AEES PRT Mock Test - 4 - AEES PRT MCQ

Checking → statement I:

References:

Point A is 3km north of library.

Point C is 3km North of Point B.

Point D is 3km East of point C.

Inferences:

From the above references, we can conclude that instruction about college is missing in statement I.

So, we can’t determine the direction between library and college.

Thus, statement I alone is not sufficient to answer the question

Checking → Statement II:

References:

College is 7km North of point F.

Point D is 6km North of point E.

Library is 7km west of point E.

Point F is 4km East of point E.

Inferences:

From the above references, we can conclude the following.

We can conclude that library is to the South West direction with respect to college.

Thus, statement II alone is sufficient to answer the question.

Hence, option B is correct.

Two numbers are in the ratio 7 : 9. If the sum of the numbers is 112, then the larger number is:

First, let's find the total parts in the ratio (7 + 9 = 16 parts).
Since the sum of the numbers is 112 and there are 16 parts in total, each part represents 
112/16=7
So, the larger number (which has 9 parts) is 
9x7=63
Therefore, the answer is (c) 63.

"मालिक नौकर से काम करवाता है।” वाक्य में प्रेरणार्थक क्रिया है।

• जिस क्रिया से ज्ञान हो कि कर्ता स्वयं कार्य को न करके किसी अन्य को कार्य करने की प्रेरणा देता है वह प्रेरणार्थक क्रिया कहलाती है।
• जैसे - माता पिता अपने बच्चो के कार्य करवाते है।

Hint

प्रेरणार्थक क्रिया के उदाहरण

• वह सबसे चालान भरवाता है.
• महेश बच्चों को रुलाता है.
• गीता बच्चों को हिंदी पढ़ाती है.
• सुरेश आज नौकर से गाड़ी धुलवाना।
• आज तुम विजय से चाय बनवाना।

Key Pointsअन्य विकल्प

शब्द जब वाक्य में प्रयुक्त होने की योग्यता प्राप्त करता है; तो पद कहलाता है।Key Points

• जब कोई शब्द व्याकरण के नियमो, प्रत्यय, उपसर्ग,वचन,लिंग,कारक,पुरुष आदि में बंधकर किसी वाक्य मे प्रयुक्त होता है तो वह शब्द स्वतंत्र शब्द न रहकर पद बन जाता है।
• उदाहरण - ईश्वर रक्षा करे, इसमें ईश्वर शब्द पद है।

Additional Information

'चतुराई' शब्द में 'आई' प्रत्यय है।

• 'चतुराई' में 'आई' प्रत्यय जुड़ा है। यहाँ 'चतुर' मूल शब्द है।
  • चतुर + आई = चतुराई
• ​‘चतुराई’ कृत प्रत्यय (कृदन्त प्रत्यय) शब्द है।
• आई प्रत्यय से बनने वाले कुछ शब्द -
  • पढ़ + आइ = पढ़ाई
  • मेल + आइ = मिलाई
  • सिल + आइ = सिलाई

Important Points

• प्रत्यय शब्द के अंत में जुड़ते हैं और ये पूर्ण रूप से अर्थ नहीं बदलते ये मूल शब्द के इर्द-गिर्द ही रहते हैं।
• उदाहरण :- ना = चलना, य = गेय, आई = मिठाई, ला = निचला आदि।
  • प्रत्यय के दो प्रकार होते हैं :-
    • कृत् प्रत्यय (अक, अन, अना, अनीय, आ, आई, आन, इ, इया, इत)
    • तद्धित प्रत्यय (आई, आइन, आई, आनी, आयत, आर/आरा, आहट, इल, इष्ठ, ई)

The correct preposition to use in this sentence is between.

• Option A: 'in' is incorrect because it implies that the book is inside the mug or the pen, which doesn't make sense in this context.
• Option B: 'between' is the correct preposition because it indicates that the book is located in the middle of the mug and the pen.
• Option C: 'on' is incorrect because it suggests that the book is placed on top of the mug or the pen, which is not the intended meaning.
• Option D: 'above' is incorrect because it implies that the book is in a higher position than the mug and the pen, which is not the intended meaning.

Therefore, the correct sentence is: The book is between the mug and the pen.

Venue: This term typically refers to a specific location where an event or activity takes place. It often carries the connotation of being chosen or designated for a particular purpose, such as a concert venue, a wedding venue, or a courtroom.

Place: "Place" is a more general term that can refer to any location or area, whether specific or undefined.

The correct option is C 
a=c=1/4, b=1/2
y=x is a tangent
∴ slopes are equal.
dy/dx=2ax+b
⇒1=2a+b at (1,1)⋯(1)
Also, the parabola passes through (1,1)
⇒a+b+c=1⋯(2)
The parabola passes through (−1,0)
⇒0=a−b+c⋯(3)
Solving (1),(2),(3), we get -
∴a=c=1/4
and b=1/2

Both of these vectors are pointing the same direction but they have different magnitude. Hence, they are collinear vectors.

Compound Event If an event has more than one sample point it is called a compound event, for example, S = {HH, HT} is a compound event.

Let matrix A is of order m x n , and matrix B is of order p x q . then , the product AB is defined only when n = p. that’s why, If A and B are any two matrices, then AB may or may not be defined.

We know that in a circle of radius r units, if an arc of length l units subtends an angle theta radian at the centre, then θ = l/ r.
Here, r = 7 m (length of rope will be equal to radius) and l = 210 m (length of arc will be the length which the cow grazed)
Thus, θ = 210^o/ 7 
= 30^o

y²+3=2(2x+y) represents parabola.
y²+3=4x+2y
y²−2y+3=4x
y²−2y+1+3=4x+1
(y−1)²=4x−2
(y−1)²=4(x−1/2)
So, the vertex of parabola=(1/2,1) and axis is parallel to x axis.
a=1
Focus=(1/2+1,1)
=(3/2,1)

Using the result, HCF × LCM = Product of two natural numbers ⇒ the other number =  product of two no. = LCM *HCF
Let unknown no. = X
>> X * 27 = 9*459
X = 9*459/27
X = 153

So X= 

So option B is correct answer. 

Greatest 5-Digit number = 99999

LCM of 8 and 9,

8 = 2 × 2 × 2

9 = 3 × 3

LCM = 2 × 2 × 2 × 3 × 3 = 72

Now, dividing 99999 by 72, we get

Quotient = 1388

Remainder = 63

So, the greatest 5-digit number divisible by 8 and 9 = 99999 - 63 = 99936

Required number = 99936 + 5 = 99941

Set P is square of the element of set Q.
{(x, y): x is the square of y, x ∈ P, y ∈ Q}

Since, HCF of 56 and 72, by Euclid’s divsion lemma,
72 = 56 × 1 + 16 ……….(i)
56 = 16 ×3 + 8 ……….(ii)
16 = 8× 2 + 0 ……….(iii) 
∴ HCF of 56 and 72 is 8. 
∴ 8 = 56 – 16× 3
8 = 56 – (72 – 56 ×1) ×3
[From eq. (i) : 16 = 72 – 56× 1]
8 = 56 – 3 ×72 + 56× 3
8 = 56 × 4 + (–3) × 72 
∴ x = 4,y = −3

As the solution turns red litmus solution blue, it must be basic. To reverse the change, we must add an acid.

Because the shared pair of electrons always stays in between two elements.

Physical Changes:
A physical change is a change in the state or form of matter without any change in the chemical composition or identity of the substance. In other words, the substance remains the same before and after the change.
Examples of Physical Changes:
A. Burning of a Natural Gas:
- This is a clear example of a combustion reaction. Natural gas comprehends methane gas. When methane reacts with oxygen in the atmosphere it produces water and carbon dioxide.
B. Rusting of iron:
- This is a chemical change, not a physical change. Rusting occurs when iron reacts with oxygen in the presence of moisture, forming iron (III) oxide (rust).
C. Freezing of water:
- This is a physical change. When water is cooled below its freezing point, it undergoes a phase change from a liquid to a solid, forming ice. The chemical composition of water (H2O) remains the same.
D. Digestion of food:
- This is a chemical change, not a physical change. Digestion involves the breakdown of complex food molecules into simpler substances through various chemical reactions in the digestive system.
Conclusion:
The freezing of water is the only example mentioned that represents a physical change. The other options involve chemical changes.

It is the only metal that is liquid at room temperature. It has the lowest melting point and boiling point of any other metal. It has low thermal conductivity, and a quite low electrical conductivity. It is the only metal that doesn’t form diatomic molecules in the gaseous phase.

Red colour has longer wavelength so least scattered by smoke or fog.

The correct option is A.
Current (I)= 0.20 A
Time(t)= 15 min

t= 15 × 60= 900 seconds
[1 minute= 60 seconds]

We know that,
I = Q/t

0.20 = Q/900
Q= 0.20 × 900
Q= 180 C
Hence, the amount of electric charge that flows through the circuit is 180 coulombs.