Mole concept - Free MCQ Practice Test with solutions, JEE Chemistry
MCQ Practice Test & Solutions: Test: Mole concept (15 Questions)
You can prepare effectively for JEE Chemistry for JEE Main & Advanced with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Mole concept". These 15 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.
Test Highlights:
- - Format: Multiple Choice Questions (MCQ)
- - Duration: 20 minutes
- - Number of Questions: 15
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1.44 g of titanium (At. mass = 48) reacted with excess of O2 and produce 
of non stoichiometric compound 
. The value of 
is:
of non stoichiometric compound . The value of is:Detailed Solution: Question 1
The mass of 
produced by the reaction of 
of 
and 
of 
is 
. What is the per cent yield?
produced by the reaction of of and of is . What is the per cent yield?Detailed Solution: Question 2
formed by 
formed by 
will be limiting and actual amount of product is 
The impure 
of 
is dissolved in water and then treated with excess of silver nitrate solution. The mass of precipitate of silver chloride is found to be 
. The 
purity of 
solution would be:
of is dissolved in water and then treated with excess of silver nitrate solution. The mass of precipitate of silver chloride is found to be . The purity of solution would be:Detailed Solution: Question 3
is produced from 
will be produced from
in common salt:
purity 
ions are in 20 ml of 0.4 M 
?Detailed Solution: Question 4
What is the empirical formula of vanadium oxide, if 2.74 g of the metal oxide contains 1.53 g of metal?
Detailed Solution: Question 5
Mass of metal 
Mass of oxygen
of ferrous ammonium sulphate crystals are dissolved in 
of water. 
of this solution requires 
of potassium permaganate during titration for complete oxidation. The weight of 
present in one litre of the solution of
of ferrous ammonium sulphate crystals are dissolved in of water. of this solution requires of potassium permaganate during titration for complete oxidation. The weight of present in one litre of the solution ofDetailed Solution: Question 6
Eq. wt of FAS is 392
ev. of 
.Specific volume of cylindrical virus particle is 
. whose radius and length are 
respectively.
If 
, find molecular weight of virus
. whose radius and length are respectively.If
, find molecular weight of virusDetailed Solution: Question 7
) of cylindrical virus particle 
Wt. of 
particle
10 moles 
and 15 moles 
were allowed to react over a suitable catalyst. 8 moles of 
were formed. The remaining moles of 
and 
respectively are -
and 15 moles were allowed to react over a suitable catalyst. 8 moles of were formed. The remaining moles of and respectively are -Detailed Solution: Question 8
On reduction with hydrogen 3.6 g of an oxide of metal leaves 3.2 g of metallic residue. If the atomic mass of metal is 64 , the formula of metal oxide is
Detailed Solution: Question 9
Vapour density of a metal chloride is 83. If equivalent weight of the metal is 6, its atomic weight will be ____.
Detailed Solution: Question 10
The amount of 
formed upon mixing 
of 
solution with 50 
of 
solution will be:
(Given that molecular weight of 
and 
Detailed Solution: Question 11
of 
solution 
.
of 
solution 
.
is the limiting reagent, only 
moles of 
will form.
of 
is formed.9 moles of "D" and 14 moles of E are allowed to react in a closed vessel according to given reactions. Calculate number of moles of B formed in the end of reaction, if 4 moles of G are present in reaction vessel. (Percentage yield of reaction is mentioned in the reaction)
Step-1 
Step-2 
Step-1
Step-2
Detailed Solution: Question 12
mole
formed 
A mixture of 
and 
contain 
mass per cent of nitrogen. What is the mass ratio of the two components in the mixture?
and contain mass per cent of nitrogen. What is the mass ratio of the two components in the mixture?Detailed Solution: Question 13
and 
are 
and y gram respectively 
of 
on heating gave 
of 
and 
of 
. This is in accordance withDetailed Solution: Question 14
A gaseous mixture contains oxygen and nitrogen in the ratio of 1: 4 by weight. Therefore, the ratio of their number of molecules is
Detailed Solution: Question 15
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