Test: Law of Equipartition of Energy - JEE MCQ

Test: Law of Equipartition of Energy - JEE MCQ

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10 Questions MCQ Test - Test: Law of Equipartition of Energy

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Test: Law of Equipartition of Energy - Question 1

How many degrees of freedom do non linear triatomic gas molecules has?

Detailed Solution for Test: Law of Equipartition of Energy - Question 1

A triatomic nonlinear gaseous atom has 6 degrees of freedom, that are 3 in all transrational directions and three rotational barriers in all the three axises.

Test: Law of Equipartition of Energy - Question 2

If a gas has n degree of freedom, ratio of principal specific heats of the gas is

Detailed Solution for Test: Law of Equipartition of Energy - Question 2

Let us consider 1 mole of an ideal gas at kelvin temperature T. It has N molecules (Avogadro's number). The internal energy of an ideal gas is entirely kinetic. The average KE per molecule of a ideal gas is ½ ​nkT (k is boltzman constant), where n is degree of freedom. Therefore, the internal energy of one mole of a gas would be

E=N(1/2​nKT)=1/2​nRT             (∵k=R/N​)

Now, Cv​=dE/dT​=n/2 ​R

and Cp​=n/2 ​R+R=(n/2​+1)R

​Cp/ Cv ​​=​(n/2​+1)R/n/2​=(1+2/n​)

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Test: Law of Equipartition of Energy - Question 3

O2  is a __________ molecule , and has __________ translational degrees of freedom

Detailed Solution for Test: Law of Equipartition of Energy - Question 3

Oxygen molecule is a diatomic molecule and  has 3 translational and 2 rotational degrees of freedom

Test: Law of Equipartition of Energy - Question 4

What is law of equipartition of energy?

Detailed Solution for Test: Law of Equipartition of Energy - Question 4

The total energy is equally distributed in all possible energy modes, with each mode having an average energy equal to ½ kBT. This is known as the law of equipartition of energy.

Test: Law of Equipartition of Energy - Question 5

The degree of freedom for diatomic gas is:

Detailed Solution for Test: Law of Equipartition of Energy - Question 5

For monoatomic gas degrees of freedom are 3, while for diatomic gas is it 5, and for triatomic gas it is 7.

Test: Law of Equipartition of Energy - Question 6

1calorie = ?

Detailed Solution for Test: Law of Equipartition of Energy - Question 6

1 calorie = 4.184 joules. That is the conversion rate, no explanation.

Test: Law of Equipartition of Energy - Question 7

The degree of freedom for tri atomic gas is:

Detailed Solution for Test: Law of Equipartition of Energy - Question 7

Degrees of freedom are the ways in which a molecule of the gas can execute motion.
So in case of triatomic gas molecule:
1. It can translate (move) in all 3 dimensions, which accounts for 3 degrees of freedom (since there are 3 dimensions in which it could translate (move)).
2. This molecule can also revolve with Moment of Inertia ≠ 0 around all three axes, x, y, and z, which accounts for another 3 degrees of freedom (since there are 3 axes of rotation).

Test: Law of Equipartition of Energy - Question 8

On which of the following factors, does the average kinetic energy of gas molecules depend?

Detailed Solution for Test: Law of Equipartition of Energy - Question 8

The average K.E. of gas molecules depends only on the absolute temperature of the gas and is directly proportional to it.

Test: Law of Equipartition of Energy - Question 9

The mean free path is the ____________

Detailed Solution for Test: Law of Equipartition of Energy - Question 9

Definition of Mean Path.

Test: Law of Equipartition of Energy - Question 10

The average distance a molecule can travel without colliding is called

Detailed Solution for Test: Law of Equipartition of Energy - Question 10

The mean free path is the average distance travelled by a molecule between two successive collisions.

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