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NEET Exam  >  NEET Test  >  Topic-wise MCQ Tests  >  Test: Collisions - NEET MCQ

Collisions - Free MCQ Practice Test with solutions, NEET


MCQ Practice Test & Solutions: Test: Collisions (10 Questions)

You can prepare effectively for NEET Topic-wise MCQ Tests for NEET with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Collisions". These 10 questions have been designed by the experts with the latest curriculum of NEET 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Collisions - Question 1
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A bomb of mass 4 kg explodes in air into two pieces of masses 3 kg and 1 kg. The smaller mass goes at a speed of 90 m/s. The total energy imparted to two fragments is.

Detailed Solution: Question 1

By conservation of momentum we get the speed of the bigger part let say, v = 1 x90 / 3
Hence we get v = 30
Thus the total KE of the system after collision is ½ (3 X 900 + 1 X 8100)
Thus KE = ½ (10800) = 5400
Now  if we apply WET to the system, as no external force has acted upon it, we get
W = ΔKE
= 5400 - 0
= 5.4 kJ

Test: Collisions - Question 2
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In an elastic collision in one dimension if a body A collides against the body B of equal mass at rest, then the body A will

Detailed Solution: Question 2

Since collision is elastic and mass is same then after velocity exchange A body will stop and B will start moving with A's velocity in the same direction.

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Test: Collisions - Question 3
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Which physical quantity is conserved during both elastic and inelastic collision?

Detailed Solution: Question 3

Momentum is conserved in all types of collision whether it is elastic or inelastic where as kinetic energy is lost in sound energy in the absence of external force in inelastic collision.

Test: Collisions - Question 4
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A moving white hockey puck collides elastically with a stationary red hockey puck on a frictionless horizontal surface. No net external force acts on the two-puck system. Select all of the following statements that must be true for this elastic collision.

1. The kinetic energy of the white puck is conserved (same before and after the collision)
2. The linear momentum of the white puck is conserved.
3. The linear momentum of the two puck system is conserved.

Detailed Solution: Question 4

  1. In an elastic collision, both kinetic energy and linear momentum are conserved

  2. The white puck is moving and collides with the stationary red puck. Therefore, the kinetic energy of the white puck before the collision is not necessarily conserved individually, but the total kinetic energy of the system (both pucks) is conserved

  3. The linear momentum of the white puck alone is not conserved because it is involved in the collision. However, the total linear momentum of the two-puck system is conserved since there are no external forces acting on it

  4. Based on the analysis:

    • Statement (1) is false because the kinetic energy of the white puck alone is not conserved
    • Statement (2) is false because the linear momentum of the white puck alone is not conserved
    • Statement (3) is true because the linear momentum of the two-puck system is conserved

Thus, the only statement that must be true is statement (3)

Test: Collisions - Question 5
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A large mass M moving with velocity v makes an elastic head-on collision with a small mass m at rest. What will be the expression for energy lost by mass M?

Detailed Solution: Question 5

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Test: Collisions - Question 6
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A bomb at rest on a horizontal frictionless surface explodes and breaks into three pieces that fly apart horizontally as shown below. Select all of the following statements that must be true after the bomb has exploded.

1. The total kinetic energy of the bomb fragments is the same as that of the bomb before explosion.
2. The total momentum of the bomb fragments is the same as that of the bomb before explosion.
3. The total momentum of all the bomb fragments together is zero.

Detailed Solution: Question 6

So as no external force acts upon the system, we can say that momentum of the system remains conserved but as an internal force acts that explodes the bomb, the KE of the system is never conserved. But every fragment has some non zero momentum while the bomb initially has zero momentum.

Test: Collisions - Question 7
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If a ball of mass 1 kg makes a head-on collision with a ball of an unknown mass initially at rest such that the ball rebounds to one third of its original speed, what is the mass of the other ball?

Detailed Solution: Question 7

Since the collision is head-on and there are no external forces, both momentum and kinetic energy of the system are conserved.

Let's denote:

  • m1 = 1 kg (mass of the first ball)
  • u = initial velocity of the first ball
  • v = final velocity of the first ball after collision = -u/3
  • m2 = mass of the second ball (unknown)
  • V = velocity of the second ball after collision

From the conservation of momentum:

m1 × u = m1 × v + m2 × V

1 × u = 1 × (-u/3) + m2 × V

u = -u/3 + m2 × V

4u/3 = m2 × V                (1)

From the conservation of kinetic energy:

(1/2) × m1 × u2 = (1/2) × m1 × (u/3)2 + (1/2) × m2 × V2

(1/2) × u2 = (1/2) × u2/9 + (1/2) × m2 × V2

u2 = u2/9 + m2 × V2

8u2/9 = m2 × V2         (2)

From equation (1):

V = 4u/(3m2)

Substitute V in equation (2):

8u2/9 = m2 × (4u/(3m2))2

8u2/9 = m2 × (16u2)/(9m22)

8u2/9 = 16u2/(9m2)

8m2 = 16

m2 = 2

Therefore, the mass of the other ball is 2 kg.

Test: Collisions - Question 8
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When a ball is allowed to fall from a height of 20 m, 40% of its energy is lost due to impact. After one impact the ball will go up to a height of

Detailed Solution: Question 8

Before the impact the KE was ½ x m x (2g x 20) = 20mg
And let say v be the velocity after impact and for height h, v2= 2gh
Thus KE = ½ mv2 = ½m2gh = ⅗ x 20mg
Thus we get mgh = 12mg
thus h = 12 m

Test: Collisions - Question 9
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A particle of mass m moving with constant velocity v strikes another particle of same mass m but moving with the same velocity v in opposite direction stick together. The joint velocity after collision will be

Detailed Solution: Question 9

Concept:

  1. Momentum: momentum is the product of the mass and velocity of an object. It is a vector quantity, possessing a magnitude and a direction.
  2. The unit of momentum (P) is kg m/s.
  3. Dimension: [MLT-1]
  4. Law of conservation of Momentum: A conservation law stating that the total linear momentum of a closed system remains constant through time, regardless of other possible changes within the system.
  5. P1 = P2
  6. m1 v1 = m2 v2
  7. Where, P1 = initial momentum of system, P2 = final momentum of system, m1 = mass of first object, v1 = velocity of first object, m2 = mass of second object and v2 = velocity of second object.

Calculation:
Given:  m1 = m kg,  m2 = m kg,  u1 = v m/s,  u2 ​=  -v m/s

Let the common velocity of the combined body be V m/s

Mass of combined body      M = m + m = 2m

Applying conservation of momentum:          

m1 v1 + m2 v2 = M V

mv + (-mv) = 2mV

0 = 2mV

V = 0 m/s
Hence the correct answer will be zero (0) m/s.

Test: Collisions - Question 10
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There is a sphere of mass m moving with constant velocity v. It hits another sphere of same mass which is at rest. If e is the coefficient of restitution, then the ratio of the velocities of the two spheres after collision will be

Detailed Solution: Question 10

Here, a sphere of mass m moving with a constant velocity v hits another stationary sphere of the same mass. As per the given problem we can write 

 

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About this NEET Practice Test

This test contains 10 MCQs on Collisions with detailed solutions for each question. It is part of the Topic-wise MCQ Tests for NEET course on EduRev, designed to align with the current NEET syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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