OSSSC TGT Science PCM Mock Test - 8 - OTET MCQ

Gender discrimination may lead to diminished effort or performance in education or the labour market, which itself gives rise to negative outcomes. What remains unclear from this line of research, however, is to what extent perceptions of discrimination correspond to some reliable depiction of reality. Because events may be misperceived or overlooked, perceptions of discrimination may over- or under-estimate the actual incidence of discrimination.

The teacher should focus on every child so that no one feels leftover, scolding weak students will discourage them, the teachers to support them so that they get motivation from their support. When children have positive support then they can work better than before and when we applause for someone and appraise for something then that children will boost up their morale.
Hence, the correct answer is "Applause and tell them to do work".

For balanced Wheatstone bridge which is shown in figure a, P/Q​=S/R​
If we interchange the cell and galvanometer then circuit becomes as shown in figure b.
and balanced condition, P/S​=Q​/R⇒P/Q​=S/R​
Thus, balanced point remains unchanged.

We know that for two coherent sources, the intensity of their maxima is (I_max +  I_min)² and that of its minima is (I_max +  I_min)² . Thus we get the intensity of maxima = 121k and that of minima = 9k, for some constant k as (I_max = 100k and  I_min = k.
Thus we get the ratio as 121:81.

When the deviation is minimum, then the incidence angle and emergence angle are equal and this is possible only when the refracted ray inside the prism is parallel to the base of the prism. 
Minimum deviation is given by δ=2i−A, where A is prism angle.

Plane mirror always forms a virtual image of the real object for all the rays emitted by the object. So, when a point source of light is placed in front of a  plane mirror, all the reflected rays meet at a point when produced backward.
Option A is correct.

A real image is defined as one that is formed when rays of light are directed in a fixed point.  A real image can be projected or seen on a screen. The best example of a real image is the one formed on a cinema screen.
A virtual image is defined as the opposite of a real image, therefore an image that cannot be obtained on a screen is referred to as a virtual image. The explanation for this is the fact that the rays of light that form a virtual image never converge therefore a virtual image can never be projected onto a screen. The best example of a virtual image is your reflection in the mirror.
Real images are produced by intersecting rays while virtual images are produced by diverging rays.
Real images can be projected on a screen while virtual ones cannot.
Real images are formed by two opposite lenses, concave and convex.
Virtual images are always upright while real images are always inverted.
 

Magnetic field part of a harmonic electromagnetic wave in vacuum
,B₀​=510×10⁻⁹T
Speed of light,
C=3×10⁸m/s
E=cB_o​=153N/C

The image of the ink spot moves up by 1cm.

Refractive index = Real depth/ apparent depth

1.5 = 3/ apparent depth

Apparent depth = 3/1.5 = 2 cm

Distance through which the microscope is moved is 3 - 2 cm = 1 cm upwards

Solution : 

The correct option is Option A.

Laws of refraction;-

The incident ray,the refracted ray and the normal to the refracting surface at the point of incidence lie in the same plane.

For a given pair of media and for a given colour of light the ration between the sine of angle of incidence to the sine of refraction is a constant.This constant is known as refractive index of the second medium with respect to the first medium.

When a ray of light passes through a glass slab, ∠i,∠r and the normal all lie in the same plane.

When a ray of light passes from one medium to another, here from air to glass or glass to air, the ratio sini / sinr = constant.

Focal length in air = 20 cm
Refractive index of air-water n₁= 1.33
Refractive index of air - glass n₂= 1.5
For focal length in air,
Using formula of lens
1/f_air={(n₂/n₁)-1}(1/R₁)-(1/R₂)
Put the value into the formula
1/20={(1.5/1)-1}{(1/R₁)-(1/R₂)}
1/20=0.5{(1/R₁)-(1/R₂)}…1
We need to calculate the focal length in water
Using formula of lens
1/f_water={(1.5/1.33)-1}{(1/R₁)-(1/R₂)}
1/f_water=0.128{(1/R₁)-(1/R₂)}….2
f_water/20=0.5/0.128
f_water=78.125cm

Z = 88, [Rn] 7s², hence belongs to group 2.

Molecular mass is the sum of the atomic masses of all atoms in a molecule, compared to the mass of a carbon-12 atom.

Option ( a) Na metal is the correct answer because other options ( b) ,( c) and ( d) are used to distinguish ethanol from ethanoic acid.

The chemical formula for baking soda is NaHCO₃, which stands for sodium bicarbonate. Baking soda is commonly used in various applications such as in cooking, as an antacid, and as a water softener due to its alkaline properties.

Metal are generally hard and produce tinkling sound when bent. Non-metals are brittle and compounds cannot be bent.

Mixtures are one product of mechanically blending or mixing chemical substances such as elements and compounds, without chemical bonding or other chemical change, so that each ingredient substance retains its own chemical properties and makeup.
A chemical compound is a substance composed of two or more different elements chemically bonded together in a fixed proportion by mass. However, not all molecules are compounds. Compounds are pure substances that contain two or more elements combined in a definite fixed proportion.
Any substance that contains only one kind of an atom is known as an element. Because atoms cannot be created or destroyed in a chemical reaction, elements such as phosphorus (P4) or sulfur (S8) cannot be broken down into simpler substances by these reactions.
When a molecule is formed from elements of a different species it is a heteroatomic molecule. As an atom is the smallest particle of an element that retains the properties of that element, a molecule is the smallest particle of a compound.

The IUPAC name of the compound above is 2-acetoxy benzoic acid.

A starch solution is a colloidal solution. in a colloidal solution, particles are relatively big. so, when a beam of light is passed, the path of light is visible. it scatters. this scattering of beam of light through a colloidal solution is called tyndall effect.

the angle subtend at center is double of the angle at the arc

so:    2x=80

so x=40 

f(x)=xlnx−x+1
f(1)=0
On differentiating w.r.t x, we get
f′(x)=x*1/x+lnx−1
=lnx
Therefore,f′(x)>0 for allx∈(1,∞)
f′(x)<0 for allx∈(0,1)
lim x→0 f(x)=1
f(x)>0
for allx∈(0,1)∪(1,∞)

4x²−9y²−8x=32
⇒4(x²−2x)−9y2 = 32
⇒4(x²−2x+1)−9y² = 32 + 4 = 36
⇒(x−1)²]/9 − [y2]/4 = 1
⇒a²=9, b²=4
∴e=[1+b²/a²]^1/2 
= [(13)^1/2]/3

Probability of getting atleast one green = 1- probability of getting no green = 1-(30C₅/60C₅) = 4367/4484

"The distance between the origin and the coordinates (2, 3) is

Square root of (2 – 0)^2 + (3 – 0)^2

Square root of 2^2 + 3^2

Square root of 4 + 9

Square root of 25

Hence 5 will be the total distance between the coordinates and origin.

In case of x-axis we will only consider the value of y coordinate that is 3.

Direction ratio of line joining (1, 2, 3) and (3, 4, 5) are (2, 2, 2).
⇒ Normal to the plane has DR’s (2, 2, 2)
Now plane passes through 
⇒ Equation of plane is
2(x – 2) + 2(y – 3) + 2(z – 4) = 0
x + y + z = 9
⇒ (A) is correct

The correlation between x and y is positive correlation because it is a correlation where if one variable increases, the other also increases, and if one variable decreases, the other also decreases.

Let radius of the circle berunits.
∴ Area of the circle = Circumference of the circle 

tan 1.tan 2.tan 3...tan (90 - 3 ).tan ( 90 - 2 ).tan ( 90 - 1) 
=tan 1.tan 2 .tan 3...cot 3.cot 2.cot 1 
=tan 1.cot 1.tan 2.cot 2.tan 3.cot 3 ... tan 89.cot 89 
1 x 1 x 1 x 1 x ... x 1 =1

The two curves meet where;

Therefore, the two curves meet where x = 9.
Therefore,required Area: