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Bihar STET Paper 1 Mathematics Mock Test - 2 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar STET Paper 1 Mathematics Mock Test - 2

Bihar STET Paper 1 Mathematics Mock Test - 2 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT/TGT/PRT preparation. The Bihar STET Paper 1 Mathematics Mock Test - 2 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 1 Mathematics Mock Test - 2 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 1 Mathematics Mock Test - 2 below.
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Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 1

Given that sinθ = a/b then cos θ is equal to

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 1

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 2

If p(x) = ax2 + bx + c and a + c = b, then one of the zeroes is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 2

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Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 3

The class mark of class interval 60 – 70 will be

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 3
class mark = [lower class interval + upper class interval]/2

= (60+70)/2

= 130/2

= 65 

(if the intervals are of uniform width)
Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 4

Direction: In the following questions, a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements, mark the correct answer as

Assertion : Two diameters of a circle intersect each other at right angles. Then the quadrilateral formed by joining their end-points is a square.

Reason : Equal chords subtend equal angles at the centre.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 4

Let AB and CD be two perpendicular diameters of a circle with centre O.

Now, ∠ABC = 90º

[Angle in semicircle is a right angle]

Similarly ∠ACD = ∠ADC

= ∠BAD = 90º ...(1)

In ΔAOB and ΔAOD, we have

AO = AO (Common)

∠AOB = ∠AOD (Each 90º, given)

BO = OD (Radii of circle)

ΔAOB ≅ ∠AOD(By SAS congruence)

AB = AD (By C.P.C.T.)

Similarly, we have,

AD = DC , DC = BC; BC = AB

Hence, AB = BC = CD = DA ...(2)

Also, it is given that diagonals of ABCD intersect at

90º ...(3)

By (1), (2) and (3) ABCD is a square.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 5

The ratio between the LCM and HCF of 5,15, 20 is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 5

Factors are following:
5 = 5 x 1
15 = 5 x 3
20 = 2 x 2 x 5

LCM = 5 x 3 x 2 x 2 = 60
HCF = 5
Ratio = LCM/HCF = 60/5 = 12/1 = 12:1

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 6

Sum and the product of zeroes of the polynomial x2 +7x +10 is 

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 6

x2 + 7x + 10 = (x + 2)(x + 5)

So, the value of x2 + 7x + 10 is zero when x + 2 = 0 or x + 5 = 0

Therefore, the zeroes of x2 + 7x + 10 are –2 and –5.

Sum of zeroes = -7 = –(Coefficient of x) / (Coefficient of x2)

Product of zeroes = 10 = Constant term / Coefficient of x2

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 7

The probability that a non leap year selected at random will contain 53 Sunday's is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 7

A non-leap year has 365 days

A year has 52 weeks. Hence there will be 52 Sundays for sure.

52 weeks = 52 x 7 = 364 days .

365– 364 = 1 day extra.

In a non-leap year there will be 52 Sundays and 1day will be left.

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, friday, Saturday, Sunday.

Of these total 7 outcomes, the favourable outcomes are 1.

Hence the probability of getting 53 sundays = 1/7.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 8

If the length of a shadow cast by a pole is √3 times the length of the pole, then the angle of elevation of the sun is​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 8

Let AB be the tree and AC be its shadow.


Let ∠ACB = θ

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 9

What is the sum of the first 50 multiples of 3?​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 9

sum=n/2x(2a+(n-1)d )
       =50/2(2x3+ (50-1)3 )
       = 25 ( 6+49x3 )
       = 25x 153
       = 3825

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 10

The graph of the polynomial f(x) = 2x – 5 intersects the x – axis at 

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 10

If The graph of the polynomial f(x) = 2x – 5 intersects the x – axis then y = 0 
2x−5 = 0 ⇒ x = 5/2

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 11

One Angle of a quadrilateral is of 108 and the remaining three angles are equal. Find each of the three equal angles.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 11

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 12

Which of the following is true –

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 12

Mean = Mode + 3/2 [Median – Mode]
Mean= Mode+3/2 Median-3/2Mode
2 Mean=2 Mode+3 Median-3 Mode
3 Median=2 Mean + Mode
So C is the correct answer.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 13

If x + 2 is a factor of x3 – 2ax2 + 16, then value of a is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 13

use factor theorem as x+2 is factor of
x³-2ax²+16 so put x = -2 and equate the equation to 0
so putting x = -2
(-2)³-2a(-2)²+16 =0
-8-8a+16=0
-8a = -8
a = 8/8= 1
So,
a = 1

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 14

The angle between two altitudes of a Parallelogram through the vertex of an obtuse angle of the Parallelogram of 60. Find the angles of the Parallelogram

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 14

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 15

An electric pole is 10√3 m high and its shadow is 10m in length, then the angle of elevation of the sun is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 15

Let AB be the electric pole of height 10√3 m and its shadow be BC of length 10 m And the angle of elevation of the

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 16

ABCDEF is any hexagon with different vertices A, B, C, D, E and F as the centres of circles with same radius r are drawn. The area of the shaded portion is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 16

Internal angles of a regular Hexagon = 120°

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 17

The angle between the bisectors of two adjacent supplementary angles is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 17


Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 18

Read the following text and answer the following questions on the basis of the same:

Aniket is studying in X standard. He is created a pole at on the boundary of a circular park of diameter 17 m in such a way that the difference of its distances from two diametrically opposite fixed gates A and B on the boundary is 7m.

Q. Find a quadratic equations in variable x for above situation.
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 18
Let the distance of the pole from the gate B be x i.e. BP = x cm.

Therefore, AP = x + 7 m Now, AB = 17 m and since AB is a diameter.

Apply Pythagoras theorem,

AB2 = AP2 + BP2

172 = (x + 7)2 + x2

289 = x2 + 49 + 14x + x2

x2 + 7x – 120 = 0

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 19

If a hemi-spherical dome has an inner diameter of 28 m, then its volume (in m3) is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 19

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 20

Two alarm clocks ring their alarms at regular intervals of 50 seconds and 48 seconds. If they first beep together at 12 noon, at what time will they beep again for the first time?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 20

LCM of 50 and 48 = 1200
∴ 1200 sec = 20 min
Hence at 12.20 pm they will beep again for the first time.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 21

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 21

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 22

If the point (5,0), (0-2) and (3,6) lie on the graph of a polynomial. Then which of the following is a zero of the polynomial?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 22

We obtain zeros of the polynomial when y=0. Observing the points we see that we have point (5,0) which means when y=0 , x= 5 this means x=5 is a solution of the polynomial.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 23

The HCF of 2472, 1284 and a third number N is 12. If their LCM is 23 x 32 x 5 x 103 x 107, then the number N is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 23

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 24

_________ is the study of cognitive development that is concerned with basic mechanics of learning.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 24

The behavioristic approach focuses on the mechanics of learning.

  • Behaviorist approach is the study of cognitive development that is concerned with the basic mechanics of learning. Learning - changes in behavior because of experiences (excluding changes due to fatigue, injury, or drug effects), is at the center of this approach.
  • The central tenet of behaviorism is that an organism learns behavioral adaptation, whose learning is governed by the principles of association (forming connections between ideas and events).
  • Behaviorism stands apart from other approaches by its emphasis on the relationship between observable behavior (responses) and environmental events (stimuli).

Behaviorism or the behaviorist approach lays stress on the role of environmental stimuli in determining the way we act. Behaviorism is also referred to as behavioristic psychology.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 25

Which of the following is the most important factor underlying the success of a new teacher?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 25

The communication ability of a teacher helps her to establish a rapport with the students. A teacher who is a good communicator can understand the dilemma of students, and can effectively solve their problems.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 26

According to NEP 2020, what is the recommended medium of instruction for foundational education?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 26

NEP 2020 recommends the use of the mother tongue or local language as the medium of instruction for foundational education.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 27

Howard Gardner's theory of multiple intelligences emphasizes:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 27

Howard Gardner's theory of multiple intelligences emphasizes the unique abilities of each individual that removes the idea of valuing intelligence as a single general ability for all. According to him, the learners should not be restricted to one modality of learning. As per his theory, intelligence is a physiological ability of processing information, activated in a cultural setting to reach the specific solution of a problem.
Hence, the correct answer is, 'The unique abilities of each individual.'

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 28

The factor that helps a teacher to solve problems like backwardness, cheating, indiscipline, and improper environment is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 28

Educational psychology is a must for solving problems like backwardness, cheating, indiscipline, and improper environment. It is the branch of psychology which is applied to the field of education and studies the behaviour of students in educational settings.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 29

Who is known as the "Father of Microbiology"?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 29

Antonie Van Leeuwenhoek was a Dutch scientist who is credited with being the first person to observe and describe microorganisms using a microscope. He made his microscopes, which were far more powerful than any that had been made before. Van Leeuwenhoek's discoveries revolutionized our understanding of the microscopic world and laid the foundation for the field of microbiology.

Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 30

Narayan Murthy walking at a speed of 20 km/h reaches his college 10 minutes late. Next time he increases his speed by 5 km/h, but finds that he is still late by 4 minutes. What is the distance ofhis college from his house?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 2 - Question 30

By increasing his speed by 25%, he will reduce his time by 20%. (This corresponds to a 6 minute
drop in his time for travel—since he goes from being 10 minutes late to only 4 minutes late.)
Hence, his time originally must have been 30 minutes. Hence, the required distance is 20 kmph ×
0.5 hours = 10 km.

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