MPPGCL JE Electrical Mock Test - 7 - Electrical Engineering (EE) MCQ

In the question, We have to find the common to all three figures which is shown below-

Here, The highlighted area is common to all shapes.

Hence, Option (3) is correct.

From the common explanation, we get the position of G is 3rd to the right of C.

Hence, Option B is correct.

Common Explanation:

References:

One person sits between A and C, who sits second to the right of H.

G sits opposite to B.

Both G and B do not sit immediate left of H.

Inferences:

From the above reference, we get two different cases:

References:

D sits second to the left of B.

A doesn’t sit beside D.

E doesn’t face C.

Inferences:

From the above reference, case 1 will be eliminated because A doesn’t sit beside of D.

So, the final arrangement:

As per the given information;

Distance between S and P = √(PQ² + QS²)
SP = √(6² + 8²)
SP = √(36 + 64)
SP = √100
SP = 10 km
Hence, S is 10 km in South-East with respect to P.

One word substitution is Evacuate.

Evade: escape or avoid (someone or something), especially by guile or trickery.

Evacuate: remove (someone) from a place of danger to a safer place.

Avoid: keep away from or stop oneself from doing (something).

Exterminate: destroy completely.

B is the correct option.Some seats are reserved in Lok Sabha for the members of the Schedule Castes and Scheduled Tribes. As per the order issued by the Delimitation Commission in 2008 , 412 are general, 84 seats are reserved for Scheduled Castes and “47 seats” for the Scheduled Tribes.

From statement I alone, we don’t get the answer.

From statement II alone, Q is sitting 2nd to the left of T. T is facing P. The number of friends sitting between P and Q is same as the number of friends sitting between P and W.

From statement II alone, we don’t get the answer.

Combining both statement I and II, we get,

From statements I and II together, we don’t get the answer.

Hence, option ‘D’ is correct.

The electrical conductivity of a semiconductor increases with increase in temperature because with increase in temperature the electrons overcome the energy barrier between the valence band and the conduction band easily.

A growler is used to check the armature for shorts, opens and grounds.

The internal impedance is complex and may be interpreted as a resistance in series with an inductance. The inductance accounts for energy stored in the magnetic field inside the wire. It has a maximum value of H/m at zero frequency and goes to zero as the frequency increases. The zero-frequency internal inductance is independent of the radius of the round wire.

The internal inductance of round wire vs. the ratio of skin depth to radius. The inductance asymptotically approaches (μ / 8 π ) H/m for large skin depth. The internal inductance is associated with the magnetic field inside the wire. As skin depth becomes small, the inductance goes linearly to zero.

Hence, the correct option is (D)

If the unit of power in kW and the unit of time is an hour, then the unit of energy = unit of power × unit of time = kWh.

Hence, the correct option is (B).

Hence, the correct option is (B)

Hence, the correct option is (D)

Hence, the correct option is (D)

Hence, the correct option is (D)

Net current,

{{chart?cht=tx chl=\(I=I}}

From the short circuit test of the Transformer we will find out full load copper loss and equivalent circuit parameter & voltage regulation.
From full load copper loss we can find out copper losses at any fraction of load by using the following formula.
W_cu at x% full load = x² [W_cu full load]

Maximum error = 2% of 240 = (200)×(2/100)= 4 V
% error when measured 100V = 4×(100/144)=2.78 %

power consumed in the circuit, P

An over-excited 3-phase synchronous motor is not only used as a motor to supply the needed mechanical power but also acts as a power factor correction device.But generally prefered for power factor correction.

Gross mechanical power output = shaft power + mechanical losses

= 4.1×103+750

= 4850

Here slip =

Slip s =

= 0.03

Rotor copper loss =

= 150W

Hence, the correct option is (B).

C_ab = (1e)μ F = 7μ F

P = V I_C cosβ cosψ

Pα cosβ cosψ

Equivalent of 6 ohm 3 ohm in parallel = 6x3/9= 2 ohm
This 2 ohm again in series with 2 ohm resistor = 2+2 =4 ohm
Equivalent of 1 ohm & 5 ohm series = 1+5 = 6 ohm
Now 6 ohm & 4 ohm in parallel so its equivalent = 6x4/10 =2.4
Hence Req of the network = 4+2.4 +8 = 14.4

p.f. of synchronous motor,