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Achievers Section: Test -1 - Class 2 MCQ


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10 Questions MCQ Test - Achievers Section: Test -1

Achievers Section: Test -1 for Class 2 2024 is part of Class 2 preparation. The Achievers Section: Test -1 questions and answers have been prepared according to the Class 2 exam syllabus.The Achievers Section: Test -1 MCQs are made for Class 2 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Achievers Section: Test -1 below.
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Achievers Section: Test -1 - Question 1

Read the given statements carefully and state 'T' for true and 'F' for false.

(p) The set of numbers 315, 492, 568, 775 are arranged in ascending order.
(q) 5 tens more than 32 is 57.
(r) The smallest 3-digit even number formed by using the digits 2, 5, and 6 each only once is 256.

Detailed Solution for Achievers Section: Test -1 - Question 1
  • (p) True. The numbers are in ascending order.
  • (q) False. 5 tens more than 32 is 82, not 57.
  • (r) True. 256 is the smallest even number that can be formed with the digits 2, 5, and 6.
Achievers Section: Test -1 - Question 2

Study the given figures carefully and fill in the blanks.

(a) There are P more circles than rectangles in the given figures.
(b) Total number of slanting lines and horizontal lines in the given figures is Q.

Detailed Solution for Achievers Section: Test -1 - Question 2

(a) There are 9 more circles than rectangles across the figures.
(b) The total number of slanting and horizontal lines is 27.

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Achievers Section: Test -1 - Question 3

Sakshi’s grandfather started walking at the time shown on the given clock. He walked for 35 minutes and then took rest for 10 minutes. He then walked back home in 15 minutes. Which of the following clocks shows the time at which he reached home?

Detailed Solution for Achievers Section: Test -1 - Question 3
  • Starting time: 6:15 from the clock.
  • Add 35 minutes of walking: 6:50.
  • Add 10 minutes of rest: 7:00 
  • Add 15 minutes of walking back: 7:15
  • Correct answer: The clock showing 7:15 .
Achievers Section: Test -1 - Question 4

Consider the given figures carefully and find the capacity of 3 

Detailed Solution for Achievers Section: Test -1 - Question 4
  • Given: One pitcher is 120 mL.
  • Calculate: If four pitchers are needed, multiply 120 mL,
    120 x 4= 480, so 1 flask can carry 480ml thus 2 will carry 960ml [480x2]
  • 960ml x 3 = 2880
Achievers Section: Test -1 - Question 5

Arrange the following from the smallest to the greatest.

Detailed Solution for Achievers Section: Test -1 - Question 5
  • Q = 25 (2 tens + 5 ones)
  • S = 67 (4 tens + 7 ones)
  • P = 78 (7 tens + 8 ones)
  • R = 91 (9 tens + 1 one)
  • Ordered from smallest to largest: Q, S,P,R
Achievers Section: Test -1 - Question 6

if 5 kg and 1 kg watermelons will have the same weight as the basket of fruits, then how many watermelons will have the same weight as the basket of fruits?

Detailed Solution for Achievers Section: Test -1 - Question 6
  • The basket weighs 5 kg.
  • Since each watermelon weighs 1 kg, it will take 5 watermelons to equal the weight of the basket.
Achievers Section: Test -1 - Question 7

The given picture graph shows the different types of food that a group of students like to eat. 12 students like to eat _______.

Detailed Solution for Achievers Section: Test -1 - Question 7
  • Each star represents 4 students.
  • Count the stars for each type of food and multiply by 4.
  • Salad has 3 stars, which represent 3 x 4 = 12 students.
Achievers Section: Test -1 - Question 8

Find Y - X.

Detailed Solution for Achievers Section: Test -1 - Question 8

Step-by-step: 1. 836 - 341 = 495

2. XY5 = 495

3. Interpret XY5 as 100X + 10Y + 5

4. Simplify to get 49 = 10X + Y

5. Therefore, Y - X = 9-4=5

 

Achievers Section: Test -1 - Question 9

Anushka has a number plate as shown here. Using the digits written on the number plate, fill in the blanks and select the CORRECT option.

(a) 5 hundreds more than the smallest 3-digit number formed from the given digits, using each digit only once is P.
(b) If the digit 7 is replaced by 2, then the sum of the largest 3-digit numbers (original and new number), using each digit only once is Q.

Detailed Solution for Achievers Section: Test -1 - Question 9

Given digits: 4, 0, 7

(a) P = 5 hundreds more than the smallest 3-digit number formed from 4, 0, 7: Smallest number = 407 P = 500 + 407 = 907

(b) If 7 is replaced by 2: Largest number with digits 4, 0, 2 = 420 Sum of original largest number (704) and new largest number (420) = 704 + 420 = 1124

Therefore: (c) P = 907 (b) Q = 1124

Achievers Section: Test -1 - Question 10

Read the given statements carefully and state 'T' for true and 'F' for false.

(p) The set of numbers 241, 325, 563, 417, are arranged in ascending order. (q) 4 hundreds more than 150 is 550. (r) The smallest 3-digit number formed by using the digits 1, 3, and 9 each only once is 139.

Detailed Solution for Achievers Section: Test -1 - Question 10

(p) False. The numbers are not in ascending order. (q) True. 4 hundreds more than 150 is 550. (r) True. 139 is the smallest number that can be formed with the digits 1, 3, and 9.

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