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APSC AE CE Paper 1 Mock Test - 5 Free Online Test 2026


Full Mock Test & Solutions: APSC AE CE Paper 1 Mock Test - 5 (100 Questions)

You can boost your Civil Engineering (CE) 2026 exam preparation with this APSC AE CE Paper 1 Mock Test - 5 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of Civil Engineering (CE) 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 120 minutes
  • - Total Questions: 100
  • - Analysis: Detailed Solutions & Performance Insights

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APSC AE CE Paper 1 Mock Test - 5 - Question 1

Tricalcium aluminate C3A

Detailed Solution: Question 1

Tricalcium aluminate ((C3A)) has lost resistance to sulfate attack.

APSC AE CE Paper 1 Mock Test - 5 - Question 2

The variation in declination due to magnetic storms is called

Detailed Solution: Question 2

Diurnal: It is a daily variation which changes with locality, season (more in summertime, more in day time)

Annual Variation: Yearly swing 1' or 2' in amplitude, it varies from place to place

Secular Variation: Has periodic character, (Pd. 250 years)

APSC AE CE Paper 1 Mock Test - 5 - Question 3

The maximum shear force in a cantilever beam with uniformly distributed load W per unit length, over the whole length L, is

Detailed Solution: Question 3

The maximum shear force in a cantilever beam with uniformly distributed load W per unit length, over the whole length L, is at the fixed end.

APSC AE CE Paper 1 Mock Test - 5 - Question 4

The standard size of modular brick is -

Detailed Solution: Question 4

The standard size of modular bricks is 19 cm×9 cm× 9 cm. So, the size of a brick with mortar becomes 20 cm× 10 cm × 10 cm.

APSC AE CE Paper 1 Mock Test - 5 - Question 5

Rocks having alumina or clay as their major constituent are called -

Detailed Solution: Question 5

Rocks are classified into three categories

1. Argillaceous rocks: the chief constituent of argillaceous rocks is clay Alumina (Al2O3). Slate and laterite are its example.

2. Silicious Rocks: The chief constituent of silicious rocks is sand (silica, (Sio2 ) ). Quartzite and Granite are its examples.

3. Calcareous Rock: The chief constituent of calcareous rocks is lime. Its examples are Limestone and marble.

APSC AE CE Paper 1 Mock Test - 5 - Question 6

The moisture content of soil below which the soil volume becomes constant is called the -

Detailed Solution: Question 6

The maximum water content at which a reduction in water content does not cause an appreciable decrease in volume of the soil mass.

We know

(W=S⋅e/G)

Where W = Water content

G = Specific gravity

e = Void ratio

For maximum water content, degree of saturation is 100%, i.e. S = 1

Then = Wa = e/G

APSC AE CE Paper 1 Mock Test - 5 - Question 7

The commonly used thinner in oil points is -

Detailed Solution: Question 7

Solvents of oil paints are used to thin the paints, increase the spread, and are also known as thinner. They make the paint of workable consistency and evaporate during drying of the film.

For example, petroleum, spirit, naphtha, and turpentine oil are used for common thining agents.

APSC AE CE Paper 1 Mock Test - 5 - Question 8

If A + B means A is the son of B; A – B means A is the husband of B; A × B means A is the sister of B, then which of the following shows the relation P is nephew of Q?

Detailed Solution: Question 8

P + B – R × Q
P + B ⇒ P is son of B
B - R ⇒ B is husband of R
R × Q ⇒ R is sister of Q

Hence, P is the nephew of Q
P – B + R × Q
P - B ⇒ P is husband of B
B + R ⇒ B is son of R

This is not possible as B is wife of P, B cannot be son of anyone.
P + B × R – Q
P + B ⇒ P is son of B
B × R ⇒ B is sister of R
R + Q ⇒ R is son of Q

This is not possible as Q is mother or
father of R, Q cannot be uncle of anyone.
P × B – R + Q
P × B ⇒ P is sister of B
B - R ⇒ B is husband of R
R + Q ⇒ R is son of Q

This is not possible as R is wife of B, R cannot be son of anyone.

APSC AE CE Paper 1 Mock Test - 5 - Question 9

Directions: A pair of number is given. Select the pair which shows the similar relationship that is shown by the given pair. 1984 : 4891

Detailed Solution: Question 9

The pattern is as follows,
1984 is the reverse of 4891
Similarly, 2874 is the reverse of 4782.
Hence the required pair is 2874 : 4782.

APSC AE CE Paper 1 Mock Test - 5 - Question 10

The type of mortar which is used for the construction works carried out in water-logged area is _____.

Detailed Solution: Question 10

Water logged area means where the irrigation of water is high. For construction in this area we use the cement mortar.
Cement mortar use to hold building materials such as brick or stone together. In this water to cement ratio is higher.

APSC AE CE Paper 1 Mock Test - 5 - Question 11

The life of teakwood doors and windows is usually taken to be ______.

Detailed Solution: Question 11

teak wood doors & windows has great properties to withstand extreme climatic conditions & it is free from knots & shakes. It’s durability is high usually taken as 40 years.

APSC AE CE Paper 1 Mock Test - 5 - Question 12

Irrigation efficiency of an irrigation system is the ratio of

Detailed Solution: Question 12

It is defined as the ratio between the amount of water utilized (i.e., used to meet the consumptive use requirement of crop plus that necessary to maintain a favorable salt balance in the crop root zone) to the total volume of water diverted, stored or pumped for irrigation.

APSC AE CE Paper 1 Mock Test - 5 - Question 13

Water required grade bag of cement is-

Detailed Solution: Question 13

Normal range for the amount of water used to mix each 50 kg bag of cement is between 20 liters and 30 liters.

Hence option (C) will be correct.

APSC AE CE Paper 1 Mock Test - 5 - Question 14

The purpose of lateral ties in short concrete columns is-

Detailed Solution: Question 14

The purpose of lateral ties in short concrete columns is to avoid buckling of longitudinal bars.

Hence the option A is correct.

APSC AE CE Paper 1 Mock Test - 5 - Question 15

Minimum thickness of main steel members, not exposed to the weather is-

Detailed Solution: Question 15

Where steelwork is directly exposed to weather, the steel is directly exposed to weather and is fully accessible for cleaning and repainting. The thickness shall be not less than 6 mm.

The steel is directly exposed to weather and is not accessible for cleaning and repainting. The thickness shall be not less than 8 mm. These provisions do not apply to the web of Indian standard rolled steel joists and channels to packings.

Steelwork not Directly Exposed to Weather. The thickness of steel in main members not directly exposed to weather shall be not less than 6 mm.

The thickness of steel in secondary members not directly exposed to weather shall be not less than 4-5 mm.

Hence the option B is correct.

APSC AE CE Paper 1 Mock Test - 5 - Question 16

The load factors for live load and dead load are-

Detailed Solution: Question 16

The load factors for live load and dead load are 2.2 and 1.5, respectively. The load factor for the dead load will always be less than the load factor for the live load.

Hence the option B is correct.

APSC AE CE Paper 1 Mock Test - 5 - Question 17

The coefficient of uniformity (Cu)for well graded gravel is

Detailed Solution: Question 17

For well-graded gravel, (Cu>4)

For well-graded sand Cu>6

It cannot be less than 1

Hence the correct answer is option B.

APSC AE CE Paper 1 Mock Test - 5 - Question 18

IS code for designing pile foundation is :

Detailed Solution: Question 18

Following are the Indian Standard Codes on Pile Foundations: IS 2911: Part 1: Sec 1: 1979 Driven cast-in-situ concrete piles. IS 2911: Part 1: Sec 2: 1979 Bored cast-in-situ piles. IS 2911: Part 1: Sec 3: 1979 Driven precast concrete pile.

Hence the correct answer is option A.

APSC AE CE Paper 1 Mock Test - 5 - Question 19

Warping stresses in a C.C. Pavement are due to:

Detailed Solution: Question 19

Warping stress is due to daily variation in temperature, whereas frictional stress is due to seasonal variation of temperature.

Hence the correct answer is option A.

APSC AE CE Paper 1 Mock Test - 5 - Question 20

The ratio of the rate of change of discharge of the outlet to the rate of change of discharge of the distributor channel is known as -

Detailed Solution: Question 20

Flexibility: It provides criteria for judging the behaviour of modules and semi-modules. It is generally denoted by the letter 'F.,’ The ratio of the rate of change of outlet discharge to the rate of change of discharge of the parent channel.

Hence the correct answer is option C

APSC AE CE Paper 1 Mock Test - 5 - Question 21

The oxidant used for the determination of COD in-

Detailed Solution: Question 21

In the laboratory determination of COD, a strong oxidant like potassium dichromate (K2Cr2O7)or Potassium Permanganate (KMnO4) is used.

Hence the correct answer is option C.

APSC AE CE Paper 1 Mock Test - 5 - Question 22

In the WCB system, a line is said to be free from the local attraction if the difference between the FB and BB is-

Detailed Solution: Question 22

FB ± BB = 180o

If not, then it indicates an error caused due to local attraction.

Hence the correct answer is option C.

APSC AE CE Paper 1 Mock Test - 5 - Question 23

For the irrigation of a crop, the base period B (in days), depth of water ∆ (in metres) are related to the duty D (in ha/cumec) at the field as

Detailed Solution: Question 23

For the irrigation of a crop, the base period B (in days), depth of water ∆ (in metres) are related to the duty D (in ha/cumec) at the field as

(D = 0.64B/∆)

Hence the correct answer is option C.

APSC AE CE Paper 1 Mock Test - 5 - Question 24

According to IS: 383, the coarsest sand falls under the grading zone

Detailed Solution: Question 24

According to IS: 383, coarse sand grading zones fall under II.

Hence the correct answer is option B.

APSC AE CE Paper 1 Mock Test - 5 - Question 25

All R.C. columns must be designed for a minimum eccentricity of

Detailed Solution: Question 25

As per Is 456: 2000, Clause 25.4

All columns shall be designed for minimum eccentricity equal to the unsupported length of column / 500 plus lateral dimension / 30, subject to a minimum of 20 mm. The minimum eccentricity is incorporated in the design equation recommended in IS 456 for axially loaded compression members.

Hence the correct answer is option C.

APSC AE CE Paper 1 Mock Test - 5 - Question 26

The minimum cover in a slab should neither be less than the diameter of the bar nor less than

Detailed Solution: Question 26

For Mild exposure – 20 mm

For Moderate exposure – 30 mm

However, if the diameter of the bar does not exceed 12 mm, or cover may be reduced by 5 mm. Thus for main reinforcement up to 12 mm diameter bar and for mild exposure, the nominal cover is 15 mm.

Hence the correct answer is option C.

APSC AE CE Paper 1 Mock Test - 5 - Question 27

The mean hydraulic depth (where A = area and P = wetted perimeter) is given by

Detailed Solution: Question 27

The mean hydraulic depth (where A = area and P = wetted perimeter) is given by (A/P)

APSC AE CE Paper 1 Mock Test - 5 - Question 28

For a tachometer, the additive and multiplying constants are:

Detailed Solution: Question 28

The formula most widely used for finding the distances is

d = k × s + c.

Here, s is the stadia interval (top intercept minus bottom intercept); k and c are additive and multiplicative constants. Generally, the instrument is made so that k = 100 and c = 0 to simplify calculations.

APSC AE CE Paper 1 Mock Test - 5 - Question 29

Among the following, which is/are not pre-treatment units?

Detailed Solution: Question 29

A pre-treatment is necessary in order to protect raw water lifting systems and pipelines against blockages as well as other treatment equipment against abrasion and, more generally, to remove anything that might interfere with subsequent treatment.
  • bar screening;

  • straining;

  • comminution;

  • grit removal

  • Flow equalization chamber

  • Proportion tank

  • Neutralization for pH adjustment tank

Nutrient removal tank is the secondary treatment process.

APSC AE CE Paper 1 Mock Test - 5 - Question 30

Which one of the following statements is correct?

Detailed Solution: Question 30

Modes of shear failure in Prestressed concrete beam are web shear cracking, Flexure-shear cracking. Shear design for a prestressed concrete beam is based on elastic theory.

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