who work and learn best when they are alone.
They are also motivated by internal forces, rather than external ones. So, Naresh is motivated by internal forces.

EMRS PGT Physics Mock Test - 10 - Question 10

All of the following are the characteristics of an effective teacher except

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 10

As a student goes through his/ her academic career, attitudes about subject matter can be strongly influenced by a teacher's attitude about that particular student. If a student receives positive feedback from teachers then the student will probably try harder, which should translate into more academic success. If a student is being unfairly singled out because a teacher has a hidden bias, then success becomes increasingly difficult, and it becomes hard to keep that student positively motivated. However, an effective teacher should have the same attitude towards every student and cannot give differential treatment to different students.

EMRS PGT Physics Mock Test - 10 - Question 11

The numerical ratio of average velocity to average speed is:

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 11
  • When an object is moving along a straight path, the magnitude of average velocity is equal to the average speed.
  • Therefore, the numerical ratio of average velocity to average speed is one in a straight line motion.
  • But, during curved motion, the displacement < distance covered, so the velocity < speed.

Therefore, the numerical ratio of average velocity to average speed is equal to or less than one but can never be more than one. 

EMRS PGT Physics Mock Test - 10 - Question 12

Identify the law which is used to find out the direction of eddy currents.

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 12
  • Eddy currents are the currents induced in solid masses when the magnetic flux threading through them changes.
  • Eddy currents also oppose the change in magnetic flux, so their direction is given by Lenz’s law.
EMRS PGT Physics Mock Test - 10 - Question 13

Hole is

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 13

Concept of holes in the semiconductor:

  1. When an electron is removed from a covalent bond, it leaves a vacancy behind. An electron from a neighbouring atom can move into this vacancy, leaving the neighbour with a vacancy. In this way the vacancy formed is called a hole (or cotter), and can travel through the material and serve as an additional current carriers.
  2. A hole is considered as a seat of positive charge, having magnitude of charge equal to that of an electron.
  3. Holes acts as a virtual charge, although there is no physical charge on it.
  4. Effective mass of hole is more than an electron.
  5. Mobility of hole is less than an electron.
EMRS PGT Physics Mock Test - 10 - Question 14

The physical properties of electromagnetic waves are decided by their

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 14

Electromagnetic waves vary in wavelength and frequency. Longer wavelength electromagnetic waves have lower frequencies, and shorter wavelength waves have higher frequencies. Higher frequency waves have more energy.

EMRS PGT Physics Mock Test - 10 - Question 15

A non-planar loop of conducting wire carrying a current I is placed as shown in the figure. Each of the straight sections of the loop is of length 2a. The magnetic field due to this loop at the point P(a, 0, a) points in the direction

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 15

NOTE : If we take individual length for the purpose of calculating the magnetic field in a 3-Dimensional figure then it will be difficult.
Here a smart choice is divide the loop into two loops.
One loop is ADEFA in y-z plane and the other loop will be ABCDA in the x – y plane.

We actually do not have any current in the segment AD. By choosing the loops we find that in one loop we have to take current from A to D and in the other one from D to A. Hence these two cancel out the effect of each other as far as creating magnetic field at the concerned point P is considered.
The point (a, 0, a) is in the X-Z plane.
The magnetic field due to current in ABCDA will be in + ve Z-direction.

NOTE : Due to symmetry the y-components and xcomponents will cancel out each other.
Similarly the magnetic field due to current in ADEFA will be  in x-direction.

∴ The resultant magnetic field will be

EMRS PGT Physics Mock Test - 10 - Question 16

A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 16

At null point (and along the axis), earth's magnetic field and bar's magnetic field are opposite in direction.
On the equatorial line, the bar's magnetic field is opposite in direction to its field on the axis. Hence, on the equatorial line, the two fields add up.
As the null points are on the axis of the bar magnet, therefore,
B1= (μ0/4π)(2M/d3)=H
On the equatorial line of magnet at same distance(d), field due to the magnet is 
B2= (μ0/4π)(M/d3)=B1/2=H/2
Therefore, total magnetic field at this point on equatorial line is 
B=B2+H=3H/2=3×0.36G/2=0.54G
 

EMRS PGT Physics Mock Test - 10 - Question 17

Find the frequency of small oscillations of a thin uniform vertical rod of mass m and length L hinged at the point O as shown in the figure. The stiffness of each spring is k. Mass of the springs is negligible. The figure shows equilibrium position.

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 17

EMRS PGT Physics Mock Test - 10 - Question 18

Light of wavelength 500 nm is incident on a slit of width 0.1 mm. The width of the central bright line on the screen is 2m. What is the distance of the screen?​

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 18

Beta(central Maxima) = 2 * lambda * D(distance of the screen) / d(distance between slits)
beta = 2 m, wavelength = 500nm = 5 ×10-7m & d = 0.1mm = 1×10-4m
► 2 = 2 × 5 × 10-7 * D/10-4
► 1 = 5 × 10-3
► D = 1000/5
► D = 200m

EMRS PGT Physics Mock Test - 10 - Question 19

Two independent monochromatic sodium lamps can not produce interference because

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 19

Two sources of light are said to be coherent if they emit light which always has a constant phase difference between them. It means that the two sources must emit radiations of the same wavelength. The two independent sources cannot be coherent because of the fact that independent sources cannot maintain a constant phase difference between them. For experimental purposes, two virtual sources obtained from a single parent source can act as coherent. In such a case, all the random phase changes occurring in the parent source are repeated in the virtual sources also, thus maintaining a constant phase difference between them. Since the wavelength of light waves is extremely small, the two sources must be narrow and must also be close to each other.
Interference can never be obtained with two independent sources of light, such as two bulbs or two candles, due to the fact that any two independent beams of light are always incoherent.
 

EMRS PGT Physics Mock Test - 10 - Question 20

Electric flux density is a function of _______.

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 20

Electric flux density is the charge per unit area. Hence it is a function of charge and not any of the other values.

EMRS PGT Physics Mock Test - 10 - Question 21

Davisson and Germer experiment proves the

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 21

The Davisson-Germer experiment demonstrated the wave nature of the electron, confirming the earlier hypothesis of deBroglie. Putting wave-particle duality on a firm experimental footing, it represented a major step forward in the development of quantum mechanics. The Bragg law for diffraction had been applied to x-ray diffraction, but this was the first application to particle waves.

EMRS PGT Physics Mock Test - 10 - Question 22

A body of mass 2 kg rests on a rough inclined plane making an angle 30o with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 22

The body is at rest on the inclined plane, as μ > tan θ  force of friction = mg sin 30o = 2 x 9.8 x (1/2) = 9.8 N  

 

EMRS PGT Physics Mock Test - 10 - Question 23

Binding energy per nucleon is the ratio of

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 23

Binding energy per nucleon is the ratio of the binding energy of a nucleus to the number of the nucleons.

Binding energy per nucleon = (Total binding energy) / (Number of nucleon)

Measure of stability of the nucleus: Larger the binding energy per nucleon, the greater the work that must be done to remove the nucleon from the nucleus, the more stable the nucleus.

EMRS PGT Physics Mock Test - 10 - Question 24

One kilometer is equal to how many miles?

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 24

for an approximate result, divide the length value by 1.609

► One kilometer is equals to 0.62 miles.

EMRS PGT Physics Mock Test - 10 - Question 25

The mutual inductance has unit of-

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 25

The unit of inductance in the SI system is the henry (H), named after American scientist Joseph Henry, which is the amount of inductance which generates a voltage of one volt when the current is changing at a rate of one ampere per second.

EMRS PGT Physics Mock Test - 10 - Question 26

A teacher should make an attempt to understand the potentialities of his/her students. Which of the following fields is related to this objective?

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 26

A teacher makes an attempt to understand the potentialities of his/her students it is related to Educational Psychology. Educational Psychology is considered as the branch of psychology that deals with the scientific study of human learning. The study of learning processes takes place from both behavioural and cognitive perspectives, allows experimenters to know about the individual differences in cognitive development, intelligence.
Hence, the correct answer is, 'Educational Psychology.'

EMRS PGT Physics Mock Test - 10 - Question 27

There is a dire need to promote diversity in the educational institutions because of

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 27
  • Globalization of Education is the integration and application of similar education systems and knowledge throughout the world across borders, improving the quality & deployment of education worldwide.
  • Globalization has also led to increasing multiculturalism in societies.
  • Multiculturalism promotes change and inclusion in attitudes.
  • Societies that promote cultural diversity are viewed as more global and open-minded than societies that promote monoculture.
  • For instance, economies and societies which promote monoculture are not as progressive and globalized as societies that promote multiculturalism.
  • Diversity not only allows different kinds of people to come together, but it also brings various functions into a city, consequently enhancing globalization. 

Therefore we can conclude that There is a dire need to promote diversity in educational institutions because of the globalization of education.

EMRS PGT Physics Mock Test - 10 - Question 28
“पुत्री का विवाह करके अजय के माता-पिता आज गंगा नहा लिए”। रेखांकित मुहावरे का अर्थ है-
Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 28

दिए गए विकल्पों में से सही उत्तर विकल्प 1 'कार्य से निवृत्त होना’ है। अन्य विकल्प इसके गलत उत्तर हैं।

Key Points

  • मुहावरा- गंगा नहाना
  • अर्थ - ​कार्य से निवृत्त होना
  • वाक्य - हर कोई अपना काम करके गंगा नहाने की चाह रखता है।
  • अन्य विकल्प अनुचित हैं।


अन्य विकल्प:


Additional Information

  • मुहावरा का शाब्दिक अर्थ ‘अभ्यास’ है।
  • मुहावरा शब्द अरबी भाषा का शब्द है।
  • हिन्दी में ऐसे वाक्यांशों को मुहावरा कहा जाता है, जो अपने साधारण अर्थ को छोड़कर विशेष अर्थ को व्यक्त करते हैं।
EMRS PGT Physics Mock Test - 10 - Question 29

“भगवान श्रीराम के अयोध्या लौटने पर प्रजा ने खुशियाँ मनाई थी।” वाक्य में रेखाँकित शब्द के लिए सही मुहावरा है-

Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 29

विकल्प घी के दिए जलाना सही है।

Key Points
  • घी के दिए जलाना
    • अर्थ: खुशियाँ मनाना
    • वाक्य प्रयोग: भगवान श्रीराम के अयोध्या लौटने पर प्रजा ने घी के दिए जलाए थे।

Additional Information

  • घाव पर नमक छिड़कन
    • अर्थ: दुखी को और दुखी करना
    • वाक्य प्रयोग : वह अनुत्तीर्ण होने के कारण पहले दुखी है, तुम जली – कटी सुनाकर उसके घाव पर नमक छिड़क रहे हो।
  • घोड़े बेचकर सोना
    • अर्थ : निश्चित होना
    • वाक्य प्रयोग: दिन-भर थकने के बाद मजदूर रात को घोड़े बेचकर सोते हैं।
  • चाँद पर थूकना
    • अर्थ:निर्दोष पर दोष लगाना
    • वाक्य प्रयोग: अरे, उस संत-महात्मा पर व्यभिचार का आरोप लगाना चाँद पर थूकना है ।
Important Points
  • अन्य उदाहरण
  • झोली भरना
    • अर्थ – भरपूर प्राप्त होना
  • टाँग अड़ाना
    • अर्थ – अड़चन डालना
  • टका सा जबाब देना
    • अर्थ – साफ़ इनकार करना
  • टस से मस न होना
    • अर्थ – कुछ भी प्रभाव न पड़ना
  • टोपी उछालना
    • अर्थ – निरादर करना
EMRS PGT Physics Mock Test - 10 - Question 30
दिए गए चार विकल्पों में से, उस विकल्प का चयन करें जो नीचे दिए मुहावरे का अर्थ व्यक्त करता है।
​आँखों में धूल झोंकना
Detailed Solution for EMRS PGT Physics Mock Test - 10 - Question 30

आँखों में धूल झोंकना का अर्थ 'धोखा देना'।

Key Points

  • आँखों में धूल झोंकना- धोखा देना या झांसा देना
  • वाक्य प्रयोग- सरकारी नौकर अपना कार्य न करके सरकार की आँखों में धूल झोंकना रहें हैं।

अन्य विकल्प-

  • ढा़ढ़स बंधाना- तसल्ली देना
  • वाक्य प्रयोग- मोहन का व्यापार में लगा पैसा डूब गया तो सोहन ने उसे समझाते हुए उसका ढाढ्स बधांया।
  • आँख फोड़ना- बड़े ध्यान से पढ़ना
  • वाक्य प्रयोग- परीक्षा के समय श्याम बहुत ध्यान से पढ़ता है।
  • आदर देना- सम्मान करना।
  • वाक्य प्रयोग- हमेशा बड़ो को आदर देना चाहिए।

Additional Information​महत्वपूर्ण मुहावरे-

  • आग लगने पर कुँआ खोदना- पहले से कोई उपाय न कर रखना।
  • अढ़ाई चावल की खिचड़ी अलग पकाना- सबसे अलग सोच-विचार रखना
  • कलम तोड़ना- बहुत सुन्दर लिखना।
  • कौड़ी को भी न पूछना- निकम्मा होना।
  • काफूर होना- भाग जाना।
View more questions
8 docs|45 tests
Information about EMRS PGT Physics Mock Test - 10 Page
In this test you can find the Exam questions for EMRS PGT Physics Mock Test - 10 solved & explained in the simplest way possible. Besides giving Questions and answers for EMRS PGT Physics Mock Test - 10, EduRev gives you an ample number of Online tests for practice
Download as PDF