Test: Solution of Triangles- Sine & Cosine Laws - JEE MCQ

# Test: Solution of Triangles- Sine & Cosine Laws - JEE MCQ

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## 10 Questions MCQ Test - Test: Solution of Triangles- Sine & Cosine Laws

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Test: Solution of Triangles- Sine & Cosine Laws - Question 1

### In the given figure,as per law of cosine which is the correct formula for a2

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Test: Solution of Triangles- Sine & Cosine Laws - Question 2

### In the given figure, X will be

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Test: Solution of Triangles- Sine & Cosine Laws - Question 3

### Law of cosineis applicable if we know All three sides of triangle two angle and sides included All three angles All three sides of triangle two angle and sides included All three angles

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The Law of Cosines is used to find the remaining parts of an oblique (non-right) triangle when either the lengths of two sides and the measure of the included angle is known (SAS) or the lengths of the three sides (SSS) are known.

Test: Solution of Triangles- Sine & Cosine Laws - Question 4

Law of cosine can be applied to

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Laws are trigonometry can be applied to all type of triangles. These rules are generalised.

Test: Solution of Triangles- Sine & Cosine Laws - Question 5

Find angle A in the following figure

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As we know that, cosA = (b2 + c2 - a2)/2bc
a = 6, b=4, c=8
cosA = (16+64-36)/2(4)(8)
44/64
= 0.687
A = cos-1(0.687)
which is approx equals to 46°36’2″

Test: Solution of Triangles- Sine & Cosine Laws - Question 6

What is the length of side c

Detailed Solution for Test: Solution of Triangles- Sine & Cosine Laws - Question 6

a = 4, b = 5
angle c = 60o
cos c = (a2 + b2 - c2)/2ab
= 1/2 = (16 + 25 - c2)/40
⇒ 20 = 41 - c2
c2 = 21
⇒ c = (21)1/2
⇒ c = 4.58

Test: Solution of Triangles- Sine & Cosine Laws - Question 7

What is the length of side b.

Detailed Solution for Test: Solution of Triangles- Sine & Cosine Laws - Question 7

a = 5, c = 3
angle c = 60o
cos b = (a2 + c2 - b2)/2ca
= 1/2 = (25 + 9 - b2)/30
=> 15 = 34 - b2
=> b2 = 19
=> b = (19)1/2
=> b = 4.35

Test: Solution of Triangles- Sine & Cosine Laws - Question 8

2(bc cos A+ ca cos B + ab cos C) =

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Test: Solution of Triangles- Sine & Cosine Laws - Question 9

Test: Solution of Triangles- Sine & Cosine Laws - Question 10

Two ships A and B, lies 33 m apart on the sea surface. There is submarine ‘C’ on the sea bed. The angle of depression of C from A is 60and the distance AC is 40 m. Calculate the distance BC.

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