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UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Mechanical Engineering MCQ


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30 Questions MCQ Test - UPSSSC JE Mechanical Paper 2 Mock Test - 6

UPSSSC JE Mechanical Paper 2 Mock Test - 6 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The UPSSSC JE Mechanical Paper 2 Mock Test - 6 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The UPSSSC JE Mechanical Paper 2 Mock Test - 6 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for UPSSSC JE Mechanical Paper 2 Mock Test - 6 below.
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UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 1

A Carnot’s engine operates with a source at 500K and sink at 375K. The engine consumes 600Kcal of heat in one cycle; the heat rejected to the sink per cycle is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 1

And W = QH - QC

QC = QH - W = 600 - 150 = 450kcal

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 2

The alloying elements in steel that improves creep strength at a specified creep rate is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 2
Creep strength is defined as the stress at specified environmental conditions that produces a steady creep rate, such as 1%; with respect to remaining segregation of alloying elements is shown for Gr.91 as one of the causes of lowered creep rupture. Increase in Ni content in 12CrMoV steel
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UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 3

The intensity of solar radiation on earth is nearly Buy Today

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 3
At Earth's average distance from the Sun (about 150 million kilometers), the average intensity of solar energy reaching the top of the atmosphere directly facing the Sun is about 1,360 watts per square meter, according to measurements made by the most recent NASA satellite missions.
UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 4

Gear that neutralizes side thrust is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 4
A herringbone gear, a specific type of double helical gear, is a special type of gear with a side-to-side combination of two helical gears of opposite hands. From the top, each helical groove of this gear looks like the letter V, and many together form a herringbone pattern.
UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 5

The normal speed of rotation of a shaft is chosen to be-

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 5
The normal speed of rotation of a shaft is chosen to be much above or below the natural frequency of the shaft. This is done so that the shaft does not malfunction in actual working condition.
UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 6

A gas perform the most work when it expounds

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 6
The work done by an expanding gas is the energy transferred to its surroundings. In effect, as the gas expands, it is compressing its surroundings, so the work done is the force exerted on the surroundings (i.e., the pressure of the surroundings times the area) times the distance moved.

An isobaric process is a thermodynamic process in which the pressure remains constant. This is usually obtained by allowing the volume to expand or contract in such a way as to neutralize any pressure changes that would be caused by heat transfer.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 7

For the same compression ratio and heat rejection

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 7

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 8

How does Young's modulus vary with the increase of temperature?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 8

Young's modulus shows the rigidity of the material. when the temperature increases, the material starts to become soft. Therefore elasticity decreases with rise in temperature.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 9

Boiling point of water due to increase in atmospheric pressure

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 9

A liquid at high pressure has a higher boiling point than when that liquid is at atmospheric pressure. For example, water boils at 100 °C (212 °F) at sea level, but at 93.4 °C (200.1 °F) at 1,905 metres (6,250 ft) altitude. For a given pressure, different liquids will boil at different temperatures.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 10

In a simply supported beam carrying a uniformly distributed load ‘w’ per unit length, the point of contraflexure

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 10
Contra-flexure = contra (opposite) + flexure (bending)

In a bending beam, a point is known as a point of contra flexure if it is a location at which no bending occurs. In a bending moment diagram, it is the point at which the bending moment curve intersects with the zero line. In other words, where the bending moment changes its sign from negative to positive or vice versa. It occurs in the overhanging beam.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 11

Which solution is used in an ice plant?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 11
The function of an ice plant or ice factory is to make or form ice in large quantities and in large size.

1. Ammonia: It is the primary refrigerant that takes heat from brine. This ammonia changes phase while moving in the circuit.

2. Brine: It is the secondary refrigerant that takes heat from the water and produces ice.

There are three main circuits of working medium in ice plant:

Refrigeration circuit: Ammonia as working medium which actually produces the cold by changes its phase at a single degree of freedom with a different location

Cooling water circuit: Cooling water as a working medium to remove the heat of the condenser

Brine circuit: Brine solution as a working medium which transfers the cold from ammonia to water-filled cans where ice is to be formed.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 12

Francis turbine is a

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 12
Impulse Turbine: If at the inlet of the turbine, the energy available is only kinetic energy, the turbine is known as an impulse turbine. e.g., a Pelton wheel turbine.

Reaction Turbine: If at the inlet of the turbine, the water possesses kinetic energy and pressure energy, the turbine is known as a reaction turbine. e.g., e Francis and Kaplan turbine.

Tangential flow turbines: In this type of turbine, the water strikes the runner in the tangent direction to the wheel. Example: Pelton wheel turbine

Radial flow turbines: In this type of turbine, the water strikes in the radial direction. accordingly, it is further classified as

  • Inward flow turbine: The flow is inward from periphery to the centre (centripetal type); Example: old Francis turbine

  • Outward flow turbine: The flow is outward from the centre to periphery (centrifugal type); Example: Fourneyron turbine

Axial flow turbine: The flow of water is in the direction parallel to the shaft axis. Example: Kaplan turbine and propeller turbine

∴ Francis turbine is a radial inward flowing reaction turbine.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 13

Auto frettage is the method of

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 13

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 14

The critical pressure ratio for maximum discharge through a nozzle is given by

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 14

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 15

A p-V diagram has been obtained from a test on a reciprocating compressor. Which of the following represents that diagram?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 15
Working of single stage reciprocating air compressor

The compressor operates on a two-stroke cycle:

Stroke 1 (a – c): The piston withdraws, causing the air in the clearance volume to expand, and when the pressure in the cylinder falls below atmospheric pressure (at b), the inlet valve opens, and the air is drawn into the cylinder for the remainder of the stroke.

Stroke 2 (c – a): The piston moves inwards, compressing the air in the cylinder, and the inlet valve closes when the cylinder pressure reaches atmospheric pressure.

Further compression follows as the piston moves toward the top of its stroke until, when the pressure in the cylinder is more than that in the receiver, the delivery valve opens. The air is delivered to the receiver for the remainder of the stroke.

Effect of suction and discharge side pressure drops on P-V diagram of a reciprocating compressor.

Typical indicator card

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 16

Automobile Steering gear is an example of

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 16
When the two elements of a pair have a surface contact when relative motion takes place, and the surface of one element slides over the surface of the other, the pair formed is known as a lower pair. Automobile Steering gear is an example of Lower pair.
UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 17

The difference between the total headline and the hydraulic grade line represents

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 17
Hydraulic gradient Line (H.G.L.) – Line representing the sum of pressure head and datum head.

Total energy line (T.E.L.) – Line representing the sum of pressure head, datum head, and velocity head.

∴ T.E.L. – H.G.L. = velocity head

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 18

The power transmitted by a circular shaft rotating at N rpm under the action of torque T is:

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 18
In S.I units, power transmitted (in watts) by the shaft,

P = 2πNT/60

In M.K.S units, horsepower transmitted by the shaft,

P = 2πNT/4500

Out of the given 4 options, only one option is the correct formula for power transmitted.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 19

Which of the following is true for a self-locking screw?

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 19
For a self - locking screw, the coefficient of friction is equal to or greater than the tangent of the helix angle.

In the Power screw, the torque Mt required to lower the load is given by

Mt = Wdm/2 tan (ϕ−α) where, W = load on the screw in N, dm = the mean diameter of the screw-in m,

ϕ = friction angle and α = helix angle

Case 1. when ϕ ≥ α

tan (ϕ - α ) ≥ 0, thus Mt ≥ 0.

i.e., positive torque is required to lower the load. Thus the load will not turn the screw and will not descend on its own unless an effort is applied.

Such cases of screws are known as 'Self-locking screws.’ And the screw will hold the hold without any application of the brake.

Also, as ϕ ≥ α

tan ϕ ≥ tan α

Case 2. when ϕ < />

tan (ϕ - α ) < 0,="" thus="" />t < />

i.e., negative torque is required to lower the load. The load will turn down the screw and will descend on its own unless a restoring torque is required to hold the load.

Such cases of screws are known as 'overhauling of the screw' or back drawing of the screw.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 20

COP of a Carnot heat pump operating between -3°C and 27°C is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 20
Given: TL = -3°C, TH = 27°C

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 21

In a free vortex, velocity

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 21
Free Vortex Flow: When no external torque is required to rotate the fluid mass, that type of flow is called free vortex flow.

The velocity of free vortex flow ∝ 1/r

∴ In a free vortex, velocity decreases with radius.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 22

Addition of magnesium to cast iron increases its

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 22

Magnesium is a powerful inoculant in cast iron. When added in concentrations exceeding 0.04%, it produces a spheroidal form of graphite that improves the iron's strength and ductility. Magnesium is an abundant metal with a price roughly comparable to that of aluminum, albeit usually higher

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 23

Gas turbine plants operate on

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 23

A gas-turbine power plant operates on the simple Brayton cycle between the pressure limits of 100 and 1600 KPa. The working fluid is a mixture of air with 20% of carbon monoxide (CO). The mixture enters the compressor at 40oC at a rate of 850 m3/min and leaves the turbine at 650oC.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 24

Surface tension is due to

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 24

Surface tension is due to cohesion between liquid particles at the surface, whereas capillarity is due to both cohesion and adhesion. The property of cohesion enables a liquid to resist tensile stress, while adhesion enables it to stick to another body.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 25

Gas contained in a closed system consisting of piston cylinder arrangement is expand. Workdone by the gas during expansion is 50 kJ. Decreases in internal energy of the gas duringexpansion is 30 kJ. Heat transfer during the process is equal to

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 25

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 26

The method of control used in SI engine is-

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 26

SI engine controls include Air/fuel ratio control, spark timing control, idle speed control. After treatment, system controls include thermal management to ensure rapid warm-up and high emission reduction efficiency; and air/fuel ratio control to ensure maximum conversion of the TWC.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 27

When inspection doors on the walls of boilers are opened, the flame does not leap out because

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 27

The flame does not leap out during the opening of the inspection door because there is negative pressure in the combustion area. Negative pressure is achieved in balanced draft boilers by using forced draft fans to force air into the boiler (pressuring it) and Induced draft fans to remove air from the boilers to create negative pressure.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 28

The value of solar constant is

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 28

The solar energy received by the earth is approximately 1.4 kW/m2. It is known as solar constant or Solar Irradiance.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 29

In an IC engine, boundary lubrication is likely to occur between surfaces with relative velocity during:

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 29

Lubrication Principles:

If one surface is moving and inclined to the other, the viscous drag of the oil tends to draw the lubricant into the space between the surfaces and builds up a wedge. This develops an oil film; the pitch circle diameter usually specifies the size of the gear pressure that can support a load.

If the two surfaces were parallel or if they did not have relative motion, the oil–film pressure would not get developed, and a developed and load would not be supported by the lubricant.

There are three lubrication regions: Hydrodynamic lubrication, Boundary lubrication, and Mixed – film lubrication.

Boundary Lubrication:

With a lower relative velocity of the moving surfaces, adequate pressure cannot be developed to support the load by the oil film. At this point in time, boundary lubrication will exist. This will occur especially during starting and stopping of an engine.

As the speed increases, a sufficient film pressure is developed, and the load is supported by the oil film, which will shift to the hydrodynamic lubrication.

Hydrodynamic Lubrication:

If a film of oil completely separates the sliding surfaces, there is no metal–to–metal contact, and the wear on the surfaces is a minimum. This type of lubrication is developed when there is a relative motion between the two inclined surfaces separated by an oil film.

UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 30

The rails are welded by

Detailed Solution for UPSSSC JE Mechanical Paper 2 Mock Test - 6 - Question 30

The thermite welding railroad method is especially suitable for broken steel rail repair, on-site joint welding on railway frog section of seamless railway line ball, and heavy transportation tasks.

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