Test: System of Particles and Rotational Motion (16 July) - JEE MCQ

Because angular momentum remains constant as the moment of inertia is increasing here so the angular velocity will decrease.

As there is no any external force acting between the two discs so according to law of conservation of angular momentum, we get
L= I_ω
So, I₁ω₁ + I₂ω₂ = (I₁ + I₂) ω

Spinning wheels have angular momentum, and when you're sitting on a bike, you and it and its wheels make up a system that obeys the principle of conservation of angular momentum.

While in the pike position the body decreases in radius as each segment moves closer to the axis of rotation, resulting in angular velocity increasing and a decrease of moment of inertia. Thus, during a dive, angular momentum is constant meaning that moment of inertia is inversely proportional to angular velocity.

M = 9 x 10^-31Kg,r = 4.5 x 10^-10
V = 8 x 10⁵m/s
L = mvr
= 9 x 10^-31 x 4.5 x 10^-10 x 8 x 10⁵ = 3.24 x 10^-34 kgm²s^-1

Because when the moment of inertia decreases, rotational kinetic energy increases as work is done in decreasing the moment of inertia of the body.
A circus acrobat performs feats involving spin by bringing his arms and legs closer to his body or vice versa. On bringing the arms and legs closer to the body, his moment of inertia decreases. Hence his angular velocity increases. The reverse is also true.

An earth satellite is moving in a circular motion due to change in the direction of velocity. Its angular momentum about centre is conserved as there is no external force acting on the system.

In case of a projectile, the angular momentum is minimum at the starting point.

L = Iw
L is the angular momentum, I is the MOI and w is the rotational velocity.
[I] = [ML²T⁰], [w] = [M⁰L⁰T^-1]
[L] = [MLT^-1]

Conservation of angular momentum is a physical property of a spinning system such that its spin remains constant unless it is acted upon by an external torque; put another way, the speed of rotation is constant as long as net torque is zero.