JEE Exam  >  JEE Tests  >  Test: Isomerism of organic compounds - JEE MCQ

Test: Isomerism of organic compounds - JEE MCQ


Test Description

20 Questions MCQ Test - Test: Isomerism of organic compounds

Test: Isomerism of organic compounds for JEE 2024 is part of JEE preparation. The Test: Isomerism of organic compounds questions and answers have been prepared according to the JEE exam syllabus.The Test: Isomerism of organic compounds MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Isomerism of organic compounds below.
Solutions of Test: Isomerism of organic compounds questions in English are available as part of our course for JEE & Test: Isomerism of organic compounds solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Isomerism of organic compounds | 20 questions in 20 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
Test: Isomerism of organic compounds - Question 1

Which statement is true regarding the following structure?

Detailed Solution for Test: Isomerism of organic compounds - Question 1

In amines, N is sp3 hybridised and thus has pyramidal shape. In the given structure, since the three alkyl groups are different, and the fourth corner of the pyramid is occupied by lone pair of electrons, the molecule is chiral. However, the two enantiomers of the amine are not resolvable because of their rapid interconversion through a transition state having planar structure (sp2 hybridised nitrogen)

Test: Isomerism of organic compounds - Question 2

Which of the following amines can be resolved into two enantiomers?

Detailed Solution for Test: Isomerism of organic compounds - Question 2

Most of the simple amines those having smaller alkyl (groups) can't be resolved, although they may contain three different alkyl groups.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Isomerism of organic compounds - Question 3

Number of stereo isomers existing for

Detailed Solution for Test: Isomerism of organic compounds - Question 3

Identify possible configurations:
- Cis Configuration: Both - COOH groups on the same side.
- Trans Configuration: -COOH groups on opposite sides.
Geometric Isomerism:
- 1 Cis isomer
- 1 Trans isomer
Optical Isomerism:
- Cis isomer can exist as two enantiomers (mirror images).
Count the stereoisomers:
- 1 Trans (achiral)
- 2 Cis (chiral enantiomers)
Total stereoisomers = 1 (Trans) +2 (Cis enantiomers) = 3

Test: Isomerism of organic compounds - Question 4

The compound which exhibits both geometrical and optical isomerism is

Detailed Solution for Test: Isomerism of organic compounds - Question 4
  • Geometrical Isomerism: Geometrical isomerism occurs when there is restricted rotation around a double bond, leading to different spatial arrangements of atoms.
  • Optical Isomerism: Optical isomerism arises due to the presence of a chiral center in a molecule, resulting in non-superimposable mirror images known as enantiomers.

In the given compounds:

- A: 4 - Bromopent - 2- ene: This compound has a double bond, which can exhibit geometrical isomerism. Additionally, it does not have a chiral center, so it does not show optical isomerism.
- B: 3-Bromo-2-methylbut-1-ene: This compound has a double bond and a chiral center, leading to both geometrical and optical isomerism.
- C: 1 - Bromobut-2-ene: This compound has a double bond, which can exhibit geometrical isomerism. However, it does not have a chiral center, so it does not show optical isomerism.
- D: 3-Bromo-2-methylpropene: This compound has a double bond but lacks a chiral center, so it only exhibits geometrical isomerism.
Therefore, the compound that exhibits both geometrical and optical isomerism is B: 3-Bromo-2-methylbut-1-ene.No solution. Refer to answer key.

Test: Isomerism of organic compounds - Question 5

Tautomerism is exhibited by-

Detailed Solution for Test: Isomerism of organic compounds - Question 5

Test: Isomerism of organic compounds - Question 6

The two compounds given below are

Detailed Solution for Test: Isomerism of organic compounds - Question 6

The given compounds are identical

Test: Isomerism of organic compounds - Question 7

The number of structural isomers for C6H12 is:

Detailed Solution for Test: Isomerism of organic compounds - Question 7


Total 5 structural isomers

Test: Isomerism of organic compounds - Question 8

Which one of the following pairs of compounds are functional isomers?

Detailed Solution for Test: Isomerism of organic compounds - Question 8

In option (d) there are two different functional groups i.e., −OH and −O−. So, these are functional isomers.

Test: Isomerism of organic compounds - Question 9

Which of the following optically active compounds racemizes in dil. KOH/CH3OH solution?

Detailed Solution for Test: Isomerism of organic compounds - Question 9

The compounds containing
group adjacent to asymmetric carbon atom carrying a hydrogen easily racemise.

Test: Isomerism of organic compounds - Question 10

The correct number of chiral centres in

Detailed Solution for Test: Isomerism of organic compounds - Question 10

The molecule contains two similar chiral centres.

Test: Isomerism of organic compounds - Question 11

An optically active compound (A) is treated with NaI in acetone to form compound (B). Determine the optical activity of compound (B).

Detailed Solution for Test: Isomerism of organic compounds - Question 11

1. Reaction type: Nal in acetone is an SN2 reaction.
2. Mechanism: SN2 causes inversion of configuration at the chiral center.
3. Outcome: Inversion of configuration retains optical activity.

Test: Isomerism of organic compounds - Question 12

Which of the following is correct set of physical properties of the geometrical isomers?

Detailed Solution for Test: Isomerism of organic compounds - Question 12

In the field of chemistry, the two types of geometric isomers that are encountered most frequently are those that originate from a double bond and those that originate from a ring structure. Both cis and trans geometric isomers have distinct differences in their physical characteristics, such as their densities, boiling points, melting points, reactivities, and solubilities.
In our case,
Dipole moment: I < II
Boiling point: I < II
Melting point: I < II
Stability: I < II

Test: Isomerism of organic compounds - Question 13

A solution of (+)−2 - chloro −2 - phenylethane in toluene racemises slowly in the presence of small amounts of SbCl5 due to the formation of

Detailed Solution for Test: Isomerism of organic compounds - Question 13

SbCl5 pulls Cl to form SbCl6 leaving behind planar C6H− CH+ − CH3 carbonium ion. It can be attacked from either side leading to racemic mixture.

Test: Isomerism of organic compounds - Question 14

The number of optical isomers possible for 2- Bromo-3-Chlorobutane are

Detailed Solution for Test: Isomerism of organic compounds - Question 14

The number of optical isomers possible for 2 - Bromo-3 - Chlorobutane are

Test: Isomerism of organic compounds - Question 15

How many cyclic structures are possible for C4H6 ?

Detailed Solution for Test: Isomerism of organic compounds - Question 15

Five cyclic structures are possible for C4H6. These are as following:

Test: Isomerism of organic compounds - Question 16

Which one of the following compounds will not show geometrical isomerism?

Detailed Solution for Test: Isomerism of organic compounds - Question 16

Prop-2-enoic acid will not show geometrical isomerism. Geometrical isomers occur where we have restricted rotation somewhere in a molecule, between carbon atoms like - but-2-ene.

Prop-2-eneonic acid does not show geometrically isomerism.

Test: Isomerism of organic compounds - Question 17

Geometrical isomerism can be found in which of the following?

Detailed Solution for Test: Isomerism of organic compounds - Question 17

No olefinic is present in butyric acid , aspartic acid
and palmitic acid .
Cinnamic acid is able to show geometrical isomerism.

Test: Isomerism of organic compounds - Question 18

In the following structure, the double bonds are marked as I, II, III and IV. Geometrical isomerism is not present at site (s) :

Detailed Solution for Test: Isomerism of organic compounds - Question 18

The site I contains two identical CH3 groups attached to double bond. This site will not show geometrical isomerism.

Test: Isomerism of organic compounds - Question 19

What is the increasing order of stability of the three main conformations (i.e., Eclipse, Anti, Gauche) of 2-fluoroethanol ?

Detailed Solution for Test: Isomerism of organic compounds - Question 19


Gauche conformation is comparatively more stable due to hydrogen linkage in between F and H (at O-atom), hence order is Eclipse, Anti (staggered), Gauche.

Test: Isomerism of organic compounds - Question 20

In open chain structure, how many chiral carbon atoms in D-(-)-Ribose ?

Detailed Solution for Test: Isomerism of organic compounds - Question 20

Structure of D-(-)-Ribose is:

The number of chiral carbon atoms is 3.

Information about Test: Isomerism of organic compounds Page
In this test you can find the Exam questions for Test: Isomerism of organic compounds solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Isomerism of organic compounds, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE