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Bihar STET Paper 2 Chemistry Mock Test - 3 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar STET Paper 2 Chemistry Mock Test - 3

Bihar STET Paper 2 Chemistry Mock Test - 3 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT/TGT/PRT preparation. The Bihar STET Paper 2 Chemistry Mock Test - 3 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 2 Chemistry Mock Test - 3 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 2 Chemistry Mock Test - 3 below.
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Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 1

The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 1

as oxygen is more electronegative than Cl,Br and I. So they have positive oxidation state.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 2

                                                  Passage I

A constant current of 30 A is passed through an aqueous solution of NaCl for a time of 1.00 h.

Thus Cl2 formed under STP condition is 

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 2

At anode 2Cl- —-±>Cl2+2e-
At cathode 2Na+ +2e- ——-> 2Na.
So 2 Faraday of electricity is required to liberate 1 mole = 22.4 liters of Cl2 at STP.
Amount of current passed
= 30 x 60 x 60=108000 coulombs.
So 108000 coulombs will liberate =108000/(96500 x2) = 0.5596 moles Cl2.
No.of liters of Chlorine liberated at STP
= 0.5596 x 22.4 = 12.53 liters.

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Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 3

Which of the following elements has the largest ionisation enthalpy?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 3

Ionisation energy increases along a period. The very next elements C,N,O,F results F with higher ionisation energy.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 4

Yellow colour of NaCl crystals in sodium vapour is due to

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 4
  • This yellow colour is due to metal excess defect of anionic valency.
  • Na+ion deposited on the surface of crystal of NaCl . The Cl-ion diffused to form NaCl. This happens by loss of electron from Na to Na+.
  • The released electro diffused into the crystal and occupy anionic site called F center which imparts yellow colour to NaCl.
Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 5

A sub-shell with n = 6 , l = 2 can accommodate a maximum of

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 5

n = 6, l = 2 means 6d → will have 5 orbitals. 

∴ max 10 electrons can be accommodate as each orbital can have maximum of 2 electrons. 

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 6

According to Bohr's theory, the angular momentum of an electron in 5th orbit is -        [AIEEE 2006]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 6

 

The angular momentum (mvr) of electron in nth orbit is equal to nh/2π
For the electron in 5th orbit

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 7

Consider the following reaction,

 

Q. 

The correct statement concerning I and II is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 7

This is an example of E1 reaction and more substituted alkene (I) is formed as the major product.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 8

Which of the following is the strongest Lewis base?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 8

Correct Answer :- D

  • Lewis bases need to be able to donate electrons. Fluorine is the most electronegative element in the halogens followed by chlorine, bromine and iodine. 
  • Due to fluorine being strongly electronegative, it draws the electron density towards itself which makes it difficult for nitrogen atom to donate its lone pair of electrons. So, NF is the least basic. This trend follows the strength of electronegativity of the halides. 
  • Since iodine is least electronegative, it is the most basic trihalide of nitrogen.

So, we have the trend, in decreasing order of basic strength:

NF3 < NCl3 < NBr3 < NI3

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 9

Uncertainty in position of a particle of 25 g in space is 10-5 m. Hence uncertainty in velocity (ms-1) is (Planck's constant h = 6.6 × 10-34 Js)                                                            [AIEEE- 2002]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 9

∆p×∆x = h/4π
Or ∆v = h/4π∆xm      (since p = mv)
=6.6×10-34Js/4×3.14×25×10-3kg ×10-5 
by solving this your answer is 2.1×10-28

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 10

The metal that can not be obtained by electrolysis of an aqueous solution of its salt is

[JEE Main 2014]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 10

In electro chemical series (ECS),

thus, Ca2+ ion is not reduced to C a instead, H2O is reduce d to H2

Ag, Cu and Cr are below H in ECS (E°reduction > 0), thus they are reduced to metals on electrolysis.

Note In ECS, Ca, H, Cr, Cu elements lying above H are better reducing agents thus are easily oxidised.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 11

If equilibrium constant of

CH3COOH + H2 CH3COO- + H3O+

Is 1.8 × 10-5, equilibrium constant for

CH3COOH + OH-  CH3COO- + H2O is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 11

Ka = 1.8 × 10–5
CH3COO + H2 CH3COOH + OH-
Given reaction is reverse of above

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 12

Correct IUPAC name of the following compound is :

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 12

The correct answer is option D
The IUPAC name for the given compound is:
3-Bromo-4-(hepta-2,4,6-trienyl)cyclopenta-2,4-dien-1-oll
according to the rule of nearly attached halogen count first.so we count the the chain where bromo is near
 

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 13

Which among the following is an instantaneous reaction?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 13

Precipitation of AgCl is an example of instantaneous reaction.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 14

Glucose solution is one molal. Glucose present in 1 kg glucose solution is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 14

Glucose solution is one molal. Thus, 1000 g water (solvent) has glucose = one mole = 180 g

Total mass of solution = 1000 +180 = 1180 g

1180 g of solution has glucose = 180 g 

∴ 1000 g of solution has glucose =
180 x 1000/1180 = 152.5 ≈ 153g  

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 15

Consider the following reaction 2A + 3F2 → 2AF3.

What is the formula for the reaction product if we substitute iodine for fluorine?​

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 15

We know that Fluorine has a charge of -1 which then means 'A' has to have a charge of +3. I got that from the AF3. If Iodine is substituted for Fluorine, the answer should be B. AI3 because Iodine also has a charge of -1. Although the actual answer should be 2AI3 because Iodine is also a diatomic element which would give us the reaction 2A+ 3I2 >>> 2AI3.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 16

Number of chiral centers are:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 16


Number of chiral centers = 2

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 17

 Benzene and toluene form nearly ideal solutions. At 20ºC, the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial pressure of benzene at 20ºC for a solution containing 78 g of benzene and 46 g of toluene in torr is

[AIEEE-2005]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 17

The correct answer is Option B.
 
The molar mass of benzene is 78 g
 
The molar mass of toluene is 92 g
 
nBen = 78/78 =1

nTol = 92/46 = 0⋅5

XBen = 1 / 1+0⋅5

        = 1⋅5

PBen = XBenP0Ben
             = (1/1⋅5) × 75
            =​  50

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 18

According to Werner’s theory , the primary valences of the central atom

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 18

Primary valency is equal to no. of ligands attachted which are negatively charges.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 19

An element has configuration 4d55s2. The element belongs to

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 19

Ford-block elements, group number is equal to the number of electrons in (n - 1)d subshell + number of electrons in valence shell (nth shell).

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 20

An aqueous solution is 6% methanol, CH3OH, by mass with d = 0.988 g mL-1. Thus, molarity of CH3OH in this solution is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 20

 (d) Aqueous 6% methanol solution by mass means 100 g of aqueous solution has = 6g CH3OH

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 21

'If you are given 100 rupees, what will you do?' The objective of asking this type of question is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 21

'If you are given 100 rupees, what will you do?' The objective of asking this type of question is to give place to child's experience and thinking. The child will think how he can use 100 rupees judiciously and take into account his previous experience in doing so. Through the use of 100 rupees the priorities of the child will reflect which he/she gained from the past experiences. There can be a child who believes more in saving the money or there may be some who prefer spending. Hence the thinking of the child can reflect.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 22

A classroom having ______, clearly shows that the classroom studies are lively.

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 22

A lively classroom is the one having frequent student-teacher discussions. This is the two-way teaching method.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 23

"A young child responds to a new situation on the basis of the response made by him/ her in a similar situation as in the past". This is related to:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 23

The response of a young child on the basis of the past situation is related to the 'Law of Analogy' of learning. 
The 'Law of Analogy' principle was developed by Edward Thorndike. According to him, an individual makes use of old experiences while learning a new situation. The way young child did he identified the similarities between the past situation and the present one.
Hence, the correct answer is, 'Law of Analogy' of learning.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 24

Which of the following is a significant cause for the failure of a teacher?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 24

Excessive strictness is a negative trait that can lead to resistance in students. The teacher must strive to create an atmosphere where the students can learn without fearing of being ridiculed or belittled. They need an environment which is safe to learn by their mistakes.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 25

The sounds th, ph, ch are:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 25

The sounds th, ph, ch are phonemes. The phoneme is the unit of sound.  A phoneme combines with other phonemes to give rise to meaningful words. Phonemes distinguish one word from another. These are established by the use of minimal pairs, such as pat vs bat or tap vs tab.
Hence, the correct answer is, 'Phonemes.'

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 26
Institutional initiative for inclusive education can be evidenced when ______.
Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 26

Inclusive Education means education for all children in school as It refers to the inclusion of all children in the education system, regardless of their differences and disabilities.

  • It values the diversity, each child brings to the classroom and facilitates all with equal opportunities to learn and grow.
  • Inclusive education improves the quality and making provisions of education for all. >Inclusive education welcomes and celebrates diversity.
  • It provides a provision to include disabled children along with normal children in a regular classroom environment.
  • It refers to an education system that accommodates all children regardless of their physical, intellectual, social, emotional, linguistic, or other conditions.

Key Points

Basic Principles of Inclusive Education:

  • Equity and equal opportunities for all.
  • Well constructed educational plan.
  • Use of multilingualism as a resource.
  • Use of specific pedagogical strategies.
  • Sensitization towards individual differences.

Important Points

Institutional initiative for inclusive education can be evidenced when :

  • Time is provided for teams of teachers and paraprofessionals to plan together
  • A differentiated curriculum is designed
  • School provides students to explore different co-curricular activities as per their interests.

Additional Information

  • Entry-level tests to enroll students should not be supported according to NCF
  • School should have differentiated material for all students
  • Instead of common assessments, assessments as per the need of learners should be conducted.

Hence, we can say that institutional initiative for inclusive education can be evidenced when time is provided for teams of teachers and paraprofessionals to plan together.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 27

Learners are asked to listen to a set of five sentences from their Environmental Studies textbook as the teacher reads out the sentences twice. Then the learners are asked to discuss in their groups to recall/recreate the sentence, not necessarily the exact sentence, but nearer to the sentences read out. What is this task known as?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 27

This task is known as paragraph dictation.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 28
Where is the largest reserves of manganese in India?
Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 28

Manganese is one of the important raw materials used for smelting iron ore.

Important Points

  • Manganese is used for making alloys.
  • It is used in manufacturing of enamel, dry cell batteries, plastics, chemicals and glasses.
  • It requires almost 10 kg of manganese to manufacture one tonne of steel.
  • Odisha is the largest producer of manganese in India with multiple mines located over the iron ore belt of India.
  • Some of the major mines are Bonai, Kendujhar, Sundergarh, Gangpur, Koraput, Kalahandi, and Bolanger.
  • After Odisha, Karnataka, Maharashtra, Telangana, Goa, and Jharkhand lies in the list of manganese producer in India.
  • In 2000-2001, Odisha produced one-third of the country's total production.

Thus, we can conclude that Odisha is the largest producer of manganese.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 29

In the QS World University Rankings 2024, what is IIT Bombay's global ranking in engineering?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 29

IIT Bombay is ranked 45th globally in engineering according to the QS World University Rankings 2024, highlighting its excellence in the field and its leading position in South Asia.

Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 30

Select the number which can be placed at the sign of the question mark (?) from the given alternatives.

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 3 - Question 30

The logic followed is:

middle number = sum of the bottom number - top number

In fig 1:

10 = (7 + 9) - 6

10 = 16 - 6

10 = 10

In fig 2:

10 = (5 + 8) - 3

10 = 13 - 3

10 = 10

Similarly,

? = (9 + 6) - 4

? = 15 - 4

? = 11 

Hence, the correct answer is "11".

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