Electronics and Communication Engineering (ECE) Exam  >  Electronics and Communication Engineering (ECE) Test  >  MPPGCL JE Electronics Mock Test Series 2026  >  MPPGCL JE Electronics Mock Test - 3 - Electronics and Communication Engineering (ECE) MCQ

MPPGCL JE Electronics Mock Test - 3 Free Online Test 2026


Full Mock Test & Solutions: MPPGCL JE Electronics Mock Test - 3 (100 Questions)

You can boost your Electronics and Communication Engineering (ECE) 2026 exam preparation with this MPPGCL JE Electronics Mock Test - 3 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of Electronics and Communication Engineering (ECE) 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 120 minutes
  • - Total Questions: 100
  • - Analysis: Detailed Solutions & Performance Insights
  • - Sections covered: Electronics, General Awareness and Aptitude

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MPPGCL JE Electronics Mock Test - 3 - Question 1

Limitation(s) of control is (are)

Detailed Solution: Question 1

Controlling can be defined as that function of management that helps to seek planned results from the subordinates, managers, and at all levels of an organization. The controlling function helps in measuring the progress towards the organizational goals & brings any deviations, & indicates corrective action.

Key Points

Limitations of Controlling:

1. Difficulty in setting quantitative standards:

  • Control system loses its effectiveness when the standard of performance cannot be defined in quantitative terms and it is very difficult to set the quantitative standard for human behavior, efficiency level, job satisfaction, employee’s morale, etc.
  • In such cases, judgment depends upon the discretion of the manager.

2. No control on external factors:

  • An enterprise cannot control external factors due to its variation and causes such as government policy, technological changes, change in fashion, change in competitor’s policy, etc.

3. Resistance from employees:

  • Employees often resist control and as result effectiveness of control reduces.
  • Employees feel control reduces or curtails their freedom.
  • Employees may resist and go against the use of cameras, to observe them minutely.

4. Costly affair:

  • Control is an expensive process it involves a lot of time and effort as sufficient attention has to be paid to observe the performance of the employees.
  • To install an expensive control system organizations have to spend a large amount.
  • Management must compare the benefits of controlling systems with the cost involved in installing them.
  • The benefits must be more than the cost involved then only controlling will be effective otherwise it will lead to inefficiency.

Therefore, option 4 is the correct answer.

MPPGCL JE Electronics Mock Test - 3 - Question 2

Which of the following instrument is used in an airplane to measure its height above the ground?

Detailed Solution: Question 2

  • The radar altimeter measures absolute altitude, i.e. the altitude that the aircraft is above the ground (Above ground level)
  • The radar altimeter system sends out a radio wave, and that radio wave bounces off the ground and is received.
  • AGL is computed by taking the speed of the radio wave and the amount of time for it to return.
  • Unlike radar, the signal is not pulsed, but is Frequency modulated and is transmitted at 4300 MHz at 350 milliwatts.
  • Radar Altimeters operate between - 20 and 2500 feet.

          

MPPGCL JE Electronics Mock Test - 3 - Question 3

The average value of the waveform is:

Detailed Solution: Question 3

Concept:

The average value of a periodic waveform is given as

It is also calculated by calculating the area of the given waveform.

Where A is the area

Calculation:

The given figure consists of rectangular pulses.

Area of rectangle = L × B

Where L = Length

B = Breadth

MPPGCL JE Electronics Mock Test - 3 - Question 4

A loss-less transmission line having characteristic impedance of 100 ohm is connected to a load of 200 ohm. The voltage reflection coefficient is:

Detailed Solution: Question 4

Concept:

The reflection coefficient gives the percentage of incident voltage reflected from the load.

Mathematically, this is defined as:

Γ = Reflection coefficient

Z= Load Impedance

Zo = Characteristic Impedance.

Application:

Given Z0 = 100 Ω and ZL = 200 Ω

Voltage reflection coefficient will be:

MPPGCL JE Electronics Mock Test - 3 - Question 5

In Ethernet Frame Format number of bits needed in Frame check sequence Field?

Detailed Solution: Question 5

A frame check sequence (FCS) refers to an error-detecting code added to a frame in a communications protocol

Layer 2 Frame Format:

Ethernet Frame Format consists of Cyclic Redundancy Check (CRC) in Frame check sequence Field.

CRC size → 4 bytes

1 byte = 8 bit

∴ 4 byte = 4 × 8 bits = 32 bits

MPPGCL JE Electronics Mock Test - 3 - Question 6

Hay’s bridge is used for measuring:

Detailed Solution: Question 6

Hay’s bridge is used for measurement of inductance of coils with high quality factor.

MPPGCL JE Electronics Mock Test - 3 - Question 7

Two incandescent light bulbs of 40 W and 60 W rating are connected in series across the mains, then

Detailed Solution: Question 7

Concept:

We know that

P = I2R

Where 

P = Power 

I = Current

R = Resistance

In this, the current through the bulbs is fixed.

The resistance of the bulb is inversely proportional to the wattage of the bulb.

Calculation:

Given

R60 < R40

The resistance of 40 W is more than 60 W bulbs.

Hence R60 Consumes less power and is less bright

So, the 40 bulb glows brighter.

MPPGCL JE Electronics Mock Test - 3 - Question 8

If a transmission line is terminated with a resistance equal to its characteristic impedance

Detailed Solution: Question 8

Concept:

The voltage standing wave ratio is defined as the ratio of the maximum voltage (or current) to the minimum voltage (or current).

VSWR is also given by:

Γ = Reflection coefficient, defined as:

ZL = Load impedance

Z0 = Characteristic Impedance

For ΓL varying from 0 to 1, VSWR varies from 1 to ∞.

Application:

Given ZL = Z0

The reflection coefficient is calculated to be:

VSWR for Γ = 0 equals 1, which is the minimum value (because it varies from 1 to ∞)

MPPGCL JE Electronics Mock Test - 3 - Question 9

Class C amplifier operates

Detailed Solution: Question 9

Class C amplifier:

  • Class C power amplifier is a type of amplifier where the active element (transistor) conduct for less than one-half cycle of the input signal.
  • Less than one-half cycle means the conduction angle is less than 180° and its typical value is 80° to 120°.
  • The reduced conduction angle improves the efficiency to a great extends but causes a lot of distortion.
  • The theoretical maximum efficiency of a Class C amplifier is around 90%.
  • In a Class C Amplifier efficiency and distortion, both are maximum.

Important Point

MPPGCL JE Electronics Mock Test - 3 - Question 10

The contents to the register pair DE after the execution of the following Intel 8085 instructions, is

PUSH H; PUSH D; POP H; POP D

Detailed Solution: Question 10

PUSH RP (Pre-decrement):

This instruction copies the contents of RP to stack.

For every PUSH:

  • Decrement SP and PUSH RPH
  • Decrement SP and PUSH RPL

POP RP (Pre-increment):

Used for retrieving the elements stored in the stack.

For every POP:

  • Get 1 byte from stack to RPL and increment.
  • Get 1 byte from stack to RPH and increment.

Let stack pointer (SP) = FFFF H and DE = 3025H ; HL = B315H

(a) PUSH H and

(b) PUSH D are as shown:

PUSH D: contents of DE register is copied to (FFFC and FFFB) H

PUSH H: contents of HL = B315 register, is copied to (FFFE & FFFD)H

Similarly,

c) POP J and

d) POP D are as shown:

POP H retrieves the contents to HL register

POP D: retrieves the contents to the DE register.

∴ After the execution of instructions, the contents of the DE register pair is DE = B315 H, which is

equal to HL before execution.

[H] → [D]

[L] → [E]

MPPGCL JE Electronics Mock Test - 3 - Question 11

Following constellation diagram represents:

Detailed Solution: Question 11

  • PSK: It stands for phase shift keying.
  • In PSK, binary 1 is represented with the actual carrier, and 0 is represented with the 180o phase shift of carrier.
  • 1 is represented as  s(t) = Accos(2πfct)
  • 0 is represented as  s(t) = - Accos(2πfct)
  • As in PSK, one bit is transmitted in a specific time constant.
  • Similarly, in 16 PSK, log2(16) = 4 bits are transmitted in a specific time constant which is known as 16-ary PSK.

B.W. of PSK = 2Rb

Whereas for M-ary PSK,

Hence M-ary is preferred due to less bandwidth.

  • In 16 APSK, Amplitude and Phase both vary in a pattern as shown in the figure.
  • 16 QAM is a signal in which two carriers shifted in phase by 90 degrees are modulated and combined. As a result of their 90° phase difference, they are in quadrature.
  • Often one signal is called the In-phase or “I” signal, and the other is the quadrature or “Q” signal.

Hence the given figure is 16 QAM.

So the solution is option (2).

MPPGCL JE Electronics Mock Test - 3 - Question 12

Consider the RLC circuit shown below. At a certain frequency f0 the circuit behaves like a purely resistive circuit. The equivalent resistance of the parallel combination at that particular frequency f0 is.

Detailed Solution: Question 12

Concept:

Any given circuit will be at the resonant frequency when the net impedance is purely resistive.

Calculation:

Calculating the net-admittance of the given combination because the impedances are in parallel.

Ynet = Y1 + Y2

Replacing s with jω, we get;

At resonance, the imaginary part is zero and Ynet will be only real.

Given, R = 1Ω

L = 2μH

C = 1μF.

1 + ω02 (4μ2) = 2

ω02 × 4μ2 = 1

ω0 = 1/2μ = 0.5 M­rad/sec

Now,  at resonance:

Ynet = ½

Rnet = 2Ω

MPPGCL JE Electronics Mock Test - 3 - Question 13

The third-generation mobile phone are digital and based on

Detailed Solution: Question 13

There are three generations in cellular telephony.

  • First Generation: It was designed for voice communication using analog signals. Example: AMPS (Advanced mobile phone system) is one of the leading analog cellular system. It uses FDMA to separate channels in a link. AMPS operates in the ISM 800 MHz band.
  • Second Generation: To provide higher quality mobile voice communication, these generation of cellular phone are required. These are used for digital voice communication. Example: D- AMPS, CDMA, GSM. The product of evolution of analog AMPS into a digital system is digital AMPS. D-AMPS uses TDMA and FDMA. GSM stands for global system for mobile communication. It provides duplex communication by using two digital bands.
  • Third generation: It refers to a combination of technologies that provide a variety of services. It can provide both digital data and voice communication. Main goal of third generation cellular telephony is to provide universal personal communication. These are based on broadband CDMA. Example: IMT-DS, IMT-MC etc

MPPGCL JE Electronics Mock Test - 3 - Question 14

​Calculate the value of Norton's current and Norton's equivalent resistance for the given circuit across the terminal AB.

Detailed Solution: Question 14

Norton's Theorem :

Any linear bilateral network consisting of multiple resistances and sources can be replaced by a resistor Rin parallel of Current source IN .

Calculation:

RN : 

Disable all independent sources and find equivalent resistance.

R= ( 20 || 10 ) + 20 = 26.6 ohm

I:

Short circuited current

Let node voltage of 10 ohm is V

Apply nodal analysis

V = 2.5V

IN = V /20 = 125 mA

MPPGCL JE Electronics Mock Test - 3 - Question 15

Which of the following methods suitable for the stability analysis of sampled data control systems?

Detailed Solution: Question 15

Sampled data system:

When the signal or information at any or some points in a system is in the form of discrete pulses, then the system is called discrete data system or sampled data system.

The following methods suitable for the stability analysis of sampled data control systems.

  • Jury’s stability test
  • Root locus technique
  • Bilinear transformation

Merits:

  • Systems are highly accurate, fast and flexible
  • Use of time sharing concept of digital computer results in economical cost and space.
  • Digital transducers used in the system have better resolution.
  • The digital components are less affected by noise, non-linearities and transmission errors of noisy channel.

Demerits:

  • Conversion of analog signals to discrete-time signals and reconstruction introduce noise and errors in the signal.
  • Additional filters have to be introduced in the system if the components of the system does not have adequate filtering characteristics.

MPPGCL JE Electronics Mock Test - 3 - Question 16

How many 3 × 8 decoders are required to Construct a 4 × 16 decoder?

Detailed Solution: Question 16

Concept:

 A decoder is a combinational circuit that converts n lines of input into 2n lines of output.

Decoder expansion

Number of Ddecoder required is given as:

∑ K = K1 + K2 + K3 + ------ 

Calculation:

Given decoder 1 is 3 × 8 and the second decoder is 4 × 16

Number of 3 × 8 decoders = 2 + 0

Number of 3 × 8 decoders = 2

The implementation is shown below.

Important Point

MPPGCL JE Electronics Mock Test - 3 - Question 17

What is an operating system?

Detailed Solution: Question 17

The Correct Answer is Option (1) i.e A program.

  • An operating system is a software or a program that manages computer hardware, software resources, and provides common services for computer programs.
  • An operating system is an interface between the computer user and computer hardware.
  • The dominant desktop operating system is Microsoft Windows with a market of around 82.74%, followed by macOS by Apple Inc.
  • Some popular operating system include Linux operating system, Windows operating system, VMS, OS/400, macOS, etc.
  • Some of the important functions of an operating system are :
    • Memory Management
    • Processor Management
    • Device Management
    • File Management
    • Security
    • Job Accounting
    • Co-ordination between other software and users.

MPPGCL JE Electronics Mock Test - 3 - Question 18

In one of the pairs of protocols given below, both the protocols can use multiple TCP connections between the same client and the server. Which one is that?

Detailed Solution: Question 18

HTTP: Multiple TCP connections can be used at client and server end.

FTP: For FTP also multiple connections can be used at the same time.

TELENT: Only one TCP connection is allowed at a time.

SMTP: SMTP also allows only one TCP connection at a time.

MPPGCL JE Electronics Mock Test - 3 - Question 19

In a semiconductor device, if the Fermi level (EF) is positioned at the conduction band (Ec). Determine the approximate probability of finding electrons in states at (Ec + kT)

(where k is Boltzmann constant and T is device temperature in Kelvin)

Detailed Solution: Question 19

Concept:

In a semiconductor, the probability of finding an electron at an energy level E is given by:

EF = fermi level

Calculation:

Given, EF = EC

The probability of finding electrons in the energy level E = EC + KT will be:

f(EC + KT) = 0.268

MPPGCL JE Electronics Mock Test - 3 - Question 20

The Zeroth generation ‘0 G’ (0G) of mobile communication used:

Detailed Solution: Question 20

  • 0 Generation:

“0G” refers to pre-cellular mobile telephony technology, such as radio telephones that were used in cars before the advent of cell phones.

  • 1st Generation:

Analogue circuit-switched technology is used for this system, with frequency division multiple access (FDMA).

  • 2nd Generation:
  1. 2G systems are digital cellular systems
  2. 2G digital technology is divided into two standards: time division multiple access (TDMA) and code-division multiple access (CDMA)
  • 2.5 Generation:
  1. The mobile technology using GPRS standard has been termed as 2.5G
  2. Provided enhanced data rates for GSM evolution (EDGE)
  • 3rd Generation:
  1. The 3G technology added multimedia facilities to 2.5G phones
  2. Examples of 3G system are universal mobile telecommunication systems (UMTS) and international mobile telecommunications at 2,000 MHz (IMT-2000)

MPPGCL JE Electronics Mock Test - 3 - Question 21

The deflecting torque of a moving iron instrument is

Detailed Solution: Question 21

Moving Iron Instruments are the most common type of ammeter and voltmeter used at power frequencies in laboratories.

These instruments are very accurate, cheap, and rugged as compared to other AC instruments.

Working Principle of Moving Iron Instruments:

In Moving Iron Instruments, a plate or van of soft iron or of high permeability steel forms the moving element of the system.

The iron van is so situated that it can move in the magnetic field produced by a stationary coil.

The below figure shows a simple moving iron instrument.

The stationary coil is excited by the current or voltage under measurement.

When the coil is excited, it becomes an electromagnet, and the iron van moves in direction of offering a low reluctance path.

Thus the force of attraction is always produced in a direction to increase the inductance of the coil.

Mind that as the van follows the low reluctance path, the net flux in the air gap will increase which means increased flux linkage of the coil, and hence inductance of coil will increase.

It shall also be noticed that the inductance of the coil is variable and depends on the position of the iron van.

Torque Equation of Moving Iron Instruments:

Deflecting torque in Moving iron Instruments is given as

Td =  (1/2)I2(dL/dƟ)

In moving iron instruments, the controlling torque is provided by spring. Controlling torque due to spring is given as

Tc = KƟ

Where K = Spring constant

Ɵ = Deflection in the needle

In equilibrium state, deflecting and controlling torque shall be equal as below.

Deflecting Torque = Controlling Torque

⇒ Td = Tc

⇒ (1/2)I2(dL/dƟ) = KƟ

 Ɵ = (1/2)(I2/K)(dL/dƟ)

MPPGCL JE Electronics Mock Test - 3 - Question 22

If 1 is added to the denominator of a fraction it becomes 1/2. If 1 is added to the numerator it becomes 1. The product of numerator and denominator of the fraction is

Detailed Solution: Question 22

Let the numerator = x and denominator = y

y + 3 = 2y ⇒ y = 3

x +1= 3 ⇒ x = 2

∴ xy = 2 × 3 = 6

MPPGCL JE Electronics Mock Test - 3 - Question 23

Directions: Study the following question carefully and choose the right answer.

In a certain code ‘TERMINAL’ is written as ‘SDQLJOBM’. How is CREDIBLE written in that code?

Detailed Solution: Question 23


Hence, option A is correct.

MPPGCL JE Electronics Mock Test - 3 - Question 24

Direction: If a Paper (Transparent Sheet) is folded in a manner and a design or pattern is drawn. When unfolded this paper appears as given below in the answer figure. Choose the correct answer figure given below.

A round punched paper is given as shown in the question figure. Figure out from the four alternatives as to how it will appear when folded.
Question Figure

Answer figure

Detailed Solution: Question 24

MPPGCL JE Electronics Mock Test - 3 - Question 25

Directions: Read the given information carefully and answer the questions given beside:

A certain number of people are sitting in a row watching F1 racing. All of them are facing towards the south direction. The distance between any two adjacent persons is the same. 
The number of people sitting between A and C is the same as the number of people sitting between X and C. At most 25 people are sitting in a row. X is an immediate neighbour of D, who sits on one of the ends. Two people are sitting between A and Z. The number of people sitting between D and C is the same as the number of people sitting between C and Y. C sits fourth to the right of Z. The number of people sitting to the right of A is the same as the number of people sitting to the left of Z.

Q. Who sits two places away from Y?

Detailed Solution: Question 25

Following the common explanation, we get “C and Z sits two places away from Y”.
Hence, option D is correct.
Final Arrangement:

Common Explanation:
References:
1. Two people are sitting between A and Z.
2. C sits fourth to the right of Z.
3. The number of people sitting to the right of A is the same as the number of people sitting to the left of Z.
4. The number of people sitting between A and C is the same as the number of people sitting between X and C.
5. X is an immediate neighbour of D, who sits on one of the ends.
6. The number of people sitting between D and C is the same as the number of people sitting between C and Y.
7. At most 25 people are sitting in a row.
Inferences:
From reference 1, we get two possible cases.
From reference 7, case2 was eliminated.
Hence, Case 1 is the final arrangement.

MPPGCL JE Electronics Mock Test - 3 - Question 26

Which of the following does not include election procedure?

Detailed Solution: Question 26

Booth capturing is a type of electoral fraud in which party loyalists "capture" a polling booth and vote in place of legitimate voters to ensure that their candidate wins.

MPPGCL JE Electronics Mock Test - 3 - Question 27

Seven persons B, C, D, E, F, G and H are born on seven different months of a year starting from January, but not necessarily in the same order. Who was born in July?

Statement I: C was born just before D. Only two persons are born after H. Three persons are born between H and B. F was born two months after B.
Statement II: E was born in April. D was born after C. Two persons are born between E and B. B was not born in July. C was born one of the months after May.

Detailed Solution: Question 27

Checking Statement I:

Using the above references, we get the following arrangement:


Clearly, D was born in July.

Hence data in statement I is sufficient to answer the question.

Checking Statement II:

Using the above references, we get the following arrangement:


Clearly, D was born in July.

Hence data in statement II is sufficient to answer the question.

Here, the data in either Statement I or II alone is sufficient to answer the question.

Hence, Option C is correct.

MPPGCL JE Electronics Mock Test - 3 - Question 28

The average monthly salary of the workers in a workshop is Rs. 8,500. If the average monthly salary of 7 technicians is Rs. 10,000 and the average monthly salary of the rest is Rs. 7,800, then the total number of workers in the workshop is 

Detailed Solution: Question 28

MPPGCL JE Electronics Mock Test - 3 - Question 29

'Dogs' is related to 'Bark' in the same way as 'Goats' is related to:

Detailed Solution: Question 29

As the cry of 'Dog' is called 'Bark' in the same way the cry of 'Goat' is called 'Bleat'.

MPPGCL JE Electronics Mock Test - 3 - Question 30

The product of two numbers is 1280 and their H.C.F. is 8. The L.C.M. of the number will be ?

Detailed Solution: Question 30

Product of two numbers = HCF × LCM
1280 = 8 × LCM
160 = LCM

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