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Chapter Test: Work, Energy & Power - 2 - JEE MCQ


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30 Questions MCQ Test - Chapter Test: Work, Energy & Power - 2

Chapter Test: Work, Energy & Power - 2 for JEE 2024 is part of JEE preparation. The Chapter Test: Work, Energy & Power - 2 questions and answers have been prepared according to the JEE exam syllabus.The Chapter Test: Work, Energy & Power - 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Chapter Test: Work, Energy & Power - 2 below.
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Chapter Test: Work, Energy & Power - 2 - Question 1


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Chapter Test: Work, Energy & Power - 2 - Question 2

A vertical spring of force constant 100 N/m is attached with a hanging mass of 10 kg. Now an external force is applied on the mass so that the spring is stretched by additional 2 m. The work done by the force F is : (g = 10m/s2)


Detailed Solution for Chapter Test: Work, Energy & Power - 2 - Question 2

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Chapter Test: Work, Energy & Power - 2 - Question 3

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Chapter Test: Work, Energy & Power - 2 - Question 4


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Chapter Test: Work, Energy & Power - 2 - Question 5


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Chapter Test: Work, Energy & Power - 2 - Question 6

A block of mass m is stationary with respect to wedge of mass M moving with uniform speed v on horizontal surface. Find the work done by friction force on the block in t second -


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Chapter Test: Work, Energy & Power - 2 - Question 7


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Chapter Test: Work, Energy & Power - 2 - Question 8

A bullet of mass m and velocity a is fired into a large block of wood of mass M. The final velocity of the system is -

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Chapter Test: Work, Energy & Power - 2 - Question 9


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Chapter Test: Work, Energy & Power - 2 - Question 10

Assertion : The work done by all forces on a system equals to the change in kinetic energy of that system. This statement is true even if non-conservative forces act on the system.

Reason : The total work done by internal forces may be positive.

Detailed Solution for Chapter Test: Work, Energy & Power - 2 - Question 10

Both (A) & (R) are true. The work done by all forces on a system is equal to change in its kinetic energy, irrespective of fact whether work done by internal forces is positive, is zero or is negative.

Chapter Test: Work, Energy & Power - 2 - Question 11

Force acting on a particle moving in a straight line varies with the velocity of the particle as F = K/v . Here K is constant. The work done by this force in time t is -

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Chapter Test: Work, Energy & Power - 2 - Question 12

A disc of radius 0.1 m rolls without sliding on a horizontal surface with a velocity of 6 m/s. It then ascends a smooth continuous track as shown in figure. The height upto which it will ascend is : (g = 10 m/s2)


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Chapter Test: Work, Energy & Power - 2 - Question 13


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Chapter Test: Work, Energy & Power - 2 - Question 14

Power applied to a particle varies with time as P = (3t2 – 2t + 1) watts, where t is time in seconds. Then the change in kinetic energy between time t = 2s to t = 4s is-

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Chapter Test: Work, Energy & Power - 2 - Question 15

A man of mass 50 kg is moving up an inclined plane pull a block of mass 25 kg with constant speed 1 m/s. Friction coefficient between block and plane is 0.5. Assuming that man doesn’t slips. Power delivered by man –


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Chapter Test: Work, Energy & Power - 2 - Question 16

A particle of mass m is projected at an angle α to the horizontal with an initial velocity v0. The work done by gravity during the time it reaches its highest point is -

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Chapter Test: Work, Energy & Power - 2 - Question 17


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Chapter Test: Work, Energy & Power - 2 - Question 18


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Chapter Test: Work, Energy & Power - 2 - Question 19

A particle of mass m = 9 × 10–31 kg moving towards the wall of a vessel at a velocity of v = 600 ms–1 strikes it at an angle of 60° to the normal and rebounds at the same angle at the same speed. The impulse of the force experienced by the wall during the impact is -

Detailed Solution for Chapter Test: Work, Energy & Power - 2 - Question 19

Impulse = change in momentum = 2 mv cosθ

Chapter Test: Work, Energy & Power - 2 - Question 20

A particle is released from a height H. At certain height its kinetic energy is two times its potential energy. Height and speed of particle at that instant are -

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Chapter Test: Work, Energy & Power - 2 - Question 21

The speed v reached by a car of mass m, driven with constant power P, is given by -

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Chapter Test: Work, Energy & Power - 2 - Question 22

A overhead tank of capacity 1000 liter has to be filled in 1/2 hour using water pump. Tank is kept at a height 10 m above ground and water level is 10 m below ground. The opening of inlet pipe inside tank is 1.11 cm2. Assuming the efficiency of motor to be 60%, the electric power used is (Neglect viscosity) -

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Chapter Test: Work, Energy & Power - 2 - Question 23

The linear momentum of a particle varies with time t as :

p = a + bt + ct2

Which of the following statements is correct ?

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Chapter Test: Work, Energy & Power - 2 - Question 24


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Chapter Test: Work, Energy & Power - 2 - Question 25

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Chapter Test: Work, Energy & Power - 2 - Question 26

 A spot light S rotates in a horizontal plane with a constant angular velocity of 0.1 rad/s. The spot of light p moves along the wall at a distance 3 m. What is the velocity of the spot P when q = 45° ?

                               

Detailed Solution for Chapter Test: Work, Energy & Power - 2 - Question 26

Linear Velocity of rotating object ν=ωr/sinθ
ω= angular velocity=0.1 rad/s
r is the distance of object from centre.
Angle = 45o
r = d/cosθ [where d is the distance from the spot light to wall] = 3/cos45o
Velocity = ν = ωr/sinθ
= [0.1x3/cos45degree]/sin45degree
= 0.1x3/sin45 degreecos45degree
= 0.3/[1√2 x 1 /2]
= 2x0.3
= 0.6m/s
The velocity of the spot P is 0.6 m/s

Chapter Test: Work, Energy & Power - 2 - Question 27

Two moving particle P and Q are 10 m apart at a certain instant. The velocity of P is 8m/s making an angle 30° with the line joining P and Q and that of Q is 6m/s making an angle 30° with PQ as shown in the figure. Then angular velocity of P with respect to Q is

                          

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Chapter Test: Work, Energy & Power - 2 - Question 28

The magnitude of displacement of a particle moving in a circle of radius a with constant angular speed w varies with time t as

Detailed Solution for Chapter Test: Work, Energy & Power - 2 - Question 28

If a particle is moving with angular velocity=ω
Its angle of rotation is given by ωt 
Now displacement= length of line AB
Position vector of a particle is given by
R =iacosωt + jasinωt
Ro=ai
displacement =R−Ro
=a(cosωt−1)i+asinωj
d=√[(a(cosωt-1))2+(asinω)2]
=a√(2(1-cosωt))=a√(2×2(sinωt/2)2)=2asinωt/2

Chapter Test: Work, Energy & Power - 2 - Question 29

 A particle moves along an arc of a circle of radius R. Its velocity depends on the distance covered as v = a, where a is a constant then the angle a between the vector of the total acceleration and the vector of velocity as a function of s will be

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*Multiple options can be correct
Chapter Test: Work, Energy & Power - 2 - Question 30

A particle with constant total energy E moves in one dimension in a region where the potential energy is U(x). The speed of the particle is zero where

Detailed Solution for Chapter Test: Work, Energy & Power - 2 - Question 30

If the total energy is E that means that E = U(x) + KE and if KE = 0 then E = U(x)

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