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NEET Exam  >  NEET Test  >  Physics Class 12  >  Test: Combination of Capacitors - NEET MCQ

Combination of Capacitors - Free MCQ Practice Test with solutions, NEET


MCQ Practice Test & Solutions: Test: Combination of Capacitors (10 Questions)

You can prepare effectively for NEET Physics Class 12 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Combination of Capacitors". These 10 questions have been designed by the experts with the latest curriculum of NEET 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Combination of Capacitors - Question 1
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Here is a combination of three identical capacitors. If resultant capacitance is 1 μƒ, calculate capacitance of each capacitor.

Detailed Solution: Question 1

Combination of Capacitors in Series
C(effective) = C/3 = 1

Test: Combination of Capacitors - Question 2
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If the potential difference of a 6µF capacitor is changed from 10V to 20V, the increase in energy stored will be

Detailed Solution: Question 2

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Test: Combination of Capacitors - Question 3
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If two spheres of different radii have equal charge, then the potential will be

Detailed Solution: Question 3

When equal charges are given to two spheres of different radii, the potential will be more or the smaller sphere as per the equation, Potential = Charge / Radius.
Since potential is inversely proportional to radius, the smaller radius will have higher potential and vice versa.

Test: Combination of Capacitors - Question 4
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The capacitor preferred for high-frequency circuit is 

Detailed Solution: Question 4

Mica capacitor. Mica capacitors have low resistive and inductive components associated with it. Hence, they have high Q factor and because of high Q factor their characteristics are mostly frequency independent, which allows this capacitor to work at high frequency.

Test: Combination of Capacitors - Question 5
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Three different capacitors are connected in series, then:

Detailed Solution: Question 5

C = Q/V
series connection splits the battery potential, hence....
V = V1 + V2
V1 = Q/C1 & V2 = Q/C2
Therefore, both have equal charge
 

Test: Combination of Capacitors - Question 6
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There are three capacitors with equal capacitance. In series combination, they have a net capacitance of C1 and in parallel combination, a net capacitance of C2.What will be the value of ratio of C1 & C2?​

Detailed Solution: Question 6

For series combination,
1/C1 = (1/C)+(1/C)+(1/C) [ Since all capacitors have equal capacitances]=3/C Or
C1 = C/3−−−(i)
For parallel combination,
C2 = C + C + C = 3 C−−−(ii)
Now,C1 / C2 = (C/3) / 3C = (C/3) × (1/3C) = 1/9

Test: Combination of Capacitors - Question 7
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Two capacitors of 20 μƒ and 30 μƒ are connected in series to a battery of 40V. Calculate charge on each capacitor.​

Detailed Solution: Question 7

C1= 20×10µf

and C2= 30×10µf

in series Ceq = C1C2/(C1+C2)

Ceq = 20×10^(-6)×30×10^(-6)/20×10^(-6)+30^×10(-6)

Ceq= 12×10^(-6)f

As we know that Q = CV

Putting the values of C and V= 40V, we get

Q = (12 * 10^-6) * 40

= 480µC

Test: Combination of Capacitors - Question 8
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Two capacitors of equal capacity are first connected in series and then in parallel. The ratio of the total capacities in the two cases will be    

Detailed Solution: Question 8

Test: Combination of Capacitors - Question 9
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When two capacitors C1 and C2 are connected in series and parallel, their equivalent capacitances comes out to be 3μƒ and 16μƒ respectively. Calculate values of C1 and C2.

Detailed Solution: Question 9

Let Cp be the equivalent capacitance of parallel
Cp=C1+C2
16= C1+C2……..(1)
Let Cs be the equivalent of capacitance in series
1/Cs=(1/C1) + (1/C2)
Or, Cs=C1C2/C1+C2
Or,3=C1C2/16
Or,C2C1=48
C2=48/C1……..(ii)
16=C1+48/C1
(C12-16C1+48)=0
(C1-4)(C1-12)=0
C1=4 ; C1=12
If,
C1=4
C2=12
If,
C2=4
C1=12
So, the answer is, Either 12μf or4μf

Test: Combination of Capacitors - Question 10
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The equivalent capacitance between points A and B in the below shown figure will be ______ μF.​

Detailed Solution: Question 10

So, the equivalent circuit for the given circuit in the problem is as follows,

We know that the equivalent capacitance of a parallel combination of capacitors is the total sum of the individual capacitances.
So, CP = 10 + 5 + 15 = 30 μF

Now this equivalent capacitance will be in a series combination with the remaining one capacitor of magnitude 30μF.
So, the circuit will look like this,

So now the equivalent capacitance of the resultant circuit between points A and B is,

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About this NEET Practice Test

This test contains 10 MCQs on Combination of Capacitors with detailed solutions for each question. It is part of the Physics Class 12 course on EduRev, designed to align with the current NEET syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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