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UGC NET Paper 2 Computer Science Mock Test - 4 - UGC NET MCQ


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30 Questions MCQ Test - UGC NET Paper 2 Computer Science Mock Test - 4

UGC NET Paper 2 Computer Science Mock Test - 4 for UGC NET 2024 is part of UGC NET preparation. The UGC NET Paper 2 Computer Science Mock Test - 4 questions and answers have been prepared according to the UGC NET exam syllabus.The UGC NET Paper 2 Computer Science Mock Test - 4 MCQs are made for UGC NET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for UGC NET Paper 2 Computer Science Mock Test - 4 below.
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UGC NET Paper 2 Computer Science Mock Test - 4 - Question 1

The RST 7 instruction in 8085 microprocessor is equivalent to

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 1

So, option (C) is correct answer.

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 2

Match the following TCP/IP protocols with their uses.

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 2

Answer --> a - iii, b - iv, c - i, d - ii

Explanation -

FTP (File Transfer Protocol) -> File Transfer
FTP is a protocol that is used for transferring files over a network. It is a standard protocol that is used for uploading and downloading files from a server to a client or vice versa.

TFTP (Trivial File Transfer Protocol) -> Trivial File Transfer
TFTP is a simplified version of FTP that is used for transferring small files over a network. It is a lightweight protocol that does not provide authentication or encryption.

Telnet -> Remote Login
Telnet is a protocol that is used for remote login to a server or a networking device. It enables a user to access and control a remote computer over a network connection.

UDP (User Datagram Protocol) -> Send Datagram
UDP is a protocol that is used for sending datagrams over a network. It is a connectionless protocol that does not provide any reliability or error checking. It is commonly used for applications that require the fast transmission of data, such as online gaming and video streaming.

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UGC NET Paper 2 Computer Science Mock Test - 4 - Question 3

Which one of the following Boolean expressions is NOT a tautology?

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 3

Concept:

Using digital logic concept, we can find out whether Boolean expressions is a tautology or not.

  • In digital logic, we can write OR as +, AND as . , Negation as complement.

     
Explanation:

Option 1:

Option 1 is tautology.

Option 3:

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 4

What is the overall number of Clock cycles Per Instruction (CPI) for a machine A for which the following performance measures were recorded when executing a set of benchmark programs? (Assume the clock rate of the CPU as 200 MHz and execution of 100 instructions)

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 4

When evaluating a computing system's efficacy, the concept of Cycles Per Instruction (CPI) is crucial in the fields of computer design and performance evaluation.

To determine the machine's overall CPI in the instance of machine A, a thorough analysis of several instruction categories and their corresponding frequencies is required. This process serves as an essential productivity gauge for the machine. Then, by contrasting this predicted CPI with the other possibilities, the optimal choice that best fits the machine's performance characteristics can be identified

The formula given below can be used to determine the overall CPI (Cycles Per Instruction):

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 5

Which of the following statement are not true?

Statement 1: The Uniform Resource Identifier is a set of rules which is used to retrieve linked web pages across the web.

Statement 2: HyperText Transfer Protocol is a unique address or path for each resource located on the web.

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 5

The correct answer is option 3.

Concept:

Statement 1: The Uniform Resource Identifier is a set of rules which is used to retrieve linked web pages across the web.

False, The HyperText Transfer Protocol is a set of rules which is used to retrieve linked web pages across the web. The more secure and advanced version is HTTPS.

HTTP is a protocol for fetching resources such as HTML documents. It is the foundation of any data exchange on the Web and it is a client-server protocol, which means requests are initiated by the recipient, usually the Web browser.

Statement 2: HyperText Transfer Protocol is a unique address or path for each resource located on the web.

False, URI (Uniform Resource Identifier) or URL (Uniform Resource Locator) is a unique address or path for each resource located on the web.

A Uniform Resource Identifier (URI) is a character sequence that identifies a logical (abstract) or physical resource usually, but not always, connected to the internet.

Hence the correct answer is Both statement 1 and statement 2.

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 6
Which of the following is an example of unsupervised neural network?
Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 6

A self-organizing map:

  • It is a type of artificial neural network (ANN) that is trained using unsupervised learning to produce a low-dimensional (typically two-dimensional), discretized representation of the input space of the training samples, called a map, and is therefore a method to do dimensionality reduction.
  • Self-organizing maps differ from other artificial neural networks as they apply competitive learning as opposed to error-correction learning (such as backpropagation with gradient descent), and in the sense that they use a neighbourhood function to preserve the topological properties of the input space.
UGC NET Paper 2 Computer Science Mock Test - 4 - Question 7
A system has 3 processes sharing 4 resources. If each process needs a maximum of 2 units, then
Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 7

Distribute each process to one less than maximum request resources i.e. 3(2 - 1) = 3

Total no. of resources = 3 + 1(additional resource for deadlock avoidance)

If total no. resources are greater than given resources then a deadlock will occur.

3 + 1 <= 4

4 <=4

Hence, deadlock can never occur
UGC NET Paper 2 Computer Science Mock Test - 4 - Question 8
A ripple counter consists of a 6 flipflops and the first flipflop, F0 receives the pulses from clock and gives an output Q0, other flip flops are connected giving outputs Q1, Q2, Q3, Q4 and Q5. If the initial counter state is 101010. What would be the state after 256 pulses.
Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 8

Modulus of given counter is = 2N = 26 = 64.

Given counter is a MOD-64 ripple counter. Since counter repeats its state after 64 pulses, if the initial count is 101010 then after 256 pulses, the counter state will be 101010.
UGC NET Paper 2 Computer Science Mock Test - 4 - Question 9
The data-link layer is responsible for
Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 9

In the OSI model, the seven layers from bottom to top are as follows: physical layer, data link layer, network layer, transport layer, session layer, presentation layer, the application layer.

Data-link layer:

  • This layer is responsible for moving frames from one hop to next.
  • The Data-link layer divides the stream of bits received from the network layer into manageable units called frames.
  • It adds a header to the frame to define the sender and receiver of the frame.
  • It provides a flow and error control mechanism.

Different networking devices and the layers on which they operate is given below:

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 10

The FOLLOW sets for the non-terminals A and B are

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 10

FIRST(A) = FIRST(s) ={a, b, ε}

FIRST(B) = FIRST(s) ={a, b, ε}

So,FIRST(A) = {a, b, ε} = FIRST(B)

FOLLOW(A) = {First of { bB}, FIRST of {aB}}

FOLLOW(A) = {a, b}

FOLLOW(B) = FOLLOW(S) ={FOLLOW(A), $}

FOLLOW(B) = FOLLOW(S) ={FOLLOW(A), $} ={a, b,$}

Now, the answer is

FOLLOW(A) = {a, b}

FOLLOW(B) = {a, b, $}

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 11

The FIRST sets for the non-terminals A and B are

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 11

FIRST(A) = FIRST(s) ={a, b, ε}

FIRST(B) = FIRST(s) ={a, b, ε}

So,FIRST(A) = {a, b, ε} = FIRST(B)

FOLLOW(A) = {First of { bB}, FIRST of {aB}}

FOLLOW(A) = {a, b}

FOLLOW(B) = FOLLOW(S) ={FOLLOW(A), $}

FOLLOW(B) = FOLLOW(S) ={FOLLOW(A), $} ={a, b,$}

Now, the answer is

FIRST(A) = {a, b, ε} = FIRST(B)

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 12

The appropriate entries for E3 is

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 12

EXPLANATION:

FIRST and FOLLOW:

Parsing Table:

Hence the answer is

E3: B → S

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 13

The appropriate entries for E2 is

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 13

FIRST and FOLLOW:

Parsing Table:

Hence the answer is

E2: S → bAaB, S → ε

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 14
In first-order predicate logic, what is the role of quantifiers?
Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 14

The correct answer is Indicating the scope of variables

Key Points

Quantifiers in first-order predicate logic are symbols that express the extent to which a statement is true. There are two main types of quantifiers:

  • Universal Quantifier (∀): It is used to express that a certain statement is true for all values of a variable within a given domain. For example, ∀x P(x) asserts that the predicate P is true for every element x in the domain.
  • Existential Quantifier (∃): It is used to express that there exists at least one value of a variable within a given domain for which a certain statement is true. For example, ∃x P(x) asserts that there is at least one element x in the domain such that the predicate P is true.

Quantifiers play a crucial role in indicating the scope of variables, specifying whether a statement holds universally or existentially over a particular set of elements. Therefore, option C is the correct answer.

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 15
Expression ((¬ p ∨ ¬ q) ∧ (p ∧ q)) ∨ r → p ∧ (q ∨ r) is logically equivalent is
Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 15

((¬ p ∨ ¬ q) ∧ (p ∧ q)) ∨ r → p ∧ (q ∨ r)

≡ (¬ (p ∧ q) ∧ (p ∧ q)) ∨ r → p ∧ (q ∨ r)

∵ F ∧ T → F

(¬ (p ∧ q) ∧ (p ∧ q)) ∨ r → p ∧ (q ∨ r)

≡ F ∨ r → p ∧ (q ∨ r)

≡ r → p ∧ (q ∨ r)

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 16

(G, o) → (G', o') is a Group Homomorphism if

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 16

Group Homorphisms :

Let (G,o) & (G’,o’) be 2 groups, a mapping “f ” from a group (G,o) to a group (G’,o’) is said to be a homomorphism

if –f(a o b) = f(a) o' f(b) for all a, b ∈ G

∴ option 1 is correct

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 17

Given the following relation instance

Which of the following functional dependencies are satisfied by the instance?

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 17

Option 1 and Option 4:

C → B (It is not satisfied for given instance)

Option 2:

AC → B ((It is not satisfied for given instance))

Option 3:

AC → A

It is trivial dependency, and therefore this dependency is always satisfied.

B → C

Since B is unique for given instance, therefore this dependency is satisfied for given instance

Hence Option 3 is correct

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 18
600 characters per minute with 11­bit format has a transfer rate of ________.
Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 18

The correct answer is option 1.

Concept:

The given data,

The time taken for 600 characters = 1 minute.

i.e 60 seconds =600 characters.

1 second= 600/ 60 characters per second.

1 second =10 characters per second.

Note:

The baud rate is the rate at which information is transferred in a communication channel.

If one character stores in eleven bit then the transfer time of 11 bit is=?

11 bits = 11x time taken each bit

11 bits= 11 x 10 bauds

11 bits=110 bauds.

Hence the correct answer is 110 bauds.

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 19
Fuzzy Computing
Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 19

Fuzzy logic:

  • Fuzzy logic is a concept of certain degree. Boolean logic is a subset of fuzzy logic.
  • Fuzzy logic is a form of many-valued logic which deals with reasoning that is approximate rather than fixed and exact.
  • Compared to traditional binary sets (where variables may take on true or false values), fuzzy logic variables may have a truth value that ranges in degree between 0 and 1.
  • It is employed to handle the concept of partial truth, where the truth value may range between completely true and completely false.
  • It mimics human behaviour and deals with information, which is vague, imprecise, uncertain, ambiguous, inexact, or probabilistic
UGC NET Paper 2 Computer Science Mock Test - 4 - Question 20

Which of the following is true in Statistical reasoning?

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 20
Statistical reasoning is the representation is extended to allow some kind of numeric measure of certainty to be associated with each statement. Much of statistical reasoning combines ideas about data and chance, which leads to making inferences and interpreting statistical results. Underlying this reasoning is a conceptual understanding of important ideas, such as distribution, center, spread, association, uncertainty, randomness, and sampling.
UGC NET Paper 2 Computer Science Mock Test - 4 - Question 21

Let P be a quicksort program to sort numbers in ascending order using the first element as the pivot. Let t1 and t2 be the number of comparison made by P for the inputs [12345] and [41532] respectively. Which one of the following holds?

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 21

If the array is sorting is increasing or non-increasing order, choosing either first or last element given the worst-case time complexity in Quick Sort.

In every step of quick sort, numbers are divided as per the following recurrence.

T(n) = T(n - 1) + O(n)

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 22

What is the action of task environment in artificial intelligence?

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 22
Task environments will pose a problem and rational agent will find the solution for the posed problem. We can sometimes manipulate the task and/or environment to make things easier.  For example, increasing the contrast of objects to make things easier for a robot’s cameras. However the task environment is usually given. 

A task environment is a theoretical construct which is supposed to supply the goal relevant consequences of allowable moves in performing the task. 

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 23

The "turn-around" time of a user job is the:

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 23
The "turn-around" time of a user job is the total time taken to execute the job. In computing, turnaround time is the total time taken between the submission of a program/process/thread/task (Linux) for execution and the return of the complete output to the customer/user. It may vary for various programming languages depending on the developer of the software or the program. Turnaround time may simply deal with the total time it takes for a program to provide the required output to the user after the program is started.
UGC NET Paper 2 Computer Science Mock Test - 4 - Question 24

Which grammar gives multiple parse trees for the same string?

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 24
Ambiguous grammar is a context-free grammar which gives more than one leftmost or rightmost derivation for the same specified sentence. An ambiguous grammar is one for which there is more than one parse tree for a single sentence. Since each parse tree corresponds to exactly one leftmost (or rightmost) derivation, an ambiguous grammar is one for which there is more than one leftmost (or rightmost) derivation of a given sentence.
UGC NET Paper 2 Computer Science Mock Test - 4 - Question 25

The time delay between two successive initiations of memory operation is __________.

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 25

The time delay between two successive initiations of memory operation is Memory cycle time. The time is taken to finish one task and to start another. It is the time that is measured in nanoseconds, the time between one Ram access of time when the next Random Access Memory (RAM) access starts. That Cycle Time finds the right place for the memory to take place in the memory and transfer time of that information/process. So, one should not get confused while thinking about the Clock Cycle or Clock Speed which have to do with the number of cycles/second to which a processor is paced.

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 26

What is Dynamic loading?

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 26

Loading a routine only when it is called Dynamic loading. Dynamic loading is a mechanism by which a computer program can, at run time, load a library (or other binary) into memory, retrieve the addresses of functions and variables contained in the library, execute those functions or access those variables, and unload the library from memory.

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 27

The Flag ‘V’ is set to 1 indicates that _____________.

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 27

This is used to check the overflow that occurs in the operation. In computer processors, the overflow flag (sometimes called the V flag) is usually a single bit in a system status register used to indicate when an arithmetic overflow has occurred in an operation, indicating that the signed two's-complement result would not fit in the number of bits used for the result. Some architectures may be configured to automatically generate an exception on an operation resulting in overflow.

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 28

Which algorithm is used to solve any kind of problem?

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 28

Tree algorithm is used to solve any kind of problem because specific variants of the algorithm embed different strategies. Much of the work on search in artificial intelligence deals with trees. These are usually defined implicitly by a so-called problem representation, and the process of searching for a solution of the given problem can be represented by a search tree (more generally an acyclic graph, because of transpositions).

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 29

Keywords are recognized in a compiler during ______________.

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 29

The lexical analysis phase of compilation breaks the input text up into sequences of lexemes that each belongs to some particular token type that's useful in later analysis. Consequently, keywords are usually first recognized during lexical analysis in order to make parsing easier.

UGC NET Paper 2 Computer Science Mock Test - 4 - Question 30

Which of the following interface design principles reduces the user's memory load?

Detailed Solution for UGC NET Paper 2 Computer Science Mock Test - 4 - Question 30

Reducing memory load means that users should not be required to memorize (or recall out of their heads) a great deal of information to carry out tasks. Memory load reduces users’ capacity to perform the main task. There are many instances where a user’s memory load can be reduced, such as:

  • Disclose information in a progressive fashion
  • Define intuitive shortcuts
  • Recognition rather than recall
  • Externalize information through visualization
  • Hierarchical structure
  • Default values
  • Concrete examples
  • Generic rules and actions
  • Establish meaningful defaults.
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