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Test: Hydrocarbons(12 Sep) - JEE MCQ


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15 Questions MCQ Test - Test: Hydrocarbons(12 Sep)

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Test: Hydrocarbons(12 Sep) - Question 1

Given below are two statements.

Statement I: The presence of weaker -bonds make alkenes less stable than alkanes.
Statement II: The strength of the double bond is greater than that of carbon-carbon single bond.

In the light of the above statements, choose the correct answer from the options given below.

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 1

The -bond present in alkenes is weaker than -bond present in alkanes. This makes alkenes less stable than alkanes. Therefore, Statement I is correct.
Carbon-carbon double bond is stronger than carbon-carbon single bond because more energy is required to break 1 sigma and 1 pi bond than to break 1 sigma bond only. Therefore, Statement II is also correct.

Test: Hydrocarbons(12 Sep) - Question 2

Benzene on nitration gives nitrobenzene in presence of HNO3 and H2SO4 mixture, where

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 2

Reagent for nitration of Benzene


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Test: Hydrocarbons(12 Sep) - Question 3

The IUPAC name of the following compound is:

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 3

The IUPAC name of the given compound is: 4-Bromo-2-methylcyclopentane carboxylic acid.

*Answer can only contain numeric values
Test: Hydrocarbons(12 Sep) - Question 4

Complete combustion of 3 g of ethane gives x × 1022 molecules of water. The value of x is ______. (Round off to the nearest integer)
[Use: NA = 6.023 × 1023; Atomic masses in u: C: 12.0; O: 16.0; H: 1.0]


Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 4

*Answer can only contain numeric values
Test: Hydrocarbons(12 Sep) - Question 5

Methylation of 10 g of benzene gave 9.2 g of toluene. Calculate the percentage yield of toluene _________. (Nearest integer)


Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 5

Test: Hydrocarbons(12 Sep) - Question 6

An unsaturated hydrocarbon X absorbs two hydrogen molecules on catalytic hydrogenation, and also gives the following reaction:


B(3-oxo-hexanedicarboxylic acid) X will be:

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 6

Test: Hydrocarbons(12 Sep) - Question 7

The major product obtained from the following reaction is

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 7

Test: Hydrocarbons(12 Sep) - Question 8

Which of the following compounds is not aromatic

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 8


[10] Annulene although follows (4n + 2) electron rule, it is non-aromatic due to its nonplanar nature. It is nonplanar due to repulsion of C-H bonds present inside the ring.

*Answer can only contain numeric values
Test: Hydrocarbons(12 Sep) - Question 9

In the following sequence of reactions, the maximum number of atoms present in molecule 'C' in one plane is __________. (In integer)



(A is the lowest molecular weight alkyne.)


Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 9


Number of atoms in one plane = 13

Test: Hydrocarbons(12 Sep) - Question 10

The number of stereoisomers possible for 1,2-dimethyl cyclopropane is:

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 10

Test: Hydrocarbons(12 Sep) - Question 11

For the following sequence of reactions, the correct products are:

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 11

Test: Hydrocarbons(12 Sep) - Question 12

Which of the following is/are Lindlar catalyst?

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 12

Partially deactivated palladised charcoal (H2/pd/CaCO3) is Lindlar catalyst. It is used for the selective reduction of alkynes to cis alkenes.

Test: Hydrocarbons(12 Sep) - Question 13

In the chemical reaction given below, A and B respectively are:

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 13



Et stands for Ethyl group (-CH2CH3).

Test: Hydrocarbons(12 Sep) - Question 14

Two isomers 'A' and 'B' with molecular formula C4H8 give different products on oxidation with KMnO4 in acidic medium. Isomer 'A' on reaction with KMnO4/H+ results in effervescence of a gas and gives ketone. The compound 'A' is:

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 14

Test: Hydrocarbons(12 Sep) - Question 15

Arrange the following conformational isomers of n-butane in order of their increasing potential energy:

Detailed Solution for Test: Hydrocarbons(12 Sep) - Question 15

The more the stability, the lesser the potential energy.
Stability order: I > III > IV > II
So,
Potential energy: II > IV > III > I

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