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APSC JE CE Paper 2 Mock Test - 3 - Civil Engineering (CE) MCQ


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30 Questions MCQ Test - APSC JE CE Paper 2 Mock Test - 3

APSC JE CE Paper 2 Mock Test - 3 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The APSC JE CE Paper 2 Mock Test - 3 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The APSC JE CE Paper 2 Mock Test - 3 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for APSC JE CE Paper 2 Mock Test - 3 below.
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APSC JE CE Paper 2 Mock Test - 3 - Question 1

The maximum n permissible shear stress given in BIS 456-1978 is based on

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 1
The maximum n permissible shear stress given in BIS 456-1978 is based on Diagonal compression failure.
APSC JE CE Paper 2 Mock Test - 3 - Question 2

The method of irrigation adopted at places where there exists an acute scarcity of irrigation water is:-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 2
In this method, water is slowly and directly applied to the root zone of plants thereby minimizing the losses by evaporation and percolation.
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APSC JE CE Paper 2 Mock Test - 3 - Question 3

When lower values are inside the loop of a contour plot it indicates

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 3
A loop of a contour plot indicates a particular level, when plots of loop values go on decreasing inside it indicates a fall in level, which is generally categorized as a depression.
APSC JE CE Paper 2 Mock Test - 3 - Question 4

The workability of rounded aggregates for given water content is a good because: -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 4
For a given water content round and cubical shape aggregates are more workable than rough, angular, or flaky aggregates because the former type of aggregates requires less cement paste for lubrication as these less surface area and lesser voids.
APSC JE CE Paper 2 Mock Test - 3 - Question 5

Age of a tree may be ascertained by -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 5
The second most accurate way to estimate tree age is to count the annual rings of wood growth. Annual rings can be counted using two different methods. We can extract an increment core from the tree using an increment borer.
APSC JE CE Paper 2 Mock Test - 3 - Question 6

The relation between coefficient of consolidation Cv, time factor Tv, drainage path d and time t, is given by:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 6
Time factor

(Tv=Cvt/d2⇒Cv=d2Tv/t)

Hence the correct answer is option A.

APSC JE CE Paper 2 Mock Test - 3 - Question 7

Undisturbed samples are obtained by -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 7
Thin-walled samplers-

Thin-walled cre samplers are most commonly used for the collection of undisturbed core samples in cohesive soils, silt, and sand above the water table.

APSC JE CE Paper 2 Mock Test - 3 - Question 8

About Resins which are incorrect:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 8
Resin is a natural or synthetic organic substance that is soluble in some organic solvent such as linseed oil turpentine only. And their resinous solution in a solvent formed varnishes.
APSC JE CE Paper 2 Mock Test - 3 - Question 9

The accuracy of measurement in chain surveying does not depend upon:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 9
The accuracy of measurement in chain surveying does not depend upon the general layout of the chain lines.

Length, Scale, and Features are important.

The general layout is because it doesn't matter how we deal with the plan or layout. Measured distance should be accurate.

APSC JE CE Paper 2 Mock Test - 3 - Question 10

Bernoulli’s theorem deals with the law of conservation of -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 10
Bernoulli's equation represents total energy per unit of weight.

((P/W V2/2g)Z=C)

Bernoulli's principle relates the pressure of a fluid to its elevation and speed.

Bernoulli's equation can be used to approximate these parameters in water, air, or any fluid that has a very low viscosity.

APSC JE CE Paper 2 Mock Test - 3 - Question 11

Calculate the volume (cubic meter) of earthwork for an embankment of length 30 m and width 4 m. The mean depth of the embankment is 4 m and side slope is 2: 1. Using mid-sectional area method.

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 11

Given,
Length of embankment(L) = 30 m
width of embankment(B) = 4 m
mean depth of embankment(dm) = 4 m
side slope is 2:1
Area of mid-section = Area of rectangular
portion + area of two triangular portion

= 1440 m3

APSC JE CE Paper 2 Mock Test - 3 - Question 12

Find out the set among the four sets which is like the given set.
Given set is (63, 54, 45)

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 12

In the given set the difference between the consecutive terms is 9 i.e.
Based on same pattern out of given options:
A) (36, 45, 32) ⇒ 36 – 45 = -9 & 45 – 32 = 13
B) (29, 20, 11) ⇒ 29 – 20 = 9 & 20 – 11 = 9
C) (30, 21, 11) ⇒ 30 – 21 = 9 & 21 – 11 = 10
D) (28, 17, 8) ⇒ 28 – 17 = 11 & 17 – 8 = 9
Thus only (29, 20, 11) follows the same pattern as similar to given set.

APSC JE CE Paper 2 Mock Test - 3 - Question 13

A mild steel wire is 10 mm in diameter and 1 mm long. If a wire is subjected to an axial tensile load of 10 kN, find the extension in the rod. (Take E = 200 x 109)

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 13
(Elongation =PL/AE)

(=100×100×1/A×200×109(m))

(A=π/4(d2)=π/4×(10×10−3)2m2)

(=7.85×10−5m2)

( Elongation =10×1000×1/7.85×10−5×200×109)

(=6.369×10−4m)(=0.64nm)

Hence the option C is correct.

APSC JE CE Paper 2 Mock Test - 3 - Question 14

Shrinkage in concrete can be reduced by using-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 14
Shrinkage can be reduced by using the maximum practical amount of aggregate in the mixture. The lowest water-to-cement ratio is important to avoid this type of shrinkage.

Hence the option D is correct.

APSC JE CE Paper 2 Mock Test - 3 - Question 15

The coefficient of uniformity (Cu)for well graded gravel is

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 15
For well-graded gravel, (Cu>4)

For well-graded sand Cu>6

It cannot be less than 1

Hence the correct answer is option B.

APSC JE CE Paper 2 Mock Test - 3 - Question 16

According to IS code, the flexural strength in (N/mm2) is given as:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 16
Flexural strength of and modulus of elasticity is given as

Hence the correct answer is option B.

APSC JE CE Paper 2 Mock Test - 3 - Question 17

Compaction generally increases the

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 17
Compaction means pressing the soil particles close to each other by mechanical methods. Air during compaction is expelled from the void space in the soil mass, and then the mass density is increased. It is also useful in reducing the compressibility and permeability of the soil.

Hence the correct answer is option D.

APSC JE CE Paper 2 Mock Test - 3 - Question 18

Two blocks A and B, each of mass m, are placed on a smooth horizontal surface. Two horizontal forces F and 2F, are applied on blocks A and B, respectively, as shown in Figure. Block a does not slide on block B. Then the normal reaction acting between the two blocks in (assume no friction between the blocks).

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 18
Consider Both masses as a system,

Total force on system FT​ = 2F − F = F (Left side)

Mass of system M = 2m

Acceleration of two mass system is a = f/2m towards left free body diagram is

N cos 60 − F = ma

N = 3F

Normal reaction acting between two blocks = N = 3F

Hence, option (D) is the correct answer.

APSC JE CE Paper 2 Mock Test - 3 - Question 19

As per codal provisions, the effective buckling length of a cantilever steel column of length L is given by

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 19
According to the codal provisions, the effective buckling length of a cantilever steel column of L is given by 2L.

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 3 - Question 20

As per the Indian soil classification system, inorganic slits of high Compressibility is defined by the symbol-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 20
As per the Indian soil classification system, inorganic slits of high Compressibility is defined by the symbol-MH
APSC JE CE Paper 2 Mock Test - 3 - Question 21

The shape of the vertical curve generally provided is-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 21
In the case of a parabolic curve, it is easy to work out the minimum sight distance, which is an important factor to be considered while calculating the length of the vertical curve.
APSC JE CE Paper 2 Mock Test - 3 - Question 22

The best-suited rolled steel section for a tension member is

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 22

The best-suited rolled steel section for a tension member is T-section.

APSC JE CE Paper 2 Mock Test - 3 - Question 23

The detention period for oxidation bonds is usually kept as :

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 23
between 10 to 15 days

Oxidation ponds have a long detention period between 10 to 15 days. Explanation: The BOD removal efficiency of an oxidation pond lies between 80% and 90%, so the maximum BOD removal efficiency is 90%.

APSC JE CE Paper 2 Mock Test - 3 - Question 24

Crushing strength of good building stone should be more than:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 24
Crushing strength or compressive strength of a stone is the load per unit area where the stone starts cracking. It should be greater than 1000 kg/cm2 to ensure sufficient strength for use in construction.
APSC JE CE Paper 2 Mock Test - 3 - Question 25

A manhole is generally provided at each:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 25
A manhole is generally provided at each:
  • Bend

  • Junction

  • Change of gradient

APSC JE CE Paper 2 Mock Test - 3 - Question 26

Settlement of soil under compressive force due to the expulsion of water from pores is known as -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 26
Settlement of soil under compressive force due to the expulsion of water from pores is known as primary consolidation.
APSC JE CE Paper 2 Mock Test - 3 - Question 27

Consider the following statement:

A) Sprinkler method of irrigation has a higher water application efficiency.

B) The duty of drip irrigation is very high due to losses are least in this irrigation system.

Which of the following is/are correct?

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 27
Sprinkler Irrigation

In this method of irrigation, water is delivered through a network of pipes and pumps.

Water is available in form of the spray.

It also reduces seepage losses and other losses.

Hence, the Sprinkler method of irrigation has a higher water application efficiency.

Drip Irrigation:

This method is also called Trickling irrigation.

In this method of irrigation water is directly applied to the root zone of the plant using the drip nozzle.

Evaporation and percolation losses are considerably reduced in this method.

Hence, the duty of drip irrigation is very high.

APSC JE CE Paper 2 Mock Test - 3 - Question 28

Aggregates affecting the durability of concrete most are:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 28
The aggregate is said to be flaky when its least dimension is less than 3/5th (or 60%) of its mean dimension. Flaky aggregates are crushed easily and hence unsuitable for concrete.
APSC JE CE Paper 2 Mock Test - 3 - Question 29

As per the working stress method of reinforced concrete design, if a concrete has permissible compressive stress of p, then the modular ratio is approximately given as:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 29

Modular ratio is given by

APSC JE CE Paper 2 Mock Test - 3 - Question 30

Which of the following statements is true?

Detailed Solution for APSC JE CE Paper 2 Mock Test - 3 - Question 30
Toughness is the ability of a material to absorb energy and plastically deform without fracturing. It is the amount of energy per unit volume that a material can absorb before rupturing.

Proof resilience is defined as the maximum energy that can be absorbed within the elastic limit, without creating a permanent distortion.

The modulus of resilience is defined as the maximum energy that can be absorbed per unit volume without creating a permanent distortion (i.e. The proof resilience per unit volume of a body is called modulus of resilience).

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