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Chapter Test: SHM - JEE MCQ


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30 Questions MCQ Test - Chapter Test: SHM

Chapter Test: SHM for JEE 2024 is part of JEE preparation. The Chapter Test: SHM questions and answers have been prepared according to the JEE exam syllabus.The Chapter Test: SHM MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Chapter Test: SHM below.
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Chapter Test: SHM - Question 1

A solid disk of radius R is suspended from a spring of linear spring constant k and torsional constant c, as shown in figure. In terms of k and c, what value of R will give the same period for the vertical and torsional oscillations of this system?


Detailed Solution for Chapter Test: SHM - Question 1


Chapter Test: SHM - Question 2

The periodic time of S.H.M. of amplitude 2 cm is 5 sec. If the amplitude is made 4 cm, its periodic time will be -

Detailed Solution for Chapter Test: SHM - Question 2

Time period is independent with amplitude.

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Chapter Test: SHM - Question 3

The motion of a particle is expressed by the equation acc. a = – bx where x is displacement from equilibrium position and b is constant. What is the periodic time ?

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Chapter Test: SHM - Question 4


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Chapter Test: SHM - Question 5


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Chapter Test: SHM - Question 6

A simple pendulum 4 m long swings with an amplitude of 0.2 m. What is its acceleration at the ends of its path ? 

(g = 10 m/s2)

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Chapter Test: SHM - Question 7

The equation of SHM of a particle is a + 4π2x = 0 where α is instantaneous linear acceleration at displacement x, the frequency of motion is -

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Chapter Test: SHM - Question 8

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Chapter Test: SHM - Question 9

In the figure shown a massless spring of stiffness 100 N/m and natural length l0 m is rigidly attached to a block of mass 20 kg and is in vertical position. A wooden ball of mass m is released from rest to fall under gravity. Having fallen through a height h the ball strikes the spring and gets stuck up in the spring at the top. What should be the minimum value of h (in cm) so that the lower block will just lose contact with the ground later on? Neglect any loss of energy.

Detailed Solution for Chapter Test: SHM - Question 9

We are given that a wooden ball falls through a height h and strikes a spring whose other end is connected to a block of mass m. The ball gets struck in the spring, pushing down on the spring, making the spring recoil and push itself and the ball with it upwards through a displacement of, say x, as shown in the figure.
The weight of the block acts downwards as gravitational force :
F= m g
From Hooke’s law, the spring force as a result of the extension of the spring through x when the ball gets stuck and subsequently gets recoiled by the spring will be:
F= kx, where k is the spring constant indicating the stiffness of the spring.

 

Now, for the block to just lose contact with the ground, the spring force acting on the block must be able to pull the block up and be at least equal to the weight of the block, i.e.,
F= Fg ⇒ kx = mg

⇒ x = mg / k

 

Now, the work done by the spring force will be the difference in the potential energy possessed by the spring at initial displacement (x1= 0) and final displacement (x= x), i.e.,

But we have x = mg / k
⇒ 

And the work done by the gravitational force will be the difference in the potential energy possessed by the ball at its initial position (h) and final position (x), i.e.,

 

W= mgh – mgx = mg(h−x)
But we have x = mg / k
⇒W= mg(h − mg / k)

From the work energy theorem which states that the net work done by the forces on an object equals the change in its kinetic energy, we have:
Wg+W= ΔK E
Since the ball is released from rest, its initial velocity is zero, which means that its initial kinetic energy is zero. Then, the ball gets stuck in the spring, so the final velocity of the ball is zero, implying that the final kinetic energy of the ball is zero. Therefore, ΔKE=0.

Chapter Test: SHM - Question 10

A body is executing SHM. When the displacement from the mean position is 4cm and 5 cm. The values of the corresponding velocity of the body are 10 cm s–1 and 8 cm s–1. Then the time period of the body is -

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Chapter Test: SHM - Question 11

A particle at the end of a spring executes simple harmonic motion with a period t1, while the corresponding period for another spring is t2. If the period of oscillation with the two springs in series is T, then -


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Chapter Test: SHM - Question 12

A particle performs harmonic oscillations along a straight line with a period T and amplitude a. The mean velocity of the particle averaged over the time interval during which it travels a distance a/2 starting from the extreme position is :

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Chapter Test: SHM - Question 13


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Chapter Test: SHM - Question 14

Particle moves on the x-axis according to the equation x = A + B sin ωt. The motion is simple harmonic with amplitude.

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Chapter Test: SHM - Question 15

A system is shown in the figure. The time period for small oscillations of the two blocks will be -


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Chapter Test: SHM - Question 16

The acceleration-displacement (a-x) graph of a particle executing simple motion is shown in figure. The frequency of oscillation is given by -


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Chapter Test: SHM - Question 17

A particle is vibrating in simple harmonic motion with an amplitude of 4 cm. At what displacement from the equilibrium position is its energy half potential and half kinetic ?

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Chapter Test: SHM - Question 18


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Chapter Test: SHM - Question 19

A pendulum of length 200 cm is horizontal when its bob of mass 200 gm is released. It has 90% of initial energy when the bob reaches the lower most point. Speed of the bob at this point is -

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Chapter Test: SHM - Question 20

A simple pendulum with angular frequency ω oscillates simple harmonically. The tension in the string at lowest point is T. The total acceleration of the bob at its lowest position is -

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Chapter Test: SHM - Question 21

A second pendulum is mounted in a space shuttle. Its period of oscillations will decrease when rocket is:

Detailed Solution for Chapter Test: SHM - Question 21

 

  • Time Period, T = 2π √(l/g')where,
    l = Length of seconds pendulum 
    g’ = Apparent Gravity
  • For the period of oscillations of Seconds Pendulum to decrease, the Apparent gravity (g’) has to increase because:
  • Hence, Time Period of oscillations of Seconds Pendulum will decrease when the rocket is ascending up with uniform acceleration.
Chapter Test: SHM - Question 22

A particle of mass 10 gm lies in a potential field v = (50x2+100) J/kg. The value of frequency of oscillations in Hz is

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Chapter Test: SHM - Question 23

 In simple harmonic motion the displacement of a particle from its equilibrium position is given by 11915_image018. Here the phase of motion is 

Detailed Solution for Chapter Test: SHM - Question 23

The phase of motion is Ø

Chapter Test: SHM - Question 24

Find the amplitude of the S.H.M whose displacement y in cm is given by equation y= 3 sin157t + 4 cos157t, where t is time in seconds.

Detailed Solution for Chapter Test: SHM - Question 24

When the displacement of a SHM is:
y=a sin wt+ b cos wt

  • Amplitude of the SHM will be:
    A=√a2+b2

Here, a = 3, b = 4
Amplitude, A= √(32+42) = 5 cm

Hence option B is correct.

Chapter Test: SHM - Question 25

A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is:

Detailed Solution for Chapter Test: SHM - Question 25

   ∴ We get, ω = √3 s-1
   T = 2π / √3

Chapter Test: SHM - Question 26

A square metal frame in the vertical plane is hinged at O at its center. A bug moves along the rod PN which is at a distance l from the hinge, such that the whole frame is always stationary, even though the frame is free to rotate in the vertical plane about the hinge. Then the motion of the bug will be simple harmonic, with time period


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Chapter Test: SHM - Question 27

A uniform solid cylinder of mass 5 kg and radius 0.1 m is resting on a horizontal platform (parallel to the x-y plane) and is free to rotate about its axis along the y-axis. The platform is given a motion in the x direction given by x = 0.2 cos(10t) m. If there is no slipping, then maximum torque acting on the cylinder during its motion is


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Chapter Test: SHM - Question 28

A short boy sits on a seat suspended by a light string from a fixed point O and starts swinging in a vertical plane from the extreme position P with a small amplitude. The graph, which shows the variation of the tension in the string with time ‘t’ is :


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Chapter Test: SHM - Question 29

Two small bobs of same mass are hung from two threads of different length as shown. The bobs are just touching each other. Now the left bob is pulled out by a small angle (θ < 10°)="" in="" same="" vertical="" plane="" and="" released="" at="" t="0." it="" collides="" with="" the="" other="" bob.="" at="" what="" time(s)="" the="" two="" bobs="" do="" not="" collide="" with="" each="" />


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Chapter Test: SHM - Question 30

A body is executing SHM. When the displacement from the mean position is 4cm and 5 cm. The values of the corresponding velocity of the body are 10 cm s–1 and 8 cm s–1. Then the time period of the body is -

Detailed Solution for Chapter Test: SHM - Question 30


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