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UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Mechanical Engineering MCQ


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30 Questions MCQ Test - UPSSSC JE Mechanical Paper 2 Mock Test - 3

UPSSSC JE Mechanical Paper 2 Mock Test - 3 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The UPSSSC JE Mechanical Paper 2 Mock Test - 3 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The UPSSSC JE Mechanical Paper 2 Mock Test - 3 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for UPSSSC JE Mechanical Paper 2 Mock Test - 3 below.
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UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 1

Creep plays an essential role in the design of

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 1
Creep-resistant steels are usually welded with fillers giving weld metals roughly. These need careful planning and design because of the differences in the fiber packing play an important role.
UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 2

If in a diesel engine, by mistake petrol fuel is supplied

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 2

Petrol has a higher auto-ignition temperature, and it won't burn at the compression ratio of a diesel engine without external help. So, the engine won't run. Whereas when you use diesel in petrol engines, it's dangerous. Diesel burns with more power, and it may damage the engine partly or entirely.

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UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 3

An ideal spark ignition engine has a compression ratio of 9. What is its Air standard efficiency ifratio of specific heats is 1.5 ?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 3

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 4

Optimum rake angle of a tool is a function of

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 4
Soft material requires a positive back rake angle, while harder material requires zero or even negative back rake angle.
UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 5

The critical value of Reynolds number for transition from laminar to turbulent boundary layer in external flows is taken as

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 5

For flow over a flat plate, transition from laminar to turbulent boundary layer occurs when Reynolds number at x exceeds Rex,crit ~ 500,000. Transition may occur earlier, but it is dependent especially on the surface roughness.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 6

A toothpaste tube can be produced by

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 6

Toothpaste tube can be produced by backward hollow extrusion also known as impact extrusion.

In impact extrusion, a heavy punch is allowed to fall over the material/billet and the material/billet takes the shape of the die. Collapsible tubes are made by this process. This process is limited to soft and ductile materials.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 7

One bar unit of Pressure =?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 7

1 Bar = 101325 Pascal

1 Bar = 101.325 Kilo Pascal

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 8

The temperature at which the new grains are formed in the metal is called

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 8
Recrystallisation is the process in which deformed grains are replaced by strain-free grains. It is generally observed that higher cold work and smaller initial grain size lead to finer recrystallized grains. The driving force for recrystallisation is the stored strain energy in the material.

The temperature at which a given material is completely recrystallised in an hour is defined as the recrystallisation temperature.

The recrystallisation temperature is low if the degree of deformation is high and if the temperature of deformation is low, and/or if the initial grain size is small. The recrystallisation temperature is also very sensitive to the purity of the material.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 9

The kinetic energy of a flywheel, having a moment of inertia I and angular speed ‘ω,’ is given by

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 9
Kinetic energy of the flywheel is given by

K.E = 1/2Iω2 = 1/2mk22

I is the mass moment of inertia of the flywheel about its axis of rotation in kg-m2 = m.k2.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 10

In gears, interference takes place when _____.

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 10
Due to interference, the tip of one of the gears of the pair will tend to dig into portions of the flank of the tooth of the other member of the pair.

Methods of elimination of Gear tooth Interference:

  • Use of a larger pressure angle (having a larger pressure angle results in a smaller base circle. As a result, more of the tooth profiles become involute)

  • Under-cutting of the tooth (A portion of teeth below the base circle is cut off. When teeth are produced by this process, the tip of one tooth of gear will not contact the non-involute portion of the tooth of other gear)

  • Tooth stubbing (In this process, a portion of the tip of the teeth is removed, thus preventing that portion of the tip of the tooth from contacting the non-involute portion of the other meshing tooth).

  • Increasing the number of teeth on the gear can also eliminate the chances of interference.

  • Increasing the center distance between the meshing gears slightly eliminates interference.

  • Tooth profile modification or profile shifting (Using profile shifted gears (gears with non-standard profile) can also be an option to eliminate interference. In profile shifted meshing gears, the addendum on the pinion is shorter compared with standard gears).

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 11

Match List – I (Measuring device) with List-II (Parameter measured) and select the correct answer using the options given below the lists:

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 11
Anemometer: It is used to measure the velocity of the wind or of any other gases passing through.

Piezometer: It is used to measure the static pressure of the fluid at any section.

Pitot tube: It is used to calculate the dynamic pressure (total pressure – static pressure) in any section.

Orifice meter – It is used to measure the discharge of fluid across a considered section.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 12

Which of the following relationships is correct?

When a body placed on the plane just begins to slide down:

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 12

Angle of Friction between any two surfaces in contact is defined as the angle which the resultant of the force of limiting friction Film and normal reaction N makes with the direction of normal reaction N.

tanθ = Flim/N = μ

The angle of repose or angle of sliding α is defined as the minimum angle of inclination of a plane with the horizontal such that a body placed on the plane just begins to slide down.

f = mg sin α

N = mg cos α

tan α = f/N

tan α = tan θ

α = θ

∴ The angle of friction = Angle of repose

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 13

The principal source of pollutant Hydrogen Sulphide in the air is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 13

Decay of organic matter or putrefaction, the process whereby heterotrophic organisms, including some bacteria, fungi, saprophytic plants, and lower animals, utilize the remains of once-living tissue as a source of nutrition. The polysaccharides, lipids, nucleic acids, and proteins of dead tissue are broken down into smaller organic molecules, often by enzymes that are secreted into the external environment by the bacteria and fungi that are involved; the breakdown products are then readily absorbed by the heterotrophs and are used both as a source of building blocks for the synthesis of their own polysaccharides, lipids, nucleic acids, and proteins and as a source of chemical energy, obtained either by fermentation (in an anaerobic environment) or respiration (in the presence of oxygen). Often during the process of putrefaction, trace elements and nitrogen are released into the environment in forms suitable for uptake by higher plants; this is the basis for the use of decayed organic matter as fertilizer. The disagreeable odor produced as putrefaction takes place is caused by the formation of certain gases, including ammonia and hydrogen sulfide, and certain volatile amines, including putrescine and cadaverine, two products of the breakdown of protein by microorganisms.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 14

A refrigerator maintains a temperature of 270 K in a room at 300 K. If heat is removed from the interior at a rate of 900 J/sec and the refrigerator operates at 50% of its maximum thermal efficiency, the power requirement is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 14

Maximum COP is of Carnot COP:

W = 900/4.5 = 200 J/sec

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 15

Another name for the coal used in the power plant is:

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 15
Steam coal, also known as thermal coal, is used in power stations to generate electricity. In electricity generation, thermal coal is ground to a powder and fired into a boiler to produce heat, converting water into steam. The steam powers a turbine coupled to an alternator, which generates electricity for the power grid.
UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 16

The conditions for the stable equilibrium of a floating body are:

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 16
Condition of stable equilibrium for a floating body in terms of metacentric height (GM) as follows:
  • Stable equilibrium : GM > 0 (M is above G)
  • Neutral equilibrium : GM = 0 (M coinciding with G)
  • Unstable equilibrium : GM < 0="" (m="" is="" below="" g)="" />

(a) Equilibrium Position (b)Tilted Position

Condition of stable equilibrium for a floating body in terms of centre of buoyancy and the centre of gravity:

  • Stable equilibrium: If its centre of gravity is directly below the centre of buoyancy
  • Neutral equilibrium: If its centre of gravity is coincident with the centre of buoyancy
  • Unstable equilibrium: If its centre of gravity is directly above the centre of buoyancy

A submerged body is in equilibrium when the centre of gravity is located below the centre of buoyancy. If the body is tilted slightly in any direction, the buoyant force and the weight always produce a restoring couple trying to return the body to its original position.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 17

In a four-stroke CI engine, the inlet valve

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 17

The exact moment at which the inlet and outlet valve opens and closes with reference to the position of the piston and crank shown diagrammatically is known as the valve timing diagram. It is expressed in terms of degree crank angle.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 18

A 1 kg block is resting on a surface with coefficient of friction μ = 0.1. A force of 0.8 N isapplied to the block as shown in the figure. The friction force is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 18

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 19

What is the heat required to raise the temperature of 1 kg mass of a substance by 1° C?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 19

The energy required to raise a mass of 1 centigrade (K or ºC) is the specific massic heat of the substance, multiplied by its mass and 1 centigrade. In the case of 1 kilogram of water: E = (4180 J/(kg×K)) ×1 kg × 1K = 4180 J. You can also use the specific molar heat with the number of moles.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 20

In case of power failure, a battery is used to light a bulb, run a fan, and heat an electric iron (each of 100 W rating) for 10 minutes. In this process, the work done and heat supplied by the battery is given by :

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 20

Work = electrical work

=3×100W

=3×100×10×60J

Work (W)=180kJ

Heat transfer, Q=0 (no heat transfer from/to battery)

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 21

The crystal structure of Aluminium is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 21

Crystal structure of Material

FCC: - Ni, Cu, Ag, Pt, Au, Pb, Al, Austenite or Ƴ-iron

BCC: - V, Mo, Ta, W, Ferrite or α-iron, δ-ferrite or δ-iron

HCP: - Mg, Zn

Cobalt: - HCP < 420°C, FCC > 420°C

Chromium: - HCP < 20°C, BCC > 20°C

Glass: - Amorphous

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 22

In an IC engine, the connecting rod connects which of the following pair of parts?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 22

In a reciprocating piston engine, the connecting rod connects the piston to the crank or crankshaft. Together with the crank, they form a simple mechanism that converts reciprocating motion into rotating motion.

In a reciprocating compressor or pump, connecting rods may also convert rotating motion into reciprocating motion.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 23

The locus of elevations that water will rise in a series of the pitot tubes is called ______.

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 23

- Within the piezometer tube, the locus of elevations to which the water would rise if open to the atmospheric pressure represent the Hydraulic grade line (HGL).

- The difference in elevation of the water surface in the successive conduit represents the friction and other minor losses in the conduits.

- If the conduit has a slope equal to the friction slope, then the HGL would be parallel to the conduit, ignoring minor losses.

- Energy grade line (EGL) = HGL + v2/2g

- The EGL will be represented by a series of pitot tubes (small tubes with their end openings pointed upstream) intercepting the kinetic energy of the flow.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 24

In an engine, the fluctuation of speed is ± 2% of mean speed. Then coefficient of fluctuation of speed is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 24

Concept:

The difference between the maximum and minimum speeds during a cycle is called the maximum fluctuation of speed. The ratio of the maximum fluctuation of speed to the mean speed is called the coefficient of fluctuation of speed (Cs).

Calculation:

ωmax – ωmin = ± 2% of ωmean

⇒ ωmax – ωmin = 4% of ωmean⇒ ωmax – ωmin = 0.04 ωmean

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 25

In the vander waal’s equation, the unit of constant a is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 25

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 26

The size of the gear is usually specified by

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 26

It is the diameter of the pitch circle. The size of the gear is usually specified by the pitch circle diameter. It is also called pitch diameter.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 27

What will be the effect on eccentricity ratio for a hydrodynamic journal bearing if there is an increase in the diameter of the journal (Assume other parameters as constant)?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 27

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 28

Evaluate the following limit:

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 28

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 29

Which boiler has a relatively large storage of steam and water?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 29

Lancashire boiler is the most commonly used boiler which is stationary and hardly used during transportation. It is used in sugar mills and textile industries not only for power generation but for various processes. It is normally used where a large quantity of steam is needed, and therefore water reserve should be in large quantity.

The Cornish boiler, Cochran boiler, and Simple vertical boiler is less than the Lancashire boiler; consequently, the capacity of steam generation is less.

UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 30

Water is a:

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 3 - Question 30

Newtonian fluids are defined as fluids for which the shear stress is linearly proportional to the shear strain rate. Newtonian fluids are analogous to elastic solids (Hooke’s law: stress proportional to strain). Any common fluids, such as air and other gases, water, kerosene, gasoline, and other oil-based liquids, are Newtonian fluids.

where μ is the shear viscosity of the fluid

Fluids for which the shear stress is not linearly related to the shear strain rate are called non-Newtonian fluids examples include slurries and colloidal suspensions, polymer solutions, blood, paste, and cake batter.

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