SSA Chandigarh TGT Math Mock Test -7 - SSA Chandigarh MCQ

The size of an organization chart object
The size of an organization chart object refers to its dimensions and can be adjusted in PowerPoint.
Options:
- Option A: Is determined by the presentation design and cannot be changed.
- Option B: Is determined by the presentation design but can be changed in PowerPoint.
- Option C: Is dependent on the amount of text within the organization chart.
- Option D: Both (b) and (c).

The correct answer is Option D, which means that the size of an organization chart object can be changed in PowerPoint and is also dependent on the amount of text within the organization chart. Here's why:
- The size of an organization chart object is not solely determined by the presentation design. While the initial size may be influenced by the design template, it can be adjusted manually in PowerPoint.
- PowerPoint allows users to resize and scale objects, including organization chart objects. This flexibility enables users to customize the size of the object according to their specific needs and preferences.
- Additionally, the size of the organization chart object can also be influenced by the amount of text within it. If the chart contains a large amount of text, it may require a larger size to accommodate all the information effectively.
- Conversely, if the chart has minimal text or fewer levels, it may be possible to reduce the size of the object without compromising readability or clarity.
In summary, the size of an organization chart object can be changed in PowerPoint, and it can also vary depending on the amount of text within the chart.

Page footing is:
A: Same as report heading
- This option is incorrect as page footing is not the same as the report heading.
B: The labels printed at the end of each page
- This option is correct. Page footing refers to the labels or information that is printed at the bottom of each page.
C: The labels printed at the end of each control group
- This option is incorrect as page footing is not specific to control groups.
D: The labels printed at the end of a report
- This option is incorrect as page footing is not limited to the end of a report.
In summary, the correct answer is B: The labels printed at the end of each page. Page footing refers to the labels or information that is printed at the bottom of each page.

Explanation:
The correct answer is B:

Dos

. DOS (Disk Operating System) is not a requirement of the internet. Here is a detailed explanation of why each of the other options is a requirement:
A: Operating System
- An operating system is required to run the necessary software and manage hardware resources on a computer. It provides the foundation for running internet-related applications and services.
C: Web browser
- A web browser is essential for accessing and viewing websites on the internet. It interprets HTML, CSS, and JavaScript code to display web pages and allows users to navigate through different websites.
D: Modem
- A modem is used to connect a computer or other device to the internet. It converts digital data from the computer into analog signals that can be transmitted over telephone lines or other communication channels. The modem at the receiving end then converts the analog signals back into digital data.
In summary, while an operating system, web browser, and modem are all requirements for accessing and using the internet, DOS is not necessary for internet connectivity.

Hence, the correct ans is UIJOL which is option b.

Learning disabilities may occur due to all of the following except cultural factors as they do not affect learning disability.

For Vygotsky, although biological factors constitute the necessary pre-requisite for elementary processes to emerge, socio-cultural factors are indispensable for elementary natural processes to develop. He argues for the uniqueness of the social milieu and regards socio-cultural settings as the primary and determining factor in the development of higher forms of human mental activity such as voluntary attention, intentional memory, logical thought, planning, and problem solving.

In our life, we try to learn new things from our family first. Then when we come into society, that leads us to learn different things from different perspectives. Social development is when we learn or develop ourselves by practising or experiencing new things from society.
Hence, the correct answer is "Social development".

When the children do new things that they did differently from what they did before, creativity, creativity is a skill that helps children to enhance their skills of thoughts, ideas, feeling, etc. It's just that they make new things on their own. Creativity is something kids like when they play or make connections for different reasons.
Hence, the correct answer is "Play".

A function is a relation in which no two ordered pairs have the same first element. A function associates each element in its domain with one and only one element in its range. R={(1,2), (1,4)(3,1),(5,1)} is not  a function because all the first elements are not different.

Above information has no common element in three of them and U of three sets forms sample set . Therefore option C is correct.

If 2/7 is probability of event A then the probability of an event not A is 1-(2/7) i.e.,    probability of not A is 5/7

In linear programming problems the optimum solution satisfies a set of linear inequalities (called linear constraints) .

Option D: The number of relations from A to B is 2^3*2= 2⁶

A(3,4,−1) and  B(2,−1,5)

Vector AB is normal to the required plane 
⇒ Directions of normal (−1,−5,6)
∴ Equation ,−x−5y+6z=k
Point (2,−3,1) passes through the plane,
∴ −2+15+6=k⇒k=19
∴ −x−5y+6z = 19
x+5y−6z+19 = 0

As the two lines intersect, we must have


∴Point of intersection is (a + a ', b + b ', c + c ')
⇒ (B) is correct   

From the given question, by using Pythagoras theorem, we get,

We need to find 
⇒AB² + BC² + CD² + DE²  
By putting the value from the equation (1), we get,
⇒ AC² + CD² + DE²
⇒ By putting the value from the equation (2), we get,
⇒ AD2 + DE²
By putting the value from the equation (3), we get,
⇒ AE²
Hence, the correct answer is AE².

6cot+2cosec=cot+5cosec
6cot-cot=5cosec-2cosec
5cot=3cosec
5cos/sin=3/sin
cos=3/5

Height of the triangle = √(13² – 12²) = 5 meters


Hence, Option A is correct.

Since, the point, where the perpendicular bisector of a line segment cuts, is the mid-point of that line segment. 
∴ Coordinates of Mid-point of line segment AB = 

f ‘ (x) = 2x – 2 = 2 (x - 1) < 0 if x < 1 i.e. x x∈ (−∞,1) x∈ (−∞,1). Hence f is strict decreasing in left decreasing in (−∞,1)

tan 1 . tan 2 . tan 3 ... tan 87 . tan 88 . tan 89 = LHS 
tan 1 . tan 2 . tan 3 ... tan (90 - 3 ) . tan ( 90 - 2 ) . tan ( 90 - 1)
tan 1 . tan 2  . tan 3 ... cot 3 . cot 2 . cot 1 

tan 1 . cot 1 . tan 2 . cot 2 . tan 3 . cot 3 ... tan 89 . cot 89 
1 x 1 x 1 x 1 x ... x 1 
As 1ⁿ = 1  = RHS 

Since the graph cuts the lines y = -1 and y = 1 , therefore ,it must cut y = 0 atleast once as the graph is a continuous curve in this case.

Hence, y = (1-0) - ( -1 -1) -(0 - 1) = 4

sinA - sinB = 2cos(A+B)/2 sin(A-B)/2
sin 35 – sin55 = 2cos(35+55)/2 sin(35-55)/2
= 2cos45 (-sin10)
= 2(√2/2) (-sin10)
= -√2 sin10

Variance is the mean of the squares of the deviations from the mean. Variance is the square of standard deviation. Therefore any unit of a given set is converted into squares at the time of calculating the variance.

Since g(x) and h(x) are integrals of the same function , therefore ; g(x) – h(x) is constant.

w’(z) = [(2-z)dy/dz(3z+9)- (3z+9)dy/dz(2-x)]/(2-z)²
[(2-z)(3) - (3z+9)(-1)]/(2-z)²
(6-3z+3z+9)/(2-z)²
= 15/(2-z)²