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MPPGCL JE Electrical Mock Test - 4 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - MPPGCL JE Electrical Mock Test - 4

MPPGCL JE Electrical Mock Test - 4 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The MPPGCL JE Electrical Mock Test - 4 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The MPPGCL JE Electrical Mock Test - 4 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MPPGCL JE Electrical Mock Test - 4 below.
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MPPGCL JE Electrical Mock Test - 4 - Question 1

What is the area of the largest square that can be made in a rectangle with 10 meters length and 4 meters width?

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 1

The side of the square must be the same as the breadth of the rectangle.
Side of the square = 4 meters
So the answer = 4 × 4 = 16 m2
Hence, Option D is correct.

MPPGCL JE Electrical Mock Test - 4 - Question 2

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Race : Fatigue :: Fast : ?

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 2

As the result of Race is Fatigue similarly the result of Fast is Hunger.

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MPPGCL JE Electrical Mock Test - 4 - Question 3

When did Zimbabwe attain independence and from whom?

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 3

The country gained official independence as Zimbabwe on 18 April 1980. The government held independence celebrations in Rufaro stadium in Salisbury, the capital.

MPPGCL JE Electrical Mock Test - 4 - Question 4

The losses in a transformer are:
(a) copper loss
(b) hysteresis loss
(c) eddy current loss
The constant power loss in a transformer is given by ;

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 4

Both hysteresis and eddy current losses depend upon A. maximum flux density Bm in the core and B. supply frequency f. Since transformers are connected to constant voltage and constant-frequency supply, both Bm and f  are constant. Hence iron or core losses in a transformer are practically the same at all loads.

MPPGCL JE Electrical Mock Test - 4 - Question 5

The energy stored in the magnetic field of a solenoid 30 cm long and 3 cm diameter with 1,000 turns of wire carrying a current of 10A is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 5
Inductance of solenoid is given as

MPPGCL JE Electrical Mock Test - 4 - Question 6

When the relative permeability of a material is slightly less than 1 , it is called a-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 6
In electromagnetism, the magnetic permeability of a material is a measure of the capability of the material to support the formation of a magnetic field within the material in response to an external magnetic field. In general, the permeability of a material depends on several factors such as the temperature, magnetic field strength, humidity and the frequency of the magnetic field. The permeability of a material is usually denoted by the symbol µ and is equal to the ratio of the magnetic flux density to the magnetic field strength. It can be expressed as µ = B/H.
MPPGCL JE Electrical Mock Test - 4 - Question 7

In an RLC circuit, supplied from an ac source, the reactive power is proportional to the-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 7
Phase angle between current and voltage is zero in Resistor.

Reactive Power PR=V1I1sin⁡q

=VIsin⁡0=0

Current is leading with voltage in capactor

Reactive power ′Pc′=V2I2sin⁡(+90)

=+V2I2

Current is lagging with voltage in inductor Reactive Power

′P2′=V3I3sin⁡(−90)

=−V3I3

So Total Reactive Power =PR+PC+PL

=0+V2I2−V3I3

Energy store in inductor by magnetic field and energy store in capacity by electric field.

So Reactive Power is Proportional to difference between average energy store in electric field and store in magnetic field.

Hence, the correct option is (d).

MPPGCL JE Electrical Mock Test - 4 - Question 8

"In all cased electromagnetic induction, an induced voltage will caused a current to flow in a closed circuit in such a direction that the magnetic field which in caused by the current will opposed the change that produces the current", is the original statement of____.

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 8
Hence, the correct option is (A)
MPPGCL JE Electrical Mock Test - 4 - Question 9

An industrial consumer has a load pattern of 2000 KW 0.8 lag for 12 hours and 1000 KW unity power factor for 12 hours. The load factor is _____

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 9
Hence, the correct option is (C)
MPPGCL JE Electrical Mock Test - 4 - Question 10

For thermionic emission

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 10
Hence, the correct option is (B)
MPPGCL JE Electrical Mock Test - 4 - Question 11

ACSR conductors have_____.

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 11
Hence, the correct option is (B)
MPPGCL JE Electrical Mock Test - 4 - Question 12

What happens when the centrifugal starting switch fails to close?

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 12
In normal use, the contact gaps of the switch changed due to arcing and pitting. If the starting switch fails to open when needed, the starting winding will be overheated and will eventually burn out.

Hence, the correct option is (B)

MPPGCL JE Electrical Mock Test - 4 - Question 13

The short circuit KVA is maximum when fault occurs

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 13
Sources of short-circuit current that are normally taken under consideration include: - Utility Generation - Local Generation - Synchronous Motors - Induction Motors - Alternate Power Sources Short circuit calculations should be done at all critical points in the system. These would include: - Service Entrance - Transfer Switches - Panel Boards - Load Centers - Motor Control Centers - Disconnects - Motor Starters - Motor Starters

Hence, the correct option is (A)

MPPGCL JE Electrical Mock Test - 4 - Question 14

Strain gauge rosettes are used when ____________.

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 14

- wire strain gage can effectively measure strain in only one direction. To determine the three independent components of plane strain, three linearly independent strain measures are needed. i.e., three strain gages positioned in a rosette-like layout.

MPPGCL JE Electrical Mock Test - 4 - Question 15

Calculate the total energy stored in magnetic field in a solenoid having inductance 100mH when carrying a current of 30 A –

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 15

Energy stored in magnetic field is given by,

MPPGCL JE Electrical Mock Test - 4 - Question 16

A circuit has inductance of 2 H. If the circuit current changes at the rate of 10 A/'sec, then self-induced emf is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 16

= 2 X 10 = 20 V

MPPGCL JE Electrical Mock Test - 4 - Question 17

The condition of a semiconductor diode can be determined quickly using:

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 17

On a digital display meter with a diode checking capability appears, the small diode symbol is the bottom option of the rotating dial to check the functionality of the diode. The curve tracer of can displays the characteristics of a host of devices, including the semiconductor diode.
By properly connecting the diode to the test panel at the bottom center of the unit and adjusting the controls, the display can be obtained.
Hence, the correct option is (C).

MPPGCL JE Electrical Mock Test - 4 - Question 18

If the terminals of armature of the D.C. motor are interchanged, this action will offer the following kind of braking-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 18
Plugging — sometimes referred to as “reverse current braking” — is possible on both DC motors and AC induction motors. For DC motors, plugging is achieved by reversing the polarity of the armature voltage. Torque is developed in the opposite direction of the motor's rotation, which produces a strong braking effect.

Hence, the correct option is (B)

MPPGCL JE Electrical Mock Test - 4 - Question 19

The stator-produced MMF and rotor-produced MMF both rotate in the air gap in-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 19
Same direction at synchronous speed

Synchronous speed is a significant parameter for the rotating magnetic field-type AC motor. It is determined by the frequency and the number of magnetic poles. Synchronous speed No = [rps, revolutions per second] f = Frequency [Hz]

Hence, the correct option is (A)

MPPGCL JE Electrical Mock Test - 4 - Question 20

The equivalent inductance seen at terminal a-b in the figure is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 20

delta to star conversion,

Hence, the correct option is (B)

MPPGCL JE Electrical Mock Test - 4 - Question 21

Electric traction in comparison to other traction systems has the advantages of_____.

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 21
The above given are all advantages of electric traction.

Electric traction has many advantages as compared to other non-electrical systems of traction, including steam traction.

Electric traction is used in Electric trains, Trolleybuses, Tramcars, Diesel-electric vehicles etc.

Hence, the correct option is (D)

MPPGCL JE Electrical Mock Test - 4 - Question 22

In a fluorescent tube, if only the ends of the tube remain lighted, it indicates that-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 22
  • The choke is defective

  • Starter is short-circuited

  • The tube is defective

Hence, the correct option is (D)

MPPGCL JE Electrical Mock Test - 4 - Question 23

The instantaneous power of a 1-phase series circuit supplying R-L load from a sinusoidal voltage source has in each cycle.

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 23
The instantaneous power of a 1-phase-series circuit supplying R-L load from a sinusoidal voltage source has in each cycle negative twice and zero four times.

MPPGCL JE Electrical Mock Test - 4 - Question 24

In indicating instruments, the springs are mainly used to-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 24
In indicating instruments, the springs are mainly used to control the pointer movement.
MPPGCL JE Electrical Mock Test - 4 - Question 25

Resistance switching is commonly employed in-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 25
Resistance switching is usually employed in air blast circuit breakers.
MPPGCL JE Electrical Mock Test - 4 - Question 26

Tesla is the unit of-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 26
The unit of magnetic flux density is Tesla.
MPPGCL JE Electrical Mock Test - 4 - Question 27

A voltmeter, when connected across a DC supply, reads 124 V. When a series combination of the voltmeter and an unknown resistance X is connected across the supply, the meter reads 4V. If the resistance of the voltmeter is. the value of X is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 27

⇒ X = 1500kΩ = 1.5MΩ

MPPGCL JE Electrical Mock Test - 4 - Question 28

In reference to the figure, the voltage waveform v9t) is measured by a PMMC, a PMMC combined with bridge rectifier and a moving iron (MI) instrument. Two lists are prepared thereafter :

Instrument list List of instrument reading
List - II
a. PMMC
b. PMMC rectifier
c. M.I.
List - II
i. 5 V
ii. 2.75 V
iii. 2.5 V
The correct option relating the instruments and their reading is

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 28

PMMC reads average value.
Vavg = area/(time period)
From given waveform
Vavg = (10*4)/16 = 2.5 Volts
PMMC rectifier will read rms value = 2.75 Volts
MI reads true rms value
Vrms = (peak value)/2 (for square wave)
= 10/2 = 5V

MPPGCL JE Electrical Mock Test - 4 - Question 29

It is desired to correct the p.f. to 0.95 by means of static capacitors connected across each phase of a 3-phase, 400 V, 50 Hz motor having a maximum load of 50 kVA at a p.f. of 0.75 lagging. The capacitors are delta connected. What is the capacitance of each capacitor?

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 29

Capacitive current/phase,

MPPGCL JE Electrical Mock Test - 4 - Question 30

A factory takes a steady load of 200 kW at a lagging power factor of 0.8. The tariff is Rs. 100 per kVA of maximum demand per annum plus 5 paise per kWh. The phase advancing plant costs Rs. 500 per kVAR and the annual interest and depreciation together amount to 10%. The most economical p.f. is

Detailed Solution for MPPGCL JE Electrical Mock Test - 4 - Question 30

Peak load of factory, P = 200 kW
Original power factor, cosϕ1=0.8lagging
Max. demand charges, x = Rs. 100/kVA/annum
Charges on phase advancing plant are
y=Rs.500×0.1=Rs.50/kVAR/annum
Most economical p.f.,

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