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Bihar STET Paper 1 Mathematics Mock Test - 1 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar STET Paper 1 Mathematics Mock Test - 1

Bihar STET Paper 1 Mathematics Mock Test - 1 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT/TGT/PRT preparation. The Bihar STET Paper 1 Mathematics Mock Test - 1 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 1 Mathematics Mock Test - 1 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 1 Mathematics Mock Test - 1 below.
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Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 1

The perimeter (in cm) of a square circumscribing a circle of radius a cm, is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 1

Side of a square circumscribing a circle of radius a cm = diameter of circle = 2a cm
∴ Perimeter of the square = 4 x 2a = 8a cm

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 2

The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are complementary. The height of the tower is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 2

Given AB is the tower.

P and Q are the points at distance of 4m and 9m respectively.

From fig, PB = 4m, QB = 9m.

Let angle of elevation from P be α and angle of elevation from Q be β.

Given that α and β are supplementary. Thus, α + β = 90

In triangle ABP,

tan α = AB/BP – (i)

In triangle ABQ,

tan β = AB/BQ

tan (90 – α) = AB/BQ (Since, α + β = 90)

cot α = AB/BQ

1/tan α = AB/BQ

So, tan α = BQ/AB – (ii)

From (i) and (ii)

AB/BP = BQ/AB

AB^2 = BQ x BP

AB^2 = 4 x 9

AB^2 = 36

Therefore, AB = 6.

Hence, height of tower is 6m.

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Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 3

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 3


Taking LCM

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 4

ABCD is a cyclic quadrilateral in which AC and BD are its diagonals. If angle DBC = 55° and angle BAC = 45°, the measure of angle BCD is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 4

∵∠BAC and ∠BDC are in the same segment.

∴ ∠BAC=∠BDC=45

Now in ΔBCD, ∠DBC+∠BDC+∠BCD=180∘ (Sum of angles of a triangle)

⇒55+45+∠BCD=180

⇒100+∠BCD=180

⇒∠BCD=180−100∘ = 80

Hence, ∠BCD=80

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 5

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): If the nth term of an A.P. is 7 – 4n, then its common differences is – 4.

Reason (R): Common differences of an A.P. is given by d = an + 1 – an

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 5
We are given, an = 7 – 4n

Also, an + 1 = 7 – 4(n + 1) = 7 – 4n – 4 = 3 – 4n

d = a(n + 1)–an

= 3 – 4n – 7 + 4n = – 4

Therefore, Both A and R are true and R is the correct explanation for A.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 6

The number of line segments determined by three collinear points is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 6

if the points are collinear then only 1 line can pass through 3 points  as colinear mean the points which are on same line.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 7

If a > b and b > c, then,

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 7
As a>b and b>c it means that a >b>c obviasly a >c is corrrect answer.
Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 8

Three face cards of spade are removed from a well shuffled pack of 52 cards and a card is drawn from the remaining pack. The probability of getting a black face card is​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 8

Three face cards from spades have been removed.
Total cards=52-3=49
Total No of black face cards=3+3(3 in each spades and clubs)
Remaining black face cards=6-3=3
Probability of getting black face card=  no. of favourable outcomes/ total no. of outcomes=3/49

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 9

The sum of a two digit number and the number obtained by reversing the order of the digits is 187. If the digits differ by 1, then what will be the number?
 

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 9

Answer: c
Explanation: Let the two digit number be 10x+y
The number obtained after reversing the digits will be 10y+x
10x+y+10y+x=187
11x+11y=187
x+y=17     (1)
Also, x-y=1     (2)
Adding (1) and (2)
2x=18
x=9
Substituting in equation (1), 9+y=17
y=8
The number is 89 or 98.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 10

The total number of propositions in the Euclid’s Elements are

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 10

In the thirteen books that comprise Euclid's Elements there is a total of 465 propositions.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 11

The volume of the largest right circular cone that can be cut out from a cube of edge 4.2 cm is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 11

The volume of the largest right circular cone that can be cut out from a cube of edge 4.2 cm is 19.404 cm3.


Edge of the cube = 4.2 cm

i.e 2r = 4.2

r = 4.2/2 = 2.1 cm

h = 4.2 cm

Volume of the cone = 1/3 * pi * r2 * h

=> 1/3 * 22/7 * 2.1 * 2.1 * 4.2

=> 19.404 cm3

Hence, the volume of the largest right circular cone that can be cut out from a cube of edge 4.2 cm is 19.404 cm3.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 12

A fair die is cast in the game of ‘Ludo’. The probability of getting a score greater than 6 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 12

A fair dice has number 1,2,3,4,5,6 only . So there are no number greater than 6
No. of favourable outcomes=0
Total no. of outcomes=6
Probability of getting no. higher than 6=No. of favourable outcomes/Total no. of outcomes=0/6=0
 

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 13

The value of 

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 13

We have Mean = 

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 14

Read the following text and answer the following questions on the basis of the same:

Rahul and Ravi planned to play Business (board game) in which they were supposed to use two dice.

Ravi got the first chance to roll the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is 8?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 14
The outcomes when two dice are thrown together are

= (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Total outcomes = 36

No. of outcomes when the sum is 8 = 5

Probability = 5/36

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 15

If the common difference of an A.P. is 5, then the value of a20 − a13 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 15

Given: a20 - a13 and d = 5
⇒ a20 - a13 = a + (20 - 1) d - [a + (13 - 1) d] = a + (20 - 1) x 5 - [a + (13 - 1) x 5]
⇒ a20 - a13 - a = a + 95 - [a + 60]
= a+95 - a - 60 = 35 

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 16

Which of the following is a solution of the equation 4x + 3y = 16?​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 16

Given equation is :

4x + 3y = 16

Putting x = 1 and y = 4 

4 .1 + 3. 4 = 16

4 + 12 = 16

16 = 16 

So option D is the correct answer.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 17

One card is drawn from a deck of 52 cards. The probability of drawing a black card is​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 17

We have total cards = 52
4 categories=spades,clubs,diamonds and hearts
Spades and clubs are black cards
No. of favourable outcomes=13+13=26
Probability of getting a black card= no. of favourable outcomes/total no. of outcomes
=26/52=1/2

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 18

How many bags of grain can be stored in a cuboid granary 12 m x 6 m x 5 m. If each bag occupies a space of 0.48 m3 ?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 18

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 19

A cubic polynomial is a polynomial with degree

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 19

A cubic polynomial is a polynomial of degree 3. A univariate cubic polynomial has the form f(x) = a3 x3 + a2 x2 + a1 x + a0. An equation involving a cubic polynomial is called a cubic equation. A closed-form solution known as the cubic formula exists for the solutions of an arbitrary cubic equation.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 20

Solution of a quadratic equation x²+ 5x + 6 = 0

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 20

x2 + 5x + 6 = 0
=x2 + 3x + 2x + 6 = 0
= x(x + 3) + 2(x + 3) = 0
= (x + 3) (x + 2) = 0
= x + 3 = 0 and x + 2 = 0
= x = -3 and x= -2

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 21
Which is not found in the symptoms of emotional disturbances of adolescents?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 21

Childhood refers to the period of the human lifespan, ranging from birth to puberty. It consists of many developmental stages and 'adolescence' is one of them.

  • 'Adolescence' comes from the Latin word 'Adolescere' which means 'to grow to become mature'. It a stage which lies between the age of '12 to 19 years'.
  • Emotion is a mental state associated with fearangerlove, etc. Emotional states of an individual are the combination of physiological arousal, psychological appraisal, and behavioral changes.
  • Emotionally disturbed children can be defined in terms of certain observable characteristics such as withdrawn behavior, failure to achieve a level reasonably commensurate with ability or tendency towards fighting, and other aggressive behavior.

Key Points

Emotional disturbances of adolescents:

  • They show the same emotions as they used to show in their childhood  i.e., fear, disgust, but the emotions of adolescence are different in their patterns.
  • The emotions at this stage are more uncontrolled, intensive, and irrational.  As they gradually grow, their emotional behavior improves and become mature.
  • Children who suffer from emotional disturbances generally do nail-biting, thumb sucking, depression, pulling or stretching of hairs, fear of specific objects or things, etc.
  • A child wearing a well-fitted dress is not a symptom of emotional disturbance but wearing proper clothes that fit them well makes them confident.

Hence, it could be concluded that wearing a well-fitted dress is not found in the symptoms of emotional disturbances of adolescents.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 22

To make the students learn rhymes more effectively, a primary class teacher should use

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 22

Tape recorder can be used as a teaching aid by primary class teachers to teach the sounds of birds and animals to the students, make them learn rhymes, or make them hear important historical speeches.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 23

The way in which students bring their finding to others and apply their understanding to new and unfamiliar circumstances grows out of

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 23

The way in which students bring their finding to others and apply their understanding to new and unfamiliar circumstances, grows out of excitement for what they have accomplished. Student would be excited to reveal his finding.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 24

Learning disabilities in Mathematics can be assessed most appropriately by which of the following tests?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 24

Learning disabilities in Mathematics can be assessed most appropriately by the diagnostic test. 
A diagnostic test is a test that is used to measure the level of understanding a student possess regarding any subject area. Teachers conduct diagnostic tests for reading and maths skills and use these results to provide remedial instructions or classes to students as per their level.
Hence, the correct answer is, 'Diagnostic Test.'

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 25

Suppose you are teaching at the primary level. You often see that the students give a response which is correct to a certain extent. In such case, what would be your duty as a teacher?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 25

The teacher must provide ask a few more questions on the same topic, so that the student arrives at the exact correct answer. The student thus would be left with a lasting impression and hence will not forget it for long time.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 26
National Education Policy (2020) recommends pedagogies which are _______.
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 26

The NEP 2020 emphasizes the need for a learner-centric pedagogy that focuses on the individual needs and interests of each learner. It calls for a shift away from traditional teacher-centric methods that focus on rote learning and memorization.

Key Points

The NEP 2020 recommends a number of pedagogies that are learner-centric, including:

  • Active learning: Active learning is a type of learning in which students are actively engaged in the learning process. This can be done through activities such as discussion, problem-solving, and hands-on learning.
  • Inquiry-based learning: Enquiry-based learning is a type of learning in which students are encouraged to ask questions and to explore their own understanding of a topic. This can be done through activities such as research, experimentation, and collaboration.
  • Project-based learning: Project-based learning is a type of learning in which students work on a real-world problem or project. This can help students to apply their knowledge and skills in a meaningful way.
  • Innovative pedagogy: Innovative pedagogy is a pedagogy that is constantly evolving and adapting to the needs of learners. It is based on the understanding that there is no one-size-fits-all approach to learning.

Hence, we can conclude that the National Education Policy (2020) recommends pedagogies that are learner-centric.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 27

A teacher is said to be research minded when

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 27

A teacher who changes the method of teaching according to the students and requirements is said to be research minded. This is a very good quality of a teacher by which he/she involves students by engaging them with different interests. A teacher who is always thinking about something may be introspecting but not research minded.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 28

In the QS World University Rankings 2024, what is IIT Bombay's global ranking in engineering?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 28

IIT Bombay is ranked 45th globally in engineering according to the QS World University Rankings 2024, highlighting its excellence in the field and its leading position in South Asia.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 29

What is the shape of the Indian Ocean?  

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 29

The Indian Ocean is the third-biggest on the planet and makes up roughly 20% of Earth's water surface shaped like that of a triangle. It is limited by southern Asia in the north, the Arabian Peninsula and Africa in the west, the Malay Peninsula, Sunda Islands and Australia in the east and the Southern Ocean in the south.

Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 30

Select the number which can be placed at the sign of the question mark (?) from the given alternatives.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 1 - Question 30

The logic followed is:

middle number = sum of the bottom number - top number

In fig 1:

10 = (7 + 9) - 6

10 = 16 - 6

10 = 10

In fig 2:

10 = (5 + 8) - 3

10 = 13 - 3

10 = 10

Similarly,

? = (9 + 6) - 4

? = 15 - 4

? = 11 

Hence, the correct answer is "11".

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