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Intercept Form And Family Of Planes - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Intercept Form And Family Of Planes (5 Questions)

You can prepare effectively for JEE Mathematics (Maths) for JEE Main & Advanced with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Intercept Form And Family Of Planes". These 5 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 5

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Test: Intercept Form And Family Of Planes - Question 1

The equation of plane through the intersection of planes (x+y+z =1) and (2x +3y – z+4) =0 is​

Detailed Solution: Question 1

The equation of any plane passing through the line of intersection of two planes

As we have learnt from the concept Equation of plane 

Test: Intercept Form And Family Of Planes - Question 2

The equation of the plane passing through the line of intersection of the planes x-2y+3z+8=0 and 2x-7y+4z-3=0 and the point (3, 1, -2) is:​

Detailed Solution: Question 2

(x - 2y + 3z + 8) + μ(2x - 7y + 4z - 3) = 0
i.e, (1 + 2μ)x - (2 + 7μ)y + (3 + 4μ)z + (8 - 3μ) = 0......(1)
 the required plane is passing through (3, 1, -2)
so, 3(1 + 2μ) - (1)(2 + 7μ) + (-2)(3 + 4μ)+ (8 - 3μ) = 0
3 + 6μ - 2 - 7μ -6 -8μ + 8 - 3μ = 0
by solving, μ = 1/4
putting μ in equation (1)
we get the required equation of plane as :- 6x - 15y + 16z + 29 = 0

Test: Intercept Form And Family Of Planes - Question 3

If  are the equations of two given lines the, what is the condition for coplanarity of the twi lines in the vector form.

Test: Intercept Form And Family Of Planes - Question 4

The equation of the plane which makes the intercepts 3, 4, 12 with X-axis, Y-axis and Z-axis respectively is:​

Detailed Solution: Question 4

To find the equation of a plane with intercepts of 3, 4, and 12 on the X, Y, and Z axes respectively:

- The equation of a plane in intercept form is x/a + y/b + z/c = 1, where a, b, and c are the intercepts on the axes.
- Substituting the given intercepts, we get x/3 + y/4 + z/12 = 1.
- Multiplying by 12 to clear the fractions, we get 4x + 3y + z = 12.
- Therefore, the correct answer is B: 4x + 3y + z = 12.

Test: Intercept Form And Family Of Planes - Question 5

The equation of the plane passing through the intersection of the planes  and and the point (1, 2, 1) is:​

Detailed Solution: Question 5

n1 = 2i + j + k
n2 = 2i + 3j - 4k
p1 = 4,   p2 = -6
r.(n1 + λn2) = p1 + λp2
=> r . [2i + j + k + λ(2i + 3j - 4k)] = 4 - 6λ
=> r . [ i(2 + 2λ) + j(1 + 3λ) + k(1 - 4k)] = 4 - 6λ
Taking r = xi + yj + zk
(2 + 2λ)x + (1 + 3λ)y + (1 - 4k)z = 4 - 6λ
(2x + y + - z - 4) + λ(2x + 3y - 4k + 6) = 0
Given points are (1,2,1) 
(2 + 2 - 1 - 4) + λ(2 + 6 - 4 + 6) = 0
-1 + λ(10) = 0
 λ = 1/10
Substitute  λ = 1/10, we get
18x + 7y + 14z - 46=0

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