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HPCL Mechanical Engineer Mock Test - 8 Free Online Test 2026


Full Mock Test & Solutions: HPCL Mechanical Engineer Mock Test - 8 (170 Questions)

You can boost your Mechanical Engineering 2026 exam preparation with this HPCL Mechanical Engineer Mock Test - 8 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of Mechanical Engineering 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 150 minutes
  • - Total Questions: 170
  • - Analysis: Detailed Solutions & Performance Insights
  • - Sections covered: General Aptitude, Technical Knowledge

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HPCL Mechanical Engineer Mock Test - 8 - Question 1

Find out the Synonym of the following word:

FORAY

Detailed Solution: Question 1

The word maraud comes from a Middle French word that means "rascal or rogue."

 A marauder is someone who marauds and marauding describes people who raid and plunder. As a noun, a maraud is a quick, short foray

HPCL Mechanical Engineer Mock Test - 8 - Question 2

Direction: In the following question, the sentences have been given in Active/ Passive Voice. From the given alternatives, choose the one that best expresses the given sentence in Passive/ Active Voice.

Some people were helping the wounded woman.

Detailed Solution: Question 2

Use structure “subject + auxiliary + past participle + by + object”
As per the given above sentence is given in Passive Voice.
The wounded woman was being helped by some people.
Therefore ,required answer will be option B .

HPCL Mechanical Engineer Mock Test - 8 - Question 3

Direction: In the following questions, choose the word opposite in meaning to the given word as your answer.

Hasten

Detailed Solution: Question 3

The word Hasten (Verb) means : hurry; to say or do something without delay.
The word Dawdle (Verb) means : to take a long time to do something or go somewhere. 

HPCL Mechanical Engineer Mock Test - 8 - Question 4

Directions: In this question, you need to replace the underlined part of the sentence with the most suitable idiom/expression given as option.

He was not agreeing to back off, as if he was arguing just for the sake of it.

Detailed Solution: Question 4

As per the meanings given below, the correct idiom will be ‘playing devil’s advocate’.
Take a rain check: postpone a plan.
Rain on someone’s parade: to spoil a moment.
Play devil’s advocate: to argue, just for the sake of it.
Play by the ear: to improvise.
Correct Sentence:
He was not agreeing to back off, as if he was playing devil’s advocate.
Hence, the correct answer is option C. 

HPCL Mechanical Engineer Mock Test - 8 - Question 5

Directions: In each of the following questions, a sentence has been given in Active (or Passive) Voice. Out of the four alternatives suggested, select the one that best expresses the same sentence in Passive/ Active Voice.

Do not disturb the patient.

Detailed Solution: Question 5

The original sentence is in the active voice: "Do not disturb the patient."

The best expression of this sentence in the passive voice is: "The patient is not to be disturbed."

Therefore, the correct answer is indeed option B: "The patient is not to be disturbed."

HPCL Mechanical Engineer Mock Test - 8 - Question 6

80 men can complete a work in 40 days and 50 women can complete the same work in 40 days. If the efficiency of each man is the same and the efficiency of each woman is also the same, the efficiency of each man is what percentage of the efficiency of each woman?

Detailed Solution: Question 6

80 men × 40 = 50 women × 40
80 men = 50 women
1 man : 1 woman = 5 : 8

Hence, Option D is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 7

The largest number which divides 70 and 125, leaving remainders 5 and 8 respectively, is      

Detailed Solution: Question 7

Since, 5 and 8 are the remainders of 70 and 125, respectively. Thus, after subtracting these remainders from the numbers, we have the numbers 65 = (70-5),
117 = (125 – 8), which is divisible by the required number.
Now, required number = HCF of 65,117                                     [for the largest number]
For this, 117 = 65 × 1 + 52 [∵ dividend = divisior × quotient + remainder]
⇒ 65 = 52 × 1 + 13
⇒ 52 = 13 × 4 + 0
∴ HCF = 13 
Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 amnd 8.

HPCL Mechanical Engineer Mock Test - 8 - Question 8

A car travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour?

Detailed Solution: Question 8

Total time taken = (160/64) + (160/80) = 9/2 hrs
∴ Average speed = 320 x (2/9) = 71.11 km/hr.

HPCL Mechanical Engineer Mock Test - 8 - Question 9

Find the volume of a cuboid whose length is 8 cm, width is 3 cm and height is 5 cm. 

Detailed Solution: Question 9

Volume of cubiod =l×b×h
=8×3×5
=120cm3 .

HPCL Mechanical Engineer Mock Test - 8 - Question 10

In a big garden 40% of the trees are mango trees. The number of mango trees is 80% of the number of guava trees. The rest of the trees are Jambolan trees. If the number of Jambolan trees is 40, what is the total number of trees in the garden?

Detailed Solution: Question 10

Total Mango trees = 40%

Remaining trees = (100 – 40 – 50)% = 10%

Hence, Option B is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 11

Suraj can complete a work in 60 days. In how many days can he complete 80% of the work with 75% of his efficiency?

Detailed Solution: Question 11


Hence, Option B is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 12

Which of the following is the product of 7/8 and -4/21?

Detailed Solution: Question 12

To find the product of 7/8 and -4/21, follow these steps:

  • Multiply the numerators: 7 × -4 = -28.
  • Multiply the denominators: 8 × 21 = 168.
  • Combine the results: -28/168.
  • Simplify the fraction: -28/168 can be reduced to -1/6.

The final answer is -1/6.

HPCL Mechanical Engineer Mock Test - 8 - Question 13

An angle is equal to one-third of its supplement. Its measure is equal to :

Detailed Solution: Question 13

Let the measured of the required angle be P degree.
Then, its supplement = 180 – P
Now use the formula,

3P + P180°
⇒ P = 45°

HPCL Mechanical Engineer Mock Test - 8 - Question 14

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Computer : fqprxvht :: Language : ?

Detailed Solution: Question 14

HPCL Mechanical Engineer Mock Test - 8 - Question 15

Direction: Study the following question carefully and choose the right answer.

If ACNE can be coded as 3, 7, 29, 11 then BOIL will be coded as ….?

Detailed Solution: Question 15

In the given coding system, we have:

So, the code for BOIL is 5, 31, 19, 25.
Hence, option D is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 16

Direction: Study the following question carefully and choose the right answer.

If STAFF is coded as $2#55 and FOLD is coded as 5@3% then how is STOLL written in that code language?

Detailed Solution: Question 16



∴ STOLL → $2@33
Hence, option B is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 17

In a certain code, MONK is written as 53. How will TUTOR be written in that code?

Detailed Solution: Question 17

The logic follows here is :

Sum of place values of alphabets of the given word = Given number.

MONK → M + O + N + K = 13 + 15 + 14 + 11 = 53.

Similarly,

TUTOR → T + U + T + O + R = 20 + 21 + 20 + 15 + 18 = 94.

Hence, the correct answer is "94".

HPCL Mechanical Engineer Mock Test - 8 - Question 18

Some equations are based on the basis of a certain system. Using the same solve the unsolved equation.

If 10 - 3 = 12, 12 - 4 = 13, 14 - 5 = 14, what is 16 - 6 = ?

Detailed Solution: Question 18

The logic followed is:

Similarly,

Hence, the correct answer is "15".

HPCL Mechanical Engineer Mock Test - 8 - Question 19

What is the number of instantaneous centres of rotation for a 6-link mechanism?

Detailed Solution: Question 19

The number of instantaneous centres in a constrained kinematic chain is equal to the number of possible combinations of two links.

The number of instantaneous centres:

where n is the number of links.

HPCL Mechanical Engineer Mock Test - 8 - Question 20

Carburising heat treatment is used for

Detailed Solution: Question 20

Case hardening produces a hard, wear-resistant surface or case over a strong, tough core. The principal forms of case hardening are carburizing, cyaniding, and nitriding. Only ferrous metals are case-hardened.

Carburization is a heat treatment process in which iron or steel absorbs carbon. In contrast, the metal is heated in the presence of a carbon-bearing material, such as charcoal or carbon monoxide. The intent is to make the metal surface harder.

HPCL Mechanical Engineer Mock Test - 8 - Question 21

In the pitot-tube the velocity of flow at a point is reduced to zero. That point is called as

Detailed Solution: Question 21

The stagnation, the point is the point when a moving fluid is brought to rest. The point at which a vertical line through the heeler centre of buoyancy crosses the line through the original, vertical centre of buoyancy is the metacentre. The metacentre remains directly above the centre of buoyancy by definition.

HPCL Mechanical Engineer Mock Test - 8 - Question 22

Modulus of resilience for the below material is

Detailed Solution: Question 22

Concept:

Proof resilience is defined as the maximum energy that can be absorbed within the elastic limit without creating a permanent distortion.

The modulus of resilience is defined as the maximum energy that can be absorbed per unit volume without creating a permanent distortion (i.e., The proof resilience per unit volume of a body is called the modulus of resilience). It can be calculated by integrating the stress-strain curve from zero to the elastic limit.

The area up to the Elastic limit is termed the modulus of resilience, and the total area up to fracture is termed the modulus of toughness.

Calculation:

Modulus of resilience = Area under stress-strain graph up to an elastic limit

= 1/2 × 2 × 10−3 × 350 = 0.35;MPa = 350;kPa

HPCL Mechanical Engineer Mock Test - 8 - Question 23

Thread angle of BSW thread in degree is

Detailed Solution: Question 23

The principal features of the British Standard Whitworth (BSW) thread form are that the angle between the thread flanks is 55 degrees, and the thread has radii at both the roots and the crests of the thread.

P= Pitch

d= depth of thread

r= radius at crest and root

HPCL Mechanical Engineer Mock Test - 8 - Question 24

Stirling and Ericsson cycle are

Detailed Solution: Question 24

Stirling cycle and Ericsson cycle are the modified forms of the Carnot cycle.

A Stirling cycle consists of two reversible isothermal and two reversible constant volume (isochoric) processes.

ηStirling = T3/T1/T3

Which is the same as Carnot’s efficiency.

Whereas an Ericsson cycle consists of two reversible isothermal and two reversible constant pressure (isobaric) processes.

ηericsson = 1−T1/T3which is the same as Carnot efficiency

HPCL Mechanical Engineer Mock Test - 8 - Question 25

The octane number of fuel in a mixture of 80% iso-octane and 20% n-heptane in an engine is

Detailed Solution: Question 25

Octane number is the percentage of isooctane in the mixture of iso-octane and n-heptane. The octane number is for gasoline (petrol) fuel. Gasoline with an octane number of 80 means 80% of isooctane and 20% of n-heptane, i.e., the branched-chain alkane is more, so knocking is less.

HPCL Mechanical Engineer Mock Test - 8 - Question 26

The pressure inside a water droplet is given by the relation

Detailed Solution: Question 26

It is because of surface tension that the pressure of a liquid increases within a bubble. If the pressure forces inside the bubble balance the force due to surface tension at the edge, we have

2πrσ = pπr2

p = 2σ/r

or

p = 4σ/d

So option A is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 27

Which of the following sand types is excellent for use in mortar and concrete work?

Detailed Solution: Question 27

Pit sand doesn’t contain any salts and has sharp, angular grains. These are the desired properties for sand to be used for mortar and concrete.

Hence, the correct option is (C).

HPCL Mechanical Engineer Mock Test - 8 - Question 28

Laminar flow is taking place in a pipe of diameter 0.3 m. The maximum velocity is 1.8 m/s. Then mean velocity is

Detailed Solution: Question 28

For a fully developed laminar viscous flow through a circular pipe, the ratio of maximum velocity to average velocity is 2.

Note: For laminar flow between two fixed parallel plates

uavg = 2umax/3

HPCL Mechanical Engineer Mock Test - 8 - Question 29

What is the ratio of displacement thickness to momentum thickness for linear velocity distribution over a flat plate?

Detailed Solution: Question 29

HPCL Mechanical Engineer Mock Test - 8 - Question 30

The critical pressure ratio for maximum discharge through a nozzle is given by

Detailed Solution: Question 30

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