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APSC JE CE Paper 2 Mock Test - 5 - Civil Engineering (CE) MCQ


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30 Questions MCQ Test - APSC JE CE Paper 2 Mock Test - 5

APSC JE CE Paper 2 Mock Test - 5 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The APSC JE CE Paper 2 Mock Test - 5 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The APSC JE CE Paper 2 Mock Test - 5 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for APSC JE CE Paper 2 Mock Test - 5 below.
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APSC JE CE Paper 2 Mock Test - 5 - Question 1

The shape of the bending moment diagram for a uniformly distributed load is:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 1
The equation for a bending moment of a UDL acting on a beam is of the order of 2nd degree, which in mathematical terms is represented by a parabola.
APSC JE CE Paper 2 Mock Test - 5 - Question 2

A two hinged arch is statically indeterminate by

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 2
Two-hinged arch is the statically indeterminate structure to degree one. Usually, the horizontal reaction is treated as redundant and is evaluated by the method of least work.
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APSC JE CE Paper 2 Mock Test - 5 - Question 3

The beam shown in the figure is:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 3
(Here re = 6)

(Dse = 6 - 3 = 3)

APSC JE CE Paper 2 Mock Test - 5 - Question 4

Plastic asphalt is -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 4
Plastic asphalt = a mixture of cement and asphalt.

Mastic asphalt = used for damp proof and waterproof layer.

Plastic bitumen = used for filling cracks in masonry structure using asbestos powder as a filler.

APSC JE CE Paper 2 Mock Test - 5 - Question 5

Venturimeter is advantageous because:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 5
Venturimeter is advantageous because

(→) It has a much smaller head loss

(→) Its coefficient of discharge ((Cd=0.98)) is more

(→) Its accuracy is quite good.

APSC JE CE Paper 2 Mock Test - 5 - Question 6

The detention period for oxidation ponds is usually kept is -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 6
Oxidation ponds have a long detention period between 10 to 15 days.The BOD removal efficiency of an oxidation pond lies between 80% and 90%, so the maximum BOD removal efficiency is 90%.
APSC JE CE Paper 2 Mock Test - 5 - Question 7

Rocks having alumina or clay as their major constituent are called -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 7
Rocks are classified into three categories

1. Argillaceous rocks: the chief constituent of argillaceous rocks is clay Alumina (Al2O3). Slate and laterite are its example.

2. Silicious Rocks: The chief constituent of silicious rocks is sand (silica, (Sio2 ) ). Quartzite and Granite are its examples.

3. Calcareous Rock: The chief constituent of calcareous rocks is lime. Its examples are Limestone and marble.

APSC JE CE Paper 2 Mock Test - 5 - Question 8

The commonly used thinner in oil points is -

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 8
Solvents of oil paints are used to thin the paints, increase the spread, and are also known as thinner. They make the paint of workable consistency and evaporate during drying of the film.

For example, petroleum, spirit, naphtha, and turpentine oil are used for common thining agents.

APSC JE CE Paper 2 Mock Test - 5 - Question 9

Directions: Select the related letters from the given alternatives.
ACFJ : EGJN ∷ IKNR : ?

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 9

The pattern here is as follows,

Hence the required term is MORV.

APSC JE CE Paper 2 Mock Test - 5 - Question 10

Cohensionless soil is

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 10

Cohesionless soils are defined as any free-running type of soil, such as sand or gravel, whose strength depends on friction between particles (measured by the friction angle, Ø).

APSC JE CE Paper 2 Mock Test - 5 - Question 11

A plate load test is used to determine

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 11

A plate load test is used to determine are bearing capacity of foundations and settlement of foundations.

APSC JE CE Paper 2 Mock Test - 5 - Question 12

The life of teakwood doors and windows is usually taken to be ______.

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 12

teak wood doors & windows has great properties to withstand extreme climatic conditions & it is free from knots & shakes. It’s durability is high usually taken as 40 years.

APSC JE CE Paper 2 Mock Test - 5 - Question 13

The characteristic strength of concrete is defined as that strength below which not more than —— of the test results are expected to fall-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 13
The characteristic strength is defined as the material below which not more than 5 percent of the test results are expected to fall.

Hence the option B is correct.

APSC JE CE Paper 2 Mock Test - 5 - Question 14

Bulking of sand is-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 14
Bulking: The increase in the volume of a given mass of fine aggregate caused by the presence of water is known as bulking.

The extent of bulking depends upon the percentage of moisture present in sand and its fineness. Bulking of sand is more in fine sand.

Hence the option D is correct.

APSC JE CE Paper 2 Mock Test - 5 - Question 15

Mohr’s circle can be drawn only for:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 15
A Mohr’s circle is a graphical representation of stress and strain acting on any plane in the body.

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 5 - Question 16

Major principal stress at A point is 200 MPa. The radius of Mohr’s stress circle is 50MPa. What is the minor principal stress at the point?

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 16
(σ1 = 200)

σ1 − σ3 =100

Hence,(σ3 = 200 − 100 = 100MPa)

Hence correct answer is option B.

APSC JE CE Paper 2 Mock Test - 5 - Question 17

The property of the stones to withstand the adverse action of weather is known as

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 17
The stone used in pavement construction should be durable and should resist disintegration due to the action of the weather. The aggregates are subjected to the physical and chemical activity of rain and groundwater and also the atmosphere. Hence the road stones used in the construction should be sound enough to withstand the weathering action.

Hence the correct answer is option B.

APSC JE CE Paper 2 Mock Test - 5 - Question 18

Which method is an accurate estimate of average rainfall in a particular catchment area

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 18
Isohyetal method is suitable for all types of catchment without any pre-condition.The isohyetal method is used to estimate the mean precipitation across an area by drawing lines of equal precipitation. In the isohyetal method, precipitation values are plotted at their respective stations on a suitable base map.

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 5 - Question 19

Identify which of the following items is not considered while designing rigid pavements.

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 19
Edge of panel items are not considered when designing rigid pavements.

Hence the correct answer is option B.

APSC JE CE Paper 2 Mock Test - 5 - Question 20

All R.C. columns must be designed for a minimum eccentricity of

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 20

As per Is 456: 2000, Clause 25.4

All columns shall be designed for minimum eccentricity equal to the unsupported length of column / 500 plus lateral dimension / 30, subject to a minimum of 20 mm. The minimum eccentricity is incorporated in the design equation recommended in IS 456 for axially loaded compression members.

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 5 - Question 21

Fully oxidized sewage, contains nitrogen in the form of-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 21
Oxidized forms of nitrogen include nitrite (NO2) and nitrate (NO3). Nitrogen mainly occurs in wastewater in this form. Because nitrite is easily oxidized to nitrate, nitrate is the compound predominantly found in groundwater and surface waters.
APSC JE CE Paper 2 Mock Test - 5 - Question 22

Three-point problem can be solved by-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 22
Three-point problem can be solved by-

Taking paper method

Lehman’s rule

Bessel's rule

APSC JE CE Paper 2 Mock Test - 5 - Question 23

The exit gradient of the seepage water through soil is-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 23
The loss of head per unit length of low through the soil is equal to the exit gradient (i), = i = h/L
APSC JE CE Paper 2 Mock Test - 5 - Question 24

Pick the correct statement with regard to super sulphated Cement:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 24
Its most important property is low total heat of hydration. It is, therefore, very suitable for the construction of dams and mass concrete work. Concrete made from super sulphated cement may expand if cured in water and may shrink if the concrete is cured in air. In contrast, a significant advantage of Super sulphated Cement is that it has comparatively high resistance to chemical attack.
APSC JE CE Paper 2 Mock Test - 5 - Question 25

Los Angeles machine is used to test the aggregate for-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 25
Los Angeles Abrasion Test on Aggregates -Values for Pavements and Roads. Los Angeles abrasion test on aggregates is the measure of aggregate toughness and abrasion resistance such as crushing, degradation and disintegration.
APSC JE CE Paper 2 Mock Test - 5 - Question 26

According to IS: 875 Part 3, desiring wind speed is obtained by multiplying the basic wind speed by factors (k1,k2) and (k3), where (k3) is-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 26
According to IS: 875 Part 3, desiring wind speed is obtained by multiplying the basic wind speed by factors (k1,k2) and (k3), where (k3) is the topography factor.

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 5 - Question 27

The only suitable method for hardening the low carbon steel is case hardening. Which of the following is a case hardening process?

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 27
Cyaniding is a case-hardening process that is fast and efficient; it is mainly used on low-carbon steels. The part is heated to 871–954 °C (1600–1750 °F) in a bath of sodium cyanide and then is quenched and rinsed, in water or oil, to remove any residual cyanide.

Hence, the correct option is (A)

APSC JE CE Paper 2 Mock Test - 5 - Question 28

Maximum value of superelevation provided in the design of horizontal alignment of a highway-

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 28
Acc to IRC the max value of superelevation to be provided is 0.07.

The maximum superelevation for a roadway section depends on climatic conditions, type of terrain, and type of development. Roadways in rural areas are typically designed with a maximum superelevation rate of 8 percent.

Hence, the correct option is (A)

APSC JE CE Paper 2 Mock Test - 5 - Question 29

The period of cleaning of a slow sand filter is usually:

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 29
Slow sand filter: They consist of fine sand, supported by gravel. They capture particles near the surface of the bed and are usually cleaned by scraping away the top layer of sand that contains the particles.

Cleaning:

  • For cleaning, the top layer of sand is scrapped and 1.5 to 3 cm of sand is removed in each cleaning.

  • The frequency of cleaning is 1 to 3 months.

  • The rate of filtration is 100-200 l/hr/m2 of filter area.

  • It is used for smaller plants in villages.

Rapid sand Filter: They consist of larger sand grains supported by gravel and capture particles throughout the bed. They are cleaned by backwashing water through the bed to 'lift out' the particles.

Cleaning:

  1. Cleaning of the filter can also be done using surface wash but it should be accompanied by backwash.

  2. Washing period = 24 to 48 hrs.

APSC JE CE Paper 2 Mock Test - 5 - Question 30

What will be the thermal stress (in MPa) developed in a rod having a diameter of 4 cm and length of 2 m. It experiences heating from temperature 50°C to 200°C. The coefficient of thermal expansion is α = 10 × 10-6/°C and young’s modulus is 250 GPa?

Detailed Solution for APSC JE CE Paper 2 Mock Test - 5 - Question 30

Thermal stresses are the stresses induced in a body due to changes in temperature.

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