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HPCL Mechanical Engineer Mock Test - 1 Free Online Test 2026


Full Mock Test & Solutions: HPCL Mechanical Engineer Mock Test - 1 (170 Questions)

You can boost your Mechanical Engineering 2026 exam preparation with this HPCL Mechanical Engineer Mock Test - 1 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of Mechanical Engineering 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 150 minutes
  • - Total Questions: 170
  • - Analysis: Detailed Solutions & Performance Insights
  • - Sections covered: General Aptitude, Technical Knowledge

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HPCL Mechanical Engineer Mock Test - 1 - Question 1

Direction: In the following question, the sentences have been given in Active/ Passive Voice. From the given alternatives, choose the one which best expresses the given sentence in Passive/ Active Voice.

The gardener ought to water the plants daily.

Detailed Solution: Question 1

Use structure “subject + auxiliary + past participle + by + object”
As per the given above sentence is given in Passive Voice.
The plants ought to be watered daily by the gardener.
Therefore ,required answer will be option D .

HPCL Mechanical Engineer Mock Test - 1 - Question 2

Direction: Choose the option closest in meaning to the OPPOSITE of the word given in capitals.

ENDOW

Detailed Solution: Question 2

Endow is to provide with something desirable.

HPCL Mechanical Engineer Mock Test - 1 - Question 3

Direction: In the following question, the sentences have been given in Active/ Passive Voice. From the given alternatives, choose the one that best expresses the given sentence in Passive/ Active Voice.

Who wrote it?

Detailed Solution: Question 3

Use structure “By + question word + auxiliary + past participle + object ?”
As per the given above sentence is given in Passive Voice.
By whom was it written?
Therefore , option B will be required answer .

HPCL Mechanical Engineer Mock Test - 1 - Question 4

The ratio of the length to the breadth of a rectangle is 5 : 4 and the area of the rectangle is 320 cm2, what is the perimeter of the rectangle?

Detailed Solution: Question 4

Length of the rectangle = 5x
Breadth of the rectangle = 4x
5x × 4x = 320
x2 = 16
x = 4
So the answer = 2 × (5x + 4x) = 2 × 9x = 2 × 9 × 4 = 72 cm
Hence, Option B is correct.

HPCL Mechanical Engineer Mock Test - 1 - Question 5

Every real number is

Detailed Solution: Question 5

Either you can make a fraction from two whole numbers (denominator ≠ 0), thus a rational number. Or you can't, thus irrational.

HPCL Mechanical Engineer Mock Test - 1 - Question 6

In a year, the average monthly expenditure of Rajat in the first 5 months is Rs. 21,000, in the next 4 months is Rs. 24,000 and in the last three months is Rs. 12,000. If he saves overall Rs. 1,80,000 in the whole year, what is his average monthly income?

Detailed Solution: Question 6

Total income of the year = 5 × 21,000 + 4 × 24,000 + 3 × 12,000 + 1,80,000 = 4,17,000

Hence, Option B is correct.

HPCL Mechanical Engineer Mock Test - 1 - Question 7

A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

Detailed Solution: Question 7

It is given in the question that a man crosses 600m long street in 5 minutes. We have to find the speed of the man in km per hour. To find the speed of the man in km per hour, we have to convert the given distance to km and also convert the given time to hour.
First, let us see the conversion of the given distance into km. We know that 1km = 1000m.
So, to convert 600m to km, we can write, 600m = x km.
x = 600/1000 km 
x = 0.6km 
Now, let us convert the given time into hours. We know that 1 hour = 60 minutes.
So, to convert 5 minutes to hours, we can write, 5 minutes = y hours.
y = 5/60 hrs
y = 0.083 hrs
Now we know that speed can be found out using the formula, Speed=Distance/Time, We have found out that distance = 0.6km and time = 0.083 hrs. So, on substituting these values in the formula of speed, we get,  
Speed = 0.6/ 0.083
= 6×1000 / 83 × 10
= 6000/ 830
= 600/83
= 7.2 km/h
Therefore, we get the speed of the man crossing a 600m long street in 5 minutes as 7.2km/h.
Hence, option (D) is the correct answer.

HPCL Mechanical Engineer Mock Test - 1 - Question 8

Which of the following  (100 - 990) x 100?

Detailed Solution: Question 8


To solve this problem, we need to evaluate the expression (100 - 990) x 100. Let's break it down step by step:
Step 1: Evaluate 990: Any number raised to the power of 0 is equal to 1. So, 990 = 1.
Step 2: Substitute the value of 990 into the expression: (100 - 1) x 100 = 99 x 100.
Step 3: Multiply 99 and 100: 99 x 100 = 9900.
Therefore, the value of the expression (100 - 990) x 100 is 9900.
Hence, the correct answer is C: 9900.

HPCL Mechanical Engineer Mock Test - 1 - Question 9

The quantity that a container holds is called its  

Detailed Solution: Question 9

The quantity that a container holds is called its "capacity" or "volume."

Hence option C is correct.

HPCL Mechanical Engineer Mock Test - 1 - Question 10

If A is 50% more than C and B is 25% less than C, A is what percent more/less than B?

Detailed Solution: Question 10

  • A : B : C = 150 : 75 : 100 = 6 : 3 : 4
  • A : B : C = 6 : 3 : 4
  • Hence, Option D is correct.

HPCL Mechanical Engineer Mock Test - 1 - Question 11

Decimal representation of a rational number cannot be 

Detailed Solution: Question 11

A rational number is a number that can be expressed as a fraction p/q, where p and q are integers and q ≠ 0 

  • Its decimal representation is either terminating (like 0.75 = ¾)
    or non-terminating but repeating (like 0.333... = ⅓).

  • It cannot be non-terminating and non-repeating, because that form represents an irrational number (like π or √2).

 Therefore, the decimal representation of a rational number cannot be non-terminating and non-repeating.

HPCL Mechanical Engineer Mock Test - 1 - Question 12

Directions to Solve

In each word of the following questions consists of pair of words bearing a relationship among these, from amongst the alternatives, pick up the pair that best illustrate a similar relationship.

Question -

Rectangle : Pentagon

Detailed Solution: Question 12

Second one had one more side than the first.

HPCL Mechanical Engineer Mock Test - 1 - Question 13

Direction: In each of the following questions a pair of capitalised words is followed by four pair of words. You are required to mark as the answer the pair of words which have a relationship between them most similar to the relationship between the capitalised pair.

Doubt : Faith

Detailed Solution: Question 13

  1. Atheist: Someone who lacks belief in the existence of gods or deities and typically rejects organized religion.
    Religion: A system of beliefs, practices, and rituals centered around the worship of one or more gods or a divine power.
  2. Sceptic: A person inclined to doubt or question accepted opinions and beliefs, especially those in religion or superstition.
    Pious: Devoutly religious or reverent, typically exhibiting strong religious devotion or dedication.
  3. Iconoclast: A person who attacks or criticizes cherished beliefs or institutions, especially those in religion.
    Idol: An image or representation of a god used as an object of worship, or a person or thing that is greatly admired, loved, or revered.
  4. Apostate: Someone who renounces or abandons a religious or political belief or principle, often after previously holding it.
    State: A politically organized community living under a government, usually sovereign, occupying a definite territory.

Both are pairs of antonyms.
Hence, Option A is correct.

HPCL Mechanical Engineer Mock Test - 1 - Question 14

Which answer figure will complete the pattern in the question figure?

Detailed Solution: Question 14

HPCL Mechanical Engineer Mock Test - 1 - Question 15

To qualify for Physical in Sub-inspector and Army recruitment, the minimum age required is 19 years and 18 years respectively, the minimum weight required is 50 kgs and 48 kgs respectively, and maximum height allowed is 170 cms and 163 cms respectively. Karan is 17 years old, has a weight of 47 kgs, and has a height of 161 cms. For which of this recruitment is he eligible?  

Detailed Solution: Question 15

The logic follows here is:

Now,

Karan is 17 years old, has a weight of 47 kgs, and a height of 161 cms.

It is clearly mentioned in the criteria of Physical in Sub-inspector and Army recruitment about the weight and height of the candidate. Karan has a weight of 47 kgs and a height of 161 cms which is less than the criteria set for both the recruitment. Therefore, Karan neither qualifies for Physical in Sub-inspector and Army recruitment.

Hence, the correct answer is "Neither Sub-inspector nor Army recruitment".

HPCL Mechanical Engineer Mock Test - 1 - Question 16

Six persons – Veer, Prakash, Bhola, Shiv, Ankur and Bhanu were sitting around a circular table facing towards the centre. Who was sitting to the immediate right of Bhanu?

Statement I: Ankur was sitting second to the right of Veer, who was sitting to the immediate left of Bhola. Prakash was sitting second to the left of Bhola.
Statement II: Shiv was sitting to the immediate right of Ankur, who was sitting second to the right of Veer. Prakash was sitting second to the left of Bhola, who is to the immediate left of Ankur.

Detailed Solution: Question 16

Checking Statement I:
Using the above references, we get the following arrangement:

Since there is no information about the position of Bhanu so we cannot find the person who sits on the immediate right of Bhanu.

Hence, data in statement I alone is not sufficient.
Checking Statement II:
Using the above references, we get the following arrangement:

Clearly, Prakash sits on the immediate right of Bhanu.

Hence, data in statement II alone is sufficient.

Hence, Option B is correct.

HPCL Mechanical Engineer Mock Test - 1 - Question 17

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Cloth : Mill :: Newspaper : ?

Detailed Solution: Question 17

As Cloth is made in a Mill, similarly Newspaper is printed in press.

HPCL Mechanical Engineer Mock Test - 1 - Question 18

Directions to Solve

Each of the following questions has a group. Find out which one of the given alternatives will be another member of the group or of that class.

Question -

Arid, Parched, Droughty

Detailed Solution: Question 18

The synonym of arid, parched and droughty is dry.

HPCL Mechanical Engineer Mock Test - 1 - Question 19

Manav born on 03 December 1999, is in final year of Engineering of a Regular Course, with an aggregate of 75% till his 5th semester, he has permanent body tattoo on his inner face of forearm.

Detailed Solution: Question 19

Hence, the person does not satisfy all the conditions.

HPCL Mechanical Engineer Mock Test - 1 - Question 20

Choose the similar figure in the options.

Detailed Solution: Question 20

The pattern followed is:
Given series:

1. There is a rotation of 90º clockwise in next each step.
2. One similar figure is added next to each step.
The figure which will come next is,

Hence, the correct answer is "Option 3".

HPCL Mechanical Engineer Mock Test - 1 - Question 21

How many '8' are followed by even number and preceded by an odd number?

184381483287848568784186

Detailed Solution: Question 21

184381483287848568784186

There are four such 8's which are followed by even number and preceded by an odd number.

HPCL Mechanical Engineer Mock Test - 1 - Question 22

Material removal rate in grinding operation is small due to

Detailed Solution: Question 22

Grinding wheels have a negative rake angle and hence have a very small material removal rate. Hence, grinding is mostly used as a finishing process.

HPCL Mechanical Engineer Mock Test - 1 - Question 23

Rankine's formula is an empirical formula that is used for

Detailed Solution: Question 23

Rankin's Formula Example for Column Crushing/Buckling Load. It is an empirical formula used for the calculation of ultimate load both for short and long columns. Rankin's formula is also known as Rankin Gordon Formula. It gives the ultimate load that the column can bear before failure.

HPCL Mechanical Engineer Mock Test - 1 - Question 24

Which of the following is the most widely used cutting tool material?

Detailed Solution: Question 24

Carbon steels are the oldest tool material, but this steel is limited to very low cutting speed. High-speed steel is named because they were developed to cut at higher speeds.

HSS accounts for the largest tonnage of tool materials used today.

HPCL Mechanical Engineer Mock Test - 1 - Question 25

A long fin extends from the external surface of a cylinder through which hot fluid flows; the excess temperature at the tip of the fin would be

Detailed Solution: Question 25

Determination of fin length is an important step in designing a fin once its cross-sectional area has been determined. The longer the fin, the larger is the surface area, and the higher is the heat transfer. However, it is not necessary that the fin should be infinitely long for maximum heat transfer. It has been observed that the temperature drops along the fin exponentially and reaches an environmental temperature at some point along the fin length. Beyond this point, the length of the fin does not contribute to the heat transfer; therefore, designing extra-long fin results in material waste, excessive weight, and increased size at increased cost without any benefit in return.

HPCL Mechanical Engineer Mock Test - 1 - Question 26

The intensity of solar radiation on earth is nearly Buy Today

Detailed Solution: Question 26

At Earth's average distance from the Sun (about 150 million kilometers), the average intensity of solar energy reaching the top of the atmosphere directly facing the Sun is about 1,360 watts per square meter, according to measurements made by the most recent NASA satellite missions.

HPCL Mechanical Engineer Mock Test - 1 - Question 27

Internal teeth in gear are cut by

Detailed Solution: Question 27

Internal gear is a gear with its teeth cut in the internal surface of a cylinder and meshes with spur gears. In its manufacturing, the usual hobbing machine used in spur gear production cannot be used because of its shape. Generally, it is made with a gear shaper (or gear shaping machine) equipped with a pinion cutter.

HPCL Mechanical Engineer Mock Test - 1 - Question 28

Consider the following statement about D'Arsonval Movement
1. It is best suited for d.c. current measurement
2. It responds to the average value of current
3. It could be used for power measurements Which of these statements is/are correct
 

Detailed Solution: Question 28

HPCL Mechanical Engineer Mock Test - 1 - Question 29

The young elasticity of a perfectly rigid body is-

Detailed Solution: Question 29

Young's Modulus = Stress/Strain, Since a perfectly rigid body, won't yield any strain, irrespective of the amount of stress, and it’s Young's modulus is infinite.

HPCL Mechanical Engineer Mock Test - 1 - Question 30

An ideal spark ignition engine has a compression ratio of 9. What is its Air standard efficiency ifratio of specific heats is 1.5 ?

Detailed Solution: Question 30

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